¢ñ.ÈçͼËùʾ£¬ÔÚ´óÊÔ¹ÜÀï·ÅÈëÒ»¶Î¹âÁÁÎÞÐâµÄÍä³ÉÂÝÐý×´µÄÌúË¿£¬°ÑÊԹܵ¹²åÈëË®ÖУ¬°ÑÕâ¸ö×°ÖÃÕâÑù·ÅÖÃÔ¼Ò»Öܺ󣬹۲쵽ÌúË¿·¢ÉúµÄ±ä»¯ÊÇ______________________£¬Ô­ÒòÊÇ____________________£®ÊÔ¹ÜÀïµÄË®Ãæ»áÉÏÉý£¬×îÖÕÉÏÉý¸ß¶ÈԼΪ_______£¬Ô­ÒòÊÇ_________________________________________________________________________________________________________________.
¢ò.A¡¢B¡¢CÈý¸öÉÕ±­ÖзֱðÊ¢ÓÐÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄÏ¡ÁòËᣮ

(1)AÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________________£®
(2)BÖÐSnµç¼«µÄµç¼«·´Ó¦Ê½Îª________________________________________£¬Snµç¼«¸½½üÈÜÒºµÄpH__________(Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±»ò¡°²»±ä¡±)£®
(3)CÖб»¸¯Ê´µÄ½ðÊôÊÇ________£¬×Ü·´Ó¦Ê½Îª________________________£®±È½ÏA¡¢B¡¢CÖÐÌú±»¸¯Ê´µÄËÙÂÊ£¬ÓÉ¿ìµ½ÂýµÄ˳ÐòÊÇ______________________£®

¢ñ.ÌúË¿±íÃæÉú³ÉÒ»²ãºì×ØÉ«µÄÌúÐâ¡¡Ìú·¢ÉúÎüÑõ¸¯Ê´¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊýԼΪ1/5£¬¾­¹ý×ã¹»³¤µÄʱ¼äºó£¬ÑõÆøÓëÌú·´Ó¦Íê
¢ò.(1)Fe£«2H£«===Fe2£«£«H2¡ü
(2)2H£«£«2e£­===H2¡ü¡¡Ôö´ó
(3)Zn¡¡Zn£«2H£«===Zn2£«£«H2¡ü¡¡B£¾A£¾C

½âÎöÊÔÌâ·ÖÎö£º¸Ã×°ÖÃÖÐÌúË¿·¢ÉúÎüÑõ¸¯Ê´Éú³ÉÌúÐâ(Fe2O3¡¤nH2O)£¬¾­¹ý×ã¹»³¤µÄʱ¼äºó£¬ÊÔ¹ÜÄÚ¿ÕÆøÖеÄÑõÆøÍêÈ«±»ÎüÊÕ£¬µ¼ÖÂѹǿ¼õС£¬ÒºÃæÉÏÉý£¬ÉÏÉý¸ß¶ÈÓë¿ÕÆøÖÐËùº¬ÑõÆøµÄÌå»ý·ÖÊýÏàͬ£¬Ô¼Õ¼.
(¢ò)AÖÐFeʧµç×Ó£¬ÇâÀë×ӵõ½µç×Ó±»»¹Ô­ÎªÇâÆø£»BÖÐÐγÉÔ­µç³Ø£¬SnΪÕý¼«£¬Îªµç×ÓÁ÷ÈëµÄÒ»¼«£¬ÇâÀë×ӵõç×Ó±»»¹Ô­²úÉúÇâÆø£¬ÓÉÓÚÏûºÄÁËÈÜÒºÖеÄÇâÀë×Ó£¬ËùÒÔpHÔö´ó£»CÖÐп×÷¸º¼«±»Ñõ»¯£¬Zn£­2e£­===Zn2£«£¬Õý¼«£º2H£«£«2e£­===H2¡ü£¬×Ü·´Ó¦ÎªZn£«2H£«===Zn2£«£«H2¡ü£¬CÖÐFe±»±£»¤£¬BÖÐÄܼӿ츯ʴ£®
¿¼µã£ºÔ­µç³Ø¼°µç½â³Ø
µãÆÀ£º±¾Ì⿼²éÌúµÄ¸¯Ê´Ïà¹ØµÄµç»¯Ñ§ÖªÊ¶£¬ÄѶȲ»´ó£¬²àÖØ¿¼²éѧÉúʵÑé¹Û²ìÄÜÁ¦¼°·ÖÎöÎÊÌâÄÜÁ¦£¬½âÌâµÄ¹Ø¼üÊÇÒª¶Á¶®Í¼£¬Á˽âÎÊÌâµÄʵÖÊ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÎïÖÊA¡«FÊÇÎÒÃÇÊìϤµÄµ¥ÖÊ»ò»¯ºÏÎÆäÖÐA¡¢B¾ùÊdz£¼ûµÄ½ðÊô£¬ÇÒBµÄºÏ½ðÓÃÁ¿×î´ó£»EÔÚ³£ÎÂÏÂÊÇ»ÆÂÌÉ«ÆøÌ壻ÔÚÊʵ±µÄÌõ¼þÏ£¬ËüÃÇÖ®¼ä¿ÉÒÔ·¢ÉúÈçͼËùʾµÄת»¯£®

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©AÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ
µÚÈýÖÜÆÚ£¬µÚ¢óA×å
µÚÈýÖÜÆÚ£¬µÚ¢óA×å
£»
£¨2£©¼ìÑéFÖнðÊôÑôÀë×ӵij£Ó÷½·¨ÊÇ
È¡ÈÜÓÚÉÙÐíÓÚÊÔ¹ÜÖУ¬¼ÓÈëKSCNÈÜÒº£¬ÈÜÒº±äΪѪºìÉ«ÈÜÒº£¬Ö¤Ã÷ÊÇÈý¼ÛÌúÀë×Ó
È¡ÈÜÓÚÉÙÐíÓÚÊÔ¹ÜÖУ¬¼ÓÈëKSCNÈÜÒº£¬ÈÜÒº±äΪѪºìÉ«ÈÜÒº£¬Ö¤Ã÷ÊÇÈý¼ÛÌúÀë×Ó
£»
£¨3£©°×É«³ÁµíÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
Al£¨OH£©3+OH-=AlO2-+2H2O
Al£¨OH£©3+OH-=AlO2-+2H2O
£»
£¨4£©·´Ó¦F¡úDµÄ»¯Ñ§·½³ÌʽÊÇ
2FeCl3+Fe=3FeCl2
2FeCl3+Fe=3FeCl2
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÏÂÁÐÎïÖÊA¡«FÊÇÎÒÃÇÊìϤµÄµ¥ÖÊ»ò»¯ºÏÎÆäÖÐA¡¢B¾ùÊdz£¼ûµÄ½ðÊô£¬ÇÒBµÄºÏ½ðÓÃÁ¿×î´ó£»EÔÚ³£ÎÂÏÂÊÇ»ÆÂÌÉ«ÆøÌ壻ÔÚÊʵ±µÄÌõ¼þÏ£¬ËüÃÇÖ®¼ä¿ÉÒÔ·¢ÉúÈçͼËùʾµÄת»¯£®

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©°×É«³ÁµíÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
Al£¨OH£©3+OH-¨TAlO2-+2H2O
Al£¨OH£©3+OH-¨TAlO2-+2H2O
£»
£¨2£©·´Ó¦F¡úDµÄ»¯Ñ§·½³ÌʽÊÇ
2FeCl3+Fe¨T3FeCl2
2FeCl3+Fe¨T3FeCl2
£»
£¨3£©¼ìÑéFÖнðÊôÑôÀë×ӵij£Ó÷½·¨ÊÇ
¼ÓÈëKSCNÈÜÒº£¬ÈÜÒº³ÊѪºìÉ«Ôòº¬Fe3+
¼ÓÈëKSCNÈÜÒº£¬ÈÜÒº³ÊѪºìÉ«Ôòº¬Fe3+
£»
£¨4£©EÓëʯ»ÒÈé·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
2Cl2+Ca£¨OH£©2=CaCl2+Ca£¨ClO£©2+H2O
2Cl2+Ca£¨OH£©2=CaCl2+Ca£¨ClO£©2+H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

ÏÂÁÐÎïÖÊA¡«FÊÇÎÒÃÇÊìϤµÄµ¥ÖÊ»ò»¯ºÏÎÆäÖÐA¡¢B¾ùÊdz£¼ûµÄ½ðÊô£¬ÇÒBµÄºÏ½ðÓÃÁ¿×î´ó£»EÔÚ³£ÎÂÏÂÊÇ»ÆÂÌÉ«ÆøÌ壻ÔÚÊʵ±µÄÌõ¼þÏ£¬ËüÃÇÖ®¼ä¿ÉÒÔ·¢ÉúÈçͼËùʾµÄת»¯£®

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©°×É«³ÁµíÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______£»
£¨2£©·´Ó¦F¡úDµÄ»¯Ñ§·½³ÌʽÊÇ______£»
£¨3£©¼ìÑéFÖнðÊôÑôÀë×ӵij£Ó÷½·¨ÊÇ______£»
£¨4£©EÓëʯ»ÒÈé·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêÌì½òÊкÍƽÇø¸ßÒ»£¨ÉÏ£©ÆÚÄ©»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

ÏÂÁÐÎïÖÊA¡«FÊÇÎÒÃÇÊìϤµÄµ¥ÖÊ»ò»¯ºÏÎÆäÖÐA¡¢B¾ùÊdz£¼ûµÄ½ðÊô£¬ÇÒBµÄºÏ½ðÓÃÁ¿×î´ó£»EÔÚ³£ÎÂÏÂÊÇ»ÆÂÌÉ«ÆøÌ壻ÔÚÊʵ±µÄÌõ¼þÏ£¬ËüÃÇÖ®¼ä¿ÉÒÔ·¢ÉúÈçͼËùʾµÄת»¯£®

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©°×É«³ÁµíÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______£»
£¨2£©·´Ó¦F¡úDµÄ»¯Ñ§·½³ÌʽÊÇ______£»
£¨3£©¼ìÑéFÖнðÊôÑôÀë×ӵij£Ó÷½·¨ÊÇ______£»
£¨4£©EÓëʯ»ÒÈé·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄê½­Î÷Ê¡¼ª°²ÊмªÖÝÇø°×ðØÖÞÖÐѧ¸ß¶þ£¨ÉÏ£©ÆÚÖл¯Ñ§ÊÔ¾í£¨ÎÄ¿Æ£©£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

ÏÂÁÐÎïÖÊA¡«FÊÇÎÒÃÇÊìϤµÄµ¥ÖÊ»ò»¯ºÏÎÆäÖÐA¡¢B¾ùÊdz£¼ûµÄ½ðÊô£¬ÇÒBµÄºÏ½ðÓÃÁ¿×î´ó£»EÔÚ³£ÎÂÏÂÊÇ»ÆÂÌÉ«ÆøÌ壻ÔÚÊʵ±µÄÌõ¼þÏ£¬ËüÃÇÖ®¼ä¿ÉÒÔ·¢ÉúÈçͼËùʾµÄת»¯£®

ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©AÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ______£»
£¨2£©¼ìÑéFÖнðÊôÑôÀë×ӵij£Ó÷½·¨ÊÇ______£»
£¨3£©°×É«³ÁµíÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ______£»
£¨4£©·´Ó¦F¡úDµÄ»¯Ñ§·½³ÌʽÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸