ÏÂÁвÙ×÷²»ÄܴﵽĿµÄµÄÊÇ£¨ £©

Ñ¡ÏîÄ¿µÄ²Ù×÷

A.ÅäÖÆ100 mL 1.0 mol¡¤L-1 CuSO4ÈÜÒº½«25 g CuSO4¡¤5H2OÈÜÓÚ100 mLÕôÁóË®ÖÐ

B.³ýÈ¥KNO3ÖÐÉÙÁ¿NaCl½«»ìºÏÎïÖƳÉÈȵı¥ºÍÈÜÒº£¬ÀäÈ´½á¾§£¬¹ýÂË

C.ÌáÈ¡äåË®ÖеÄBr2ÏòÈÜÒºÖмÓÈëÒÒ´¼ºóÕñµ´£¬¾²Ö㬷ÖÒº

D.ÈÜÒºÖÐÊÇ·ñº¬ÓÐNH4£« È¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈëNaOHºó£¬¼ÓÈÈ£¬ÔÚÊԹܿڷÅÖÃÒ»¿éʪÈóµÄʯÈïÊÔÖ½

 

 

A¡¢C

¡¾½âÎö¡¿

ÊÔÌâ½âÎö£ºA¡¢²»Äܽ«ÈÜÖÊÒ»´ÎÐÔ¼ÓÈë100mlµÄË®ÖУ¬´íÎó£»B¡¢ÀûÓÃKNO3¡¢NaClµÄÈܽâ¶ÈÊÜζȱ仯ӰÏìµÄ²»Í¬£¬¿É½«¶þÕß·ÖÀ뿪À´£¬ÕýÈ·£»C¡¢ÒÒ´¼ÓëË®»¥Èܲ»ÄÜÝÍÈ¡äåË®ÖеÄä壬´íÎó£»D¡¢¼Ó¼îºó²úÉúʹºìɫʪÈóʯÈïÊÔÖ½±äÀ¶µÄÆøÌåÒ»¶¨ÊÇ°±Æø£¬´Ó¶ø¿ÉÒÔ¼ìÑéNH4£«£¬ÕýÈ·£¬´ð°¸Ñ¡A¡¢C¡£

¿¼µã£º¿¼²éÈÜÒºµÄÅäÖÆ¡¢³ýÔÓ¡¢·ÖÀë¡¢¼ìÑéµÄʵÑé֪ʶ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡ËÞǨÊиßÒ»ÉÏѧÆÚµÚ¶þ´ÎÔ¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÓйØÊÔ¼ÁµÄ±£´æ·½·¨£¬´íÎóµÄÊÇ

A£®½ðÊôÄƱ£´æÔÚúÓÍÖÐ

B£®´æ·ÅFeSO4ÈÜҺʱ¼ÓÈëÉÙÁ¿Ìú·Û

C£®NaOHÈÜÒº±£´æÔÚ´ø½ºÈûµÄ²£Á§ÊÔ¼ÁÆ¿ÖÐ

D£®ÐÂÖƵÄÂÈË®±£´æÔÚÎÞÉ«¹ã¿ÚÆ¿ÖÐ

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡ÄϾ©Êиߴ¾Çø¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁи÷×éÖеÄÀë×Ó£¬ÄÜÔÚÈÜÒºÖдóÁ¿¹²´æµÄÊÇ

A£®Na+¡¢Cu2+¡¢Cl-¡¢SO42- B£®Na+¡¢Ca2+¡¢CO32-¡¢NO3-

C£®Na+¡¢H+¡¢Cl-¡¢CO32- D£®K+¡¢H+¡¢SO42-¡¢OH-

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡ÄϾ©Êиߴ¾Çø¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÐÂÄêÒÁʼ£¬ÎÒ¹úÖж«²¿¸÷µØ½Ðø³öÏÖ´ó·¶Î§ºÍ³¤Ê±¼äÎíö²ÌìÆø£¬Ö÷ÒªÔ­ÒòÊÇÓÉÓÚ´óÆøÖÐPM2.5º¬Á¿Éý¸ßËùÔì³É£¬PM2.5ÊÇÖ¸´óÆøÖÐÖ±¾¶Ð¡ÓÚ»òµÈÓÚ2.5΢Ã×£¨1΢Ã×=10-6Ã×£©µÄ¿ÅÁ£Îï¡£ÆäÖÐPM2.5µÄÖ÷ÒªÀ´Ô´ÓëÆû³µÅŷŵÄβÆøÓйء£ÏÂÁÐÓйØÐðÊöÕýÈ·µÄÊÇ

A£®½ºÌåµÄ±¾ÖÊÌØÕ÷ÊǾßÓж¡´ï¶ûÏÖÏó

B£®½«Ö±¾¶µÈÓÚ2.5΢Ã׵ĿÅÁ£Îï·ÖÉ¢ÓÚË®¼´³ÉΪ½ºÌå

C£®Îí¾ßÓж¡´ï¶ûÏÖÏó

D£®Ôö¼ÓʹÓÃÆû³µ£¬Ìá¸ß½»Í¨Ð§ÂÊ¿É»º½âÎíö²ÌìÆøµÄ²úÉú

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡¶«Ì¨ÊиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

ÓйØÎïÖʼäת»¯¹ØϵÈçÏÂͼ£¬ÊԻشð£º

£¨1£©×ª»¯¢ÙµÄ·´Ó¦Ìõ¼þΪ .

£¨2£©×ª»¯¢ÚµÄ»¯Ñ§·½³ÌʽΪ .ת»¯¢ÛµÄÀë×Ó·½³ÌʽΪ .

£¨3£©Èôת»¯¢ÝÓÃÓÚʵÑéÊÒÖÆAl(OH)3£¬ÔòÊÔ¼ÁAÒËÑ¡Ôñ £¨ÌîÃû³Æ£©.

£¨4£©Ïò50 mL 3 mol¡¤L-1 AlCl3ÈÜÒºÖеμÓ1 mol¡¤L-1 NaOHÈÜÒº£¬½á¹ûAl3+Àë×ÓÓÐ1/3ת»¯ÎªAl(OH) 3³Áµí£¬Ôò¼ÓÈëµÄNaOHÈÜÒºµÄÌå»ý¿ÉÄÜΪ »ò mL¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡¶«Ì¨ÊиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÅäÖÆ250 mL 0.10 mol/LµÄNaOHÈÜҺʱ£¬ÏÂÁÐʵÑé²Ù×÷»áʹÅäµÃµÄÈÜҺŨ¶ÈƫСµÄÊÇ £¨ £©

A£®ÈÝÁ¿Æ¿Î´¸ÉÔï¾ÍÖ±½Ó¼ÓË®¶¨ÈÝ

B£®ÔÚÈÝÁ¿Æ¿ÖнøÐж¨ÈÝʱÑöÊӿ̶ÈÏß

C£®³ÆÁ¿µÄNaOH¹ÌÌåÒѳ±½â

D£®¶¨Èݺó°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ£¬·¢ÏÖÒºÃæµÍÓڿ̶È

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÊ¡¶«Ì¨ÊиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÐðÊöÖдíÎóµÄÊÇ£¨ £©

A£®Cl2¿ÉÓÃÓÚ×ÔÀ´Ë®µÄɱ¾úÏû¶¾ B£®³£ÎÂÏ£¬ÂÁÖÆÈÝÆ÷Ê¢·ÅÏ¡ÁòËá

C£®Al2O3ÐÔÖÊÓÃ×÷ÄÍ»ð²ÄÁÏ D£®¹èËáÄÆÓÃ×÷ľ²ÄµÄ·À»ð¼Á

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì½­ËÕÄϾ©ÊиßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ijÈÜÒºÖдæÔڽ϶àµÄH£«¡¢SO42£­¡¢C1£­£¬¸ÃÈÜÒºÖл¹¿ÉÄÜ´óÁ¿´æÔÚµÄÀë×ÓÊÇ

A£®OH£­ B£®Ba2£« C£®NH4£« D£®Ag+

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016½ì¹ã¶«Ê¡Ã·ÖÝÊиßÒ»ÉÏѧÆÚÖʼ컯ѧÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ÔªËØR¡¢X¡¢T¡¢Z¡¢QÔÚÔªËØÖÜÆÚ±íÖеÄÏà¶ÔλÖÃÈçϱíËùʾ£¬ ÆäÖÐRµ¥ÖÊÔÚ°µ´¦ÓëH2¾çÁÒ»¯ºÏ²¢·¢Éú±¬Õ¨¡£ÔòÏÂÁÐÅжÏÕýÈ·µÄÊÇ

A£®·Ç½ðÊôÐÔ£ºZ£¼T£¼X

B£®RÓëQµÄµç×ÓÊýÏà²î26

C£®Æø̬Ç⻯ÎïÎȶ¨ÐÔ£ºR £¼T£¼Q

D£®×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔ£ºT£¾Q

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸