ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍHµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄʽÁ¿±ÈDµÄʽÁ¿´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçÏÂͼËùʾ£¨²úÎïÖÐË®ÒѺöÂÔ£©£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£º±û.___________£¬H. ___________¡£

£¨2£©Ð´³öÏÂÁб仯µÄÀë×Ó·½³Ìʽ

B+H2O±û+C£º__________________________________________________¡£

£¨3£©ÒÒ+±ûFÊǹ¤ÒµÉϵõ½FµÄ·´Ó¦Ö®Ò»£¬Çëд³ö¹¤ÒµÉϵõ½FµÄÁíÒ»»¯Ñ§·´Ó¦·½³Ìʽ£º______

_____________________________________________________________________¡£

£¨1£©O2  Na2S

£¨2£©2Na2O2+2H2O====4Na++4OH-+O2¡ü

£¨3£©4FeS2+11O22Fe2O3+8SO2£¨ÆäËûºÏÀí´ð°¸¾ù¿É£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµÄµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢H¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍHµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈD´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçͼ1Ëùʾ£¨²úÎïÖÐË®ÒѺöÂÔ£©£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£º±û£º
O2
O2
H£º
Na2S
Na2S

£¨2£©Ð´³öBºÍF·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
Na2O2+SO2=Na2SO4
Na2O2+SO2=Na2SO4
£®
£¨3£©ÒÑÖª25¡æ£¬101Kpaʱ£¬ÒÒµÄȼÉÕÈÈΪakJ/mol£¬Ð´³öÒÒȼÉÕµÄÈÈ»¯Ñ§·½³Ìʽ
S£¨s£©+O2£¨g£©=SO2£¨g£©£»¡÷H=-akJ/mol
S£¨s£©+O2£¨g£©=SO2£¨g£©£»¡÷H=-akJ/mol
£®
£¨4£©Ð´³öB+H2O¡ú±û+CµÄ»¯Ñ§·½³Ìʽ
2Na2O2+2H2O=4NaOH+O2¡ü
2Na2O2+2H2O=4NaOH+O2¡ü
£®
£¨5£©ÔÚ2LµÄÃܱÕÈÝÆ÷ÄÚ£¬500¡æʱ£¬·´Ó¦2F£¨g£©+±û£¨g£©¨T2G£¨g£©£¬n£¨F£©Ëæʱ¼ä±ä»¯ÈçÏÂ±í£º
ʱ¼ä£¨s£© 0 1 2 3 4 5
n£¨F£©/mol 0.020 0.010 0.008 0.007 0.007 0.007
Èçͼ2ÖбíʾGµÄ±ä»¯ÇúÏßÊÇ
b
b
£®Óñû±íʾ´Ó0¡«2sÄڸ÷´Ó¦µÄƽ¾ùËÙÂÊ
0.0015mol?L-1?s-1
0.0015mol?L-1?s-1
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬ÇÒ±ûÊÇÎÞÉ«ÆøÌ壻A-G¾ùΪ³£¼ûµÄ»¯ºÏÎBΪµ­»ÆÉ«¹ÌÌ壬BµÄʽÁ¿±ÈAµÄʽÁ¿´ó16£¬EÊÇÐγÉËáÓêµÄÖ÷ÒªÎïÖÊ£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçͼËùʾ£¨²úÎïÖÐË®ÒѺöÂÔ£©£º

£¨1£©Ð´³öÏÂÁÐÎïÖʵĻ¯Ñ§Ê½£ºG
Na2S
Na2S
£¬F
SO3
SO3
£»
£¨2£©Ð´³öÏÂÁб仯µÄ»¯Ñ§·½³ÌʽB+H2O¡ú±û+C£º
2Na2O2+2H2O=O2¡ü+4NaOH
2Na2O2+2H2O=O2¡ü+4NaOH
£»
£¨3£©EÊÇÒ»ÖÖÓж¾ÆøÌ壬¹¤ÒµÉϳ£ÓÃÉúʯ»Ò¶ÔEÆøÌå½øÐд¦Àí£®Ð´³öÆ仯ѧ·´Ó¦·½³Ìʽ
CaO+SO2=CaSO3
CaO+SO2=CaSO3
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢X¡¢Y¡¢ZΪ³£¼ûµÄ»¯ºÏÎYµÄĦ¶ûÖÊÁ¿ÊýÖµ±ÈZµÄС16£¬ÒÒ¡¢±ûµÄĦ¶ûÖÊÁ¿Ïàͬ£¬BµÄĦ¶ûÖÊÁ¿±ÈDµÄС2£¬B¡¢XµÄĦ¶ûÖÊÁ¿Ïàͬ£®¸÷ÎïÖÊת»¯¹ØϵÈçÏ£º
¾«Ó¢¼Ò½ÌÍø
£¨1£©Ð´³ö±ûµÄ»¯Ñ§Ê½
 
£»BµÄµç×Óʽ
 
£®
£¨2£©Ð´³öY¡úZµÄ»¯Ñ§·½³Ìʽ£º
 

£¨3£©ÊµÑéÊÒÖü´æYÈÜҺʱÒ×±äÖÊ£¬Çëд³ö¼ìÑéYÈÜÒºÊÇ·ñ±äÖÊËùÐèÊÔ¼ÁÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

Àý

ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢X¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈDµÄÏà¶Ô·Ö×ÓÖÊÁ¿´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçÏÂͼËùʾ£º

(1)д³öXµÄµç×ÓʽºÍGµÄ»¯Ñ§Ê½£ºX__________£¬G__________£»

(2)д³öÓйر仯µÄ»¯Ñ§·½³Ìʽ£º

        B£«H2O£º______________________________£»

        D£«±û£º______________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2009-2010ѧÄêÕý¶¨ÖÐѧ¸ßÒ»ÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§£¨Àí¿Æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

£¨6·Ö£©ÒÑÖª¼×¡¢ÒÒ¡¢±ûΪ³£¼ûµ¥ÖÊ£¬A¡¢B¡¢C¡¢D¡¢E¡¢F¡¢G¡¢X¾ùΪ³£¼ûµÄ»¯ºÏÎBºÍXµÄĦ¶ûÖÊÁ¿Ïàͬ£¬EµÄÏà¶Ô·Ö×ÓÖÊÁ¿±ÈDµÄÏà¶Ô·Ö×ÓÖÊÁ¿´ó16£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬¸÷ÎïÖÊÏ໥ת»¯¹ØϵÈçÏÂͼËùʾ£º

¢Å д³öXµÄµç×ÓʽºÍGµÄ»¯Ñ§Ê½£ºX__________£¬G__________£»

¢Æ д³öÓйر仯µÄ»¯Ñ§·½³Ìʽ£º

    B£«H2O£º______________________________£»

D£«±û£º______________________________¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸