·¢ÉúÌìÈ»Æø¾®ÅçʹÊÖÐÅç·¢³öµÄÌìÈ»Æøº¬ÓÐÁò»¯ÇâÆøÌ壬ÇëÄãÓÃѧµ½µÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Îª·ÀÖ¹¾®ÅçʹÊÖиü´óµÄÈËÔ±ÉËÍö£¬ÇÀ¾ÈÈËÔ±Óû²ÉÓõã»ðȼÉÕ·½·¨À´³ýÈ¥Óж¾ÆøÌ壬ÊÔд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                      

£¨2£©ÔÚʯÓÍ×ê¾®ÖУ¬Îª·ÀÖ¹¾®Åçʹʣ¬Òª¸ù¾Ý¾®ÏÂѹǿ£¬½«Öؾ§Ê¯£¨ÃܶÈ4.5g/cm3×óÓÒ£©ÓëÄཬ°´Ò»¶¨±ÈÀý»ìºÏºó¹àÈë¾®ÖС£Ð´³öÖؾ§Ê¯µÄ»¯Ñ§Ê½             ÊÔ˵Ã÷Öؾ§Ê¯·Û×öѹ¾®²ÄÁϵÄÔ­Òò                                   

£¨3£©º¬ÁòµØÇø×ê¾®ÒºµÄpHÖµÓ¦¿ØÖÆ9.5ÒÔÉÏ£¬ÈôÓÃÇâÑõ»¯ÄÆÈÜÒº×ö¿ØÖÆÒº£¬Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ                   

 

£¨1£©2H2S + 3O2¡ú 2SO2 + 2H2O

£¨2£©BaSO4   £»   Ãܶȴó

£¨3£©H2S + 2NaOH ¡ú Na2S+ H2O

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

2003Äê12ÔÂ23ÈÕ£¬´¨¶«±±Ä³ÌìÈ»Æø¿ó¾®·¢ÉúÌØ´ó¡°¾®Å硱£¬º¬ÓдóÁ¿Áò»¯ÇâµÄÌìÈ»ÆøÒݳö£¬Ôì³É243ÈËËÀÍöµÄÖØ´óʹʣ¬Áò»¯Ç⣨H2S£©ÊÇÒ»ÖÖÎÞÉ«Óгô¼¦µ°ÆøζµÄ¾ç¶¾ÆøÌ壬¿ÉÈÜÓÚË®£¬ÓпÉȼÐÔ£¬ÍêȫȼÉÕÉú³É¶þÑõ»¯ÁòºÍË®£®
Çë¸ù¾ÝÒÔÉÏÐÅÏ¢£¬½áºÏѧ¹ýµÄ֪ʶ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ê¹ʷ¢Éúºó£¬Èô¼°Ê±²ÉÈ¡¶ÔÒݳöÆøÌåµã»ðȼÉյĴëÊ©£¬¿ÉÒÔ¼õÉÙ¶ÔÈËÔ±µÄΣº¦ºÍËÀÍö£®Ð´É½ÒݳöÆøÌåÍêȫȼÉյĻ¯Ñ§·½³Ì£º
2H2S+3O2
 µãȼ 
.
 
2SO2+2H2O
2H2S+3O2
 µãȼ 
.
 
2SO2+2H2O
£®
£¨2£©ÓõãȼµÄ·½·¨¿É³ýÈ¥H2SÆøÌ壬µ«Éú³ÉµÄ¶þÑõ»¯ÁòÓÖ¿ÉÄÜÔì³ÉµÄΣº¦ÊÇ
ËáÓê
ËáÓê
£®
£¨3£©×¨¼ÒÌáÐÑ£º·¢ÉúH2SÆøÌåй©ʱ£¬¿ÉÓÃʪë½íÎæס±Ç×ÓѸËÙÀ뿪ÏÖ³¡£®ÕâÀû×ö·¨µÄÀíÓÉÊÇ
H2SÆøÌå¿ÉÈÜÓÚË®£¬ÕâÖÖ×ö·¨¿É¼õÉÙÓж¾ÆøÌåµÄÎüÈë
H2SÆøÌå¿ÉÈÜÓÚË®£¬ÕâÖÖ×ö·¨¿É¼õÉÙÓж¾ÆøÌåµÄÎüÈë
£®
£¨4£©¡°¾®Å硱ʹʷ¢Éúºó£¬´åÃñËäÒÑÎŵ½ÃÖÂþÔÚ¿ÕÆøÖеijô棬µ«Ö±µ½¼¸Ð¡Ê±ºó£¬´å¸É²¿Í¨ÖªËûÃÇѸËÙ³·À룬²ÅÒâʶµ½Î£ÏÕ£®¶Ô´Ë£¬Äã¶Ôѧϰ»¯Ñ§ÖªÊ¶ÓкθÐÏ룺
ѧϰ»¯Ñ§ÖªÊ¶£¬¶Ô±£»¤×Ô¼ººÍËûÈËÉúÃüÒâÒåÖØ´ó
ѧϰ»¯Ñ§ÖªÊ¶£¬¶Ô±£»¤×Ô¼ººÍËûÈËÉúÃüÒâÒåÖØ´ó
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÉϺ£Êпؽ­ÖÐѧ¸ßÒ»µÚ¶þѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

·¢ÉúÌìÈ»Æø¾®ÅçʹÊÖÐÅç·¢³öµÄÌìÈ»Æøº¬ÓÐÁò»¯ÇâÆøÌ壬ÇëÄãÓÃѧµ½µÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Îª·ÀÖ¹¾®ÅçʹÊÖиü´óµÄÈËÔ±ÉËÍö£¬ÇÀ¾ÈÈËÔ±Óû²ÉÓõã»ðȼÉÕ·½·¨À´³ýÈ¥Óж¾ÆøÌ壬ÊÔд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                      
£¨2£©ÔÚʯÓÍ×ê¾®ÖУ¬Îª·ÀÖ¹¾®Åçʹʣ¬Òª¸ù¾Ý¾®ÏÂѹǿ£¬½«Öؾ§Ê¯£¨ÃܶÈ4.5g/cm3×óÓÒ£©ÓëÄཬ°´Ò»¶¨±ÈÀý»ìºÏºó¹àÈë¾®ÖС£Ð´³öÖؾ§Ê¯µÄ»¯Ñ§Ê½             ÊÔ˵Ã÷Öؾ§Ê¯·Û×öѹ¾®²ÄÁϵÄÔ­Òò                                   
£¨3£©º¬ÁòµØÇø×ê¾®ÒºµÄpHÖµÓ¦¿ØÖÆ9.5ÒÔÉÏ£¬ÈôÓÃÇâÑõ»¯ÄÆÈÜÒº×ö¿ØÖÆÒº£¬Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ                   

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÉϺ£ÊиßÒ»µÚ¶þѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

·¢ÉúÌìÈ»Æø¾®ÅçʹÊÖÐÅç·¢³öµÄÌìÈ»Æøº¬ÓÐÁò»¯ÇâÆøÌ壬ÇëÄãÓÃѧµ½µÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Îª·ÀÖ¹¾®ÅçʹÊÖиü´óµÄÈËÔ±ÉËÍö£¬ÇÀ¾ÈÈËÔ±Óû²ÉÓõã»ðȼÉÕ·½·¨À´³ýÈ¥Óж¾ÆøÌ壬ÊÔд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                       

£¨2£©ÔÚʯÓÍ×ê¾®ÖУ¬Îª·ÀÖ¹¾®Åçʹʣ¬Òª¸ù¾Ý¾®ÏÂѹǿ£¬½«Öؾ§Ê¯£¨ÃܶÈ4.5g/cm3×óÓÒ£©ÓëÄཬ°´Ò»¶¨±ÈÀý»ìºÏºó¹àÈë¾®ÖС£Ð´³öÖؾ§Ê¯µÄ»¯Ñ§Ê½              ÊÔ˵Ã÷Öؾ§Ê¯·Û×öѹ¾®²ÄÁϵÄÔ­Òò                                   

£¨3£©º¬ÁòµØÇø×ê¾®ÒºµÄpHÖµÓ¦¿ØÖÆ9.5ÒÔÉÏ£¬ÈôÓÃÇâÑõ»¯ÄÆÈÜÒº×ö¿ØÖÆÒº£¬Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ                   

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

·¢ÉúÌìÈ»Æø¾®ÅçʹÊÖÐÅç·¢³öµÄÌìÈ»Æøº¬ÓÐÁò»¯ÇâÆøÌ壬ÇëÄãÓÃѧµ½µÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Îª·ÀÖ¹¾®ÅçʹÊÖиü´óµÄÈËÔ±ÉËÍö£¬ÇÀ¾ÈÈËÔ±Óû²ÉÓõã»ðȼÉÕ·½·¨À´³ýÈ¥Óж¾ÆøÌ壬ÊÔд³ö·´Ó¦µÄ»¯Ñ§·½³Ìʽ                                       

£¨2£©ÔÚʯÓÍ×ê¾®ÖУ¬Îª·ÀÖ¹¾®Åçʹʣ¬Òª¸ù¾Ý¾®ÏÂѹǿ£¬½«Öؾ§Ê¯£¨ÃܶÈ4.5g/cm3×óÓÒ£©ÓëÄཬ°´Ò»¶¨±ÈÀý»ìºÏºó¹àÈë¾®ÖС£Ð´³öÖؾ§Ê¯µÄ»¯Ñ§Ê½              ÊÔ˵Ã÷Öؾ§Ê¯·Û×öѹ¾®²ÄÁϵÄÔ­Òò                                   

£¨3£©º¬ÁòµØÇø×ê¾®ÒºµÄpHÖµÓ¦¿ØÖÆ9.5ÒÔÉÏ£¬ÈôÓÃÇâÑõ»¯ÄÆÈÜÒº×ö¿ØÖÆÒº£¬Ð´³ö·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ                   

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸