Question

15£®Ò»¶¨Î¶ÈÏ£¬½«3molAÆøÌåºÍ1molBÆøÌåͨÈëÒ»ÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÈçÏ·´Ó¦£º3A£¨g£©+B£¨g£©?xC£¨g£©£®ÇëÌîдÏÂÁпհףº
£¨1£©ÈôÈÝÆ÷Ìå»ý¹Ì¶¨Îª2L£¬·´Ó¦2minʱ²âµÃÊ£Óà0.6molB£¬CµÄŨ¶ÈΪ0.4mol/L£®
¢Ù2minÄÚ£¬AµÄƽ¾ù·´Ó¦ËÙÂÊΪ0.3mol/£¨L•min£©£»x=2£»
¢ÚÈô·´Ó¦¾­4min´ïµ½Æ½ºâ£¬Æ½ºâʱCµÄŨ¶ÈСÓÚ0.8mol/L £¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©£»
¢Ûƽºâ»ìºÏÎïÖÐCµÄÌå»ý·ÖÊýΪ22%£¬ÔòBµÄת»¯ÂÊÊÇ36%£»
£¨2£©Èôά³ÖÈÝÆ÷ѹǿ²»±ä£º
¢Ù´ïµ½Æ½ºâʱCµÄÌå»ý·ÖÊý´óÓÚ22%£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©£»
¢Ú¸Ä±äÆðʼÎïÖʼÓÈëµÄÁ¿£¬Óûʹ·´Ó¦´ïµ½Æ½ºâʱCµÄÎïÖʵÄÁ¿ÊÇԭƽºâµÄ2±¶£¬ÔòÓ¦¼ÓÈë6mol AÆøÌåºÍ2mol BÆøÌ壮

Answer 1

·ÖÎö £¨1£©¢Ù¼ÆËã²Î¼Ó·´Ó¦BµÄÎïÖʵÄÁ¿£¬ÔÙ¸ù¾Ý·½³Ìʽ¼ÆËã²Î¼Ó·´Ó¦AµÄÎïÖʵÄÁ¿£¬¸ù¾Ýv=$\frac{\frac{¡÷n}{V}}{¡÷t}$¼ÆËãv£¨A£©£»¸ù¾Ýn=cV¼ÆËãÉú³ÉCµÄÎïÖʵÄÁ¿£¬ÀûÓÃÎïÖʵÄÁ¿Ö®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È¼ÆËãx£»
¢ÚËæ×Å·´Ó¦µÄ½øÐУ¬·´Ó¦ËÙÂÊÖð½¥¼õС£¬Èô·´Ó¦¾­4min´ïµ½Æ½ºâ£¬ºó2minµÄƽ¾ùËÙÂÊСÓÚÇ°2minµÄƽ¾ùËÙÂÊ£¬ºó2minÄÚCµÄŨ¶È±ä»¯Ð¡ÓÚ0.4mol/L£»
¢Ûƽºâ»ìºÏÎïÖУ¬CµÄÌå»ý·ÖÊýΪ22%£¬Éèת»¯ÁËymolB£¬ÀûÓÃÈý¶Îʽ±íʾ³öƽºâʱ¸÷×é·ÖµÄÎïÖʵÄÁ¿£¬ÀûÓÃCµÄÌå»ý·ÖÊýÁз½³Ì¼ÆËãy£¬½ø¶ø¼ÆËãBµÄת»¯ÂÊ£»
£¨2£©¢ÙÈôά³ÖÈÝÆ÷ѹǿ²»±ä£¬ÅжÏÌõ¼þÌå»ý±ä»¯£¬µÈЧΪѹǿ±ä»¯£¬·ÖÎöƽºâÒƶ¯·½Ïò£»
¢ÚÈôά³ÖÈÝÆ÷ѹǿ²»±ä£¬¸Ä±äÆðʼÎïÖʼÓÈëµÄÁ¿£¬Óûʹ·´Ó¦´ïµ½Æ½ºâʱCµÄÎïÖʵÄÁ¿ÊÇԭƽºâµÄ2±¶£¬ÓëԭƽºâµÈЧ£¬·´Ó¦Îïת»¯ÂÊÏàµÈ£¬Ó¦Âú×ãA¡¢BµÄÎïÖʵÄÁ¿Ö®±ÈÓë³õʼÅä±ÈÊýÏàµÈÇÒΪԭÀ´µÄ2±¶£®

½â´ð ½â£º£¨1£©·´Ó¦2minʱ²âµÃÊ£Óà0.6mol B£¬Ôò²Î¼Ó·´Ó¦µÄBΪ1mol-0.6mol=0.4mol£¬ÓÉ·½³Ìʽ¿ÉÖª²Î¼Ó·´Ó¦µÄAΪ0.4mol¡Á3=1.2mol£¬¹Êv£¨A£©=$\frac{\frac{1.2mol}{2L}}{2min}$=0.3mol/£¨L•min£©£¬
CµÄŨ¶ÈΪ0.4mol/L£¬ÔòÉú³ÉCµÄÎïÖʵÄÁ¿=2L¡Á0.4mol/L=0.8mol£¬Ôò0.4mol£º0.8mol=1£ºx£¬½âµÃ£ºx=2£¬
¹Ê´ð°¸Îª£º0.3mol/£¨L•min£©£»2£»
¢ÚËæ×Å·´Ó¦µÄ½øÐУ¬·´Ó¦ËÙÂÊÖð½¥¼õС£¬Èô·´Ó¦¾­4min´ïµ½Æ½ºâ£¬ºó2minµÄƽ¾ùËÙÂÊСÓÚÇ°2minµÄƽ¾ùËÙÂÊ£¬Ç°2minÄÚCµÄŨ¶È±ä»¯Îª0.4mol/L£¬Ôòºó2minÄÚCµÄŨ¶È±ä»¯Ð¡ÓÚ0.4mol/L£¬¹ÊƽºâʱCµÄŨ¶ÈСÓÚ0.8mol/L£¬
¹Ê´ð°¸Îª£ºÐ¡ÓÚ£»
¢Ûƽºâ»ìºÏÎïÖУ¬CµÄÌå»ý·ÖÊýΪ22%£¬Éèת»¯ÁËxmolB£¬ÔòÓУº
           3A£¨g£©+B£¨g£©¨T2C£¨g£©
Æðʼ£¨mol£©£º3       1       0
ת»¯£¨mol£©£º3x      x      2x
ƽºâ£¨mol£©£º3-3x  1-x      2x
Ôò£º$\frac{2x}{3-3x+1-x2+x}$=22%£¬½âµÃ£ºx=0.36£¬
ÔòBµÄת»¯ÂÊÊÇ£º$\frac{0.36mol}{1mol}$¡Á100%=18%£¬
¹Ê´ð°¸Îª£º36%£»
£¨2£©¢ÙÈÝÆ÷Ìå»ý¹Ì¶¨Ê±CµÄÌå»ý·ÖÊýΪ22%£¬Èôά³ÖÈÝÆ÷ѹǿ²»±ä£¬Ó¦ËõСÌå»ý£¬µÈЧΪÔö´óѹǿ£¬Æ½ºâÏòÕý·½ÏòÒƶ¯£¬Ôò´ïµ½Æ½ºâʱCµÄÌå»ý·ÖÊý´óÓÚ22%£¬
¹Ê´ð°¸Îª£º´óÓÚ£»
¢ÚÈôά³ÖÈÝÆ÷ѹǿ²»±ä£¬¸Ä±äÆðʼÎïÖʼÓÈëµÄÁ¿£¬Óûʹ·´Ó¦´ïµ½Æ½ºâʱCµÄÎïÖʵÄÁ¿ÊÇԭƽºâµÄ2±¶£¬ÓëԭƽºâµÈЧ£¬·´Ó¦Îïת»¯ÂÊÏàµÈ£¬Ó¦Âú×ãA¡¢BµÄÎïÖʵÄÁ¿Ö®±ÈÓë³õʼÅä±ÈÊýÏàµÈÇÒΪԭÀ´µÄ2±¶£¬ÔòÓ¦¼ÓÈë6molA£¬2molB£¬
¹Ê´ð°¸Îª£º6£»2£®

µãÆÀ ±¾Ìâ×ۺϿ¼²é»¯Ñ§Æ½ºâµÄ¼ÆË㣬ÌâÄ¿ÄѶÈÖеȣ¬Ã÷È·»¯Ñ§Æ½ºâ¼°ÆäÓ°ÏìΪ½á¹¹¼þ£¬×¢ÒâÀûÓÃÈý¶Îʽ·¨½â´ð¸ÃÌ⣬Ò×´íµãΪ£¨2£©£¬×¢ÒâµÈЧƽºâµÄÀí½âºÍÓ¦Óã¬ÊÔÌâÅàÑøÁËѧÉúµÄ»¯Ñ§¼ÆËãÄÜÁ¦£®