½üÄêÀ´£¬ÓÉCO2´ß»¯¼ÓÇâºÏ³É¼×´¼µÄÏà¹ØÑо¿Êܵ½Ô½À´Ô½¶àµÄ¹Ø×¢¡£¸Ã·½·¨¼È¿É½â¾öCO2·ÏÆøµÄÀûÓÃÎÊÌ⣬ÓÖ¿É¿ª·¢Éú²ú¼×´¼µÄÐÂ;¾¶£¬¾ßÓÐÁ¼ºÃµÄÓ¦ÓÃÇ°¾°¡£ÒÑÖª4.4 g CO2ÆøÌåÓëH2¾­´ß»¯¼ÓÇâÉú³ÉCH3OHÆøÌåºÍË®ÕôÆøʱ·Å³ö4.95 kJµÄÄÜÁ¿¡£
(1)¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º__________________________________________.
(2)ÔÚ270¡æ¡¢8 MPaºÍÊʵ±´ß»¯¼ÁµÄÌõ¼þÏ£¬CO2µÄת»¯ÂÊ´ïµ½22%£¬Ôò4.48 m3(ÒÑÕÛºÏΪ±ê×¼×´¿ö)µÄCO2ÔںϳÉCH3OHÆøÌå¹ý³ÌÖÐÄܷųöÈÈÁ¿________ kJ.
(3)ÓÖÒÑÖªH2O(g)===H2O(l)¡¡¦¤H£½£­44 kJ/mol£¬ÔòCO2ÆøÌåÓëH2ÆøÌå·´Ó¦Éú³ÉCH3OHÆøÌå16gºÍҺ̬ˮʱ·Å³öÈÈÁ¿Îª           kJ£®

(1) CO2(g)+3H2(g)=CH3OH(g)+H2O(g);¦¤H=-49.5KJ/mol
(2) 2178kJ    (3) 2.75 kJ

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½üÄêÀ´£¬ÓÉCO2´ß»¯¼ÓÇâºÏ³É¼×´¼µÄÏà¹ØÑо¿Êܵ½Ô½À´Ô½¶àµÄ¹Ø×¢£®¸Ã·½·¨¼È¿É½â¾öCO2·ÏÆøµÄÀûÓÃÎÊÌ⣬ÓÖ¿É¿ª·¢Éú²ú¼×´¼µÄÐÂ;¾¶£¬¾ßÓÐÁ¼ºÃµÄÓ¦ÓÃÇ°¾°£®ÒÑÖª4.4g CO2ÆøÌåÓëH2¾­´ß»¯¼Ó³ÉÉú³ÉCH3OHÆøÌåºÍË®ÕôÆøʱ·Å³ö4.95kJµÄÄÜÁ¿£®
£¨1£©¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º
CO2£¨g£©+3H2£¨g£©¨TCH3OH£¨g£©+H2O£¨g£©¡÷H=-49.5kJ/mol
CO2£¨g£©+3H2£¨g£©¨TCH3OH£¨g£©+H2O£¨g£©¡÷H=-49.5kJ/mol

£¨2£©ÔÚ270¡æ¡¢8MPaºÍÊʵ±´ß»¯¼ÁµÄÌõ¼þÏ£¬CO2µÄת»¯ÂÊ´ïµ½22%£¬Ôò4.48m3£¨ÒÑÕÛºÏΪ±ê×¼×´¿ö£©µÄCO2ÄܺϳÉCH3OHÆøÌåµÄÎïÖʵÄÁ¿ÊÇ
44mol
44mol
£¬´Ë¹ý³ÌÖÐÄÜ  ·Å³öÈÈÁ¿
2178
2178
 kJ£®
£¨3£©ÓÖÒÑÖªH2O£¨g£©¨TH2O£¨l£©¡÷H=-44kJ/mol£¬Ôò22g CO2ÆøÌåÓëH2·´Ó¦Éú³ÉCH3OHÆøÌåºÍҺ̬ˮʱ·Å³öÈÈÁ¿Îª
46.75KJ
46.75KJ
£®
£¨4£©¸ù¾Ý¸Ã·´Ó¦Ìص㣬ÓÐÀûÓÚ¼×´¼ºÏ³ÉµÄÌõ¼þÊÇ
C
C
£®
A£®¸ßѹ¸ßΡ¡¡¡¡¡¡¡¡¡¡¡B£®µÍѹ¸ßÎÂ
C£®¸ßѹµÍΠ           D£®µÍѹµÍΣ®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½üÄêÀ´£¬ÓÉCO2´ß»¯¼ÓÇâºÏ³É¼×´¼µÄÏà¹ØÑо¿Êܵ½Ô½À´Ô½¶àµÄ¹Ø×¢£®¸Ã·½·¨¼È¿É½â¾öCO2·ÏÆøµÄÀûÓÃÎÊÌ⣬ÓÖ¿É¿ª·¢Éú²ú¼×´¼µÄÐÂ;¾¶£¬¾ßÓÐÁ¼ºÃµÄÓ¦ÓÃÇ°¾°£®ÒÑÖª4.4g CO2ÆøÌåÓëH2¾­´ß»¯¼ÓÇâÉú³ÉCH3OHÆøÌåºÍË®ÕôÆøʱ·Å³ö4.95kJµÄÄÜÁ¿£®
£¨1£©¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º
 
£®
£¨2£©ÔÚ270¡æ¡¢8MPaºÍÊʵ±´ß»¯¼ÁµÄÌõ¼þÏ£¬CO2µÄת»¯ÂÊ´ïµ½22%£¬Ôò4.48m3£¨ÒÑÕÛºÏΪ±ê×¼×´¿ö£©µÄCO2ÔںϳÉCH3OHÆøÌå¹ý³ÌÖÐÄܷųöÈÈÁ¿
 
 kJ£®
£¨3£©ÓÖÒÑÖªH2O£¨g£©¨TH2O£¨l£©¡÷H=-44kJ/mol£¬ÔòCO2ÆøÌåÓëH2ÆøÌå·´Ó¦Éú³ÉCH3OHÆøÌå16gºÍҺ̬ˮʱ·Å³öÈÈÁ¿Îª
 
kJ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

½üÄêÀ´£¬ÓÉCO2´ß»¯¼ÓÇâºÏ³É¼×´¼µÄÏà¹ØÑо¿Êܵ½Ô½À´Ô½¶àµÄ¹Ø×¢¡£¸Ã·½·¨¼È¿É½â¾öCO2·ÏÆøµÄÀûÓÃÎÊÌ⣬ÓÖ¿É¿ª·¢Éú²ú¼×´¼µÄÐÂ;¾¶£¬¾ßÓÐÁ¼ºÃµÄÓ¦ÓÃÇ°¾°¡£ÒÑÖª4.4 g CO2ÆøÌåÓëH2¾­´ß»¯¼ÓÇâÉú³ÉCH3OHÆøÌåºÍË®ÕôÆøʱ·Å³ö4.95 kJµÄÄÜÁ¿¡£

(1)¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º__________________________________________.

(2)ÔÚ270¡æ¡¢8 MPaºÍÊʵ±´ß»¯¼ÁµÄÌõ¼þÏ£¬CO2µÄת»¯ÂÊ´ïµ½22%£¬Ôò4.48 m3(ÒÑÕÛºÏΪ±ê×¼×´¿ö)µÄCO2ÔںϳÉCH3OHÆøÌå¹ý³ÌÖÐÄܷųöÈÈÁ¿________ kJ.

(3)ÓÖÒÑÖªH2O(g)===H2O(l)¡¡¦¤H£½£­44 kJ/mol£¬ÔòCO2ÆøÌåÓëH2ÆøÌå·´Ó¦Éú³ÉCH3OHÆøÌå16gºÍҺ̬ˮʱ·Å³öÈÈÁ¿Îª            kJ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äêºþ±±Ê¡¸ß¶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

½üÄêÀ´£¬ÓÉCO2´ß»¯¼ÓÇâºÏ³É¼×´¼µÄÏà¹ØÑо¿Êܵ½Ô½À´Ô½¶àµÄ¹Ø×¢¡£¸Ã·½·¨¼È¿É½â¾öCO2·ÏÆøµÄÀûÓÃÎÊÌ⣬ÓÖ¿É¿ª·¢Éú²ú¼×´¼µÄÐÂ;¾¶£¬¾ßÓÐÁ¼ºÃµÄÓ¦ÓÃÇ°¾°¡£ÒÑÖª4.4 g CO2ÆøÌåÓëH2¾­´ß»¯¼ÓÇâÉú³ÉCH3OHÆøÌåºÍË®ÕôÆøʱ·Å³ö4.95 kJµÄÄÜÁ¿¡£

(1)¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º__________________________________________.

(2)ÔÚ270¡æ¡¢8 MPaºÍÊʵ±´ß»¯¼ÁµÄÌõ¼þÏ£¬CO2µÄת»¯ÂÊ´ïµ½22%£¬Ôò4.48 m3(ÒÑÕÛºÏΪ±ê×¼×´¿ö)µÄCO2ÔںϳÉCH3OHÆøÌå¹ý³ÌÖÐÄܷųöÈÈÁ¿________ kJ.

(3)ÓÖÒÑÖªH2O(g)===H2O(l)¡¡¦¤H£½£­44 kJ/mol£¬ÔòCO2ÆøÌåÓëH2ÆøÌå·´Ó¦Éú³ÉCH3OHÆøÌå16gºÍҺ̬ˮʱ·Å³öÈÈÁ¿Îª            kJ£®

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸