£¨ 10·Ö  £©A~I·Ö±ð±íʾÖÐѧ»¯Ñ§Öг£¼ûµÄÒ»ÖÖÎïÖÊ£¬ÆäÖÐA¡¢IΪ³£¼û½ðÊô£¬ËüÃÇÖ®¼äµÄÏ໥¹ØϵÈçͼËùʾ£¨²¿·Ö·´Ó¦Îï¡¢Éú³ÉÎïûÓÐÁгö£©£¬ÇÒÒÑÖªGΪÖ÷×åÔªËصĹÌ̬Ñõ»¯ÎA¡¢B¡¢C¡¢D¡¢E¡¢FÁù¸÷ÎïÖÊÖоùº¬Í¬Ò»ÖÖÔªËØ£¬FÊǺìºÖÉ«¹ÌÌå¡£

ÇëÌîдÏÂÁпհףº

£¨1£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖÐËùº¬µÄͬһÖÖÔªËØÊÇ                         ¡£

£¨2£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ»òÀë×Ó·½³Ìʽ£º

·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º                                               £»

·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£º                                               £»

·´Ó¦¢ÞµÄ»¯Ñ§·½³Ìʽ£º                                               £»

£¨3£©´ÓÄÜÁ¿±ä»¯µÄ½Ç¶È¿´£¬·´Ó¦¢Ù¢Ú¢ÛÖУ¬ÊôÓÚ¡÷H£¼0µÄ·´Ó¦ÊÇ         £¨ÌîÐòºÅ£©¡£

 

¡¾´ð°¸¡¿

£¨10·Ö£¬Ã¿¿Õ2·Ö£©

£¨1£©Ìú£¨»òFe£©£¨2£©8Al+3Fe3O4 4Al2O3+9Fe

2Al+2OH- +2H2O =2AlO2-+3H2¡ü  4Fe(OH)2+O2+2H2O=4Fe(OH) (3) ¢Ù¢Ú

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨ 10·Ö  £©A~I·Ö±ð±íʾÖÐѧ»¯Ñ§Öг£¼ûµÄÒ»ÖÖÎïÖÊ£¬ÆäÖÐA¡¢IΪ³£¼û½ðÊô£¬ËüÃÇÖ®¼äµÄÏ໥¹ØϵÈçͼËùʾ£¨²¿·Ö·´Ó¦Îï¡¢Éú³ÉÎïûÓÐÁгö£©£¬ÇÒÒÑÖªGΪÖ÷×åÔªËصĹÌ̬Ñõ»¯ÎA¡¢B¡¢C¡¢D¡¢E¡¢FÁù¸÷ÎïÖÊÖоùº¬Í¬Ò»ÖÖÔªËØ£¬FÊǺìºÖÉ«¹ÌÌå¡£

ÇëÌîдÏÂÁпհףº

£¨1£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖÐËùº¬µÄͬһÖÖÔªËØÊÇ                        ¡£

£¨2£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ»òÀë×Ó·½³Ìʽ£º

·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º                                              £»

·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£º                                              £»

·´Ó¦¢ÞµÄ»¯Ñ§·½³Ìʽ£º                                              £»

£¨3£©´ÓÄÜÁ¿±ä»¯µÄ½Ç¶È¿´£¬·´Ó¦¢Ù¢Ú¢ÛÖУ¬ÊôÓÚ¡÷H£¼0µÄ·´Ó¦ÊÇ         £¨ÌîÐòºÅ£©¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ìɽ¶«Ý·ÏØʵÑé¸ßÖиßÈýµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨ 10·Ö £©A~I·Ö±ð±íʾÖÐѧ»¯Ñ§Öг£¼ûµÄÒ»ÖÖÎïÖÊ£¬ÆäÖÐA¡¢IΪ³£¼û½ðÊô£¬ËüÃÇÖ®¼äµÄÏ໥¹ØϵÈçͼËùʾ£¨²¿·Ö·´Ó¦Îï¡¢Éú³ÉÎïûÓÐÁгö£©£¬ÇÒÒÑÖªGΪÖ÷×åÔªËصĹÌ̬Ñõ»¯ÎA¡¢B¡¢C¡¢D¡¢E¡¢FÁù¸÷ÎïÖÊÖоùº¬Í¬Ò»ÖÖÔªËØ£¬FÊǺìºÖÉ«¹ÌÌå¡£

ÇëÌîдÏÂÁпհףº
£¨1£©A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖÎïÖÊÖÐËùº¬µÄͬһÖÖÔªËØÊÇ                        ¡£
£¨2£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ»òÀë×Ó·½³Ìʽ£º
·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º                                              £»
·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£º                                              £»
·´Ó¦¢ÞµÄ»¯Ñ§·½³Ìʽ£º                                              £»
£¨3£©´ÓÄÜÁ¿±ä»¯µÄ½Ç¶È¿´£¬·´Ó¦¢Ù¢Ú¢ÛÖУ¬ÊôÓÚ¡÷H£¼0µÄ·´Ó¦ÊÇ        £¨ÌîÐòºÅ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010-2011ѧÄêºÚÁú½­Ê¡¸ßÈýµÚÈý´Î¿¼ÊÔ£¨Àí×Û£©»¯Ñ§²¿·Ö ÌâÐÍ£ºÌî¿ÕÌâ

¢ñ(10·Ö)ÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖ¶ÌÖÜÆÚÔªËØ£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬AÔªËصÄÔ­×ÓÊǰ뾶×îСµÄÔ­×Ó¡£BÔªËصÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÓëÆäÇ⻯Îï·´Ó¦Éú³ÉÒ»ÖÖÑÎX£¬DÓëAͬ×壬ÇÒÓëEͬÖÜÆÚ£¬EÔªËصÄ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3£¯4±¶¡£A¡¢B¡¢D¡¢EÕâËÄÖÖÔªËØ£¬Ã¿Ò»ÖÖ¶¼ÄÜÓëCÔªËØÐγÉÔ­×Ó¸öÊý±È²»ÏàͬµÄ¶àÖÖ»¯ºÏÎï¡£»Ø´ðÏÂÁÐÎÊÌ⣺

(1)д³öÏàÓ¦ÔªËØ·ûºÅ£¬A        B        C         E      

(2)ÓÉA¡¢C¡¢D¡¢EËÄÖÖÔªËØËù×é³ÉµÄÒ»ÖÖÖÐѧ³£¼ûµÄ»¯ºÏÎËü¼ÈÄÜÓëÑÎËá·´Ó¦£¬ÓÖÄÜÓëNaOHÈÜÒº·´Ó¦£¬ÔÚÕâÖÖ»¯ºÏÎïµÄË®ÈÜÒºÖУ¬µÎÈË×ÏɫʯÈïÊÔÒºÈÜÒº³ÊºìÉ«£¬ÔòÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄÅÅÁÐ˳ÐòΪ£º                              ¡£

(3)½«ÂÁƬºÍþƬ²åÈëÓÉA¡¢C¡¢DÈýÖÖÔªËØ×é³ÉÎïÖʵÄÏ¡ÈÜÒºÖй¹³ÉÔ­µç³Ø£¬Ôò¸º¼«µÄµç¼«·´Ó¦Ê½Îª                                ¡£

¢ò(5·Ö)ÒÑÖªXÊÇÒ»ÖÖÑΣ¬HÊdz£¼û½ðÊôµ¥ÖÊ£¬F¡¢IÊdz£¼û·Ç½ðÊôµ¥ÖÊ£¬E¡¢G¶¼Êǹ¤ÒµÉÏÖØÒªµÄ¼îÐÔÎïÖÊ£¬ËüÃÇÓÐÓÒͼËùʾµÄ¹Øϵ¡£

ÊԻشðÏÂÁÐÎÊÌâ

(1)GµÄ»¯Ñ§Ê½Îª£º                                  

(2)д³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ

¢Ù                                  

¢Ú                                   

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(10·Ö)ÓÃA¡¢B¡¢C·Ö±ð±íʾº¬ÓÐ10¸öµç×ÓµÄ΢Á£(·Ö×Ó),D¡¢E¡¢F¡¢G·Ö±ð±íʾº¬ÓÐ18¸öµç×ÓµÄ΢Á£(·Ö×Ó),Çë»Ø´ð:
(1) ÆäÖÐAºÍDÊÇͬϵÎÔòDËÄÂÈ´úÎïÓР            Öֽṹ

   (2) BÓëEº¬ÓÐÏàͬµÄÔªËØ£¬BµÄË®ÈÜÒº³Ê¼îÐÔ£¬EÊÇÒ»ÖÖ»ð¼ýȼÁϵijɷ֣¬ÔòEµÄµç×Óʽ            

   (3) CÓëFº¬ÓÐÏàͬԪËØ£¬Ð´³öFÓëI-·´Ó¦µÄÀë×Ó·´Ó¦·½³Ìʽ

                                                                

(4) GÊÇÓÉÁ½ÖÖÔªËØ×é³ÉµÄÈýÔ­×Ó·Ö×Ó£¬Ïòº¬8.0g NaOHµÄÈÜÒºÖÐͨÈëÒ»¶¨Á¿Gºó£¬½«µÃµ½µÄÈÜҺСÐÄÕô¸É£¬³ÆµÃÎÞË®Îï7.9g£¬Ôò¸ÃÎÞË®ÎïÖÐÒ»¶¨º¬ÓеÄÎïÖÊÊÇ                 £¨Ìѧʽ£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸