¡¾ÌâÄ¿¡¿Ä¿Ç°È«Çò·¶Î§ÄÚ»·¾³ÎÛȾ±¸ÊܹØ×¢£¬»¯¹¤Éú²úÖÐÓ¦´óÁ¦³«µ¼¡°ÂÌÉ«»¯Ñ§¡±ºÍ¡°Ô­×Ó¾­¼Ã¡±µÄÀíÄ¹¤ÒµÉú²úÖеķÏÎïÀûÓÃÓÈΪÖØÒª¡£¹¤ÒµÉÏÉú²ú¸ßÂÈËáʱ£¬»¹Í¬Ê±Éú²úÁËÒ»ÖÖ³£¼ûµÄÖØÒªº¬ÂÈÏû¶¾¼ÁºÍƯ°×¼ÁÑÇÂÈËáÄÆ(NaClO2)£¬Æ乤ÒÕÁ÷³ÌÈçÏ£º

ÒÑÖª£º¢ÙNaHSO4Èܽâ¶ÈËæζȵÄÉý¸ß¶øÔö´ó£¬Êʵ±Ìõ¼þÏ¿ɽᾧÎö³ö¡£¢Ú¸ßÂÈËáÊÇÖÁ½ñΪֹÈËÃÇÒÑÖªËáÖеÄ×îÇ¿Ëᣬ·Ðµã90¡æ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©·´Ó¦Æ÷¢ñÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______£¬ÀäÈ´µÄÄ¿µÄÊÇ____________¡£

£¨2£©·´Ó¦Æ÷¢òÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________¡£

£¨3£©Í¨Èë·´Ó¦Æ÷¢òÖеÄSO2ÓÃH2O2´úÌæͬÑùÄÜÉú³ÉNaClO2£¬Çë¼òҪ˵Ã÷Ë«ÑõË®ÔÚ·´Ó¦ÖÐÄÜ´úÌæSO2µÄÔ­ÒòÊÇ_________________________¡£

£¨4£©Ca(ClO)2¡¢ClO2¡¢NaClO2µÈº¬ÂÈ»¯ºÏÎﶼÊdz£ÓõÄÏû¶¾¼ÁºÍƯ°×¼Á£¬Çëд³ö¹¤ÒµÉÏÓÃÂÈÆøºÍÏûʯ»ÒÉú²úƯ·Û¾«µÄ»¯Ñ§·½³Ìʽ£º___________________________________¡£

¡¾´ð°¸¡¿ 3NaClO3+3H2SO4£½HClO4+2ClO2¡ü+3NaHSO4+H2O ½µµÍNaHSO4µÄÈܽâ¶È£¬Ê¹NaHSO4½á¾§Îö³ö 2ClO2+SO2+4OH£­£½2ClO2£­+SO42£­+2H2O H2O2Óл¹Ô­ÐÔÒ²ÄÜ°ÑClO2»¹Ô­ÎªNaClO2 2Cl2+2 Ca(OH )2£½CaCl2+ Ca(ClO)2+2H2O

¡¾½âÎö¡¿£¨1£©¸ù¾Ý¼ÓÈëµ½·´Ó¦Æ÷¢ñÖеÄÔ­ÁÏÓÐNaClO3¡¢Å¨ÁòËᣬÉú³ÉÎïÓÐClO2ÆøÌå¡¢NaHSO4¡¢HClO4ÈÜÒº£®ÒÀ¾ÝÊéд»¯Ñ§·½³ÌʽµÄ¹æÔò£¬¼´·¢Éú»¯Ñ§·´Ó¦Ê±Âú×ãÔ­×ÓµÄÖÖÀàºÍÊýÄ¿²»±ä£¬Êéд³ö»¯Ñ§·´Ó¦·½³ÌʽΪ£º3NaClO3+3H2SO4=HClO4+2ClO2+3NaHSO4+H2O£»È»ºó½«·´Ó¦Éú³ÉÎïµÄÈÜÒºÀäÈ´µÃµ½NaHSO4¾§Ì壬˵Ã÷ÁòËáÇâÄƵÄÈܽâ¶ÈËæζȵĽµµÍ¶ø¼õС£»
£¨2£©¸ù¾ÝͨÈëµ½·´Ó¦ÈÝÆ÷¢òÖеķ´Ó¦ÎïÓÐNaOH¡¢SO2¡¢H2O¡¢ClO2£¬Éú³ÉÎïÓÐNaClO2£¬ÂȵĻ¯ºÏ¼ÛÓÉ+4¼Û±ä³ÉÁË+3¼Û£¬µÃµ½µç×Ó£¬¸ù¾ÝÑõ»¯»¹Ô­·´Ó¦µÄÔ­ÀíÁòӦʧµç×Ó£¬ÓÉ+4¼Û±ä³É+6¼Û£¬¸ù¾ÝÑõ»¯»¹Ô­·´Ó¦Ô­ÀíµÄÑõ»¯¼ÁµÃµ½µç×Ó×ÜÊýµÈÓÚ»¹Ô­¼Áʧȥµç×ÓµÄ×ÜÊý£¬ÔòÑõ»¯»¹Ô­·´Ó¦·½³ÌʽΪ2ClO2+SO2+4OH-=2ClO2-+SO42-+2H2O£»
£¨3£©Èç¹û½«·´Ó¦Æ÷¢òÖеÄSO2ÓÃH2O2´úÌæͬÑùÄÜÉú³ÉNaClO2£¬ËµÃ÷±ä»»ÎïÖʺó£¬Ñõ»¯»¹Ô­·´Ó¦ÕÕÑùÄÜ·¢ÉúÉú³ÉNaClO2£¬Ò²¾Í˵Ã÷H2O2Ò²¾ßÓл¹Ô­ÐÔ£¬Ò²ÄÜ°ÑClO2»¹Ô­ÎªNaClO2£»
£¨4£©Ïû¶¾¼ÁºÍƯ°×¼ÁµÄÏû¶¾Ô­ÀíºÍƯ°×Ô­ÀíÊÇÀûÓÃËüÃǵÄÇ¿Ñõ»¯ÐÔÀ´´ïµ½Ä¿µÄ£®¸ù¾Ý½Ì²Ä֪ʶ¹¤ÒµÉÏÖÆȡƯ°×·ÛÊÇÓÃÂÈÆøÓëÏûʯ»Ò·´Ó¦µÃµ½µÄ£¬Æä·´Ó¦Ô­ÀíΪ2Cl2+2 Ca(OH )2£½CaCl2+ Ca(ClO)2+2H2O¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿A¡¢B¡¢C¡¢D¡¢E¡¢FÊǶÌÖÜÆÚÔªËØ£¬ÖÜÆÚ±íÖÐAÓëB¡¢BÓëCÏàÁÚ£»CÓëEͬÖ÷×壻AÓëC×îÍâ²ãµç×ÓÊýÖ®±ÈΪ2:3£¬BµÄ×îÍâ²ãµç×ÓÊý±ÈCµÄ×îÍâ²ãµç×ÓÊýÉÙ1¸ö£» FÔªËصÄÔ­×ÓÔÚÖÜÆÚ±íÖа뾶×îС£»³£¼û»¯ºÏÎïD2C2ÓëË®·´Ó¦Éú³ÉCµÄµ¥ÖÊ£¬ÇÒÈÜҺʹ·Ó̪ÈÜÒº±äºì¡£

£¨1£©FµÄÈýÖÖºËËرíʾ·ûºÅΪ______£¬EµÄÃû³ÆΪ______£¬DµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄµç×Óʽ£º______¡£

£¨2£©ÔÚB¡¢C¡¢D¡¢E¡¢FÔ­×ÓÐγɵĵ¥ºËÀë×ÓÖÐÀë×Ӱ뾶×îСµÄÊÇ____£¬Àë×Ӱ뾶×î´óµÄÊÇ____¡££¨ÌîÀë×Ó·ûºÅ£©

£¨3£©A¡¢B¡¢CµÄÇ⻯ÎïÎȶ¨ÐÔ˳ÐòΪ_____£¨Ó÷Ö×Óʽ±íʾ£©£»BµÄÇ⻯ÎïºÍBµÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯Îï·´Ó¦Éú³ÉZ,·´Ó¦ÖжÏÁÑ»¯Ñ§¼üÊÇ_____£¬ÐγɵĻ¯Ñ§¼üÊÇ________¡££¨Ìî¡°Àë×Ó¼ü¡±¡¢¡°¼«ÐÔ¼ü¡±¡¢¡°·Ç¼«ÐÔ¼ü¡±¡¢¡°Çâ¼ü¡±£©

£¨4£©F2CºÍF2EÖУ¬·Ðµã½Ï¸ßµÄÊÇ__________£¨Ìѧʽ£©£¬ÆäÖ÷ÒªÔ­ÒòÊÇ_________¡£

£¨5£©Á½ÖÖ¾ùº¬C¡¢D¡¢E¡¢FËÄÖÖÔªËصĻ¯ºÏÎïÏ໥·´Ó¦·Å³öÆøÌåµÄ·´Ó¦Àë×Ó·½³ÌʽΪ________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐÊôÓÚÈËÌåÄÚ³£Á¿ÔªËصÄÊÇ

A£® Í­¡¢·ú B£® п¡¢Îø C£®µª¡¢Çâ D£® µâ¡¢Ìú

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁз´Ó¦¼ÈÊôÓÚÑõ»¯»¹Ô­·´Ó¦£¬ÓÖÊôÓÚÎüÈÈ·´Ó¦µÄÊÇ(¡¡¡¡)

A. þÌõÔÚ¿ÕÆøÖÐȼÉÕ B. Ba(OH)2¡¤8H2OÓëNH4ClµÄ·´Ó¦

C. ÂÁƬÓëÏ¡ÑÎËáµÄ·´Ó¦ D. ×ÆÈȵÄÌ¿ÓëCO2µÄ·´Ó¦

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿½«Ò»¶¨Á¿µÄп·ÅÈË100mLl8£®4mol/LŨÁòËáÖмÓÈÈ£¬³ä·Ö·´Ó¦ºóпÍêÈ«Èܽ⣬ͬʱÉú³ÉÆøÌåX 22£®4L(±ê×¼×´¿ö)¡£½«·´Ó¦ºóµÄÈÜҺϡÊÍÖÁ0£®8L£¬²âµÃÈÜÒºc(H+)=0.1mol/L£¬ÔòÏÂÁÐÅжϴíÎóµÄÊÇ

A. ÆøÌåXΪSO2ºÍH2µÄ»ìºÏÎï B. ÆøÌåXÖÐSO2ÓëH2µÄÌå»ýÏàµÈ C. ·´Ó¦Öй²×ªÒÆ2molµç×Ó D. ·´Ó¦Öй²ÏûºÄZn 65 g

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÑÇÂÈËáÄÆ£¨NaClO2£©ÊÇÖØÒªµÄƯ°×¼Á¡£Ä³Ð¡×鿪չÈçÏÂʵÑ飬°´ÈçͼװÖÃÖÆÈ¡ÎÞË®NaClO2¾§Ì壬»Ø´ðÏÂÁÐÎÊÌ⣺

ÒÑÖª£ºNaClO2±¥ºÍÈÜÒºÔÚµÍÓÚ38¡æʱÎö³öNaClO23H2O£¬¸ßÓÚ38¡æʱÎö³öNaClO2£¬¸ßÓÚ60¡æʱNaClO2·Ö½â³ÉNaClO3ºÍNaCl£®

£¨1£©×°ÖÃCµÄ×÷ÓÃÊÇ_________________£»

£¨2£©ÒÑ֪װÖÃBÖеIJúÎïÓÐClO2ÆøÌ壬ÔòBÖз´Ó¦µÄ·½³ÌʽΪ_________________£»×°ÖÃDÖз´Ó¦Éú³ÉNaClO2µÄ»¯Ñ§·½³ÌʽΪ_________________________£»

£¨3£©´Ó×°ÖÃD·´Ó¦ºóµÄÈÜÒºÖлñµÃÎÞË®NaClO2¾§ÌåµÄ²Ù×÷²½ÖèΪ£º¢Ù¼õѹ£¬55¡æÕô·¢½á¾§£»¢Ú____________£»¢ÛÓÃ38¡æ¡«60¡æÈÈË®________£»¢ÜÔÚ_____________Ìõ¼þϸÉÔïµÃµ½³ÉÆ·£®

£¨4£©Èç¹û³·È¥DÖеÄÀäˮԡ£¬¿ÉÄܵ¼Ö²úÆ·ÖлìÓеÄÔÓÖÊÊÇ_________ºÍ____________£»

£¨5£©²â¶¨ÑùÆ·ÖÐNaClO2µÄ´¿¶È£®²â¶¨Ê±½øÐÐÈçÏÂʵÑ飺

׼ȷ³ÆÒ»¶¨ÖÊÁ¿µÄÑùÆ·£¬¼ÓÈëÊÊÁ¿ÕôÁóË®ºÍ¹ýÁ¿µÄKI¾§Ì壬ÔÚËáÐÔÌõ¼þÏ·¢ÉúÈçÏ·´Ó¦£ºClO2£­+4I£­+4H+¨T2H2O+2I2+Cl£­£¬½«ËùµÃ»ìºÏҺϡÊͳÉ100mL´ý²âÈÜÒº£®È¡25.00mL´ý²âÈÜÒº£¬¼ÓÈëµí·ÛÈÜÒº×öָʾ¼Á£¬ÓÃc molL£­1 Na2S2O3±ê×¼ÒºµÎ¶¨ÖÁÖյ㣬²âµÃÏûºÄ±ê×¼ÈÜÒºÌå»ýµÄƽ¾ùֵΪV mL£¨ÒÑÖª£ºI2+2S2O32£­¨T2I£­+S4O62£­£©£®Çë¼ÆËãËù³ÆÈ¡µÄÑùÆ·ÖÐNaClO2µÄÎïÖʵÄÁ¿Îª__________£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿»¯Ñ§ÖªÊ¶ÓëÉú²úÉú»îϢϢÏà¹Ø¡£

I.¹è¼°Æ仯ºÏÎï

£¨1£©¹è¼°Æ仯ºÏÎïÔÚÏÖ´úÐÅÏ¢¼¼ÊõÖÐÓ¦Óù㷺¡£ÆäÖÐÓÃÓÚÖÆÔì¼ÆËã»úоƬµÄ²ÄÁÏÊÇ__________£¨Ð´»¯Ñ§Ê½£©£¬ÓÃÓÚÖÆÔì¹âµ¼ÏËάµÄ²ÄÁÏÊÇ__________£¨Ð´»¯Ñ§Ê½£©¡£¹âµ¼ÏËάÔÚ¼îÐÔÍÁÈÀÖÐÒ×±»¸¯Ê´£¬Çëд³öÏà¹ØµÄÀë×Ó·´Ó¦·½³Ìʽ______________________

II.Âȼ°Æ仯ºÏÎï

£¨2£©Æ¯°×·ÛÊÇÉú»î³£±¸ÓÃÆ·£¬ÆäÖ÷Òª³É·ÝÊÇ__________________£¨Ð´»¯Ñ§Ê½£©£»Æ¯°×·Û±£´æ²»µ±Ò×±äÖÊ£¬Çëд³öƯ°×·ÛʧЧµÄ·½³Ìʽ________________£»È粻СÐÄ°ÑƯ°×·ÛÓë½à²ÞÁ飨Ö÷Òª³É·ÝΪÑÎËᣩ»ìºÏ£¬Ò×Éú³ÉÂÈÆøʹÈËÖж¾¡£Çëд³öÓйط´Ó¦µÄÀë×Ó·½³Ìʽ________________________¡£

£¨3£©Ä³ÊµÑéС×飬ÏòÒ»¶¨Á¿µÄʯ»ÒÈéÖлºÂýÔÈËÙµØͨÈë×ãÁ¿ÂÈÆø£¬·¢ÏÖ²úÎïÖл¹»ìÓÐÁËClO3£­£¬ËûÃÇÌÖÂÛºóÈÏΪ£¬ÊÇ·´Ó¦·ÅÈÈζÈÉý¸ßµÄÔ­Òò¡£²¢»­³öÁËClO£­¡¢ClO3£­Á½ÖÖÀë×ÓµÄÎïÖʵÄÁ¿£¨n£©Ó뷴Ӧʱ¼ä(t)µÄ¹ØϵÇúÏߣ¬´ÖÂÔ±íʾΪÏÂͼ£¨²»¿¼ÂÇÂÈÆøºÍË®µÄ·´Ó¦£©¡£

¢ÙͼÖÐÇúÏßI±íʾ_____________Àë×ÓµÄÎïÖʵÄÁ¿Ë淴Ӧʱ¼ä±ä»¯µÄ¹Øϵ¡£

¢ÚËùȡʯ»ÒÈéÖк¬ÓÐCa(OH)2µÄÎïÖʵÄÁ¿Îª__________mol¡£

¢ÛÁíÈ¡Ò»·ÝÓë¢ÚµÈÎïÖʵÄÁ¿µÄʯ»ÒÈ飬ÒԽϴóµÄËÙÂÊͨÈë×ãÁ¿ÂÈÆø£¬·´Ó¦ºó²âµÃ²úÎïÖÐCl£­µÄÎïÖʵÄÁ¿Îª0.37mol£¬Ôò²úÎïÖÐn(ClO£­)/n(ClO3£­)=______________¡£

III.µª¼°Æ仯ºÏÎï

£¨4£©ÏõËáÉú²ú¹ý³ÌÖÐÅŷųöÀ´µÄ·ÏÆø£¬º¬NO¡¢NO2µÈ´óÆøÎÛȾÎï¡£

¢Ù¹¤ÒµÉϳ£ÓÃÔ­Àí£ºNOx+NH3¡úN2+H2O£¬Ê¹Æäת»¯ÎªÎÞ¶¾µÄN2£¬ÏÖÓÐNO¡¢NO2µÄ»ìºÏ3.0L£¬¿ÉÓë3.5LÏàͬ״¿öµÄNH3ÍêÈ«·´Ó¦£¬È«²¿×ª»¯ÎªN2£¬ÔòÔÚÔ­»ìºÏÆøÌåÖÐNOºÍNO2µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ_____________£»

¢ÚÒÑÖª¼îÄܳýÈ¥ÏõËáβÆø£º2NO2+2NaOH£½NaNO2+NaNO3+H2O;NO+NO2+2NaOH£½2NaNO2+H2O

¸ù¾ÝÏõËáβÆø´¦ÀíµÄ·´Ó¦Ô­Àí£¬ÏÂÁÐÆøÌåÖв»Äܱ»¹ýÁ¿NaOHÈÜÒºÎüÊÕµÄÊÇ_______________

A£®1molO2ºÍ4molNO2¡¡

B£®1molO2ºÍ4molNO¡¡

C£®1molNOºÍ5molNO2¡¡ ¡¡

D£®4molNOºÍ1molNO2

£¨5£©Æû³µÅŷŵÄβÆøÖÐÒòº¬ÓеªµÄÑõ»¯Îï¶øÎÛȾ´óÆø£¬Ôì³É²úÉúµªµÄÑõ»¯ÎïµÄÖ÷ÒªÔ­ÒòÊÇ_____________

A£®È¼ÉÕº¬µª»¯ºÏÎïȼÁÏ¡¡¡¡¡¡¡¡¡¡¡¡¡¡

B£®È¼ÉÕº¬Ç¦ÆûÓÍ

C£®ÓÉÓÚȼÉÕ²»³ä·Ö¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡

D£®ÄÚȼ»úÖпÕÆøÖеÄN2ÔÚ¸ßÎÂϱ»Ñõ»¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨ £©

A. H2SO4ÈÜÓÚË®ÄܵçÀë³öH£«ºÍSO42£­£¬ËùÒÔÁòËáÊÇÀë×Ó»¯ºÏÎï

B. Ba(OH)2¾§ÌåÖмȴæÔÚ¹²¼Û¼üÓÖÓÐÀë×Ó¼ü

C. SiO2ÊôÓÚÔ­×Ó¾§Ì壬ÈÛ»¯ÆÆ»µ¹²¼Û¼üºÍ·Ö×Ó¼ä×÷ÓÃÁ¦

D. ¸É±ùÉý»ªÊ±£¬·Ö×ÓÄÚ¹²¼Û¼ü»á·¢Éú¶ÏÁÑ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Ä³Í¬Ñ§ÎªÁ˼ìÑéŨÁòËáÓëľ̿·ÛÔÚ¼ÓÈÈÌõ¼þÏ·´Ó¦²úÉúµÄËùÓÐÆøÌå²úÎѡÓÃÁËÈçÏÂͼËùʾµÄʵÑé×°Öá£

(1)д³öŨÁòËáÓëľ̿·ÛÔÚ¼ÓÈÈÌõ¼þϵĻ¯Ñ§·½³Ìʽ______________________¡£

(2)¢ÙÖÐÎÞË®ÁòËáÍ­µÄ×÷ÓÃÊÇ___________________________¡£

(3)¢ÚÖÐËáÐÔKMnO4ÈÜÒºµÄ×÷ÓÃÊÇ__________________________¡£

(4)¢ÚÖÐÁ½´ÎÓõ½Æ·ºìÈÜÒº£¬ËüÃǵÄ×÷Ó÷ֱðÊÇ

A_____________________£¬ B ___________________ ¡£

(5)¢ÛÖгöÏÖµÄÏÖÏó____________________________________________________£¬

·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ_________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸