Question

£¨14·Ö£©ºÏ³É°±¶Ô¹¤¡¢Å©ÒµÉú²úºÍ¹ú·À¶¼ÓÐÖØÒªÒâÒå¡£
ÒÑÖª£ºN₂£¨g£©+3H₂£¨g£©2NH₃£¨g£©£»¡÷H= -92£®4 kJ¡¤mol^-1£¬Çë»Ø´ð£º
£¨1£©ºÏ³É°±¹¤ÒµÖвÉÈ¡µÄÏÂÁдëÊ©¿ÉÒÔÓÃÀÕÏÄÌØÁÐÔ­Àí½âÊ͵ÄÊǣߣߣߣߣߣ¨Ìî×Öĸ£©¡£
a£®ÓÃÌú´¥Ã½£¨´ß»¯¼Á£©¼Ó¿ì»¯Ñ§·´Ó¦ËÙÂÊ     
b£®²ÉÓýϸßѹǿ£¨20 MPa~50 MPa£©
c£®½«Ô­ÁÏÆøÖеÄÉÙÁ¿COµÈÆøÌå¾»»¯³ýÈ¥ 
d£®½«Éú³ÉµÄ°±Òº»¯²¢¼°Ê±´ÓÌåϵÖзÖÀë³öÀ´
£¨2£©Ò»¶¨Î¶ÈÏ£¬ÔÚÃܱÕÈÝÆ÷ÖгäÈë1 mol N₂ºÍ3 mol H₂²¢·¢Éú·´Ó¦¡£
¢ÙÈôÈÝÆ÷ÈÝ»ýVºã¶¨£¬´ïµ½Æ½ºâʱ£¬ÆøÌåµÄѹǿΪԭÀ´µÄ£¬ÔòN₂µÄת»¯ÂʧÑ₁=£ß£ß£ß£ß£ß£¬´Ëʱ£¬·´Ó¦·ÅÈȣߣߣߣߣßkJ£»¸ÃζÈϺϳɰ±·´Ó¦µÄƽºâ³£ÊýK=£ß£ß£ß£ß£ß£¨Ö»ÐèÁгöÊý×Ö±í´ïʽ£©£»
¢ÚÈôÈÝÆ÷ѹǿºã¶¨£¬Ôò´ïµ½Æ½ºâʱ£¬ÈÝÆ÷ÖÐN₂µÄת»¯ÂʧÑ₂£ß£ß§Ñ₁£¨Ìî¡°£¾¡¢£¼»ò£½¡±£©¡£
£¨3£©Ëæ×ŶԺϳɰ±Ñо¿µÄ·¢Õ¹£¬Ï£À°¿Æѧ¼Ò²ÉÓøßÖÊ×Óµ¼µçÐÔµÄSCYÌÕ´É£¨ÄÜ´«µÝH⁺£©Îª½éÖÊ£¬ÓÃÎü¸½ÔÚËüÄÚÍâ±íÃæÉϵĽðÊôîٶྦྷ±¡Ä¤×öµç¼«£¬ÊµÏÖÁ˳£Ñ¹¡¢570¡æÌõ¼þϸßת»¯Âʵĵç½â·¨ºÏ³É°±£¨×°ÖÃÈçÏÂͼ£©¡£îٵ缫AÊǵç½â³ØµÄ£ß£ß£ß£ß¼«£¨Ìî¡°Ñô¡±»ò ¡°Òõ¡±£©£¬¸Ã¼«Éϵĵ缫·´Ó¦Ê½ÊÇ                                      ¡£
  

Answer 1

£¨14·Ö£©
£¨1£©bd  £¨2·Ö£©£¨2£©¢Ù 25%£¨2·Ö£©    23£®1 kJ£¨2·Ö£©   ¢Ú £¾£¨2·Ö£©  K=£¨2·Ö£©
£¨3£©Òõ£¨2·Ö£©  N₂£« 6H⁺ + 6e^-£½ 2NH₃£¨2·Ö£©

ÂÔ