£¨6·Ö£©2008Äê±±¾©°ÂÔË»áËùÓûð¾æȼÁÏΪ±ûÍ飨C3H8£©£¬Ï¤Äá°ÂÔË»áËùÓûð¾æȼÁÏΪ65%¶¡Í飨C4H10£©ºÍ35%±ûÍ飨C3H8£©£¬ÒÑÖª³£ÎÂÏÂ1mol±ûÍéȼÉշųö2220kJÈÈÁ¿£¬1molÕý¶¡ÍéȼÉշųö2878kJÈÈÁ¿£¬1molÒ춡ÍéȼÉշųö2869.6kJÈÈÁ¿¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©±íʾÕý¶¡ÍéȼÉÕµÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ                                         £»
£¨2£©ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ       £»
A£®°ÂÔË»ð¾æȼÉÕʱµÄÄÜÁ¿×ª»¯Ö÷ÒªÊÇÓÉ»¯Ñ§ÄÜת±äΪÈÈÄÜ
B£®ÏàͬÌõ¼þÏ£¬Õý¶¡ÍéµÄÈÈÖµ±È±ûÍé´ó
C£®Õý¶¡Íé±ÈÒ춡Íé²»Îȶ¨
D£®Ò춡Íé·Ö×ÓÖеÄ̼Çâ¼ü±ÈÕý¶¡ÍéµÄ¶à
£¨3£©ÒÑÖª1mol H2ȼÉÕÉú³ÉҺ̬ˮ·Å³öÈÈÁ¿ÊÇ285.8 kJ£¬ÏÖÓÐ5mol ÇâÆøºÍ±ûÍéµÄ»ìºÏÆøÌ壬ÍêȫȼÉÕʱ·ÅÈÈ3847kJ£¬ÔòÇâÆøºÍ±ûÍéµÄÌå»ý±ÈΪ         ¡£
£¨1£©C4H10(Õý¶¡Í飬g) + 13/2O2(g)¡ú4CO2(g)+5H2O(l) ¡÷H=" -2878" kJ?mol-1_£¨2·Ö£¬ÆäËûºÏÀí´ð°¸¶¼¶Ô£©£»
£¨2£©A C£¨2·Ö£¬ÓдíÈ«¿Û£¬²»È«¿Û1·Ö£©£»
£¨3£©3:1£¨2·Ö£©
£¨2£©B£ºÓÉÌâÉèÌõ¼þ¿ÉÖªµ¥Î»ÖÊÁ¿µÄ±ûÍéÓëÕý¶¡ÍéȼÉշųöµÄÈÈÁ¿·Ö±ðΪ50.5kJºÍ49.6£»C£ºµÈÁ¿µÄÕý¶¡ÍéÓëÒ춡ÍéȼÉշųöµÄÈÈÁ¿Ç°Õߴ󣬹ÊÕý¶¡Íé×ÔÉíµÄÄÜÁ¿´ó£¬Ïà¶Ô²»Îȶ¨¡£D£ºÁ½ÕßµÄ̼Çâ¼üÊýÄ¿Ïàͬ¡£
£¨3£©ÉèÇâÆøΪxmol£¬Ôò285.8x £« 2220¡Á£¨5¡ªx£©=3847£¬Çó½â¼´¿É
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚ25 ¡æ¡¢101 kPaÏ£¬1 g¼×´¼(CH3OH)ȼÉÕÉú³ÉCO2ºÍҺ̬ˮʱ·ÅÈÈ22.68 kJ¡£ÏÂÁÐÈÈ»¯Ñ§·½³ÌʽÕýÈ·µÄÊÇ
A£®CH3OH(l)£«3/2O2(g)===CO2(g)£«2H2O(l)¦¤H£½£«725.8 kJ¡¤mol£­1
B£®2CH3OH(l)£«3O2(g)===2CO2(g)£«4H2O(l)¦¤H£½£­1452 kJ¡¤mol£­1
C£®2CH3OH(l)£«3O2(g)===2CO2(g)£«4H2O(l)¦¤H£½£­725.8 kJ¡¤mol£­1
D£®2CH3OH(l)£«3O2(g)===2CO2(g)£«4H2O(l)¦¤H£½£«1452 kJ¡¤mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºÌî¿ÕÌâ

ÁÐÁ½¸öÈÈ»¯Ñ§·½³Ìʽ£º2H2£¨g£©+O2£¨g£©==H2O£¨l£©£»¡÷H=" ¡ª" 571.6KJ/mol£¬
C3H8£¨g£©+5O2£¨g£©==3CO2£¨g£©+4H2O£¨l£©£»¡÷H= ¡ª2220.0KJ/mol£¬
¢ÅH2µÄȼÉÕÈÈΪ                        £¬
¢ÆʵÑé²âµÃH2ºÍC3H8µÄ»ìºÏÆøÌå¹²5mol£¬ÍêȫȼÉÕÉú³ÉҺ̬µÄˮʱ·ÅÈÈ6264.5KJ£¬Ôò»ìºÏÆøÌåÖÐH2ºÍC3H8µÄÌå»ý±ÈÊÇ                ¡£
£¨3£©ÒÑÖªH2O£¨l£©==H2O£¨g£©¡÷H= +44KJ/molд³ö±ûÍéȼÉÕÉú³ÉCO2ºÍÆø̬ˮµÄÈÈ»¯Ñ§·½³Ìʽ£º                                                               ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

1840Ä꣬ÈðÊ¿»¯Ñ§¼Ò¸Ç˹(G£®H£®Hess)´Ó´óÁ¿µÄʵÑéÊÂʵÖÐ×ܽá³öÁËÒ»Ìõ¹æÂÉ£º»¯Ñ§·´Ó¦²»¹ÜÊÇÒ»²½Íê³É»¹ÊÇ·Ö¼¸²½Íê³É£¬Æä·´Ó¦ìʱäÊÇÏàͬµÄ£¬¼´¸Ç˹¶¨ÂÉ£®¸Ç˹¶¨ÂÉÔÚÉú²úºÍ¿ÆѧÑо¿ÖÐÓкÜÖØÒªµÄÒâÒ壬ÓÐЩ·´Ó¦µÄ·´Ó¦ìʱäËäÈ»ÎÞ·¨Ö±½Ó²âµÃ£¬µ«¿ÉÒÔÀûÓøÇ˹¶¨Âɼä½Ó¼ÆËãÇóµÃ£®ÒÑÖª3£®6 g̼ÔÚ6£®4 gÑõÆøÖÐȼÉÕ£¬ÖÁ·´Ó¦ÎïºÄ¾¡£®¹²·Å³öx kJÈÈÁ¿£®ÒÑÖªµ¥ÖÊ̼µÄȼÉÕÈÈΪÁËy kJ¡¤mol£­1£¬Ôò1 mol CÓëO2·´Ó¦Éú³ÉCOµÄ·´Ó¦ìʱä¡÷HΪ    ( ¡¡)
A£®£­y kJ¡¤mol£­1
B£®£­(10x£­y)kJ¡¤mol£­1
C£®£­(5x£­0£®5y)kJ¡¤mol£­1
D£®(10x£­y)kJ¡¤mol£­1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚ25¡æ101 kPaÏ£¬°×Á×£¨»¯Ñ§Ê½ÎªP4£©¡¢ºìÁ×£¨»¯Ñ§Ê½ÎªP£©È¼ÉÕµÄÈÈ»¯Ñ§·½³Ì
ʽ·Ö±ðΪ£ºP4£¨s£©+5O2£¨g£©= P4O10£¨s£©£»¡÷H = £­3093.2 kJ/mol
4P£¨s£©+5O2£¨g£©= P4O10£¨s£©£»¡÷H = £­2954.0 kJ/mol
ÓÉ´ËÅжϣ¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨£©
A£®ÓɺìÁ×ת»¯Îª°×Á×ÊÇÎüÈÈ·´Ó¦£¬µÈÖÊÁ¿Ê±ºìÁ×ÄÜÁ¿±È°×Á׸ß
B£®ÓɺìÁ×ת»¯Îª°×Á×ÊÇ·ÅÈÈ·´Ó¦£¬µÈÖÊÁ¿Ê±ºìÁ×ÄÜÁ¿±È°×Á×µÍ
C£®ÓɺìÁ×ת»¯Îª°×Á×ÊÇ·ÅÈÈ·´Ó¦£¬µÈÖÊÁ¿Ê±ºìÁ×ÄÜÁ¿±È°×Á׸ß
D£®ÓɺìÁ×ת»¯Îª°×Á×ÊÇÎüÈÈ·´Ó¦£¬µÈÖÊÁ¿Ê±ºìÁ×ÄÜÁ¿±È°×Á×µÍ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖª£º¢Ù C (s) + O2 (g)     CO (g) ¡÷H =" ¨C" 110.5 kJ ¡¤ mol ¨C 1
¢Ú C (s) + O2 (g)     CO2 (g)  ¡÷H =" ¨C" 393.51 kJ ¡¤ mol ¨C 1
Ôò·´Ó¦£ºC (s) + CO2 (g)     2CO (g) µÄ¡÷HΪ£¨   £©
A£®¨C 283.01 kJ ¡¤ mol ¨C 1B£®+ 172.51 kJ ¡¤ mol ¨C1
C£®+ 283.01 kJ ¡¤ mol ¨C 1D£®+ 504.00 kJ ¡¤ mol ¨C 1

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÔÚ298 K  101 kPaʱ£¬ÒÑÖª£º2H2 (g) + O2 (g) = 2H2O(g) ¦¤H1£»Cl2 (g) + H2 (g) =" 2HCl(g)" ¦¤H2£»2Cl2(g) + 2H2O(g) =" 4HCl(g)" + O2 (g) ¦¤H3£»Ôò¦¤H3Ó릤H1ºÍ¦¤H2¼äµÄ¹ØϵÕýÈ·µÄÊÇ
A£®¦¤H3 =¦¤H1 + 2¦¤H2B£®¦¤H3 =¦¤H1 +¦¤H2
C£®¦¤H3 = 2¦¤H2£­¦¤H1D£®¦¤H3 =¦¤H1£­¦¤H2

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÒÑÖª1gÇâÆøȼÉÕÉú³ÉҺ̬ˮʱ·Å³ö142.9KJÈÈÁ¿£¬Ôò·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ
A£®H2(g) + O2(g) ="=" H2O(l)£»¡÷H= ¡ª142.9kJ/mol
B£®2H2(g) + O2(g) ="=" 2H2O(l)£»¡÷H= 571.6kJ/mol
C£®2H2(g) + O2(g) ="=" 2H2O(l)£»¡÷H= ¡ª571.6kJ/mol
D£®2H2 + O2 ="=" 2H2O£»¡÷H= ¡ª571.6kJ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º²»Ïê ÌâÐÍ£ºµ¥Ñ¡Ìâ

ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ    (     )
A£®Ä³·´Ó¦ÔÚµÍÎÂÌõ¼þÏÂÄÜ×Ô·¢½øÐУ¬ÄÇô¸Ã·´Ó¦ÔÚ¸ßÎÂÌõ¼þÏÂÒ²Ò»¶¨ÄÜ×Ô·¢½øÐÐ
B£®Ä³·´Ó¦ÔÚ¸ßÎÂÌõ¼þϲ»ÄÜ×Ô·¢½øÐУ¬ÄÇô¸Ã·´Ó¦ÔÚµÍÎÂÌõ¼þÏÂÒ²Ò»¶¨²»ÄÜ×Ô·¢½øÐÐ
C£®·´Ó¦·½ÏòÊÇÓÉìʱäºÍìر乲ͬ¾ö¶¨µÄ£¬Ó뷴ӦζÈÎÞ¹Ø
D£®Î¶ÈÓпÉÄܶԷ´Ó¦µÄ·½ÏòÆð¾ö¶¨ÐÔ×÷ÓÃ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸