A¡¢B¡¢C¡¢D¡¢EÎåÖÖÎïÖÊÖоùº¬ÓÐͬһÖַǽðÊôÔªËØ£¬ËüÃÇÄÜ·¢ÉúÈçͼËùʾµÄת»¯¹Øϵ£¬¸ÃÔªËØ(ÓÃR±íʾ)µÄµ¥ÖÊÄÜÓëNaOHÈÜÒº·´Ó¦Éú³ÉÑÎ(Na2RO3)ºÍÇâÆø¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)д³ö¸÷ÎïÖʵĻ¯Ñ§Ê½£ºA__________£»B__________£»C__________£»D__________£»E__________¡£
(2)д³ö·´Ó¦¢ÙµÄ»¯Ñ§·½³Ìʽ£º____________________________________________£¬
¸Ã·´Ó¦ÖÐÑõ»¯¼ÁÓ뻹ԼÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ________¡£
(3)д³ö·´Ó¦¢ÜµÄÀë×Ó·½³Ìʽ£º__________________________________________¡£
(4)д³ö·´Ó¦¢ÝµÄÀë×Ó·½³Ìʽ£º___________________________________________¡£
(5)H2CO3µÄËáÐÔÇ¿ÓÚEµÄ£¬ÇëÓÃÀë×Ó·½³ÌʽÓèÒÔÖ¤Ã÷£º
________________________________________________________________________¡£
´ð°¸¡¡(1)SiO2¡¡CaSiO3¡¡Na2SiO3¡¡Si¡¡H2SiO3
(2)SiO2£«2CSi£«2CO¡ü¡¡1¡Ã2
(3)Si£«2OH££«H2O===SiO£«2H2¡ü
(4)SiO£«Ca2£«===CaSiO3¡ý
(5)SiO£«CO2£«H2O===H2SiO3¡ý£«CO
½âÎö¡¡½â´ð±¾ÌâµÄ¡°Í»ÆÆ¿Ú(1)¡±ÊǷǽðÊôÔªËØRµÄµ¥ÖÊÄÜÓëNaOHÈÜÒº·´Ó¦Éú³ÉÑÎ(Na2RO3)ºÍÇâÆø£¬ËµÃ÷Êǹ輰Æ仯ºÏÎïÖ®¼äµÄת»¯¡£¡°Í»ÆÆ¿Ú(2)¡±ÊÇ·´Ó¦Ìõ¼þ¡°¸ßΡ±£¬AÔÚ¸ßÎÂÌõ¼þÏ£¬ÄÜÓ뽹̿¡¢CaCO3·¢Éú·´Ó¦£¬ÔòAΪSiO2¡£´Ó¶ø˳ÌÙÃþ¹ÏÍÆÖªBΪCaSiO3£¬DΪSi£¬EΪH2SiO3¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Ìú¼°Æ仯ºÏÎïÔÚÈÕ³£Éú»î¡¢Éú²úÖÐÓ¦Óù㷺¡£ÂÈ»¯ÌúºÍ¸ßÌúËá¼Ø¶¼Êdz£¼ûµÄË®´¦Àí¼Á¡£ÏÂͼΪÖƱ¸ÂÈ»¯Ìú¼°½øÒ»²½Ñõ»¯ÖƱ¸¸ßÌúËá¼ØµÄ¹¤ÒÕÁ÷³Ì¡£
Çë»Ø´ðÏÂÁÐÎÊÌâ
ÓóàÌú¿óΪÔÁÏÔڸ߯Á¶Ìú¹ý³ÌÖз¢ÉúµÄÖ÷Òª·´Ó¦Îª
mol¡£
(2)ÎüÊÕ¼ÁxµÄÈÜÖÊΪ____________(д»¯Ñ§Ê½)¡£
(3)Ñõ»¯¼ÁYΪ¡°84Ïû¶¾Òº¡±µÄÓÐЧ³É·Ö£¬ÔòÔÚ¼îÐÔÌõ¼þÏ·´Ó¦¢ÙµÄÀë×Ó·½³ÌʽΪ
__________________________________________________________________
(4)¹ý³Ì¢ÚÊÇÔÚijµÍÎÂϽøÐеģ¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ=£¬ËµÃ÷´ËζÈÏÂ__________ (Ìî¡°>¡±»ò¡°<¡±)¡£
¼Ù¶¨´Ë¹ý³ÌÖÐÍêȫת»¯Îª£¬Èô×îÖÕÖƵôֲúÆ·206.25t£¬²úÆ·´¿¶ÈΪ96£¥£¬ÔòÀíÂÛÉÏÖÁÉÙÐèÒªÑõ»¯¼ÁYµÄÖÊÁ¿ÊÇ___________t¡£
(5)¸ßÌúµç³ØÊÇÒ»ÖÖÐÂÐͶþ´Îµç³Ø£¬µç½âҺΪǿ¼îÈÜÒº£¬Æäµç³Ø·´Ó¦Îª£º
·Åµçʱµç³ØµÄ¸º¼«·´Ó¦Ê½Îª______________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÈçͼËùʾ£¬ÔÚ×¢ÉäÆ÷ÖмÓÈëÉÙÁ¿Na2SO3¾§Ì壬²¢ÎüÈëÉÙÁ¿Å¨ÁòËá(ÒÔ²»½Ó´¥Ö½ÌõΪ׼)£¬ÔòÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ
A£®À¶É«Ê¯ÈïÊÔÖ½ÏȱäºìºóÍÊÉ«
B£®NaOHÈÜÒº¿ÉÓÃÓÚ³ýȥʵÑéÖжàÓàµÄSO2
C£®ÊªÈóKI£µí·ÛÊÔֽδ±äÀ¶£¬ËµÃ÷SO2µÄÑõ»¯ÐÔÇ¿ÓÚI2
D£®Æ·ºìÊÔÖ½¡¢Õ´ÓÐKMnO4ÈÜÒºµÄÂËÖ½¾ùÍÊÉ«£¬Ö¤Ã÷ÁËSO2µÄƯ°×ÐÔ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ϱíÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£
×å | ¢ñA | ¢òA | ¢óA | ¢ôA | ¢õA | ¢öA | ¢÷A |
Ò» | ¢Ù | ||||||
¶þ | ¢Ú | ¢Û | ¢Ü | ¢Ý | ¢Þ | ||
Èý | ¢ß | ¢à | ¢á | ¢â | |||
ËÄ | ¢Ï | ¢Ð | ¢Ñ |
£¨1£©ÔªËØ µÄµ¥ÖÊÊÒÎÂϳÊҺ̬£»ÔªËØ µÄÇ⻯Îï×îÎȶ¨£»ÔªËØ µÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔ×îÇ¿£»ÔªËØ µÄ¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄ¼îÐÔ×îÇ¿£¨Ìîд¡°ÔªËØ·ûºÅ¡±£©£»
£¨2£©±íÖÐÔªËØ¢ÛÓë¢áÐγÉÎȶ¨»¯ºÏÎïµÄ½á¹¹Ê½ÊÇ £»
£¨3£©±íÖÐÔªËآ٢ۢÝ×é³ÉµÄ¡°A4B2C2¡±ÐÍÎïÖÊ£¬·Ö×ÓÄÚº¬ÓеļüÐÍÊÇ £»
A£®Àë×Ó¼üºÍ¹²¼Û¼ü B£®½öΪ¹²¼Û¼ü
C£®½öΪ¼«ÐÔ¹²¼Û¼ü D£®¼«ÐÔ¹²¼Û¼üºÍ·Ç¼«ÐÔ¹²¼Û¼ü
£¨4£©±íÖÐÔªËØ µÄÇ⻯ÎïµÄ·Ö×Ó¼ä´æÔÚÇâ¼ü£¨Ìîд¡°Êý×ÖÐòºÅ¡±£©£»
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÓÃËÄÖÖÈÜÒº½øÐÐʵÑ飬ϱíÖС°²Ù×÷¼°ÏÖÏó¡±Óë¡°ÈÜÒº¡±¶ÔÓ¦¹Øϵ´íÎóµÄÊÇ (¡¡¡¡)
Ñ¡Ïî | ²Ù×÷¼°ÏÖÏó | ÈÜÒº |
A | ͨÈëCO2£¬ÈÜÒº±ä»ë×Ç | ±¥ºÍNa2CO3ÈÜÒº |
B | ͨÈëCO2£¬ÈÜÒº±ä»ë×Ç£¬¼ÌÐøͨCO2ÖÁ¹ýÁ¿£¬»ë×ÇÏûʧ | Na2SiO3ÈÜÒº |
C | ͨÈëCO2£¬ÈÜÒº±ä»ë×Ç£¬ÔÙ¼ÓÈëÆ·ºìÈÜÒº£¬ºìÉ«ÍÊÈ¥ | Ca(ClO)2ÈÜÒº |
D | ͨÈëCO2£¬ÈÜÒº±ä»ë×Ç£¬¼ÌÐøͨCO2ÖÁ¹ýÁ¿£¬»ë×ÇÏûʧ£¬ÔÙ¼ÓÈë×ãÁ¿NaOHÈÜÒº£¬ÓÖ±ä»ë×Ç | ³ÎÇåʯ»ÒË® |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
µ¥¾§¹èÊÇÐÅÏ¢²úÒµÖÐÖØÒªµÄ»ù´¡²ÄÁÏ¡£Í¨³£ÓÃ̼ÔÚ¸ßÎÂÏ»¹Ô¶þÑõ»¯¹èÖƵôֹè(º¬Ìú¡¢ÂÁ¡¢Åð¡¢Á×µÈÔÓÖÊ)£¬´Ö¹èÓëÂÈÆø·´Ó¦Éú³ÉËÄÂÈ»¯¹è(·´Ó¦Î¶È450¡«500 ¡æ)£¬ËÄÂÈ»¯¹è¾Ìá´¿ºóÓÃÇâÆø»¹Ô¿ÉµÃ¸ß´¿¹è¡£ÒÔÏÂÊÇʵÑéÊÒÖƱ¸ËÄÂÈ»¯¹èµÄ×°ÖÃʾÒâͼ¡£
Ïà¹ØÐÅÏ¢ÈçÏ£º
a£®ËÄÂÈ»¯¹èÓöË®¼«Ò×Ë®½â£»
b£®Åð¡¢ÂÁ¡¢Ìú¡¢Á×ÔÚ¸ßÎÂϾùÄÜÓëÂÈÆøÖ±½Ó·´Ó¦Éú³ÉÏàÓ¦µÄÂÈ»¯Î
c£®ÓйØÎïÖʵÄÎïÀí³£Êý¼ûÏÂ±í£º
ÎïÖÊ | SiCl4 | BCl3 | AlCl3 | FeCl3 | PCl5 |
·Ðµã/¡æ | 57.7 | 12.8 | £ | 315 | £ |
ÈÛµã/¡æ | £70.0 | £107.2 | £ | £ | £ |
Éý»ªÎ¶È/¡æ | £ | £ | 180 | 300 | 162 |
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)д³ö×°ÖÃAÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________________________
________________________________________________________________________¡£
(2)×°ÖÃAÖÐg¹ÜµÄ×÷ÓÃÊÇ____________£»×°ÖÃCÖеÄÊÔ¼ÁÊÇ__________£»×°ÖÃEÖеÄhÆ¿ÐèÒªÀäÈ´µÄÀíÓÉÊÇ________________________________________________________
________________________________________________________________________¡£
(3)×°ÖÃEÖÐhÆ¿ÊÕ¼¯µ½µÄ´Ö²úÎï¿Éͨ¹ý¾«Áó(ÀàËƶà´ÎÕôÁó)µÃµ½¸ß´¿¶ÈËÄÂÈ»¯¹è£¬¾«ÁóºóµÄ²ÐÁôÎïÖУ¬³ýÌúÔªËØÍâ¿ÉÄÜ»¹º¬ÓеÄÔÓÖÊÔªËØÊÇ________(ÌîдԪËØ·ûºÅ)¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
½«×ãÁ¿CO2ÆøÌåͨÈëË®²£Á§(Na2SiO3ÈÜÒº)ÖУ¬È»ºó¼ÓÈÈÕô¸É£¬ÔÙÔÚ¸ßÎÂϳä·Ö×ÆÉÕ£¬×îºóµÃµ½µÄ¹ÌÌåÎïÖÊÊÇ (¡¡¡¡)
A£®Na2SiO3 B£®Na2CO3¡¢Na2SiO3
C£®Na2CO3¡¢SiO2 D£®SiO2
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
Áò»¯¼î·¨Êǹ¤ÒµÉÏÖƱ¸Na2S2O3µÄ·½·¨Ö®Ò»£¬·´Ó¦ÔÀíΪ£º
2Na2S+Na2CO3+4SO2==3Na2S2O3+CO2 £¨¸Ã·´Ó¦¡÷H>0£©
ijÑо¿Ð¡×éÔÚʵÑéÊÒÓÃÁò»¯¼î·¨ÖƱ¸Na2S2O3¡¤5H2OÁ÷³ÌÈçÏ¡£
£¨1£©ÎüÁò×°ÖÃÈçͼËùʾ¡£
¢Ù×°ÖÃBµÄ×÷ÓÃÊǼìÑé×°ÖÃAÖÐSO2µÄÎüÊÕЧÂÊ£¬BÖÐÊÔ¼ÁÊÇ £¬±íÃ÷SO2ÎüÊÕЧÂʵ͵ÄʵÑéÏÖÏóÊÇBÖÐÈÜÒº ¡£
¢ÚΪÁËʹSO2¾¡¿ÉÄÜÎüÊÕÍêÈ«£¬ÔÚ²»¸Ä±äAÖÐÈÜҺŨ¶È¡¢Ìå»ýµÄÌõ¼þÏ£¬³ýÁ˼°Ê±½Á°è·´Ó¦ÎïÍ⣬»¹¿É²ÉÈ¡µÄºÏÀí´ëÊ©ÊÇ ¡¢ ¡££¨Ð´³öÁ½Ìõ£©
£¨2£©¼ÙÉ豾ʵÑéËùÓõÄNa2CO3º¬ÉÙÁ¿NaCl¡¢NaOH£¬Éè¼ÆʵÑé·½°¸½øÐмìÑé¡££¨ÊÒÎÂʱCaCO3±¥ºÍÈÜÒºµÄpH=10.2£©
ÏÞÑ¡ÊÔ¼Á¼°ÒÇÆ÷£ºÏ¡ÏõËá¡¢AgNO3ÈÜÒº¡¢CaCl2ÈÜÒº¡¢Ca(NO3)2ÈÜÒº¡¢·Ó̪ÈÜÒº¡¢ÕôÁóË®¡¢pH¼Æ¡¢ÉÕ±¡¢ÊԹܡ¢µÎ¹Ü
ÐòºÅ | ʵÑé²Ù×÷ | Ô¤ÆÚÏÖÏó | ½áÂÛ |
¢Ù | È¡ÉÙÁ¿ÑùÆ·ÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿ÕôÁóË®£¬³ä·ÖÕñµ´Èܽ⣬___________________¡£ | _______________ | ÑùÆ·º¬NaCl |
¢Ú | ÁíÈ¡ÉÙÁ¿ÑùÆ·ÓÚÉÕ±ÖУ¬¼ÓÈëÊÊÁ¿ÕôÁóË®£¬³ä·Ö½Á°èÈܽ⣬___________________¡£ | _______________ | ÑùÆ·º¬NaOH |
£¨3£©Na2S2O3ÈÜÒºÊǶ¨Á¿ÊµÑéÖеij£ÓÃÊÔ¼Á£¬²â¶¨ÆäŨ¶ÈµÄ¹ý³ÌÈçÏ£º×¼È·³ÆÈ¡a g KIO3£¨»¯Ñ§Ê½Á¿£º214£©¹ÌÌåÅä³ÉÈÜÒº£¬¼ÓÈë¹ýÁ¿KI¹ÌÌåºÍH2SO4ÈÜÒº£¬µÎ¼Óָʾ¼Á£¬ÓÃNa2S2O3ÈÜÒºµÎ¶¨ÖÁÖյ㣬ÏûºÄNa2S2O3ÈÜÒºµÄÌå»ýΪV mL¡£Ôòc(Na2S2O3)£½_________mol¡¤L£1¡££¨Ö»ÁгöËãʽ£¬²»×÷ÔËË㣩
ÒÑÖª£ºCr2O72££«6I£+14H+=== 2Cr3+£«3I2£«7H2O 2S2O32££«I2===S4O62££«2I£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
º£Ë®ÊǾ޴óµÄ×ÊÔ´±¦¿â£¬ÔÚº£Ë®µ»¯¼°×ÛºÏÀûÓ÷½Ã棬Ìì½òÊÐλ¾ÓÈ«¹úÇ°ÁС£´Óº£Ë®ÖÐÌáȡʳÑκÍäåµÄ¹ý³ÌÈçÏ£º
(1)ÇëÁоٺ£Ë®µ»¯µÄÁ½ÖÖ·½·¨£º______________________¡¢________________________¡£
(2)½«NaClÈÜÒº½øÐеç½â£¬ÔÚµç½â²ÛÖпÉÖ±½ÓµÃµ½µÄ²úÆ·ÓÐH2¡¢________¡¢________»òH2¡¢________¡£
(3)²½Öè¢ñÖÐÒÑ»ñµÃBr2£¬²½Öè¢òÖÐÓÖ½«Br2»¹ÔΪBr££¬ÆäÄ¿µÄΪ________________________________________________________________________¡£
(4)²½Öè¢òÓÃSO2Ë®ÈÜÒºÎüÊÕBr2£¬ÎüÊÕÂÊ¿É´ï95%£¬Óйط´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________________________________________________£¬
ÓÉ´Ë·´Ó¦¿ÉÖª£¬³ý»·¾³±£»¤Í⣬ÔÚ¹¤ÒµÉú²úÖÐÓ¦½â¾öµÄÖ÷ÒªÎÊÌâÊÇ________________________________________________________________________¡£
(5)ij»¯Ñ§Ñо¿ÐÔѧϰС×éΪÁ˽â´Ó¹¤ÒµäåÖÐÌá´¿äåµÄ·½·¨£¬²éÔÄÁËÓйØ×ÊÁÏ£ºBr2µÄ·ÐµãΪ59 ¡æ£¬Î¢ÈÜÓÚË®£¬Óж¾ÐÔºÍÇ¿¸¯Ê´ÐÔ¡£ËûÃDzιÛÉú²ú¹ý³Ìºó£¬»æÖÆÁËÈçÏÂ×°Öüòͼ£º
ÇëÄã²ÎÓë·ÖÎöÌÖÂÛ£º
¢ÙͼÖÐÒÇÆ÷BµÄÃû³Æ£º________________£»
¢ÚÕûÌ×ʵÑé×°ÖÃÖÐÒÇÆ÷Á¬½Ó¾ù²»ÄÜÓÃÏð½ºÈûºÍÏ𽺹ܣ¬ÆäÔÒòΪ________________________________________________________________________£»
¢ÛʵÑé×°ÖÃÆøÃÜÐÔÁ¼ºÃ£¬Òª´ïµ½Ìá´¿äåµÄÄ¿µÄ£¬²Ù×÷ÖÐÈçºÎ¿ØÖƹؼüÌõ¼þ£º________________________________________________________________________£»
¢ÜCÖÐÒºÌå²úÎïÑÕɫΪ________£¬Îª³ýÈ¥¸Ã²úÎïÖÐÈÔ²ÐÁôµÄÉÙÁ¿Cl2£¬¿ÉÏòÆäÖмÓÈëNaBrÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬ÔÙ½øÐеķÖÀë²Ù×÷ÊÇ___________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com