ÖØË®(D2O)µÄÀë×Ó»ýC(D+)¡¤C(OD£­)£½1.6¡Á10£­15£¬¿ÉÒÔÓÃpHÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨pD£¬pD£½£­lgC(D+)£®ÏÂÁйØÓÚpDµÄÐðÊöÕýÈ·µÄÊÇ

[¡¡¡¡]

A£®ÖÐÐÔÈÜÒºpD£½7

B£®º¬0.01mol/L NaODµÄD2OÈÜÒº1L£¬pD£½12.0

C£®Èܽâ0.01mol DClµÄD2OÈÜÒº1L£¬pD£½2.0

D£®ÔÚ100mL 0.25mol/LµÄDClÖØË®ÈÜÒºÖУ¬¼ÓÈë50mL 0.2mol/LµÄNaODÖØË®ÈÜÒº£¬pD£½1.0

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ijζÈÏ£¬ÖØË®D2OµÄÀë×Ó»ýΪ1.6¡Á10-15£¬ÈôÓÃpHÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨pD=-lgc(D+)£¬ÒÔϹØÓÚpDµÄÐðÊöÕýÈ·µÄÊÇ£¨    £©

A.ÖÐÐÔÈÜÒºµÄpD=7.0

B.º¬0.01 molµÄNaOHµÄD2OÈÜÒº1 L£¬ÆäpD=12.0

C.ÈÜÓÐ0.01 mol DClµÄË®ÈÜÒº1 L£¬ÆäpD=2.0

D.ÔÚ100 mL 0.25 mol¡¤L-1µÄDClÖØË®ÈÜÒºÖУ¬¼ÓÈë50 mL 0.2 mol¡¤L-1µÄNaODµÄÖØË®ÈÜÒº£¬ÆäpD=1.0

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêɽ¶«Ê¡Ý·ÏØʵÑé¸ßÖи߶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

ÉèË®µÄµçÀëƽºâÏßÈçͼËùʾ¡£

£¨1£©ÈôÒÔAµã±íʾ25¡æʱˮÔÚµçÀëƽºâʱµÄÀë×ÓŨ¶È£¬µ±Î¶ÈÉÏÉýµ½100¡æʱ£¬Ë®µÄµçÀëƽºâ״̬µ½Bµã£¬Ôò´ËʱˮµÄÀë×Ó»ý´Ó________Ôö¼Óµ½______¡£
£¨2£©pH=8µÄBa£¨OH£©2ÈÜÒºÓëpH=5µÄÏ¡ÑÎËá»ìºÏ£¬²¢±£³Ö100¡æµÄºãΣ¬Óûʹ»ìºÏÈÜÒºpH=7£¬ÔòBa(OH)2ÈÜÒºÓëÑÎËáµÄÌå»ý±ÈΪ_________¡£
£¨3£©ÈôÔÚijζÈÏ£¬ÖØË®(D2O)µÄÀë×Ó»ý³£ÊýΪ1¡Á10-12¡£ÈôÓÃpHÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨pDÖµ£¬ÔòpD=£­lg{ c£¨D+£©}¡£¸ÃζÈÏ£º´¿ÖØË®µÄpD=_____£¬1LÈÜÓÐ0.01molNaODµÄD2OÈÜÒº£¬ÆäpD="___" £¬1 00mL0.1mol/LµÄD2SO4ÈÜÒºÓë100mL0.4mol/LµÄKODµÄD2OÈÜÒº»ìºÏ£¬pD=______¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêËս̰æ¸ßÖл¯Ñ§Ñ¡ÐÞ4 3.2ÈÜÒºµÄËá¼îÐÔÁ·Ï°¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ

ijζÈÏ£¬ÖØË®D2OµÄÀë×Ó»ýΪ1.6¡Á10-15£¬ÈôÓÃpHÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨pD=-lgc(D+)£¬ÒÔϹØÓÚpDµÄÐðÊöÕýÈ·µÄÊÇ£¨   £©

A£®ÖÐÐÔÈÜÒºµÄpD=7.0

B£®º¬0.01 molµÄNaOHµÄD2OÈÜÒº1 L£¬ÆäpD=12.0

C£®ÈÜÓÐ0.01 mol DClµÄË®ÈÜÒº1 L£¬ÆäpD=2.0

D£®ÔÚ100 mL 0.25 mol¡¤L-1µÄDClÖØË®ÈÜÒºÖУ¬¼ÓÈë50 mL 0.2 mol¡¤L-1µÄNaODµÄÖØË®ÈÜÒº£¬ÆäpD=1.0

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2013½ìºÓ±±ÌÆɽÊи߶þÄ꼶µ÷Ñп¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÑ¡ÔñÌâ

ÖØË®D2OµÄÀë×Ó»ýΪ1.6¡Á10-15£¬¿ÉÒÔÓÃpHÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨pD=¡ªlg c(D+),ÒÔϹØÓÚpDµÄÐðÊöÕýÈ·µÄÊÇ£¨   )

A.ÖÐÐÔÈÜÒºÖÐpD=7

B.ÔÚ1L D2OµÄÈÜÒºÖÐÈܽâ0.01mol NaOD£¨ÉèÈÜÒºµÄÌå»ýΪ1L£©£¬ÆäÖÐpD=12

C.ÔÚ1L D2OÖÐÈܽâ 0.01mol DCl(ÉèÈÜÒºµÄÌå»ýΪ1L)£¬ÆäÖÐpD=2

D.ÔÚ100mL 0.25mol¡¤L-1µÄNaODÖØË®ÈÜÒºÖмÓÈë50mL 0.2mol¡¤L-1DClµÄµÄÖØË®ÈÜÒº£¬ÆäpD=1

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010Äê¹ãÎ÷ÁøÖݶþÖиßÈýµÚÈý´ÎÄ£Ä⿼ÊÔ£¨Àí¿Æ×ۺϣ©»¯Ñ§²¿·Ö ÌâÐÍ£ºÑ¡ÔñÌâ

250Cʱ£¬ÖØË®(D2O)µÄÀë×Ó»ýΪ1£®6¡Á10-15Ò²¿ÉÓÃpHÖµÒ»ÑùµÄ¶¨ÒåÀ´¹æ¶¨ÆäËá¼î¶È£ºpD==-lgCD+£¬ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ(    )

  ¢ÙÖÐÐÔD2OµÄpD=7

  ¢ÚÔÚ1LD2OÖУ¬Èܽâ0£®01molDCl£¬ÆäpDֵΪ1

  ¢Û1L0.1mol£¯LµÄNaODµÄÖØË®ÈÜÒº£¬pD=12

  ¢ÜÔÚ100mL0 .25rnoL£¯LDClµÄÖØË®ÈÜÒºÖУ¬¼ÓÈë50mL0. 2mo1£®£¯L NaODµÄÖØË®ÈÜÒº£¬·´Ó¦ºóÈÜÒºµÄpD=1

  ¢ÝζÈÉý¸ß£¬CD+¡ÁCOD-µÄÖµ»áÉý¸ß

A£®¢Ú¢Û    B£®¢Û¢Ü    C£®¢Ù¢Ú    D£®¢Ü¢Ý

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸