£¨10·Ö£©ÕÕÏàÓõķ϶¨Ó°ÒºÖк¬ÓÐNa£«¡¢[Ag(S2O3)2]3£­¡¢Br£­µÈÀë×Ó¡£Ä³Ñо¿ÐÔѧϰС×éÄâͨ¹ýÏÂÁÐʵÑé³ÌÐò£¬¶ÔijÕÕÏ๫˾µÄ·Ï¶¨Ó°Òº½øÐÐʵÑé´¦Àí£¬»ØÊÕÆäÖеÄÒøºÍäå¡££¨ÒÑÖª£º4H£«+2 [Ag(S2O3)2]3£­= Ag2S¡ý+3S¡ý+3SO2¡ü+SO42£­+2H2O£©

¢Å²Ù×÷¢óµÄÃû³ÆÊÇ   ¡ø £»²Ù×÷¢òÐèÒªµÄÖ÷Òª²£Á§ÒÇÆ÷ÓР   ¡ø  ¡£
¢Æ¼ÓÈëп·ÛµÄÄ¿µÄÊǽ«ÉÙÁ¿ä廯ÒøÖеÄÒø»¹Ô­³öÀ´£¬¸Ã·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ   ¡ø¡£
¢ÇÒºÌåBÖгýº¬ÓÐBr£­£¬»¹ÓÐSO42£­£¬¼ìÑéÈÜÒºÖдæÔÚSO42£­µÄ²Ù×÷ÊÇ   ¡ø  ¡£
¢È²½Öè¢ÛʵÑé²Ù×÷ʱ£¬Ò²³£²ÉÓüÓÈëÊÊÁ¿ÏõËá¼Ø¼Ó¸ÇºóÔÙ×ÆÈȵķ½·¨£¬ÍƲâ¼ÓÏõËá¼ØµÄÄ¿µÄ¿ÉÄÜÊÇ         ¡ø        ¡£
¢Éͨ¹ýÉÏÊö»ØÊÕÒøµÄÁ÷³ÌÖУ¬´ÓÂÌÉ«»¯Ñ§µÄÒªÇó¿´£¬´æÔڵIJ»×ãΪ    ¡ø   ¡£

£¨10·Ö£©
¢ÅÕôÁó(1·Ö)     ·ÖҺ©¶·¡¢ÉÕ±­(2·Ö)
¢Æ2AgBr + Zn =" 2Ag" + Zn2+ + 2Br¡ª  (2·Ö)
¢ÇÈ¡ÉÙÁ¿ÒºÌåBÓÚСÊÔ¹ÜÖУ¬µÎ¼ÓBaCl2ÈÜÒº£¬Óа×É«³Áµí˵Ã÷ÓÐSO42¡ª(2·Ö)
¢ÈÌṩÑõ£¬Ê¹Ag2S³ä·Ö·´Ó¦(2·Ö)
¢ÉÔÚ¿ÕÆøÖÐ×ÆÉÕ²úÉúµÄSO2Óж¾£¬ÎÛȾ¿ÕÆø(1·Ö)

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÕÕÏàÓõķ϶¨Ó°ÒºÖк¬ÓÐNa+¡¢[Ag£¨S2O3£©2]3-¡¢Br-µÈÀë×Ó£®Ä³Ñо¿ÐÔѧϰС×éÄâͨ¹ýÏÂÁÐʵÑé³ÌÐò£¬¶ÔijÕÕÏ๫˾µÄ·Ï¶¨Ó°Òº½øÐÐʵÑé´¦Àí£¬»ØÊÕÆäÖеÄÒøºÍä壮£¨ÒÑÖª£º4H++2[Ag£¨S2O3£©2]3-¨TAg2S¡ý+3S¡ý+3SO2¡ü+SO42-+2H2O£©

£¨1£©×÷¢óµÄÃû³ÆÊÇ
ÕôÁó
ÕôÁó
£»²Ù×÷¢òÐèÒªµÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐ
·ÖҺ©¶·¡¢ÉÕ±­
·ÖҺ©¶·¡¢ÉÕ±­
£®
£¨2£©¼ÓÈëп·ÛµÄÄ¿µÄÊǽ«ÉÙÁ¿ä廯ÒøÖеÄÒø»¹Ô­³öÀ´£¬¸Ã·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ
2AgBr+Zn¨T2Ag+Zn2++2Br-
2AgBr+Zn¨T2Ag+Zn2++2Br-
£®
£¨3£©ÒºÌåBÖгýº¬ÓÐBr-£¬»¹ÓÐSO42-£¬¼ìÑéÈÜÒºÖдæÔÚSO42-µÄ²Ù×÷ÊÇ
È¡ÉÙÁ¿ÒºÌåBÓÚСÊÔ¹ÜÖУ¬µÎ¼ÓBaCl2ÈÜÒº£¬Óа×É«³Áµí˵Ã÷ÓÐSO42-
È¡ÉÙÁ¿ÒºÌåBÓÚСÊÔ¹ÜÖУ¬µÎ¼ÓBaCl2ÈÜÒº£¬Óа×É«³Áµí˵Ã÷ÓÐSO42-
£®
£¨4£©²½Öè¢ÛʵÑé²Ù×÷ʱ£¬Ò²³£²ÉÓüÓÈëÊÊÁ¿ÏõËá¼Ø¼Ó¸ÇºóÔÙ×ÆÈȵķ½·¨£¬ÍƲâ¼ÓÏõËá¼ØµÄÄ¿µÄ¿ÉÄÜÊÇ
ÌṩÑõ£¬Ê¹Ag2S³ä·Ö·´Ó¦
ÌṩÑõ£¬Ê¹Ag2S³ä·Ö·´Ó¦
£®
£¨5£©Í¨¹ýÉÏÊö»ØÊÕÒøµÄÁ÷³ÌÖУ¬´ÓÂÌÉ«»¯Ñ§µÄÒªÇó¿´£¬´æÔڵIJ»×ãΪ
ÔÚ¿ÕÆøÖÐ×ÆÉÕ²úÉúµÄSO2Óж¾£¬ÎÛȾ¿ÕÆø
ÔÚ¿ÕÆøÖÐ×ÆÉÕ²úÉúµÄSO2Óж¾£¬ÎÛȾ¿ÕÆø
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÕÕÏàÓõķ϶¨Ó°ÒºÖк¬ÓÐNa+¡¢[Ag£¨S2O3£©2]3-¡¢Br-µÈÀë×Ó£®Ä³Ñо¿ÐÔѧϰС×éÄâͨ¹ýÏÂÁÐʵÑé³ÌÐò£¬¶ÔijÕÕÏ๫˾µÄ·Ï¶¨Ó°Òº½øÐÐʵÑé´¦Àí£¬»ØÊÕÆäÖеÄÒøºÍä壮
¾«Ó¢¼Ò½ÌÍø
ÒÑÖª£º4H++2[Ag£¨S2O3£©2]3-=Ag2S¡ý+3S¡ý+3SO2¡ü+SO42-+2H2
£¨1£©¼ÓÈëп·ÛµÄÄ¿µÄÊǽ«ÈÜÒºÖеÄÉÙÁ¿ä廯Òø»¹Ô­³öÀ´£¬¸Ã·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ
 
£®
£¨2£©²Ù×÷¢ñµÄÃû³ÆÊÇ
 
£»²Ù×÷¢òµÄÃû³ÆÊÇ
 
£»²Ù×÷¢óÐèÒªµÄÖ÷ÒªÒÇÆ÷³ýÌú¼Ų̈¡¢¾Æ¾«µÆ¡¢×¶ÐÎÆ¿¡¢½ÓÒºÆ÷Í⣬»¹ÓÐ
 
£®
£¨3£©ÒºÌåBÖгýº¬ÓÐBr-£¬»¹ÓÐSO42-£¬¼ìÑéÈÜÒºÖдæÔÚSO42-µÄ²Ù×÷ÊÇ
 
£®
£¨4£©Í¨¹ýÉÏÊöÁ÷³Ì»ØÊÕÒøµÄÁ÷³ÌÖУ¬´ÓÂÌÉ«»¯Ñ§µÄÒªÇó¿´£¬´æÔڵIJ»×ãΪ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê½­ËÕÊ¡Ì©ÖÝÖÐѧ¸ßÈý»¯Ñ§ÆÚÖл¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

(12·Ö) (12·Ö) ÕÕÏàÓõķ϶¨Ó°ÒºÖк¬ÓÐNa£«¡¢[Ag(S2O3)2]3£­¡¢Br£­µÈÀë×Ó¡£Ä³Ñо¿ÐÔѧϰС×éÄâͨ¹ýÏÂÁÐʵÑé³ÌÐò£¬¶ÔijÕÕÏ๫˾µÄ·Ï¶¨Ó°Òº½øÐÐʵÑé´¦Àí£¬»ØÊÕÆäÖеÄÒøºÍäå¡££¨ÒÑÖª£º 4H£«+2 [Ag(S2O3)2]3£­ = Ag2S¡ý+3S¡ý+3SO2¡ü+SO42£­+2H2O£©

£¨1£©²Ù×÷¢óµÄÃû³ÆÊÇ  ¡ø £»²Ù×÷¢òÐèÒªµÄÖ÷Òª²£Á§ÒÇÆ÷ÓР  ¡ø  ¡£
£¨2£©¼ÓÈëп·ÛµÄÄ¿µÄÊǽ«ÉÙÁ¿ä廯ÒøÖеÄÒø»¹Ô­³öÀ´£¬¸Ã·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ  ¡ø¡£
£¨3£©ÒºÌåBÖгýº¬ÓÐBr£­£¬»¹ÓÐSO42£­£¬¼ìÑéÈÜÒºÖдæÔÚSO42£­µÄ²Ù×÷ÊÇ  ¡ø  ¡£
£¨4£©²½Öè¢ÛʵÑé²Ù×÷ʱ£¬Ò²³£²ÉÓüÓÈëÊÊÁ¿ÏõËá¼Ø¼Ó¸ÇºóÔÙ×ÆÈȵķ½·¨£¬ÍƲâ¼ÓÏõËá¼ØµÄÄ¿µÄ¿ÉÄÜÊÇ        ¡ø        ¡£
£¨5£©Í¨¹ýÉÏÊö»ØÊÕÒøµÄÁ÷³ÌÖУ¬´ÓÂÌÉ«»¯Ñ§µÄÒªÇó¿´£¬´æÔڵIJ»×ãΪ   ¡ø   ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012½ì½­Î÷ʡʦ´ó¸½ÖиßÈýÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨10·Ö£©ÕÕÏàÓõķ϶¨Ó°ÒºÖк¬ÓÐNa£«¡¢[Ag(S2O3)2]3£­¡¢Br£­µÈÀë×Ó.ijÑо¿ÐÔѧϰС×éÄâͨ¹ýÏÂÁÐʵÑé³ÌÐò£¬¶ÔijÕÕÏ๫˾µÄ·Ï¶¨Ó°Òº½øÐÐʵÑé´¦Àí£¬»ØÊÕÆäÖеÄÒøºÍäå.
£¨ÒÑÖª£º4H£«+2 [Ag(S2O3)2]3£­ = Ag2S¡ý+3S¡ý+3SO2¡ü+SO42£­+2H2O£©

£¨1£©²Ù×÷¢óµÄÃû³ÆÊÇ         £»²Ù×÷¢òÐèÒªµÄÖ÷Òª²£Á§ÒÇÆ÷ÓР           .
£¨2£©¼ÓÈëп·ÛµÄÄ¿µÄÊǽ«ÉÙÁ¿ä廯ÒøÖеÄÒø»¹Ô­³öÀ´£¬¸Ã·´Ó¦µÄÀë×Ó·´Ó¦·½³ÌʽΪ                                                         .
£¨3£©ÒºÌåBÖгýº¬ÓÐBr£­£¬»¹ÓÐSO42£­£¬¼ìÑéÈÜÒºÖдæÔÚSO42£­µÄ²Ù×÷ÊÇ     
                                                                     .
£¨4£©²½Öè¢ÛʵÑé²Ù×÷ʱ£¬Ò²³£²ÉÓüÓÈëÊÊÁ¿ÏõËá¼Ø¼Ó¸ÇºóÔÙ×ÆÈȵķ½·¨£¬ÍƲâ¼ÓÏõËá¼ØµÄÄ¿µÄ¿ÉÄÜÊÇ                                                             .
£¨5£©ÉÏÊö»ØÊÕÒøµÄÁ÷³ÌÖУ¬´ÓÂÌÉ«»¯Ñ§µÄÒªÇó¿´£¬´æÔڵIJ»×ãÊÇ                                .

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸