£¨15·Ö£©
¢ñ£®²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷¡£ÏÂÁÐʵÑé¹ý³ÌÖУ¬Ò»°ã²»ÐèÒªÓò£Á§°ôµÄÊÇ
           £¨Ìîд±àºÅ£©
¢ÙÓÃpHÊÔÖ½²â¶¨Na2CO3ÈÜÒºµÄpH£» ¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº£» ¢Û½«ÊÊÁ¿ÂÈ»¯Ìú±¥ºÍÈÜÒºµÎÈë·ÐË®ÖÐÖƱ¸ÇâÑõ»¯Ìú½ºÌ壻 ¢Ü̽¾¿Ba(OH)28H2O¾§ÌåºÍNH4Cl¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯£» ¢ÝÓÃÕôÁó·¨·ÖÀëÁ½Öַеã²î¾à½Ï´óµÄÒºÌ壻 ¢Þ¹ýÂË·ÖÀ뻥²»ÏàÈܵĹÌÌåºÍÒºÌ壻 ¢ßÓÃÒÑ֪Ũ¶ÈµÄÑÎËáµÎ¶¨´ý²âŨ¶ÈµÄNaOHÈÜÒºµÄËá¼îÖк͵ζ¨¹ý³Ì£» ¢àÏ¡ÊÍŨH2SO4µÄ¹ý³Ì
¢ò£®Îª²â¶¨Ä³º¬ÓÐÔÓÖÊNa2OµÄNa2O2ÑùÆ·µÄ´¿¶È£¬Ä³Ð¡×éͬѧ·Ö±ðÉè¼ÆÁËÈçÏ·½°¸¡£
¡¾·½°¸Ò»¡¿×¼È·³ÆÁ¿ÑùÆ·mg£¬ÓëË®³ä·Ö·´Ó¦ºó½«ÈÜÒºµÄÌå»ýÏ¡ÊÍΪVmL£¬´ÓÖÐÈ¡³öV1mLÈÜÒº£¬×°Èë׶ÐÎÆ¿£¬ÓÃÒÑ֪Ũ¶ÈµÄÑÎËá½øÐе樣¬ÒÔÈ·¶¨ÈÜÒºµÄŨ¶È£¬ÔÙ¼ÆËã³öÑùÆ·ÖÐNa2O2µÄº¬Á¿¡£
£¨1£©´Ë·½°¸ÖУ¬Ëá¼îÖк͵ζ¨Ê±Ó¦Ñ¡ÓÃָʾ¼ÁÊÇ         ¡£
¡¾·½°¸¶þ¡¿×¼È·³ÆÁ¿ÑùÆ·mg£¬½«ÑùÆ·Óë¶þÑõ»¯Ì¼³ä·Ö·´Ó¦£¬Í¨¹ý²â¶¨·´Ó¦²úÉúÑõÆøµÄÌå»ý£¬¼ÆËã³öÑùÆ·ÖÐNa2O2µÄº¬Á¿¡£

£¨2£©¸Ã·½°¸µÄʵÑé¹ý³ÌÖУ¬ÒÇÆ÷µÄÁ¬½Ó˳ÐòÊÇ                 £¨ÌîÒÇÆ÷Ï·½ÐòºÅ£©£¬¢ÙÖеĽøÆø¿ÚΪ    £¨Ìî¡°A¡±»ò¡°B¡±£©
£¨3£©×°ÖâݵÄ×÷ÓÃÊÇ                                                     ¡£
£¨4£©Ôڿɹ©Ñ¡Óõķ´Ó¦ÎïÖ»ÓÐCaCO3¹ÌÌå,6mol/LÑÎËáºÍÕôÁóˮʱ£¬ÇëÉè¼ÆÒ»ÖÖ×î¼òµ¥µÄ²â¶¨Na2O2´¿¶ÈµÄʵÑé·½°¸                                       ¡£

¢ñ¢Û¢Ý¢ß£¨3·Ö£©¢ò¢Å·Ó̪£¨¼×»ù³È£©£¨1·Ö£©
¢Æ¢Ú¢Ü¢Ý¢Ù¢Û£¨3·Ö£©A£¨1·Ö£©
¢Ç³ýÈ¥O2ÖлìÓеÄCO2µÈÆøÌ壨3·Ö£©
¢È½«ÑùÆ·Óë¹ýÁ¿Ë®·´Ó¦£¬²â²úÉúO2µÄÌå»ý¡££¨4·Ö£©

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷£®ÏÂÁÐʵÑé¹ý³ÌÖУ¬Ò»°ã²»ÐèÒªÓò£Á§°ôµÄÊÇ
¢Û¢Ý
¢Û¢Ý
£¨Ìîд±àºÅ£©
¢Ù¾«ÑÎÌá´¿
¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº
¢Û½«ÊÊÁ¿ÂÈ»¯Ìú±¥ºÍÈÜÒºµÎÈë·ÐË®ÖÐÖƱ¸ÇâÑõ»¯Ìú½ºÌå
¢Ü̽¾¿Ba£¨OH£©2?8H2O¾§ÌåºÍNH4Cl¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯
¢ÝʵÑéÊÒÓÃÐÂÖƵÄFeSO4ÈÜÒººÍÔ¤´¦Àí¹ýµÄNaOHÈÜÒºÖƱ¸Fe£¨OH£©2°×É«³Áµí
£¨2£©Ìî¿Õ£º
¢Ù¶ÁÈ¡µÎ¶¨¹ÜÖеÎÌåÌå»ýʱ£¬ÑöÊÓÒºÃ棬¶ÁÈ¡µÄÌå»ýÊý
£¾
£¾
ʵ¼ÊÌå»ýÊý£¨Ìî¡°£¾¡±¡¢¡°=¡±»ò¡°£¼¡±£©
¢ÚÓÃÍÐÅÌÌìƽ³ÆÈ¡10.4gʳÑΣ¬½«íÀÂëºÍʳÑεÄλÖõߵ¹£¬Ëù³ÆȡʳÑεÄÖÊÁ¿Îª
9.6
9.6
g£®
¢ÛʵÑéÐèÓÃ480mL 0.1mol?L-1NaOHÈÜÒº£¬ÅäÖÆÈÜҺʱ³ýÐèÓýºÍ·µÎ¹Ü¡¢ÉÕ±­¡¢ÍÐÅÌÌìƽ£¨´øíÀÂ룩¡¢²£Á§°ô¡¢Ò©³×Í⣬»¹±ØÐèÓõ½µÄÒÇÆ÷ÊÇ
500mLÈÝÁ¿Æ¿
500mLÈÝÁ¿Æ¿
£¨ÌîÃû³Æ£©£¬Ëù³ÆÈ¡NaOH¹ÌÌåµÄÖÊÁ¿Îª
2.0
2.0
g£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨2009?Ϋ·»Ò»Ä££©£¨1£©²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷£®ÏÂÁÐʵÑé¹ý³ÌÖУ¬Ò»°ã²»ÐèÒªÓò£Á§°ôµÄÊÇ
¢Û¢Ý
¢Û¢Ý
£¨Ìîд±àºÅ£©
¢ÙÓÃpHÊÔÖ½²â¶¨Na2CO3ÈÜÒºµÄ pH
¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº
¢Û½«ÊÊÁ¿ÂÈ»¯Ìú±¥ºÍÈÜÒºµÎÈë·ÐË®ÖÐÖƱ¸ÇâÑõ»¯Ìú½ºÌå
¢Ü̽¾¿Ba£¨OH£©2?8H2O ¾§ÌåµÄNH4Cl ¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯
¢ÝʵÑéÊÒÓÃÐÂÖƵÄFeSO4 ÈÜÒººÍÔ¤´¦Àí¹ýµÄNaOH ÈÜÒºÖƱ¸Fe£¨OH£©2 °×É«³Áµí
£¨2£©Óá°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±¡¢»ò¡°µÈÓÚ¡±Ìî¿Õ£º
¢Ù¶ÁÈ¡Á¿Í²ÖÐÒºÌåÌå»ýʱ£¬ÊÓÏßÆ«¸ß£¬¶ÁÈ¡µÄÌå»ýÊý
´óÓÚ
´óÓÚ
ʵ¼ÊÌå»ýÊý
¢ÚÓÃÍÐÅÌÌìƽ³ÆÈ¡10.4gʳÑΣ¬½«íÀÂëºÍʳÑεÄλÖõߵ¹£¬Ëù³ÆȡʳÑεÄÖÊÁ¿
СÓÚ
СÓÚ
10.4g£®
¢ÛÅäÖÆ500mL0.1mol?L-1NaOH ÈÜÒº£¬¶¨ÈÝʱ¸©Êӿ̶ÈÏߣ¬ËùµÃÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È
´óÓÚ
´óÓÚ
0.1mol?L-1
¢ÜÓÃÖк͵樲âijNaOH ÈÜÒºµÄŨ¶È£¬Á¿È¡´ý²âҺʱĩÓøÃÈÜÒºÈóÏ´µÎ¶¨¹Ü£¬²âµÃµÄÈÜҺŨ¶È
СÓÚ
СÓÚ
ʵ¼ÊŨ¶È£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨1£©»¯Ñ§ÊÇÒ»ÃÅÒÔʵÑéΪ»ù´¡µÄѧ¿Æ£¬»¯Ñ§ÊµÑéÊÇ»¯Ñ§Ñ§Ï°µÄÖØÒªÄÚÈÝ£®¸ù¾ÝÄãÕÆÎÕµÄ֪ʶÅжϣ¬ÏÂÁÐʵÑé²Ù×÷µÄÃèÊöÖУ¬ÕýÈ·µÄÊÇ
 
£¨ÌîдÏÂÁи÷ÏîÐòºÅ£©£®
A£®´ÓÊÔ¼ÁÆ¿ÖÐÈ¡³öµÄÈκÎÒ©Æ·£¬ÈôÓÐÊ£Ó಻ÄÜÔÙ·Å»ØÔ­ÊÔ¼ÁÆ¿
B£®ÓÃÏ¡ÑÎËáÏ´µÓÊ¢·Å¹ýʯ»ÒË®µÄÊÔ¼ÁÆ¿
C£®ÅäÖÆH2SO4ÈÜҺʱ£¬¿ÉÏÈÔÚÁ¿Í²ÖмÓÈëÒ»¶¨Ìå»ýµÄË®£¬ÔÙÔÚ½Á°èÏÂÂýÂý¼ÓÈëŨÁòËá
D£®¸÷·ÅÒ»ÕÅÖÊÁ¿ÏàͬµÄÂËÖ½ÓÚÌìƽµÄÁ½ÍÐÅÌÉÏ£¬½«NaOH¹ÌÌå·ÅÔÚ×óÅÌÖ½ÉϳÆÁ¿
E£®Na2CO3ÈÜÒº²»Äܱ£´æÔÚ´øÓв£Á§ÈûµÄÊÔ¼ÁÆ¿ÖÐ
F£®½«ÓÃË®ÈóʪµÄpHÊÔÖ½½þÈëÏ¡ÑÎËáÖУ¬²â¶¨ÈÜÒºµÄpH
£¨2£©»¯Ñ§ÊµÑéÖУ¬²»ÕýÈ·µÄ²Ù×÷»á¶ÔʵÑé½á¹ûµÄ׼ȷÐÔÔì³ÉÒ»¶¨µÄÓ°Ï죬ÇëÓá°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±ÌîдÏÂÁпհףº
¢ÙʵÑéʱδÓñê×¼ÈÜÒºÈóÏ´µÎ¶¨¹Ü£¬Ôò²âµÃ׶ÐÎÆ¿Öдý²âÒºµÄŨ¶È
 
ʵ¼ÊŨ¶È£®
¢ÚÓÃÍÐÅÌÌìƽ³ÆÈ¡10.4gÂÈ»¯ÄÆ£¬Èô½«íÀÂëºÍÂÈ»¯ÄƵÄλÖ÷ŵߵ¹ÁË£¬Ëù³ÆÈ¡ÂÈ»¯ÄƵÄÖÊÁ¿
 
10.4g£®
¢ÛÓÃÈÝÁ¿Æ¿ÅäÖÆ500mL 0.1mol?L-1 NaOHÈÜÒº£¬¶¨ÈÝʱÑöÊӿ̶ÈÏߣ¬ËùµÃÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È
 
0.1mol?L-1£®
£¨3£©²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷£®ÏÂÁйý³ÌÖУ¬Ò»°ã²»ÐèÒª²£Á§°ôµÄÊÇ
 
£¨Ìîд±àºÅ£©£®
¢ÙÓÃpHÊÔÖ½²â¶¨Na2CO3ÈÜÒºµÄpH
¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº
¢Û½«ÊÊÁ¿ÂÈ»¯Ìú±¥ºÍÈÜÒºµÎÈë·ÐË®ÖÐÖƱ¸ÇâÑõ»¯Ìú½ºÌå
¢Ü̽¾¿Ba£¨OH£©2?8H2O¾§ÌåºÍNH4Cl¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯
¢ÝʵÑéÊÒÓÃÐÂÖƱ¸µÄFeSO4ÈÜÒººÍÔ¤´¦Àí¹ýµÄNaOHÈÜÒºÖƱ¸Fe£¨OH£©2°×É«³Áµí£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¢ñ£®²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÊÒÖг£ÓõÄÒÇÆ÷£®ÏÂÁÐʵÑé¹ý³ÌÖУ¬Ò»°ã²»ÐèÒªÓò£Á§°ôµÄÊÇ
 
£¨Ìîд±àºÅ£©
¢ÙÓÃpHÊÔÖ½²â¶¨Na2CO3ÈÜÒºµÄpH 
¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº 
¢Û½«ÊÊÁ¿ÂÈ»¯Ìú±¥ºÍÈÜÒºµÎÈë·ÐË®ÖÐÖƱ¸ÇâÑõ»¯Ìú½ºÌå 
¢Ü̽¾¿Ba£¨OH£©28H20¾§ÌåºÍNH4Cl¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯ 
¢ÝÓÃÕôÁó·¨·ÖÀëÁ½Öַеã²î¾à½Ï´óµÄÒºÌå 
¢Þ¹ýÂË·ÖÀ뻥²»ÏàÈܵĹÌÌåºÍÒºÌå 
¢ßÓÃÒÑ֪Ũ¶ÈµÄÑÎËáµÎ¶¨´ý²âŨ¶ÈµÄNaOHÈÜÒºµÄËá¼îÖк͵ζ¨¹ý³Ì 
¢àÏ¡ÊÍŨH2SO4µÄ¹ý³Ì
¢ò£®Îª²â¶¨Ä³º¬ÓÐÔÓÖÊNa2OµÄNa2O2ÑùÆ·µÄ´¿¶È£¬Ä³Ð¡×éͬѧ·Ö±ðÉè¼ÆÁËÈçÏ·½°¸£®
[·½°¸Ò»]׼ȷ³ÆÁ¿ÑùÆ·mg£¬ÓëË®³ä·Ö·´Ó¦ºó½«ÈÜÒºµÄÌå»ýÏ¡ÊÍΪVmL£¬´ÓÖÐÈ¡³öV1mLÈÜÒº£¬×°Èë׶ÐÎÆ¿£¬ÓÃÒÑ֪Ũ¶ÈµÄÑÎËá½øÐе樣¬ÒÔÈ·¶¨ÈÜÒºµÄŨ¶È£¬ÔÙ¼ÆËã³öÑùÆ·ÖÐNa2O2µÄº¬Á¿£®
£¨1£©´Ë·½°¸ÖУ¬Ëá¼îÖк͵ζ¨Ê±Ó¦Ñ¡ÓÃ
 
µÎ¶¨¹Ü£®
£¨2£©Ð´³ö´Ë·½°¸ÖÐÉæ¼°µ½µÄ·´Ó¦µÄÀë×Ó·½³Ìʽ
 
£®
[·½°¸¶þ]׼ȷ³ÆÁ¿ÑùÆ·mg£¬½«ÑùÆ·Óë¶þÑõ»¯Ì¼³ä·Ö·´Ó¦£¬Í¨¹ý²â¶¨·´Ó¦²úÉúÑõÆøµÄÌå»ý£¬¼ÆËã³öÑùÆ·ÖÐNa2O2µÄº¬Á¿£®
¾«Ó¢¼Ò½ÌÍø
£¨3£©¸Ã·½°¸µÄʵÑé¹ý³ÌÖУ¬Èçͼ£¬ÒÇÆ÷µÄÁ¬½Ó˳ÐòÊÇ
 
£¨ÌîÒÇÆ÷Ï·½ÐòºÅ£©£¬¢ÙÖеĽøÆø¿ÚΪ
 
£¨Ìî¡°A¡±»ò¡°B¡±£©
£¨4£©×°ÖâݵÄ×÷ÓÃÊÇ
 
£®
£¨5£©ÄãÈÏΪ·½°¸Ò»¡¢·½°¸¶þÖвⶨ½á¹û±È½Ï׼ȷµÄÊÇ
 
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

²£Á§°ôÊÇÖÐѧ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷£®ÏÂÁÐʵÑé¹ý³ÌÖУ¬Ò»°ã²»ÐèÒªÓò£Á§°ôµÄÊÇ
 
£¨Ìîд±àºÅ£©
¢ÙÓÃpHÊÔÖ½²â¶¨Na2CO3ÈÜÒºµÄpH£»
¢ÚÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÂÈ»¯ÄÆÈÜÒº£»
¢Û̽¾¿Ba£¨OH£©2?8H2O¾§ÌåºÍNH4Cl¾§Ìå·´Ó¦¹ý³ÌÖеÄÄÜÁ¿±ä»¯£»
¢ÜÓÃÕôÁó·¨·ÖÀëÁ½Öַеã²î¾à½Ï´óµÄÒºÌ壻
¢Ý¹ýÂË·ÖÀ뻥²»ÏàÈܵĹÌÌåºÍÒºÌ壻
¢ÞÓÃÒÑ֪Ũ¶ÈµÄÑÎËáµÎ´ý²âŨ¶ÈµÄNaOHÈÜÒºµÄËá¼îÖк͵ζ¨¹ý³Ì£»
¢ßÏ¡ÊÍŨH2SO4µÄ¹ý³Ì£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸