ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬NH4£«¡¢K£«¡¢Na£«¡¢Mg2£«¡¢Ba2£«¡¢Al3£«¡¢Fe3£«¡¢SO42£­¡¢CO32£­¡¢NO3£­¡¢Cl£­¡¢I£­£¬È¡¸ÃÈÜÒº½øÐÐÈçÏÂʵÑ飺

¢ÅÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ£»

¢ÆÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÉÙÁ¿CCl4¼°ÊýµÎÐÂÖƵÄÂÈË®£¬¾­Õñµ´ºó¾²ÖÃCCl4²ã³Ê×ϺìÉ«£»

¢ÇÈ¡²¿·ÖÈÜÒº£¬ÖðµÎ¼ÓÈëÏ¡NaOHÈÜÒº£¬Ê¹ÈÜÒº´ÓËáÐÔÖð½¥×ª±äΪ¼îÐÔ£¬Ôڵμӹý³ÌÖм°µÎ¼ÓÍê±Ïºó£¬ÈÜÒºÖоùÎÞ³ÁµíÉú³É£»

¢ÈÈ¡²¿·ÖÉÏÊö³Ê¼îÐÔµÄÈÜÒº£¬¼ÓNa2CO3ÈÜÒº£¬Óа×É«³ÁµíÉú³É£»

¢É½«¢ÇµÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶¡£

¸ù¾ÝÉÏÊöʵÑéÊÂʵȷ¶¨²¢»Ø´ð£º

ÔÚÈÜÒºÖп϶¨´æÔÚµÄÉÏÊöÀë×ÓÓС¡¡¡¡¡£¬¿Ï¶¨²»´æÔÚµÄÉÏÊöÀë×ÓÓС¡¡¡¡£

I£­¡¢NH4£«¡¢Ba2£«£»SO42£­¡¢CO32£­¡¢NO3£­¡¢Mg2£«¡¢Al3£«¡¢Fe3£«

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

ʵÑé̽¾¿ºÍÍÆÀí¶¼ÊÇ¿ÆѧÑо¿µÄ»ù±¾·½·¨£¬ÇëÄã¶ÔÒÔÏÂʵÑé½øÐÐ̽¾¿ºÍÍÆÀí
¢ñ¡¢ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐH+¡¢NH4+¡¢K+¡¢Na+¡¢Mg2+¡¢Ba2+¡¢Fe3+¡¢SO42-¡¢CO32-¡¢Cl-ºÍI-£®È¡¸ÃÈÜÒº½øÐÐÁËÒÔÏÂʵÑ飺
£¨1£©ÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ£»
£¨2£©È¡²¿·ÖÈÜÒº£¬¼ÓÈëCCl4¼°ÊýµÎÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«£»
£¨3£©ÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÏ¡NaOH ÈÜҺʹÆä±äΪ¼îÐÔ£¬ÈÜÒºÖÐÎÞ³ÁµíÉú³É£»
£¨4£©È¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº£¬¼ÓNa2CO3ÈÜÒºÓа×É«³ÁµíÉú³É£»
£¨5£©½«£¨3£©µÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶£»¸ù¾ÝÉÏÊöʵÑéÊÂʵ£¬Äã¿ÉÖªµÀ¸ÃÈÜÒºÖп϶¨º¬ÓеÄÀë×ÓÊÇ¢Ù
H+¡¢NH4+¡¢Ba2+¡¢I-
H+¡¢NH4+¡¢Ba2+¡¢I-
£»¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇ¢Ú
Mg2+¡¢Fe3+¡¢SO32-¡¢CO32-
Mg2+¡¢Fe3+¡¢SO32-¡¢CO32-
£»»¹²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ¢Û
K+¡¢Na+¡¢Cl-
K+¡¢Na+¡¢Cl-
£®
¢ò¡¢ÐËȤС×éͨ¹ýʵÑé̽¾¿ÈܽâÍ­µÄ·½·¨ºÍ±¾ÖÊ£®
£¨1£©ÔÚÈÈˮԡÖнøÐÐ3¸öʵÑ飬²¿·ÖʵÑ鱨¸æÈçϱíËùʾ£®
ÐòºÅ ʵÑé²Ù×÷ ʵÑéÏÖÏó I Ï¡ÁòËáÖмÓÈëͭƬ ÎÞÃ÷ÏԱ仯 II ÏõËáÄÆÈÜÒºÖмÓÈëͭƬ ÎÞÃ÷ÏԱ仯 III Ï¡ÁòËáÖмÓÈëÏõËáÄÆÈÜÒº ÎÞÃ÷ÏԱ仯 ÔÙ¼ÓÈëͭƬ ÓÐÎÞÉ«ÆøÅÝ£»ÈÜÒº±äÀ¶
¢ÙʵÑéI¡¢IIµÄÄ¿µÄÊÇ
Ö¤Ã÷Cu²»ÓëH+¡¢NO3-µ¥¶À·´Ó¦
Ö¤Ã÷Cu²»ÓëH+¡¢NO3-µ¥¶À·´Ó¦
£®
¢ÚʵÑéIIIÖз´Ó¦µÄ±¾ÖÊÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐNH4+¡¢K+£¬Na+¡¢Mg2+¡¢Ba2+¡¢Fe3+¡¢SO42-¡¢CO32-¡¢Cl-ºÍI-£®È¡¸ÃÈÜÒº½øÐÐÒÔÏÂʵÑ飺
¢ÙÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜҺΪǿËáÐÔ£»
¢ÚÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÏ¡NaOHÈÜҺʹÆä±ä³É¼îÐÔ£¬ÈÜÒºÖÐÎÞ³ÁµíÉú³É£»
¢ÛÈ¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº£¬¼ÓÈëNa2CO3ÈÜÒºÓа×É«³ÁµíÉú³É£»
¢Ü½«¢ÚµÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶£»
¢ÝÁíÈ¡²¿·ÖÔ­ÈÜÒº£¬¼ÓÈëCCl4¼°ÊýµÎÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«£®
¸ù¾ÝÉÏÊöʵÑéÊÂʵ»Ø´ð£º
£¨1£©¸ÃÈÜÒºÖп϶¨º¬ÓеÄÀë×ÓÊÇ
NH4+¡¢Ba2+¡¢I-
NH4+¡¢Ba2+¡¢I-

£¨2£©¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇ
Mg2+¡¢Fe3+¡¢SO42-¡¢CO32-
Mg2+¡¢Fe3+¡¢SO42-¡¢CO32-
£®
£¨3£©²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ
K+¡¢Na+¡¢Cl-
K+¡¢Na+¡¢Cl-
ÈôҪȷ¶¨ÆäÖеÄÑôÀë×ӿɲÉÓõķ½·¨Îª
ÑæÉ«·´Ó¦
ÑæÉ«·´Ó¦
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐNH4+¡¢Na+¡¢Mg2+¡¢Al3+¡¢Fe3+¡¢SO42-¡¢CO32-¡¢Cl-ºÍI-£®È¡¸ÃÈÜÒº½øÐÐÁËÒÔÏÂʵÑ飺
£¨1£©ÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊËáÐÔ£»
£¨2£©È¡²¿·ÖÈÜÒº£¬¼ÓÈëCCl4¼°ÊýµÎÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«£»
£¨3£©ÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÏ¡NaOH ÈÜҺʹÆä±äΪ¼îÐÔ£¬ÈÜÒºÖÐÎÞ³ÁµíÉú³É£»
£¨4£©È¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº£¬Í¨Èë¹ýÁ¿CO2ÆøÌåÓа×É«³ÁµíÉú³É£»
£¨5£©½«£¨3£©µÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶£»
¸ù¾ÝÉÏÊöʵÑéÊÂʵ£¬ÏÂÁÐÅжϴíÎóµÄÊÇ£¨¡¡¡¡£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÄþÏÄÒø´¨Ò»ÖиßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

ʵÑé̽¾¿ºÍÍÆÀí¶¼ÊÇ¿ÆѧÑо¿µÄ»ù±¾·½·¨,ÇëÄã¶ÔÒÔÏÂʵÑé½øÐÐ̽¾¿ºÍÍÆÀí
¢ñ¡¢ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐH+¡¢NH4£«¡¢K£«¡¢Na£«¡¢Mg2£«¡¢Ba2£«¡¢Fe3£«¡¢SO42¨D¡¢CO32¨D¡¢Cl¨DºÍI¨D¡£È¡¸ÃÈÜÒº½øÐÐÁËÒÔÏÂʵÑ飺
£¨1£©ÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ£»
£¨2£©È¡²¿·ÖÈÜÒº£¬¼ÓÈëCCl4¼°ÊýµÎÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«£»
£¨3£©ÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÏ¡NaOH ÈÜҺʹÆä±äΪ¼îÐÔ£¬ÈÜÒºÖÐÎÞ³ÁµíÉú³É£»
£¨4£©È¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº£¬¼ÓNa2CO3ÈÜÒºÓа×É«³ÁµíÉú³É£»
£¨5£©½«£¨3£©µÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶£»
¸ù¾ÝÉÏÊöʵÑéÊÂʵ£¬Äã¿ÉÖªµÀ¸ÃÈÜÒºÖп϶¨º¬ÓеÄÀë×ÓÊÇ¢Ù              £»¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇ¢Ú                       £»»¹²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ¢Û                  ¡£
¢ò¡¢ÐËȤС×éͨ¹ýʵÑé̽¾¿ÈܽâÍ­µÄ·½·¨ºÍ±¾ÖÊ¡£
£¨1£©ÔÚÈÈˮԡÖнøÐÐ3¸öʵÑ飬²¿·ÖʵÑ鱨¸æÈçϱíËùʾ¡£

ÐòºÅ
ʵÑé²Ù×÷
ʵÑéÏÖÏó
I
Ï¡ÁòËáÖмÓÈëͭƬ
ÎÞÃ÷ÏԱ仯
II
ÏõËáÄÆÈÜÒºÖмÓÈëͭƬ
ÎÞÃ÷ÏԱ仯
III
Ï¡ÁòËáÖмÓÈëÏõËáÄÆÈÜÒº
ÎÞÃ÷ÏԱ仯
ÔÙ¼ÓÈëͭƬ
ÓÐÎÞÉ«ÆøÅÝ£»ÈÜÒº±äÀ¶
 
¢Ù ʵÑéI¡¢IIµÄÄ¿µÄÊÇ           ¡£
¢Ú ʵÑéIIIÖз´Ó¦µÄ±¾ÖÊÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©           ¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ìÕã½­ÀÖÇåµÚ¶þÖÐѧ¸ßÒ»µÚ¶þ´Î£¨12Ô£©Ô¿¼»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ

£¨6·Ö£©ÓÐһƿ³ÎÇåµÄÈÜÒº£¬ÆäÖпÉÄܺ¬ÓÐNH4£«¡¢K£«¡¢Na£«¡¢Mg2£«¡¢Al3£«¡¢Fe3£«¡¢SO42¨D¡¢CO32¨D¡¢Cl¨DºÍI¨D¡£ÄãÈ¡¸ÃÈÜÒº½øÐÐÁËÒÔÏÂʵÑ飺

£¨1£©ÓÃpHÊÔÖ½¼ìÑ飬±íÃ÷ÈÜÒº³ÊÇ¿ËáÐÔ£»

£¨2£©È¡²¿·ÖÈÜÒº£¬¼ÓÈëCCl4¼°ÊýµÎÂÈË®£¬¾­Õñµ´ºóCCl4²ã³Ê×ϺìÉ«£»

£¨3£©ÁíÈ¡²¿·ÖÈÜÒº£¬¼ÓÈëÏ¡NaOH ÈÜҺʹÆä±äΪ¼îÐÔ£¬ÈÜÒºÖÐÎÞ³ÁµíÉú³É£»

£¨4£©È¡²¿·ÖÉÏÊö¼îÐÔÈÜÒº£¬Í¨Èë¹ýÁ¿CO2ÆøÌåÓа×É«³ÁµíÉú³É£»

£¨5£©½«£¨3£©µÃµ½µÄ¼îÐÔÈÜÒº¼ÓÈÈ£¬ÓÐÆøÌå·Å³ö£¬¸ÃÆøÌåÄÜʹÈóʪµÄºìɫʯÈïÊÔÖ½±äÀ¶£»

¸ù¾ÝÉÏÊöʵÑéÊÂʵ£¬Äã¿ÉÖªµÀ¸ÃÈÜÒºÖУº

¢Ù ¿Ï¶¨º¬ÓеÄÀë×ÓÊÇ         £»

¢Ú ¿Ï¶¨²»´æÔÚµÄÀë×ÓÊÇ                     £»

¢Û »¹²»ÄÜÈ·¶¨ÊÇ·ñ´æÔÚµÄÀë×ÓÊÇ               ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸