( 15 ·Ö£©
ʵÑéÊÒ³£ÓÃMnO2ÓëŨÑÎËá·´Ó¦ÖƱ¸Cl2£¨·¢Éú×°ÖÃÈçͼËùʾ£©¡£
(1)ÖƱ¸ÊµÑ鿪ʼʱ£¬Ïȼì²é×°ÖÃÆøÃÜÐÔ£¬½ÓÏÂÀ´µÄ²Ù×÷ÒÀ´ÎÊǣߣ¨ÌîÐòºÅ£©
A.ÍùÉÕÆ¿ÖмÓÈËMnO2·ÛÄ©
B.¼ÓÈÈ
C.ÍùÉÕÆ¿ÖмÓÈËŨÑÎËá
(2)ÖƱ¸·´Ó¦»áÒòÑÎËáŨ¶ÈϽµ¶øÍ£Ö¹¡£Îª²â¶¨·´Ó¦²ÐÓàÒºÖÐÑÎËáµÄŨ¶È£¬Ì½¾¿Ð¡×éͬѧÌá³öÏÂÁÐʵÑé·½°¸£º
¼×·½°¸£ºÓë×ãÁ¿AgNO3ÈÜÒº·´Ó¦£¬³ÆÁ¿Éú³ÉµÄAgClÖÊÁ¿¡£
ÒÒ·½°¸£º²ÉÓÃËá¼îÖк͵ζ¨·¨²â¶¨¡£
±û·½°¸£ºÓëÒÑÖªÁ¿CaCO3£¨¹ýÁ¿£©·´Ó¦£¬³ÆÁ¿Ê£ÓàµÄCaCO3ÖÊÁ¿¡£
¶¡·½°¸£ºÓë×ãÁ¿Zn ·´Ó¦£¬²âÁ¿Éú³ÉµÄH2Ìå»ý¡£
¼Ì¶ø½øÐÐÏÂÁÐÅжϺÍʵÑ飺
¢Ù Åж¨¼×·½°¸²»¿ÉÐУ¬ÀíÓÉÊÇ ¡£
¢Ú ½øÐÐÒÒ·½°¸ÊµÑ飺׼ȷÁ¿È¡²ÐÓàÇåҺϡÊÍÒ»¶¨±¶Êýºó×÷ΪÊÔÑù¡£
a.Á¿È¡ÊÔÑù20.00 mL£¬ÓÃ0 . 1000 mol¡¤L-1 NaOH±ê×¼ÈÜÒºµÎ¶¨£¬ÏûºÄ22.00mL£¬¸Ã´ÎµÎ¶¨²âµÃÊÔÑùÖÐÑÎËáŨ¶ÈΪ mol¡¤L-1
b.ƽÐеζ¨ºó»ñµÃʵÑé½á¹û¡£
¢Û Åжϱû·½°¸µÄʵÑé½á¹û £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°×¼È·¡±£©¡£
£ÛÒÑÖª£ºKsp£¨CaCO3 ) = 2.8¡Á10-9¡¢Ksp£¨MnCO3 ) = 2.3¡Á10-11
¢Ü ½øÐж¡·½°¸ÊµÑ飺װÖÃÈçͼËùʾ£¨¼Ð³ÖÆ÷¾ßÒÑÂÔÈ¥£©¡£
(i) ʹYÐιÜÖеIJÐÓàÇåÒºÓëпÁ£·´Ó¦µÄÕýÈ·²Ù×÷Êǽ« תÒƵ½ ÖС£
(ii)·´Ó¦Íê±Ï£¬Ã¿¼ä¸ô1 ·ÖÖÓ¶ÁÈ¡ÆøÌåÌå»ý£¬ÆøÌåÌå»ýÖð´Î¼õС£¬Ö±ÖÁ²»±ä¡£ÆøÌåÌå»ýÖð´Î¼õСµÄÔÒòÊǣߣ¨ÅųýÒÇÆ÷ºÍʵÑé²Ù×÷µÄÓ°ÏìÒòËØ£©¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
£¨ 15·Ö£©ÊµÑéÊÒÓÃNaOH¹ÌÌåÅäÖÆ250mL 1.25mol/LµÄNaOHÈÜÒº£¬Ìî¿Õ²¢Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ250mL1.25mol/LµÄNaOHÈÜÒº£¬Ó¦³ÆÈ¡NaOHµÄÖÊÁ¿_____________g
£¨2£©ÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£© £»
A¡¢ÓÃ30mLˮϴµÓÉÕ±2¡ª3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B¡¢ÓÃÌìƽ׼ȷ³ÆÈ¡ËùÐèµÄNaOHµÄÖÊÁ¿£¬¼ÓÈëÉÙÁ¿Ë®£¨Ô¼30mL£©£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä³ä·ÖÈܽâ
C¡¢½«ÒÑÀäÈ´µÄNaOHÈÜÒºÑز£Á§°ô×¢Èë250mLµÄÈÝÁ¿Æ¿ÖÐ
D¡¢½«ÈÝÁ¿Æ¿¸Ç½ô£¬µßµ¹Ò¡ÔÈ
E¡¢¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ
F¡¢¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1¡ª2cm´¦
£¨3£©ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ðè»Ö¸´µ½ÊÒΣ¬ÕâÊÇÒòΪ_____________________________£»
£¨4£©ÏÂÁÐÅäÖƵÄÈÜҺŨ¶ÈÆ«µÍµÄÊÇ £»
A¡¢³ÆÁ¿NaOHʱ£¬íÀÂë´í·ÅÔÚ×óÅÌ£¨ÒÑÒƶ¯ÓÎÂ룩
B¡¢ÏòÈÝÁ¿Æ¿ÖÐתÒÆÈÜҺʱ²»É÷ÓÐÒºµÎÈ÷ÔÚÈÝÁ¿Æ¿ÍâÃæ
C¡¢¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß
D¡¢¶¨ÈÝʱ¸©Êӿ̶ÈÏß
E¡¢ÅäÖÆÇ°£¬ÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®
£¨5£©ÈôʵÑé¹ý³ÌÖгöÏÖÈçÏÂÇé¿öÈçºÎ´¦Àí£¿¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß ¡£]
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ÄêÁÉÄþÊ¡¸§Ë³¸ß¼¶ÖÐѧ¸ßÒ»10ÔÂÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ
£¨ 15·Ö£©ÊµÑéÊÒÓÃNaOH¹ÌÌåÅäÖÆ250mL 1.25mol/LµÄNaOHÈÜÒº£¬Ìî¿Õ²¢Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ250mL 1.25mol/LµÄNaOHÈÜÒº£¬Ó¦³ÆÈ¡NaOHµÄÖÊÁ¿_____________g
£¨2£©ÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£© £»
A¡¢ÓÃ30mLˮϴµÓÉÕ±2¡ª3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B¡¢ÓÃÌìƽ׼ȷ³ÆÈ¡ËùÐèµÄNaOHµÄÖÊÁ¿£¬¼ÓÈëÉÙÁ¿Ë®£¨Ô¼30mL£©£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä³ä·ÖÈܽâ
C¡¢½«ÒÑÀäÈ´µÄNaOHÈÜÒºÑز£Á§°ô×¢Èë250mLµÄÈÝÁ¿Æ¿ÖÐ
D¡¢½«ÈÝÁ¿Æ¿¸Ç½ô£¬µßµ¹Ò¡ÔÈ
E¡¢¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ
F¡¢¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1¡ª2cm´¦
£¨3£©ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ðè»Ö¸´µ½ÊÒΣ¬ÕâÊÇÒòΪ_____________________________£»
£¨4£©ÏÂÁÐÅäÖƵÄÈÜҺŨ¶ÈÆ«µÍµÄÊÇ £»
A¡¢³ÆÁ¿NaOHʱ£¬íÀÂë´í·ÅÔÚ×óÅÌ£¨ÒÑÒƶ¯ÓÎÂ룩
B¡¢ÏòÈÝÁ¿Æ¿ÖÐתÒÆÈÜҺʱ²»É÷ÓÐÒºµÎÈ÷ÔÚÈÝÁ¿Æ¿ÍâÃæ
C¡¢¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß
D¡¢¶¨ÈÝʱ¸©Êӿ̶ÈÏß
E¡¢ÅäÖÆÇ°£¬ÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®
£¨5£©ÈôʵÑé¹ý³ÌÖгöÏÖÈçÏÂÇé¿öÈçºÎ´¦Àí£¿¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß ¡£]
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012ÄêÆÕͨ¸ßµÈѧУÕÐÉúÈ«¹úͳһ¿¼ÊÔÀí×Û»¯Ñ§²¿·Ö£¨¸£½¨¾í½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ
( 15 ·Ö£©
ʵÑéÊÒ³£ÓÃMnO2ÓëŨÑÎËá·´Ó¦ÖƱ¸Cl2£¨·¢Éú×°ÖÃÈçͼËùʾ£©¡£
(1)ÖƱ¸ÊµÑ鿪ʼʱ£¬Ïȼì²é×°ÖÃÆøÃÜÐÔ£¬½ÓÏÂÀ´µÄ²Ù×÷ÒÀ´ÎÊǣߣ¨ÌîÐòºÅ£©
A.ÍùÉÕÆ¿ÖмÓÈËMnO2·ÛÄ©
B.¼ÓÈÈ
C.ÍùÉÕÆ¿ÖмÓÈËŨÑÎËá
(2)ÖƱ¸·´Ó¦»áÒòÑÎËáŨ¶ÈϽµ¶øÍ£Ö¹¡£Îª²â¶¨·´Ó¦²ÐÓàÒºÖÐÑÎËáµÄŨ¶È£¬Ì½¾¿Ð¡×éͬѧÌá³öÏÂÁÐʵÑé·½°¸£º
¼×·½°¸£ºÓë×ãÁ¿AgNO3ÈÜÒº·´Ó¦£¬³ÆÁ¿Éú³ÉµÄAgClÖÊÁ¿¡£
ÒÒ·½°¸£º²ÉÓÃËá¼îÖк͵ζ¨·¨²â¶¨¡£
±û·½°¸£ºÓëÒÑÖªÁ¿CaCO3£¨¹ýÁ¿£©·´Ó¦£¬³ÆÁ¿Ê£ÓàµÄCaCO3ÖÊÁ¿¡£
¶¡·½°¸£ºÓë×ãÁ¿Zn ·´Ó¦£¬²âÁ¿Éú³ÉµÄH2Ìå»ý¡£
¼Ì¶ø½øÐÐÏÂÁÐÅжϺÍʵÑ飺
¢Ù Åж¨¼×·½°¸²»¿ÉÐУ¬ÀíÓÉÊÇ ¡£
¢Ú ½øÐÐÒÒ·½°¸ÊµÑ飺׼ȷÁ¿È¡²ÐÓàÇåҺϡÊÍÒ»¶¨±¶Êýºó×÷ΪÊÔÑù¡£
a.Á¿È¡ÊÔÑù20.00 mL£¬ÓÃ0 . 1000 mol¡¤L-1 NaOH±ê×¼ÈÜÒºµÎ¶¨£¬ÏûºÄ22.00mL£¬¸Ã´ÎµÎ¶¨²âµÃÊÔÑùÖÐÑÎËáŨ¶ÈΪ mol¡¤L-1
b.ƽÐеζ¨ºó»ñµÃʵÑé½á¹û¡£
¢Û Åжϱû·½°¸µÄʵÑé½á¹û £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°×¼È·¡±£©¡£
£ÛÒÑÖª£ºKsp£¨CaCO3 ) = 2.8¡Á10-9¡¢Ksp£¨MnCO3 ) = 2.3¡Á10-11
¢Ü ½øÐж¡·½°¸ÊµÑ飺װÖÃÈçͼËùʾ£¨¼Ð³ÖÆ÷¾ßÒÑÂÔÈ¥£©¡£
(i) ʹYÐιÜÖеIJÐÓàÇåÒºÓëпÁ£·´Ó¦µÄÕýÈ·²Ù×÷Êǽ« תÒƵ½ ÖС£
(ii)·´Ó¦Íê±Ï£¬Ã¿¼ä¸ô1 ·ÖÖÓ¶ÁÈ¡ÆøÌåÌå»ý£¬ÆøÌåÌå»ýÖð´Î¼õС£¬Ö±ÖÁ²»±ä¡£ÆøÌåÌå»ýÖð´Î¼õСµÄÔÒòÊǣߣ¨ÅųýÒÇÆ÷ºÍʵÑé²Ù×÷µÄÓ°ÏìÒòËØ£©¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ÄêÁÉÄþÊ¡¸ßÒ»10ÔÂÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ
£¨ 15·Ö£©ÊµÑéÊÒÓÃNaOH¹ÌÌåÅäÖÆ250mL 1.25mol/LµÄNaOHÈÜÒº£¬Ìî¿Õ²¢Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÅäÖÆ250mL 1.25mol/LµÄNaOHÈÜÒº£¬Ó¦³ÆÈ¡NaOHµÄÖÊÁ¿_____________g
£¨2£©ÅäÖÆʱ£¬ÆäÕýÈ·µÄ²Ù×÷˳ÐòÊÇ£¨×Öĸ±íʾ£¬Ã¿¸ö×ÖĸֻÄÜÓÃÒ»´Î£© £»
A¡¢ÓÃ30mLˮϴµÓÉÕ±2¡ª3´Î£¬Ï´µÓÒº¾ù×¢ÈëÈÝÁ¿Æ¿£¬Õñµ´
B¡¢ÓÃÌìƽ׼ȷ³ÆÈ¡ËùÐèµÄNaOHµÄÖÊÁ¿£¬¼ÓÈëÉÙÁ¿Ë®£¨Ô¼30mL£©£¬Óò£Á§°ôÂýÂý½Á¶¯£¬Ê¹Æä³ä·ÖÈܽâ
C¡¢½«ÒÑÀäÈ´µÄNaOHÈÜÒºÑز£Á§°ô×¢Èë250mLµÄÈÝÁ¿Æ¿ÖÐ
D¡¢½«ÈÝÁ¿Æ¿¸Ç½ô£¬µßµ¹Ò¡ÔÈ
E¡¢¸ÄÓýºÍ·µÎ¹Ü¼ÓË®£¬Ê¹ÈÜÒº°¼ÃæÇ¡ºÃÓë¿Ì¶ÈÏàÇÐ
F¡¢¼ÌÐøÍùÈÝÁ¿Æ¿ÄÚСÐļÓË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1¡ª2cm´¦
£¨3£©ÈÜҺעÈëÈÝÁ¿Æ¿Ç°Ðè»Ö¸´µ½ÊÒΣ¬ÕâÊÇÒòΪ_____________________________£»
£¨4£©ÏÂÁÐÅäÖƵÄÈÜҺŨ¶ÈÆ«µÍµÄÊÇ £»
A¡¢³ÆÁ¿NaOHʱ£¬íÀÂë´í·ÅÔÚ×óÅÌ£¨ÒÑÒƶ¯ÓÎÂ룩
B¡¢ÏòÈÝÁ¿Æ¿ÖÐתÒÆÈÜҺʱ²»É÷ÓÐÒºµÎÈ÷ÔÚÈÝÁ¿Æ¿ÍâÃæ
C¡¢¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß
D¡¢¶¨ÈÝʱ¸©Êӿ̶ÈÏß
E¡¢ÅäÖÆÇ°£¬ÈÝÁ¿Æ¿ÖÐÓÐÉÙÁ¿ÕôÁóË®
£¨5£©ÈôʵÑé¹ý³ÌÖгöÏÖÈçÏÂÇé¿öÈçºÎ´¦Àí£¿¼ÓÕôÁóˮʱ²»É÷³¬¹ýÁ˿̶ÈÏß ¡£]
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com