äåÒÒÍ飨CH3CH2Br£©ÊÇÒ»ÖÖÄÑÈÜÓÚË®£¬ÃܶÈԼΪˮµÄÃܶȵÄ1.5±¶£¬·ÐµãΪ38.4 ¡æµÄÎÞÉ«ÒºÌ壬ʵÑéÊÒÓÉÒÒ´¼£¨CH3CH2OH£©ÖÆäåÒÒÍéµÄ·´Ó¦ÈçÏ£º

NaBr+H2SO4NaHSO4+HBr

CH3CH2OH+HBrCH3CH2Br+H2O

ÒÑÖª·´Ó¦ÎïµÄÓÃÁ¿£º0.3 mol NaBr(¹ÌÌå)¡¢0.25 molÒÒ´¼¡¢36 mLŨÁòËᣨ98%£¬ÃܶÈΪ1.84 g¡¤cm-3£©¡¢25 mLË®£¬ÆäÖÐÒÒ´¼µÄÃܶÈԼΪˮµÄÃܶȵÄ4/5¡£ÊԻشð£º

£¨1£©½öÓÃÏÂͼËùʾÒÇÆ÷À´°²×°ÖÆÈ¡ºÍÊÕ¼¯äåÒÒÍéµÄ×°Öã¬ÒªÇó´ïµ½°²È«¡¢ËðʧÉÙ¡¢²»ÎÛȾ»·¾³µÄÄ¿µÄ¡£ÓйØÒÇÆ÷µÄÑ¡ÔñºÍÁ¬½Ó˳ÐòΪ____________£¨ÌîÊý×Ö£©¡£

£¨2£©Ð´³ö²»ÄÜÑ¡ÓõÄÒÇÆ÷¼°ÀíÓÉ____________________¡£

£¨3£©·´Ó¦Ê±Èôζȹý¸ß£¬¿ÉÒԹ۲쵽ºì×ØÉ«ÆøÌåÉú³É£¬Ð´³ö´Ë·´Ó¦µÄ»¯Ñ§·½³Ìʽ_________

____________________¡£

£¨4£©ÓÃ×Ø»ÆÉ«µÄ´ÖäåÒÒÍéÖÆÈ¡ÎÞÉ«µÄäåÒÒÍéÓ¦¼ÓÈëµÄÊÔ¼ÁÊÇ___________£¬±ØÐëʹÓõÄÒÇÆ÷ÊÇ________¡£

£¨5£©±¾ÊµÑéµÄ²úÂÊΪ60%£¬Ôò¿ÉÖÆÈ¡äåÒÒÍé________g¡£

£¨1£©2  8  9  3  4  5

£¨2£©¼×£ºÈÝ»ýС£¬·´Ó¦Îﳬ¹ýÆäÈÝ»ýµÄ2/3£»Î죺²»ÀûÓÚÎüÊÕβÆø£¬Ò×Ôì³É»·¾³ÎÛȾ£¬²¢²úÉúµ¹Îü

£¨3£©2HBr+H2SO4(Ũ)Br2+SO2¡ü+2H2O

£¨4£©NaOHÈÜÒº  ·ÖҺ©¶· 

£¨5£©16.35

½âÎö£º£¨1£©¼×¡¢ÒÒÊÇ×÷ΪäåÒÒÍéµÄÖÆȡװÖù©Ñ¡Óõģ¬Ó¦¸Ã¿¼ÂÇʵÑéÖÐÒºÌåÌå»ýÓ¦½éÓÚÉÕÆ¿ÈÝ»ýµÄ1/3¡ª2/3ΪÒË¡£0.25 molÒÒ´¼µÄÌå»ýΪ0.25 mol¡Á46 g¡¤mol-1¡Á0.8 g¡¤cm-3¡Ö14 mL£¬ÈýÖÖÒºÌå»ìºÏºó£¬²»¿¼ÂÇ»ìºÏʱҺÌåµÄÌå»ý±ä»¯£¬ÔòV×Ü=36 mL+25 mL+14 mL=75 mL£¬ÕâÒ»Ìå»ý³¬¹ýÁ˼×ÈÝÆ÷ÈÝ»ýµÄ2/3£¬¹ÊӦѡÔñÒÒÈÝÆ÷¡£

£¨2£©ÓÉÓÚ²úÆ·£¨äåÒÒÍ飩µÄ·ÐµãµÍ£¬ÊÜÈÈʱ»á±»Õô³ö£¬¿¼Âǵ½äåÒÒÍé²»ÈÜÓÚË®ÇÒÃܶȱÈË®´ó£¬¹Ê¿ÉÓÃË®ÊÕ¼¯äåÒÒÍ飬´ËʱäåÒÒÍé³ÁÓÚË®µÄϲ㣬ˮÆðÒº·â×÷ÓúÍÀäÄý×÷Ó㬱ÜÃâäåÒÒÍé»Ó·¢£¨äåÒÒÍéÕôÆøÓж¾£©£¬Óɴ˿ɼûÊÕ¼¯äåÒÒÍé±ØÐëÒªÓÃÒÇÆ÷¼ººÍ¶¡£¬ÆäÖмºÁ¬½ÓÒÒ¡£

·´Ó¦ÖÐÓÉÓÚ¸±·´Ó¦µÄ·¢Éú»áµ¼ÖÂÕô³öµÄäåÒÒÍéÖлìÓÐäåÕôÆøºÍHBrÆøÌ壬ÕâÁ½ÖÖÆøÌåÓж¾£¬±ØÐëÎüÊÕÍêÈ«£¬HBr¼«Ò×ÈÜÓÚË®£¬ÎªÁËÓÐÀûÓÚÕôÆøµÄÎüÊÕ£¬·ÀÖ¹µ¹Îü£¬Ó¦Ñ¡Óñû¡£

£¨3£©·´Ó¦Î¶ȸߣ¬HBrºÍŨH2SO4»á·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬ºì×ØÉ«ÆøÌåΪäåÕôÆø¡£

£¨4£©´ÖäåÒÒÍé³ÊÏÖ×Ø»ÆÉ«ÊÇÓÉÓÚ»ìÓÐÁËBr2£¬Òª³ýÈ¥Br2£¬¿ÉÓÃNaOHÈÜÒºÎüÊÕ¡£

£¨5£©n(H2SO4)=36 mL¡Á1.84 g¡¤mL-1¡Á98%/98 g¡¤mol-1¡Ö0.66 mol£¬´ÓµÚÒ»¸ö·´Ó¦Ê½¿ÉÅжϳöHBrΪ0.3 mol£¬´ÓµÚ¶þ¸ö·´Ó¦Ê½ÅжϳöHBr¹ýÁ¿£¬CH3CH2BrµÄÎïÖʵÄÁ¿¸ù¾ÝCH3CH2OHÎïÖʵÄÁ¿È·¶¨£¬ËùÒÔCH3CH2BrÀíÂÛ²úÁ¿Îª0.25 mol¡Á109 g¡¤mol-1=27.25 g,äåÒÒÍéµÄʵ¼Ê²úÁ¿Îª27.25 g¡Á60%=16.35 g¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ijÐËȤС×éÔÚʵÑéÊÒÓüÓÈÈÒÒ´¼¡¢Å¨H2SO4¡¢ä廯ÄƺÍÉÙÁ¿Ë®µÄ»ìºÏÎïÀ´ÖƱ¸äåÒÒÍ飬¼ìÑé·´Ó¦µÄ²¿·Ö¸±²úÎ²¢Ì½¾¿äåÒÒÍéµÄÐÔÖÊ£®

£¨Ò»£©äåÒÒÍéµÄÖƱ¸¼°²úÎïµÄ¼ìÑ飺Éè¼ÆÁËÈçͼ1×°Öã¬ÆäÖмгÖÒÇÆ÷¡¢¼ÓÈÈÒÇÆ÷¼°ÀäÈ´Ë®¹ÜûÓл­³ö£®Çë¸ù¾ÝʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÒÇÆ÷AµÄÃû³ÆÊÇ
Èý¾±ÉÕÆ¿
Èý¾±ÉÕÆ¿
£®
£¨2£©ÖƱ¸²Ù×÷ÖУ¬¼ÓÈëµÄÉÙÁ¿µÄË®£¬ÆäÄ¿µÄÊÇ
abc
abc
£®£¨Ìî×Öĸ£©
a£®¼õÉÙ¸±²úÎïÏ©ºÍÃѵÄÉú³É           
b£®¼õÉÙBr2µÄÉú³É
c£®¼õÉÙHBrµÄ»Ó·¢              
d£®Ë®ÊÇ·´Ó¦µÄ´ß»¯¼Á£®
£¨3£©¼ÓÈÈƬ¿Ìºó£¬AÖеĻìºÏÎï³öÏֳȺìÉ«£¬¸Ã³ÈºìÉ«ÎïÖÊ¿ÉÄÜÊÇ
Br2
Br2
£®
£¨4£©ÀíÂÛÉÏ£¬ÉÏÊö·´Ó¦µÄ¸±²úÎﻹ¿ÉÄÜÓУºÒÒÃÑ£¨CH3CH2-O-CH2CH3£©¡¢ÒÒÏ©¡¢ä廯ÇâµÈ£®
¢Ù¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐä廯Ç⣺ϨÃð¾Æ¾«µÆ£¬ÔÚÊúÖ±ÀäÄý¹ÜÉÏ·½ÈûÉÏÈû×Ó¡¢´ò¿ªa£¬ÀûÓÃÓàÈȼÌÐø·´Ó¦Ö±ÖÁÀäÈ´£¬Í¨¹ýB¡¢C×°ÖüìÑ飮B¡¢CÖÐӦʢ·ÅµÄÊÔ¼Á·Ö±ðÊÇ
±½£¨»òËÄÂÈ»¯Ì¼µÈÓлúÈܼÁ£©
±½£¨»òËÄÂÈ»¯Ì¼µÈÓлúÈܼÁ£©
¡¢
ÏõËáÒø»òʯÈïÊÔÒº£¨´ð³öÒ»ÖÖ¼´¿É£©
ÏõËáÒø»òʯÈïÊÔÒº£¨´ð³öÒ»ÖÖ¼´¿É£©

¢Ú¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐÒÒÃÑ£ºÍ¨¹ýºìÍâ¹âÆ×ÒǼø¶¨ËùµÃ²úÎïÖк¬ÓС°-CH2CH3¡±»ùÍÅ£¬À´È·¶¨¸±²úÎïÖдæÔÚÒÒÃÑ£®ÇëÄã¶Ô¸ÃͬѧµÄ¹Ûµã½øÐÐÆÀ¼Û£º
²»ÕýÈ·£¬äåÒÒÍéÖÐÒ²º¬ÒÒ»ù
²»ÕýÈ·£¬äåÒÒÍéÖÐÒ²º¬ÒÒ»ù

£¨5£©Óû³ýÈ¥äåÒÒÍéÖеÄÉÙÁ¿ÔÓÖÊBr2£¬ÏÂÁÐÎïÖÊÖÐ×îÊʺϵÄÊÇ
c
c
£®£¨Ìî×Öĸ£©
a£®NaI           b£®NaOH            c£®NaHSO3           d£®KCl
£¨¶þ£©äåÒÒÍéÐÔÖʵÄ̽¾¿£º
ÓÃÈçͼ2ʵÑé×°Öã¨Ìú¼Ų̈¡¢¾Æ¾«µÆÂÔ£© ÑéÖ¤äåÒÒÍéµÄÐÔÖÊ£º
¢ñ£ºÔÚÊÔ¹ÜÖмÓÈë10mL6mol/L NaOHÈÜÒººÍ2mL äåÒÒÍ飬Õñµ´£®
¢ò£º½«ÊÔ¹ÜÈçͼ2Ëùʾ¹Ì¶¨ºó£¬Ë®Ô¡¼ÓÈÈ£®
£¨1£©¹Û²ìµ½
ÒºÌå²»·Ö²ã
ÒºÌå²»·Ö²ã
ÏÖÏóʱ£¬±íÃ÷äåÒÒÍéÓëNaOHÈÜÒºÒÑÍêÈ«·´Ó¦£®
£¨2£©ÎªÖ¤Ã÷äåÒÒÍéÔÚNaOHÒÒ´¼ÈÜÒºÖз¢ÉúµÄÊÇÏûÈ¥·´Ó¦£¬½«Éú³ÉµÄÆøÌåͨÈëÈçͼ3×°Öã®AÊÔ¹ÜÖеÄË®µÄ×÷ÓÃÊÇ
ÎüÊÕÒÒ´¼
ÎüÊÕÒÒ´¼
£¬ÈôÎÞAÊԹܣ¬BÊÔ¹ÜÖеÄÊÔ¼ÁӦΪ
äåË®
äåË®
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ijÐËȤС×éÔÚʵÑéÊÒÓüÓÈÈÒÒ´¼¡¢Å¨H2SO4¡¢ä廯ÄƺÍÉÙÁ¿Ë®µÄ»ìºÏÎïÀ´ÖƱ¸äåÒÒÍ飬¼ìÑé·´Ó¦µÄ²¿·Ö¸±²úÎ²¢Ì½¾¿äåÒÒÍéµÄÐÔÖÊ£®
¾«Ó¢¼Ò½ÌÍø
£¨Ò»£©äåÒÒÍéµÄÖƱ¸¼°²úÎïµÄ¼ìÑ飺Éè¼ÆÁËÈçͼ1×°Öã¬ÆäÖмгÖÒÇÆ÷¡¢¼ÓÈÈÒÇÆ÷¼°ÀäÈ´Ë®¹ÜûÓл­³ö£®Çë¸ù¾ÝʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊúÖ±ÀäÄý¹ÜÀäÄýË®Á÷Ïò
 
¿Ú½ø
 
¿Ú³ö£¬ÊúÖ±ÀäÄý¹ÜÀäÄýµÄ×÷ÓÃ
 
£®
£¨2£©ÖƱ¸²Ù×÷ÖУ¬¼ÓÈëµÄÉÙÁ¿µÄË®£¬ÆäÄ¿µÄÊÇ
 
£»£¨Ìî×Öĸ£©
a£®¼õÉÙ¸±²úÎïÏ©ºÍÃѵÄÉú³É        b£®¼õÉÙBr2µÄÉú³É
c£®¼õÉÙHBrµÄ»Ó·¢               d£®Ë®ÊÇ·´Ó¦µÄ´ß»¯¼Á
£¨3£©¸ÃʵÑé×°ÖÃÖÐ
 
×°ÖÿɷÀÖ¹µ¹Îü£¬ÖÐѧ»¯Ñ§ÊµÑéÖÐ
 
Óô˷½·¨·ÀÖ¹µ¹Îü£®
£¨4£©ÀíÂÛÉÏ£¬ÉÏÊö·´Ó¦µÄ¸±²úÎﻹ¿ÉÄÜÓУºÒÒÃÑ£¨CH3CH2-O-CH2CH3£©¡¢ÒÒÏ©¡¢ä廯ÇâµÈ£º¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐä廯Ç⣺ϨÃð¾Æ¾«µÆ£¬ÔÚÊúÖ±ÀäÄý¹ÜÉÏ·½ÈûÉÏÈû×Ó¡¢´ò¿ªa£¬ÀûÓÃÓàÈȼÌÐø·´Ó¦Ö±ÖÁÀäÈ´£¬Í¨¹ýB¡¢C×°ÖüìÑ飮B¡¢CÖÐӦʢ·ÅµÄÊÔ¼Á·Ö±ðÊÇ
 
¡¢
 
£®
£¨5£©Óû³ýÈ¥äåÒÒÍéÖеÄÉÙÁ¿ÔÓÖÊBr2£¬ÏÂÁÐÎïÖÊÖÐ×îÊʺϵÄÊÇ
 
£®£¨Ìî×Öĸ£©
a£®NaI         b£®NaOH           c£®NaHSO3          d£®KCl
£¨¶þ£©äåÒÒÍéÐÔÖʵÄ̽¾¿£º
ÓÃÈçͼ2ʵÑé×°Öã¨Ìú¼Ų̈¡¢¾Æ¾«µÆÂÔ£© ÑéÖ¤äåÒÒÍéµÄÐÔÖÊ£º
¢ñ£ºÔÚÊÔ¹ÜÖмÓÈë10mL 6mol/L NaOHÈÜÒººÍ2mLäåÒÒÍ飬Õñµ´£®
¢ò£º½«ÊÔ¹ÜÈçͼ2¹Ì¶¨ºó£¬Ë®Ô¡¼ÓÈÈ£®
£¨6£©¹Û²ìµ½
 
ÏÖÏóʱ£¬±íÃ÷äåÒÒÍéÓëNaOHÈÜÒºÒÑÍêÈ«·´Ó¦£®
£¨7£©ÎªÖ¤Ã÷äåÒÒÍéÔÚNaOHÒÒ´¼ÈÜÒºÖз¢ÉúµÄÊÇÏûÈ¥·´Ó¦£¬½«Éú³ÉµÄÆøÌåͨÈëÈçͼ3×°Öã®AÊÔ¹ÜÖеÄË®µÄ×÷ÓÃÊÇ
 
£¬ÈôÎÞAÊԹܣ¬BÊÔ¹ÜÖеÄÊÔ¼ÁӦΪ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013-2014ѧÄ꼪ÁÖÊ¡¾ÅУÁªºÏÌå¸ßÈýµÚ¶þ´ÎÃþµ×¿¼ÊÔÀí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ijÐËȤС×éÔÚʵÑéÊÒÓüÓÈÈÒÒ´¼¡¢Å¨H2SO4¡¢ä廯ÄƺÍÉÙÁ¿Ë®µÄ»ìºÏÎïÀ´ÖƱ¸äåÒÒÍ飬¼ìÑé·´Ó¦µÄ²¿·Ö¸±²úÎ²¢Ì½¾¿äåÒÒÍéµÄÐÔÖÊ¡£

£¨Ò»£©äåÒÒÍéµÄÖƱ¸¼°²úÎïµÄ¼ìÑ飺Éè¼ÆÁËÈçÉÏͼװÖã¬ÆäÖмгÖÒÇÆ÷¡¢¼ÓÈÈÒÇÆ÷¼°ÀäÈ´Ë®¹ÜûÓл­³ö¡£Çë¸ù¾ÝʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÊúÖ±ÀäÄý¹ÜÀäÄýË®Á÷Ïò     ¿Ú½ø    ¿Ú³ö£¬ÊúÖ±ÀäÄý¹ÜÀäÄýµÄ×÷Óà           

£¨2£©ÖƱ¸²Ù×÷ÖУ¬¼ÓÈëµÄÉÙÁ¿µÄË®£¬ÆäÄ¿µÄÊÇ         £»£¨Ìî×Öĸ£©

a£®¼õÉÙ¸±²úÎïÏ©ºÍÃѵÄÉú³É       b£®¼õÉÙBr2µÄÉú³É

c£®¼õÉÙHBrµÄ»Ó·¢               d£®Ë®ÊÇ·´Ó¦µÄ´ß»¯¼Á

£¨3£©¸ÃʵÑé×°ÖÃÖР         ×°ÖÿɷÀÖ¹µ¹Îü£¬ÖÐѧ»¯Ñ§ÊµÑéÖР                 Óô˷½·¨·ÀÖ¹µ¹Îü¡£

£¨4£©ÀíÂÛÉÏ£¬ÉÏÊö·´Ó¦µÄ¸±²úÎﻹ¿ÉÄÜÓУºÒÒÃÑ£¨CH3CH2£­O£­CH2CH3£©¡¢ÒÒÏ©¡¢ä廯ÇâµÈ£º¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐä廯Ç⣺ϨÃð¾Æ¾«µÆ£¬ÔÚÊúÖ±ÀäÄý¹ÜÉÏ·½ÈûÉÏÈû×Ó¡¢´ò¿ªa£¬ÀûÓÃÓàÈȼÌÐø·´Ó¦Ö±ÖÁÀäÈ´£¬Í¨¹ýB¡¢C×°ÖüìÑé¡£B¡¢CÖÐӦʢ·ÅµÄÊÔ¼Á·Ö±ðÊÇ             ¡¢          ¡£

£¨5£©Óû³ýÈ¥äåÒÒÍéÖеÄÉÙÁ¿ÔÓÖÊBr2£¬ÏÂÁÐÎïÖÊÖÐ×îÊʺϵÄÊÇ    ¡££¨Ìî×Öĸ£©

a£®NaI         b£®NaOH           c£®NaHSO3          d£®KCl

£¨¶þ£©äåÒÒÍéÐÔÖʵÄ̽¾¿£º

ÓÃÈçͼʵÑé×°ÖÃ(Ìú¼Ų̈¡¢¾Æ¾«µÆÂÔ) ÑéÖ¤äåÒÒÍéµÄÐÔÖÊ£º

¢ñ£ºÔÚÊÔ¹ÜÖмÓÈë10 mL6mol/L NaOHÈÜÒººÍ2 mL äåÒÒÍ飬Õñµ´¡£

II£º½«ÊÔ¹ÜÈçͼ¹Ì¶¨ºó£¬Ë®Ô¡¼ÓÈÈ¡£

£¨6£©¹Û²ìµ½___________ÏÖÏóʱ£¬±íÃ÷äåÒÒÍéÓëNaOHÈÜÒºÒÑÍêÈ«·´Ó¦¡£

£¨7£©ÎªÖ¤Ã÷äåÒÒÍéÔÚNaOHÒÒ´¼ÈÜÒºÖз¢ÉúµÄÊÇÏûÈ¥·´Ó¦£¬½«Éú³ÉµÄÆøÌåͨÈë  ÈçͼװÖá£AÊÔ¹ÜÖеÄË®µÄ×÷ÓÃÊÇ           £¬ÈôÎÞAÊԹܣ¬BÊÔ¹ÜÖеÄÊÔ¼ÁӦΪ      ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìɽ¶«Ê¡ÁijÇÊÐËÄÏØÁùУ¸ß¶þÏÂѧÆÚÆÚÄ©Áª¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

ijÐËȤС×éÔÚʵÑéÊÒÓüÓÈÈÒÒ´¼¡¢Å¨H2SO4¡¢ä廯ÄƺÍÉÙÁ¿Ë®µÄ»ìºÏÎïÀ´ÖƱ¸äåÒÒÍ飬¼ìÑé·´Ó¦µÄ²¿·Ö¸±²úÎ²¢Ì½¾¿äåÒÒÍéµÄÐÔÖÊ¡£

£¨Ò»£©äåÒÒÍéµÄÖƱ¸¼°²úÎïµÄ¼ìÑ飺Éè¼ÆÁËÈçÉÏͼװÖã¬ÆäÖмгÖÒÇÆ÷¡¢¼ÓÈÈÒÇÆ÷¼°ÀäÈ´Ë®¹ÜûÓл­³ö¡£Çë¸ù¾ÝʵÑé²½Ö裬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÒÇÆ÷AµÄÃû³ÆÊÇ         

£¨2£©ÖƱ¸²Ù×÷ÖУ¬¼ÓÈëµÄÉÙÁ¿µÄË®£¬ÆäÄ¿µÄÊÇ         ¡££¨Ìî×Öĸ£©

a£®¼õÉÙ¸±²úÎïÏ©ºÍÃѵÄÉú³É        b£®¼õÉÙBr2µÄÉú³É

c£®¼õÉÙHBrµÄ»Ó·¢               d£®Ë®ÊÇ·´Ó¦µÄ´ß»¯¼Á

£¨3£©¼ÓÈÈƬ¿Ìºó£¬AÖеĻìºÏÎï³öÏֳȺìÉ«£¬¸Ã³ÈºìÉ«ÎïÖÊ¿ÉÄÜÊÇ_____ _______

£¨4£©ÀíÂÛÉÏ£¬ÉÏÊö·´Ó¦µÄ¸±²úÎﻹ¿ÉÄÜÓУºÒÒÃÑ£¨CH3CH2£­O£­CH2CH3£©¡¢ÒÒÏ©¡¢ä廯ÇâµÈ

¢Ù ¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐä廯Ç⣺ϨÃð¾Æ¾«µÆ£¬ÔÚÊúÖ±ÀäÄý¹ÜÉÏ·½ÈûÉÏÈû×Ó¡¢´ò¿ªa£¬ÀûÓÃÓàÈȼÌÐø·´Ó¦Ö±ÖÁÀäÈ´£¬Í¨¹ýB¡¢C×°ÖüìÑé¡£B¡¢CÖÐӦʢ·ÅµÄÊÔ¼Á·Ö±ðÊÇ        ¡¢         

¢Ú ¼ìÑ鸱²úÎïÖÐÊÇ·ñº¬ÓÐÒÒÃÑ£ºÍ¨¹ýºìÍâ¹âÆ×ÒǼø¶¨ËùµÃ²úÎïÖк¬ÓС°£­CH2CH3¡±»ùÍÅ£¬À´È·¶¨¸±²úÎïÖдæÔÚÒÒÃÑ¡£ÇëÄã¶Ô¸ÃͬѧµÄ¹Ûµã½øÐÐÆÀ¼Û£º             

£¨5£©Óû³ýÈ¥äåÒÒÍéÖеÄÉÙÁ¿ÔÓÖÊBr2£¬ÏÂÁÐÎïÖÊÖÐ×îÊʺϵÄÊÇ          ¡££¨Ìî×Öĸ£©

a£®NaI         b£®NaOH           c£®NaHSO3          d£®KCl

£¨¶þ£©äåÒÒÍéÐÔÖʵÄ̽¾¿£º

ÓÃÈçͼʵÑé×°ÖÃ(Ìú¼Ų̈¡¢¾Æ¾«µÆÂÔ) ÑéÖ¤äåÒÒÍéµÄÐÔÖÊ£º

¢ñ£ºÔÚÊÔ¹ÜÖмÓÈë10 mL6mol/L NaOHÈÜÒººÍ2 mL äåÒÒÍ飬Õñµ´¡£

II£º½«ÊÔ¹ÜÈçͼ¹Ì¶¨ºó£¬Ë®Ô¡¼ÓÈÈ¡£

 (1)¹Û²ìµ½______ _____ÏÖÏóʱ£¬±íÃ÷äåÒÒÍéÓëNaOHÈÜÒºÒÑÍêÈ«·´Ó¦¡£

(2)Ϊ֤Ã÷äåÒÒÍéÔÚNaOHÒÒ´¼ÈÜÒºÖз¢ÉúµÄÊÇÏûÈ¥·´Ó¦£¬½«Éú³ÉµÄÆøÌåͨÈëÈçͼװÖá£AÊÔ¹ÜÖеÄË®µÄ×÷ÓÃÊÇ                               £¬ÈôÎÞAÊԹܣ¬BÊÔ¹ÜÖеÄÊÔ¼ÁӦΪ              ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡¸ßÈýµÚÈý´ÎÖÊÁ¿¼ì²â»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ

ÏÂÁÐÀë×Ó·½³ÌʽÊéд²»ÕýÈ·µÄÊÇ

A.ÏòH2SO4ËữµÄKIÈÜÒºÖеμÓH2O2£º2I-+H2O2+2H+=I2+2H2O

B.СËÕ´òÖÎÁÆθËá¹ý¶à£ºH++HCO3-=H2O+CO2¡ü

C.ÂÈÆøÈÜÓÚË®£ºCl2+H2OH++Cl-+HClO

D.¼ìÑéäåÒÒÍéÖк¬ÓеÄäåÔªËØ£ºCH3CH2Br+Ag+=AgBr¡ý+CH3CH2+

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸