£¨8·Ö£©ÈçÏÂͼËùʾ£¬ÏòAÖгäÈë1mol XºÍ1mol Y£¬ÏòBÖгäÈë2mol XºÍ2mol Y£¬ÆðʼʱA¡¢BµÄÌå»ý¾ùΪa L£¬ÔÚÏàͬζȺÍÓд߻¯¼ÁÌõ¼þÏ£¬Á½ÈÝÆ÷Öи÷×Ô·¢Éú·´Ó¦£º
X(g)+Y(g) ?2Z(g)+W(g)£¨Õý·´Ó¦Îª·ÅÈÈ·´Ó¦£©´ïµ½Æ½ºâʱAÈÝÆ÷µÄÌå»ýΪ1.2a L¡£
(1) AÖÐXµÄת»¯ÂʦÁA=
(2) A¡¢BÖÐXµÄת»¯ÂʦÁA ¦ÁB£¨Ìî >¡¢< »ò = £©
(3) ´ò¿ªK£¬Ò»¶Îʱ¼äÓִﵽƽºâʱAµÄÌå»ýΪ L£¨Á¬Í¨¹ÜÖÐÆøÌåÌå»ýºöÂÔ²»¼Æ£©
(4) ÔÚ(3)´ïµ½Æ½ºâºó£¬Í¬Ê±µÈ·ùÉý¸ßA¡¢BµÄζȣ¬´ïµ½ÐÂƽºâºó£¬AµÄÌå»ý £¨Ìî±ä´ó¡¢±äС»ò²»±ä£©
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)AÖÐXµÄת»¯ÂʦÁ(A)=_______________¡£
(2)A¡¢BÖÐXת»¯ÂʵĹØϵ£º¦Á(A)_____________¦Á(B)(Ìî¡°£¾¡±¡°=¡±»ò¡°£¼¡±)¡£
(3)´ò¿ªK£¬Ò»¶Îʱ¼äÓÖ´ïƽºâʱ£¬AµÄÌå»ýΪ____________L(Á¬Í¨¹ÜÖÐÆøÌåÌå»ý²»¼Æ)¡£
(4)ÔÚ(3)´ïƽºâºó£¬Í¬Ê±µÈ·ùÉý¸ßA¡¢BµÄζȣ¬´ïÐÂƽºâºóAµÄÌå»ý__________(Ìî¡°±ä´ó¡±¡°²»±ä¡±»ò¡°±äС¡±)£¬ÆäÀíÓÉÊÇ________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨8·Ö£©ÈçÏÂͼËùʾ£¬ÏòAÖгäÈë1mol XºÍ1mol Y£¬ÏòBÖгäÈë2mol XºÍ2mol Y£¬ÆðʼʱA¡¢BµÄÌå»ý¾ùΪa L£¬ÔÚÏàͬζȺÍÓд߻¯¼ÁÌõ¼þÏ£¬Á½ÈÝÆ÷Öи÷×Ô·¢Éú·´Ó¦£º
X(g)+Y(g) ⇌2Z(g)+W(g)£¨Õý·´Ó¦Îª·ÅÈÈ·´Ó¦£©´ïµ½Æ½ºâʱAÈÝÆ÷µÄÌå»ýΪ1.2a L¡£
(1) AÖÐXµÄת»¯ÂʦÁA=
(2) A¡¢BÖÐXµÄת»¯ÂʦÁA ¦ÁB£¨Ìî >¡¢< »ò = £©
(3) ´ò¿ªK£¬Ò»¶Îʱ¼äÓִﵽƽºâʱAµÄÌå»ýΪ L£¨Á¬Í¨¹ÜÖÐÆøÌåÌå»ýºöÂÔ²»¼Æ£©
(4) ÔÚ(3)´ïµ½Æ½ºâºó£¬Í¬Ê±µÈ·ùÉý¸ßA¡¢BµÄζȣ¬´ïµ½ÐÂƽºâºó£¬AµÄÌå»ý £¨Ìî±ä´ó¡¢±äС»ò²»±ä£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìºÓ±±Ê¡¸ßÒ»ÏÂѧÆÚÈýµ÷¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
£¨8·Ö£©ÈçÏÂͼËùʾ£¬ÏòAÖгäÈë1mol XºÍ1mol Y£¬ÏòBÖгäÈë2mol XºÍ2mol Y£¬ÆðʼʱA¡¢BµÄÌå»ý¾ùΪa L£¬ÔÚÏàͬζȺÍÓд߻¯¼ÁÌõ¼þÏ£¬Á½ÈÝÆ÷Öи÷×Ô·¢Éú·´Ó¦£º
X(g)+Y(g) ⇌2Z(g)+W(g)£¨Õý·´Ó¦Îª·ÅÈÈ·´Ó¦£©´ïµ½Æ½ºâʱAÈÝÆ÷µÄÌå»ýΪ1.2a L¡£
(1) AÖÐXµÄת»¯ÂʦÁA=
(2) A¡¢BÖÐXµÄת»¯ÂʦÁA ¦ÁB£¨Ìî >¡¢< »ò = £©
(3) ´ò¿ªK£¬Ò»¶Îʱ¼äÓִﵽƽºâʱAµÄÌå»ýΪ L£¨Á¬Í¨¹ÜÖÐÆøÌåÌå»ýºöÂÔ²»¼Æ£©
(4) ÔÚ(3)´ïµ½Æ½ºâºó£¬Í¬Ê±µÈ·ùÉý¸ßA¡¢BµÄζȣ¬´ïµ½ÐÂƽºâºó£¬AµÄÌå»ý £¨Ìî±ä´ó¡¢±äС»ò²»±ä£©
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÈçÏÂͼËùʾ£¬ÏòAÖгäÈë1 mol XºÍ1 mol Y£¬ÏòBÖгäÈë2 mol XºÍ2 mol Y£¬Æðʼʱ£¬VA=VB=a L¡£ÔÚÏàͬζȺÍÓд߻¯¼Á´æÔÚµÄÌõ¼þÏ£¬Á½ÈÝÆ÷Öи÷×Ô·¢ÉúÏÂÊö·´Ó¦£º
X+Y2Z+W ¦¤H£¼0(X¡¢Y¡¢Z¡¢W¾ùΪÆøÌå)£¬´ïµ½Æ½ºâʱ£¬VA=1.2a L¡£
ÊԻشð£º
(1)AÖÐXµÄת»¯ÂÊaA=________£»
(2)A¡¢BÖÐXת»¯ÂʵĹØϵ£ºaA_________aB(Ìî¡°£¾¡±¡°=¡±»ò¡°£¼¡±)£»
(3)´ò¿ªK£¬Ò»¶Îʱ¼äºóÓÖ´ïƽºâʱ£¬AµÄÌå»ýΪ________L(Á¬Í¨¹ÜÖÐÆøÌåÌå»ý²»¼Æ)£»
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com