¡¾ÌâÄ¿¡¿ÎïÖÊÔÚË®ÖпÉÄÜ´æÔÚµçÀëƽºâ¡¢ÑεÄË®½âƽºâºÍ³ÁµíÈܽâƽºâ£¬ËüÃǶ¼¿É¿´×÷»¯Ñ§Æ½ºâ¡£Çë¸ù¾ÝËùѧ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺
(1)AlCl3ÈÜÒº³Ê______ÐÔ(Ìî¡°Ëᡱ¡°ÖС±¡°¼î¡±)ÔÒòÊÇ_________________________(ÓÃÀë×Ó·½³Ìʽ±íʾ)£»Èô°ÑAlCl3ÈÜÒºÕô¸É£¬×ÆÉÕ£¬×îºóÖ÷ÒªµÃµ½¹ÌÌå²úÎïÊÇ________£»Èô½«AlCl3ÈÜÒººÍNaHCO3ÈÜÒº»ìºÏ£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________________¡£
(2)½«1L0.2 mol¡¤L£1HAÈÜÒºÓë1L0.1 mol¡¤L£1NaOHÈÜÒºµÈÌå»ý»ìºÏ(»ìºÏºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¬²âµÃ»ìºÏÈÜÒºÖÐc(Na£«)>c(A£)£¬Ôò£º
¢Ù»ìºÏÈÜÒºÖУ¬c(A£)________c(HA)(Ìî¡°>¡±¡°<¡±»ò¡°£½¡±£¬ÏÂͬ)¡£
¢Ú»ìºÏÈÜÒºÖУ¬c(HA)£«c(A£)________0.1 mol¡¤L£1¡£
(3)³£ÎÂÏ£¬ÈôNaOHÈÜÒºÖÐc(OH¡ª)ÓëNH4ClÈÜÒºÖÐc(H+)Ïàͬ£¬ÏÖ½«NaOHÈÜÒººÍNH4ClÈÜÒº·Ö±ðÏ¡ÊÍ10±¶£¬Ï¡ÊͺóNaOHÈÜÒººÍNH4CIÈÜÒºµÄpH·Ö±ðÓÃpH1ºÍpH2±íʾ¡£ÔòpH1 +pH2________(Ìî¡°>¡±¡°<¡±»ò¡°£½¡±)14¡£
(4)pHÏàͬµÄ¢ÙCH3COONa¡¢¢ÚNaHCO3¡¢¢ÛNaClOÈýÖÖÈÜÒºµÄc(Na£«)£º___________________¡£
¡¾´ð°¸¡¿Ëá Al3£«£«3H2OAl(OH)3£«3H£« Al2O3 Al3£«£«3HCO3££½Al(OH)3¡ý£«3CO2¡ü £¼ £½ £¼ ¢Ù£¾¢Ú£¾¢Û
¡¾½âÎö¡¿
£¨1£©¸ù¾ÝÂÈ»¯ÂÁË®½âÒÔ¼°Íâ½çÌõ¼þ¶ÔË®½âƽºâµÄÓ°Ïì·ÖÎö£»¸ù¾Ý·´Ó¦ÎïºÍÉú³ÉÎïÊéд·½³Ìʽ£»
£¨2£©¸ù¾ÝµçºÉÊغãºÍÎïÁÏÊغã·ÖÎöÅжϣ»
£¨3£©¸ù¾ÝÏ¡Ê͹ý³ÌÖжÔË®½âƽºâµÄÓ°Ïì·ÖÎöÅжϣ»
£¨4£©¸ù¾ÝËáÔ½Èõ£¬ÏàÓ¦µÄËá¸ùÔ½ÈÝÒ×Ë®½â·ÖÎö¡£
£¨1£©ÂÈ»¯ÂÁÈÜÒºÖÐÂÁÀë×ÓË®½â£¬ÈÜÒºÏÔËáÐÔ£¬Ë®½â·½³ÌʽΪAl3£«£«3H2OAl(OH)3£«3H£«£»Ë®½âÎüÈÈ£¬¼ÓÈÈ´Ù½øË®½â£¬Éú³ÉµÄHClÒ×»Ó·¢£¬×îºóÕô¸ÉµÃµ½ÇâÑõ»¯ÂÁ£¬×ÆÉÕʱÇâÑõ»¯ÂÁ·Ö½âÉú³ÉÑõ»¯ÂÁºÍË®£¬ËùÒÔ×îºóÖ÷ÒªµÃµ½¹ÌÌå²úÎïÊÇAl2O3£»Èô½«AlCl3ÈÜÒººÍNaHCO3ÈÜÒº»ìºÏ¶þÕßË®½âÏ໥´Ù½øÉú³ÉÇâÑõ»¯ÂÁºÍ¶þÑõ»¯Ì¼£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪAl3£«£«3HCO3££½Al(OH)3¡ý£«3CO2¡ü¡£
£¨2£©¢Ù½«1L0.2 mol¡¤L£1HAÈÜÒºÓë1L0.1 mol¡¤L£1NaOHÈÜÒºµÈÌå»ý»ìºÏ(»ìºÏºóÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ)£¬ËùµÃÈÜÒºÖÐÈÜÖÊÊǵÈŨ¶ÈµÄHAºÍNaAµÄ»ìºÏÈÜÒº£¬²âµÃ»ìºÏÈÜÒºÖÐc(Na£«)£¾c(A£)£¬Ôò¸ù¾ÝµçºÉÊغãc(Na£«)+c(H£«)£½c(A£)+c(OH¡ª)¿ÉÖªc(H£«)£¼c(OH¡ª)£¬¼´ÈÜÒºÏÔ¼îÐÔ£¬Õâ˵Ã÷Ë®½â³Ì¶È´óÓÚµçÀë³Ì¶È£¬ËùÒÔ»ìºÏÈÜÒºÖУ¬c(A£)£¼c(HA)¡£
¢ÚËùµÃÈÜÒºÖÐÈÜÖÊÊǵÈŨ¶ÈµÄHAºÍNaAµÄ»ìºÏÈÜÒº£¬Å¨¶È¾ùÊÇ0.05mol/L£¬Ôò¸ù¾ÝÎïÁÏÊغã¿ÉÖª»ìºÏÈÜÒºÖУ¬c(HA)£«c(A£)£½0.1 mol¡¤L£1¡£
£¨3£©ÉèÏ¡ÊÍÇ°NaOHÈÜÒººÍNH4ClÈÜÒºµÄpH·Ö±ðÓÃpH3ºÍpH4±íʾ£¬½«NaOHÈÜҺϡÊÍ10±¶£¬ÓÉÓÚÇâÑõ»¯ÄÆÊÇһԪǿ¼î£¬ÔòpH1£½pH3£1£»ÂÈ»¯ï§ÊÇÇ¿ËáÈõ¼îÑΣ¬ï§¸ùË®½â£¬Ï¡ÊÍ´Ù½ø笠ùË®½â£¬ÔòÏ¡ÊÍ10±¶ºópH2£¼pH4+1£¬ÓÉÓÚNaOHÈÜÒºÖÐc(OH¡ª)ÓëNH4ClÈÜÒºÖÐc(H+)Ïàͬ£¬¼´pH3+pH4£½14£¬ËùÒÔpH1 +pH2£¼pH3£1+pH4+1£½14¡£
£¨4£©ÈõËá¸ùÀë×ÓµÄË®½â³Ì¶ÈÔ½´ó£¬ÏàͬpHµÄÄÆÑÎÈÜÒºµÄŨ¶ÈԽС£¬ÄÆÀë×ÓŨ¶ÈԽС£¬ÓÉÓÚË®½â³Ì¶È¢Ù£¼¢Ú£¼¢Û£¬ÔòpHÏàͬµÄ¢ÙCH3COONa¡¢¢ÚNaHCO3¡¢¢ÛNaClOÈýÖÖÈÜÒºµÄc(Na£«)Ϊ¢Ù£¾¢Ú£¾¢Û¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿Ä³Ñ§ÉúÓÃÒÑÖªÎïÖʵÄÁ¿Å¨¶ÈµÄÑÎËáÀ´²â¶¨Î´ÖªÎïÖʵÄÁ¿Å¨¶ÈµÄNaOHÈÜҺʱ£¬Ñ¡Ôñ¼×»ù³È×÷ָʾ¼Á¡£ÇëÌîдÏÂÁпհס£
(1)Óñê×¼µÄÑÎËáµÎ¶¨´ý²âµÄNaOHÈÜҺʱ£¬×óÊÖÎÕËáʽµÎ¶¨¹ÜµÄ»îÈû£¬ÓÒÊÖÒ¡¶¯×¶ÐÎÆ¿£¬ÑÛ¾¦×¢ÊÓ_______£¬Ö±µ½Òò¼ÓÈëÒ»µÎÑÎËáºó£¬ÈÜÒºÓÉ________É«±äΪ________É«£¬²¢________Ϊֹ¡£
(2)ÏÂÁвÙ×÷ÖпÉÄÜʹËù²âNaOHÈÜÒºµÄŨ¶ÈÊýֵƫµÍµÄÊÇ__________¡£
A£®ËáʽµÎ¶¨¹ÜδÓñê×¼ÑÎËáÈóÏ´¾ÍÖ±½Ó×¢Èë±ê×¼ÑÎËá
B£®µÎ¶¨Ç°Ê¢·ÅNaOHÈÜÒºµÄ׶ÐÎÆ¿ÓÃÕôÁóˮϴ¾»ºóûÓиÉÔï
C£®ËáʽµÎ¶¨¹ÜÔڵζ¨Ç°ÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ
D£®¶ÁÈ¡ÑÎËáÌå»ýʱ£¬¿ªÊ¼ÑöÊÓ¶ÁÊý£¬µÎ¶¨½áÊøʱ¸©ÊÓ¶ÁÊý
(3)ÈôµÎ¶¨¿ªÊ¼ºÍ½áÊøʱ£¬ËáʽµÎ¶¨¹ÜÖеÄÒºÃæÈçͼËùʾ£¬ÔòÆðʼ¶ÁÊýΪ_______mL£¬ÖÕµã¶ÁÊýΪ_______mL£¬ËùÓÃÑÎËáÈÜÒºµÄÌå»ýΪ_______mL¡£
(4)ijѧÉú¸ù¾Ý3´ÎʵÑé·Ö±ð¼Ç¼ÓйØÊý¾ÝÈçÏÂ±í£º
µÎ¶¨ ´ÎÊý | ´ý²âNaOHÈÜÒºµÄÌå»ý/mL | 0.100 0 mol¡¤L£1 ÑÎËáµÄÌå»ý/mL | ||
µÎ¶¨Ç°¶ÁÊý | µÎ¶¨ºó¶ÁÊý | ÈÜÒºÌå»ý/mL | ||
µÚÒ»´Î | 25.00 | 0.00 | 26.11 | 26.11 |
µÚ¶þ´Î | 25.00 | 1.56 | 30.30 | 28.74 |
µÚÈý´Î | 25.00 | 0.22 | 26.31 | 26.09 |
ÒÀ¾ÝÉϱíÊý¾ÝÁÐʽ¼ÆËã¸ÃNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È__________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÎÒ¹ú¿ÆÑÐÈËÔ±ÒÔZnºÍ¼â¾§Ê¯ÐÍÃÌËáп£¨ZnMn2O4£©Îªµç¼«²ÄÁÏ£¬ÑÐÖƳöÒ»ÖÖˮϵпÀë×Óµç³Ø¡£¸Ãµç³ØµÄ×Ü·´Ó¦·½³Ìʽ£ºxZn + Zn1xMn2O4ZnMn2O4£¨0 < x < 1£©¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A. ³äµçʱ£¬Zn2+ÏòZnMn2O4µç¼«Ç¨ÒÆ
B. ³äµçʱ£¬Ñô¼«·´Ó¦£ºZnMn2O4 2xe¡ª£½Zn1-xMn2O4+xZn2+
C. ·Åµçʱ£¬Ã¿×ªÒÆ1mol e-£¬ZnMn2O4µç¼«ÖÊÁ¿Ôö¼Ó65g
D. ³ä·Åµç¹ý³ÌÖУ¬Ö»ÓÐZnÔªËصĻ¯ºÏ¼Û·¢Éú±ä»¯
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿£¨1£©Åäƽ·½³Ìʽ KMnO4+ HCl(Ũ)£ KCl+ MnCl2+ Cl2¡ü+ H2O£¬²¢ÓÃË«Ïß·¨·ÖÎö´Ë·´Ó¦£»___¡£
£¨2£©Ö¸³ö___ÊÇÑõ»¯¼Á£¬___ÔªËر»Ñõ»¯£¬Ñõ»¯²úÎïÊÇ___£¬´Ë·´Ó¦ÖУ¬HCl±íÏÖµÄÐÔÖÊÓÐ___ÐÔºÍ___ÐÔ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÀûÓû¯Ñ§ÔÀí¿ÉÒÔ¶Ô¹¤³§ÅŷŵķÏË®¡¢·ÏÔüµÈ½øÐÐÓÐЧ¼ì²âÓëºÏÀí´¦Àí¡£Ä³¹¤³§¶ÔÖƸ﹤ҵÎÛÄàÖÐCr(¢ó)µÄ´¦Àí¹¤ÒÕÁ÷³ÌÈçͼ£º
ÒÑÖª£º¢ÙÁòËá½þÈ¡ÒºÖеĽðÊôÀë×ÓÖ÷ÒªÊÇCr3£«£¬Æä´ÎÊÇFe3£«¡¢Al3£«¡¢Ca2£«ºÍMg2£«¡£
¢Ú³£ÎÂÏ£¬²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïÐÎʽ³ÁµíʱÈÜÒºµÄpHÈç±í£º
¢ÛCr(OH)(H2O)5SO4ÊÇÄÑÈÜÎï¡£
ÑôÀë×Ó | Fe3£« | Mg2£« | Al3£« | Cr3£« | |
³ÁµíÍêȫʱµÄpH | 3.7 | 11.1 | 5.4(£¾8Èܽâ) | 9(£¾9)Èܽâ |
£¨1£©ÊµÑéÊÒÓÃ18.4mol¡¤L£1µÄŨÁòËáÅäÖÆ480 mL2mol¡¤L£1µÄÁòËᣬÐèÒªÁ¿È¡Å¨ÁòËá___mL£»ÅäÖÆʱËùÓò£Á§ÒÇÆ÷³ýÁ¿Í²¡¢ÉÕ±ºÍ²£Á§°ôÍ⣬»¹Ðè____¡£
£¨2£©H2O2µÄ×÷ÓÃÊǽ«ÂËÒº¢ñÖеÄCr3£«×ª»¯ÎªCr2O72-£¬Ð´³ö´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ£º_____¡£
£¨3£©¼ÓÈëNaOHÈÜҺʹÈÜÒº³Ê¼îÐÔ£¬¼È¿ÉÒÔ³ýȥijЩÔÓÖÊÀë×Ó£¬Í¬Ê±ÓÖ¿ÉÒÔ½«Cr2O72-ת»¯Îª___(Ìî΢Á£µÄ»¯Ñ§Ê½)¡£
£¨4£©ÄÆÀë×Ó½»»»Ê÷Ö¬µÄ·´Ó¦ÔÀíΪMn£«£«nNaR=MRn£«nNa£«£¬ÔòÀûÓÃÄÆÀë×Ó½»»»Ê÷Ö¬¿É³ýÈ¥ÂËÒº¢òÖеĽðÊôÑôÀë×ÓÓÐ___¡£
£¨5£©Ð´³öÉÏÊöÁ÷³ÌÖÐÓÃSO2½øÐл¹Ôʱ·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º__¡£
£¨6£©³ÁµíµÎ¶¨·¨ÊDzⶨÁ£×ÓŨ¶ÈµÄ·½·¨Ö®Ò»£¬ÎªÁ˲ⶨij·ÏË®ÖÐSCN£µÄŨ¶È£¬¿ÉÓñê×¼AgNO3ÈÜÒºµÎ¶¨´ý²âÒº£¬ÒÑÖª£º
ÒøÑÎÐÔÖÊ | AgCl | AgI | AgCN | Ag2CrO4 | AgSCN |
ÑÕÉ« | °× | »Æ | °× | שºì | °× |
Ksp | 1.8¡Á10£10 | 8.3¡Á10£17 | 1.2¡Á10£16 | 3.5¡Á10£11 | 1.0¡Á10£12 |
µÎ¶¨Ê±¿ÉѡΪµÎ¶¨Ö¸Ê¾¼ÁµÄÊÇ___(Ìî±àºÅ)£¬µÎ¶¨ÖÕµãµÄÏÖÏóÊÇ___¡£
A£®NaCl B£®K2CrO4 C£®KI D£®NaCN
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÊµÑéÊÇ»¯Ñ§Ñо¿µÄ»ù´¡¡£ÏÂÁйØÓÚ¸÷ʵÑé×°ÖõÄÐðÊöÕýÈ·µÄÊÇ£¨ £©
A. ×°Öâٳ£ÓÃÓÚ·ÖÀ뻥²»ÏàÈܵÄÒºÌå»ìºÏÎï
B. ×°ÖâڿÉÓÃÓÚÎüÊÕNH3»òHClÆøÌ壬²¢·ÀÖ¹µ¹Îü
C. ×°ÖâܿÉÓÃÓÚ¸ÉÔï¡¢ÊÕ¼¯ÂÈ»¯Ç⣬²¢ÎüÊÕ¶àÓàµÄÂÈ»¯Çâ
D. ×°ÖâۿÉÓÃÓÚÊÕ¼¯H2¡¢CO2¡¢Cl2¡¢NH3µÈÆøÌå
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÏÖÓÐÏÂÁÐÊ®ÖÖÎïÖÊ£º¢ÙҺ̬HCl ¢ÚNaHCO3 ¢ÛNaClÈÜÒº ¢ÜCO2 ¢ÝÕáÌǾ§Ìå ¢ÞBa(OH)2 ¢ßºìºÖÉ«µÄÇâÑõ»¯Ìú½ºÌå ¢àNH3H2O ¢á¿ÕÆø ¢âAl2(SO4)3
£¨1£©ÉÏÊöÊ®ÖÖÎïÖÊÖÐÓÐÁ½ÖÖÎïÖÊÔÚË®ÈÜÒºÖпɷ¢Éú·´Ó¦£¬Àë×Ó·½³ÌʽΪ£ºH++OH£=H2O£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________________________¡£
£¨2£©¢ÚÔÚË®ÖеĵçÀë·½³ÌʽΪ______________________________¡£
£¨3£©Î¸ÒºÖк¬ÓÐÑÎËᣬθËá¹ý¶àµÄÈ˳£ÓÐθÌÛÉÕÐĵĸоõ£¬Ò×ÍÂËáË®£¬·þÓÃÊÊÁ¿µÄСËÕ´ò£¨NaHCO3£©£¬ÄÜÖÎÁÆθËá¹ý¶à£¬Çëд³öÆä·´Ó¦µÄÀë×Ó·½³Ìʽ_________________£»Èç¹û²¡ÈËͬʱ»¼Î¸À£Ññ£¬Îª·Àθ±Ú´©¿×£¬²»ÄÜ·þÓÃСËÕ´ò£¬´Ëʱ×îºÃÓú¬Al(OH)3µÄθҩ£¨ÈçθÊæƽ£©£¬ËüÓëθËá·´Ó¦µÄÀë×Ó·½³Ìʽ________¡£
£¨4£©Ð´³öÏÂÁз´Ó¦µÄÀë×Ó·½³Ìʽ£º
ÏòBa(OH)2ÈÜÒºÖÐÖðµÎ¼ÓÈëÁòËáÈÜÒº___________________________¡£
ÏòBa(OH)2ÈÜÒºÖÐͨÈë¹ýÁ¿µÄCO2_______________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿ÓÉA¡¢B¡¢C¡¢DËÄÖÖ½ðÊô°´Ï±íÖÐ×°ÖýøÐÐʵÑ飬¸ù¾ÝʵÑéÏÖÏóÌî±í£º
ÏÖÏó | £¨I£©½ðÊôAÖð½¥Èܽâ | £¨¢ò£©CµÄÖÊÁ¿Ôö¼Ó | £¨¢ó£©AÉÏÓÐÆøÌå²úÉú |
ÌîÕý¼«·´Ó¦Ê½ | ___ | ___ | |
ËÄÖÖ½ðÊô»î¶¯ÐÔÓÉÇ¿µ½ÈõµÄ˳Ðò£º___¡£ | |||
Èô×°Ö㨢ó£©ÖÐA¼«²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýΪ224mL£¬Ôòͨ¹ýµ¼ÏßÖеĵç×ÓµÄÎïÖʵÄÁ¿Îª___mol¡£ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¡¾ÌâÄ¿¡¿È¡28gÌú½«ÆäͶÈë×ãÁ¿Ï¡ÁòËáÖÐÍêÈ«Èܽ⣬
£¨1£©²úÉúÇâÆø¶àÉÙÌå»ý£¿
£¨2£©£¨±ê×¼×´¿ö£©²Î¼Ó·´Ó¦µÄÁòËáÎïÖʵÄÁ¿ÊǶàÉÙ£¿
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com