ij»¯Ñ§¿ÎÍâ»î¶¯Ð¡×é¶ÔijÆøÌå»ìºÏÎïÑùÆ·Éè¼ÆÁËÈçϲ½Öè½øÐÐʵÑ飺

¢ÙÈ¡Ò»¸öÅäÓкÏÊʽºÈûÇҽྻ¡¢¸ÉÔïµÄ500 mL׶ÐÎÆ¿£¬Óþ«È·¶ÈΪ0.001 gµÄ·ÖÎöÌìƽ(ÏÂͬ)׼ȷ³ÆÁ¿£¬µÃÖÊÁ¿Îªm1¡£

¢ÚÏò׶ÐÎÆ¿ÖÐͨÈë×ãÁ¿µÄ¸ÉÔïµÄ¸Ã»ìºÏÆøÌåÑùÆ·£¬ÈûºÃÆ¿Èû£¬×¼È·³ÆÁ¿£¬µÃµ½ÖÊÁ¿Îªm2¡£

¢ÛÍù׶ÐÎÆ¿ÖмÓÂúË®£¬ÈûºÃÆ¿Èû³ÆÁ¿£¬µÃÖÊÁ¿Îªm3¡£

¢ÜË®µÄÃܶÈΪ¦ÑË® g¡¤cm-3£¬¿ÕÆøµÄÃܶÈΪ¦Ñ¿ÕÆø g¡¤cm-3¿ÕÆøµÄʽÁ¿Îª29.0£¬Ôò¸Ã»ìºÏÑùÆ·µÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿Îª£º29¡Á¡£

ÇëÍê³ÉÏÂÁÐÎÊÌ⣺

(1)ʵÑéÄ¿µÄ_____________________________________________________________¡£

(2)¼ÆËã¢Ù׶ÐÎÆ¿ÖпÕÆøµÄÖÊÁ¿£¬m¿ÕÆø=__________¡£¢Ú׶ÐÎÆ¿ÖÐÑùÆ·µÄÖÊÁ¿mÑùÆ·=_________¡£

(3)ÎÊÌâÌÖÂÛ£º

ÎÊÌâÒ»£ºÊµÑéÍê³Éºó£¬ÓеÄͬѧÌá³ö£¬ÊµÑé²»ÊÇÔÚ±ê×¼×´¿öϽøÐеģ¬Ó¦¸Ã¼Ç¼ʵÑéµÄζÈ(t ¡æ)ºÍѹǿ(p kpa)£¬²¢¶ÔÓйØÊý¾Ý½øÐл»Ë㣬ÄãÈÏΪÊÇ·ñÓбØÒª£¬²¢ËµÃ÷ÀíÓÉ¡£

´ð£º_________________________________________________________________¡£

ÎÊÌâ¶þ£ºÀÏʦ¶Ô¸ÃС×éµÄʵÑéÉè¼ÆµãÆÀʱָ³ö£ºÎªÁËʹʵÑéÊý¾ÝºÏÀíÓÐЧ£¬ÔÚÿ´Î²âÁ¿Ê±£¬×¶ÐÎÆ¿ÖеÄÆøÌå(»òË®)Ìå»ý¶¼Ó¦¸ÃÏàµÈ¡£¶Ô´Ë£¬ÄãÈÏΪ²ÉÈ¡µÄ²Ù×÷Ϊ___________________

_____________________________________________________________________¡£

(1)²â¶¨Ä³ÆøÌå»ìºÏÎïÑùÆ·µÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿

 

(3)û±ØÒª£¬ÒòΪ¸Ã²â¶¨ÆøÌå»ìºÏÎïÑùÆ·µÄÏà¶Ô·Ö×ÓÖÊÁ¿ËùÀûÓõÄÔ­Àí¾ÍÊÇÔÚͬΡ¢Í¬Ñ¹¡¢Í¬Ìå»ýʱ¿ÕÆøÓëÑùÆ·µÄÖÊÁ¿±ÈµÈÓÚÏà¶Ô·Ö×ÓÖÊÁ¿Ö®±È£¬Ö»ÒªÊÇÔÚͬһʵÑéÌõ¼þϽøÐеľͿÉÒÔ  ÔÚµÚ1²½³ÆÁ¿Ê±£¬×¶ÐÎÆ¿½ºÈûÈû½ôºó£¬ÔÚÆ¿Íâ±ÚÉÏ×÷¸ö¼ÇºÅ£¬ÒÔºóÿ´Î³ÆÁ¿£¬½ºÈûÈûÈëÆ¿¿ÚµÄλÖÃÒÔ´ËΪ׼¡£

½âÎö£ºÓÉʵÑé²½Öè¢Ù¢Ú¢Û¿ÉµÃÑùÆ·ÖÊÁ¿£¬ÓɢܿɵÃÑùÆ·µÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿¡£½ö´ËÊý¾ÝÒ²Ö»ÄÜËã³öÑùÆ·µÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿£¬Òò´ËÆäʵÑéÄ¿µÄ¾ÍÊDzⶨ»ìºÏÆøÌåÑùÆ·µÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£ºÔĶÁÀí½â

£¨2013?ºìÇÅÇøһģ£©I£®Ä³»¯Ñ§¿ÎÍâ»î¶¯Ð¡×é¶ÔÎÛȾ´óÆøµÄ²¿·Ö·Ç½ðÊôÑõ»¯Îï½øÐÐ̽¾¿£®Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣮
£¨1£©Ð´³öÓÃÏõËáÖÆÈ¡Ò»Ñõ»¯µªµÄÀë×Ó·½³Ìʽ
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
3Cu+8H++2NO3-=3Cu2++2NO¡ü+4H2O
£®
£¨2£©²é×ÊÁϵÃÖª£¬HCOOH
H2SO4
΢ÈÈ
 CO¡ü+H2O£®ÊµÑéÊÒÓÐÈçͼ1ËùʾµÄ×°Öã¬ÖÆÈ¡COÆøÌå¿ÉÑ¡ÓõÄ×°ÖÃΪ
A
A
£¨ÌîÐòºÅ£©£¬ÊµÑéÊÒÀûÓøÃ×°Öû¹¿ÉÖÆÈ¡µÄ³£¼ûÆøÌåÓÐ
Cl2
Cl2
£¨ÌîдһÖÖÆøÌåµÄ·Ö×Óʽ£©£®
£¨3£©²é×ÊÁϵÃÖª£¬ÀûÓô߻¯¼Á¿ÉʹÆû³µÎ²ÆøÖеÄÒ»Ñõ»¯Ì¼ºÍµªÑõ»¯Îï´ó²¿·Ö·¢Éú·´Ó¦×ª»¯Îª¶þÑõ»¯Ì¼ºÍµªÆø£®¸ÃС×éÔÚʵÑéÊÒÄ£ÄâÆû³µÎ²Æø´¦Àí£¬Éè¼ÆÁËÈçͼ2ËùʾװÖ㨲¿·Ö¼Ð³ÖºÍ×°ÖÃÒÑÂÔÈ¥£©£®

¢ÙʵÑéÇ°¹Ø±ÕÐýÈûK£¬ÏÈͨµªÆøÅž»×°ÖÃÖеĿÕÆø£¬ÆäÄ¿µÄÊÇ
·ÀÖ¹COÓë¿ÕÆø»ìºÏ¼ÓÈȱ¬Õ¨
·ÀÖ¹COÓë¿ÕÆø»ìºÏ¼ÓÈȱ¬Õ¨
£®
¢Ú×°Ö㨢󣩵ÄÖ÷Òª×÷ÓÃÊÇ
¼ìÑéCOÊÇ·ñת»¯ÎªCO2
¼ìÑéCOÊÇ·ñת»¯ÎªCO2
£®
¢Û¸ÃÌ××°ÖÃÖÐÓв»ÍêÉÆÖ®´¦£¬»¹Ó¦ÔÚ×°Ö㨢ô£©ºó²¹³ä
βÆø´¦Àí×°ÖÃ
βÆø´¦Àí×°ÖÃ
×°Öã®
II£®¸Ã¿ÎÍâС×éÉè¼ÆµÄ´ÓZnSO4¡¢FeCl3µÄ»ìºÏÈÜÒºÖÐÖÆÈ¡ZnSO4?7H2O¹ý³ÌÈçÏ£º
a£®ÔÚ»ìºÏÒºÖмÓÈë6mol?L-1 NaOHÈÜÒº£¬ÖÁpH=8Ϊֹ£®
b£®¹ýÂ˺óµÃµ½³Áµí£¬ÓÃÕôÁóË®¶à´ÎÏ´µÓ³Áµí£®
c£®ÏòÏ´µÓºóµÄ³ÁµíÖмÓÈë2mol?L-1µÄÁòËᣬ±£³ÖÈÜÒºµÄpHÔÚ4¡«6£¬¼ÓÈÈÖó·Ð£¬³ÃÈȹýÂË£¬ÂËÒº¼´ÎªZnSO4ÈÜÒº£®
d£®ÂËÒºÖмÓÈë2mol?L-1µÄÁòËᣬʹÆäpH=2£®
ÒÑÖª²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïµÄÐÎʽ¿ªÊ¼³ÁµíÖÁÍêÈ«³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£¬»Ø´ðÏÂÁÐÎÊÌ⣺
³ÁµíÎï Fe£¨OH£©3 Zn£¨OH£©2
pH 1.5¡«3.2 6.4¡«8.0
£¨1£©²½ÖèbÖÐÈçºÎ¼ìÑé³ÁµíÒѾ­Ï´µÓ¸É¾»
È¡×îºóÒ»´ÎÏ´µÓÒºÉÙÁ¿£¬µÎ¼ÓÏõËáÒøÈÜÒº£¬ÈôÎÞ°×É«³Áµí£¬ËµÃ÷ÒѾ­Ï´µÓ¸É¾»
È¡×îºóÒ»´ÎÏ´µÓÒºÉÙÁ¿£¬µÎ¼ÓÏõËáÒøÈÜÒº£¬ÈôÎÞ°×É«³Áµí£¬ËµÃ÷ÒѾ­Ï´µÓ¸É¾»
£®
£¨2£©²½ÖèdÖмÓÈëÁòËᣬʹÆäpH=2µÄÄ¿µÄÊÇ
ÒÖÖÆZn2+µÄË®½â
ÒÖÖÆZn2+µÄË®½â
£» ÒªÖƵÃZnSO4?7H2OµÄ²½Öèd»¹È±ÉٵIJÙ×÷ÊÇ
½«ÈÜÒº¼ÓÈÈŨËõ
½«ÈÜÒº¼ÓÈÈŨËõ
£¬ËùÓõÄÖ÷Òª¹èËáÑÎÒÇÆ÷ÊÇ
Õô·¢Ã󣬾ƾ«µÆ£¬²£Á§°ô
Õô·¢Ã󣬾ƾ«µÆ£¬²£Á§°ô
£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÌì½òÊкìÇÅÇø¸ßÈýµÚÒ»´ÎÄ£Ä⿼ÊÔÀí×Û»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

I¡¢Ä³»¯Ñ§¿ÎÍâ»î¶¯Ð¡×é¶ÔÎÛȾ´óÆøµÄ²¿·Ö·Ç½ðÊôÑõ»¯Îï½øÐÐ̽¾¿¡£Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ¡£

(1)д³öÓÃÏõËáÖÆÈ¡NOµÄÀë×Ó·½³Ìʽ                       ¡£

(2)²é×ÊÁϵÃÖª£¬HCOOHCO+H2O¡£ÊµÑéÊÒÓÐÈçͼlËùʾµÄ×°Öã¬ÖÆÈ¡COÆøÌå¿ÉÑ¡ÓõÄ×°ÖÃΪ

              (ÌîÐòºÅ)£¬ÊµÑéÊÒÀûÓøÃ×°Öû¹¿ÉÖÆÈ¡µÄ³£¼ûÆøÌåÓÐ               £¨Ð´Ò»ÖÖÆøÌåµÄ·Ö×Óʽ£©¡£

(3)²é×ÊÁϵÃÖª£¬ÀûÓô߻¯¼Á¿ÉʹÆû³µÎ²ÆøÖеÄÒ»Ñõ»¯Ì¼ºÍµªÑõ»¯Îï´ó²¿·Ö·¢Éú·´Ó¦×ª»¯Îª¶þÑõ»¯Ì¼ºÍµªÆø¡£¸ÃС×éÔÚʵÑéÊÒÄ£ÄâÆû³µÎ²Æø´¦Àí£¬Éè¼ÆÁËÈçͼ2ËùʾװÖÃ(²¿·Ö¼Ð³ÖºÍ×°ÖÃÒÑÂÔÈ¥)¡£

¢ÙʵÑéÇ°£¬¹Ø±ÕÐýÈûK£¬ÏÈͨµªÆøÅž»×°ÖÃÖеĿÕÆø£¬ÆäÄ¿µÄÊÇ          ¡£

¢Ú×°ÖÃ(III)µÄÖ÷Òª×÷ÓÃÊÇ                                              ¡£

¢Û¸ÃÌ××°ÖÃÖÐÓв»ÍêÉÆÖ®´¦£¬»¹Ó¦ÔÚ×°ÖÃ(¢ô)ºó²¹³ä              ×°Öá£

II¡¢¸Ã¿ÎÍâС×éÉè¼ÆµÄ´ÓZnSO4¡¢FeCl3µÄ»ìºÏÈÜÒºÖÐÖÆÈ¡ZnSO4¡¤7H2O¹ý³ÌÈçÏ£º

a£®ÔÚ»ìºÏÒºÖмÓÈë6 mol/L NaOHÈÜÒº£¬ÖÁpH=8Ϊֹ¡£

b£®¹ýÂ˺óµÃµ½³Áµí£¬ÓÃÕôÁóË®¶à´ÎÏ´µÓ³Áµí¡£

c£®ÏòÏ´µÓºóµÄ³ÁµíÖмÓÈë2 mol/LµÄÁòËᣬ±£³ÖÈÜÒºµÄpHÔÚ4¡«6£¬¼ÓÈÈÖó·Ð£¬³ÃÈȹýÂË£¬ÂËÒº¼´ÎªZnSO4ÈÜÒº¡£

d£®ÂËÒºÖмÓÈë2 mol/LµÄÁòËᣬʹÆäpH=2¡£

ÒÑÖª²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïµÄÐÎʽ¿ªÊ¼³ÁµíÖÁÍêÈ«³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£¬»Ø´ðÏÂÁÐÎÊÌ⣺

³ÁµíÎï

Fe(OH)3

Zn(OH)2

pH

1.5¡«3.2

6.4¡«8.0

 

(1)²½ÖèbÖÐÈçºÎ¼ì²â³ÁµíÒѾ­Ï´µÓ¸É¾»                   ¡£

(2)²½ÖèdÖмÓÈëÁòËᣬʹÆäpH=2µÄÄ¿µÄÊÇ              £»ÒªÖƵÃZnSO4¡¤7H2OµÄ²½Öèd»¹È±ÉٵIJÙ×÷ÊÇ       £¬ËùÓõÄÖ÷Òª¹èËáÑÎÒÇÆ÷ÊÇ                ¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ººìÇÅÇøһģ ÌâÐÍ£ºÎÊ´ðÌâ

I£®Ä³»¯Ñ§¿ÎÍâ»î¶¯Ð¡×é¶ÔÎÛȾ´óÆøµÄ²¿·Ö·Ç½ðÊôÑõ»¯Îï½øÐÐ̽¾¿£®Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣮
£¨1£©Ð´³öÓÃÏõËáÖÆÈ¡Ò»Ñõ»¯µªµÄÀë×Ó·½³Ìʽ______£®
£¨2£©²é×ÊÁϵÃÖª£¬HCOOH
H2SO4
΢ÈÈ
 CO¡ü+H2O£®ÊµÑéÊÒÓÐÈçͼ1ËùʾµÄ×°Öã¬ÖÆÈ¡COÆøÌå¿ÉÑ¡ÓõÄ×°ÖÃΪ______£¨ÌîÐòºÅ£©£¬ÊµÑéÊÒÀûÓøÃ×°Öû¹¿ÉÖÆÈ¡µÄ³£¼ûÆøÌåÓÐ______£¨ÌîдһÖÖÆøÌåµÄ·Ö×Óʽ£©£®
£¨3£©²é×ÊÁϵÃÖª£¬ÀûÓô߻¯¼Á¿ÉʹÆû³µÎ²ÆøÖеÄÒ»Ñõ»¯Ì¼ºÍµªÑõ»¯Îï´ó²¿·Ö·¢Éú·´Ó¦×ª»¯Îª¶þÑõ»¯Ì¼ºÍµªÆø£®¸ÃС×éÔÚʵÑéÊÒÄ£ÄâÆû³µÎ²Æø´¦Àí£¬Éè¼ÆÁËÈçͼ2ËùʾװÖ㨲¿·Ö¼Ð³ÖºÍ×°ÖÃÒÑÂÔÈ¥£©£®

¾«Ó¢¼Ò½ÌÍø

¢ÙʵÑéÇ°¹Ø±ÕÐýÈûK£¬ÏÈͨµªÆøÅž»×°ÖÃÖеĿÕÆø£¬ÆäÄ¿µÄÊÇ______£®
¢Ú×°Ö㨢󣩵ÄÖ÷Òª×÷ÓÃÊÇ______£®
¢Û¸ÃÌ××°ÖÃÖÐÓв»ÍêÉÆÖ®´¦£¬»¹Ó¦ÔÚ×°Ö㨢ô£©ºó²¹³ä______×°Öã®
II£®¸Ã¿ÎÍâС×éÉè¼ÆµÄ´ÓZnSO4¡¢FeCl3µÄ»ìºÏÈÜÒºÖÐÖÆÈ¡ZnSO4?7H2O¹ý³ÌÈçÏ£º
a£®ÔÚ»ìºÏÒºÖмÓÈë6mol?L-1 NaOHÈÜÒº£¬ÖÁpH=8Ϊֹ£®
b£®¹ýÂ˺óµÃµ½³Áµí£¬ÓÃÕôÁóË®¶à´ÎÏ´µÓ³Áµí£®
c£®ÏòÏ´µÓºóµÄ³ÁµíÖмÓÈë2mol?L-1µÄÁòËᣬ±£³ÖÈÜÒºµÄpHÔÚ4¡«6£¬¼ÓÈÈÖó·Ð£¬³ÃÈȹýÂË£¬ÂËÒº¼´ÎªZnSO4ÈÜÒº£®
d£®ÂËÒºÖмÓÈë2mol?L-1µÄÁòËᣬʹÆäpH=2£®
ÒÑÖª²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïµÄÐÎʽ¿ªÊ¼³ÁµíÖÁÍêÈ«³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£¬»Ø´ðÏÂÁÐÎÊÌ⣺
³ÁµíÎï Fe£¨OH£©3 Zn£¨OH£©2
pH 1.5¡«3.2 6.4¡«8.0
£¨1£©²½ÖèbÖÐÈçºÎ¼ìÑé³ÁµíÒѾ­Ï´µÓ¸É¾»______£®
£¨2£©²½ÖèdÖмÓÈëÁòËᣬʹÆäpH=2µÄÄ¿µÄÊÇ______£» ÒªÖƵÃZnSO4?7H2OµÄ²½Öèd»¹È±ÉٵIJÙ×÷ÊÇ______£¬ËùÓõÄÖ÷Òª¹èËáÑÎÒÇÆ÷ÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011Äêɽ¶«Ê¡ÊµÑéÖÐѧ¸ß¿¼»¯Ñ§¶þÄ£ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£º½â´ðÌâ

I£®Ä³»¯Ñ§¿ÎÍâ»î¶¯Ð¡×é¶ÔÎÛȾ´óÆøµÄ²¿·Ö·Ç½ðÊôÑõ»¯Îï½øÐÐ̽¾¿£®Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣮
£¨1£©Ð´³öÓÃÏõËáÖÆÈ¡Ò»Ñõ»¯µªµÄÀë×Ó·½³Ìʽ______£®
£¨2£©²é×ÊÁϵÃÖª£¬HCOOH CO¡ü+H2O£®ÊµÑéÊÒÓÐÈçͼ1ËùʾµÄ×°Öã¬ÖÆÈ¡COÆøÌå¿ÉÑ¡ÓõÄ×°ÖÃΪ______£¨ÌîÐòºÅ£©£¬ÊµÑéÊÒÀûÓøÃ×°Öû¹¿ÉÖÆÈ¡µÄ³£¼ûÆøÌåÓÐ______£¨ÌîдһÖÖÆøÌåµÄ·Ö×Óʽ£©£®
£¨3£©²é×ÊÁϵÃÖª£¬ÀûÓô߻¯¼Á¿ÉʹÆû³µÎ²ÆøÖеÄÒ»Ñõ»¯Ì¼ºÍµªÑõ»¯Îï´ó²¿·Ö·¢Éú·´Ó¦×ª»¯Îª¶þÑõ»¯Ì¼ºÍµªÆø£®¸ÃС×éÔÚʵÑéÊÒÄ£ÄâÆû³µÎ²Æø´¦Àí£¬Éè¼ÆÁËÈçͼ2ËùʾװÖ㨲¿·Ö¼Ð³ÖºÍ×°ÖÃÒÑÂÔÈ¥£©£®

¢ÙʵÑéÇ°¹Ø±ÕÐýÈûK£¬ÏÈͨµªÆøÅž»×°ÖÃÖеĿÕÆø£¬ÆäÄ¿µÄÊÇ______£®
¢Ú×°Ö㨢󣩵ÄÖ÷Òª×÷ÓÃÊÇ______£®
¢Û¸ÃÌ××°ÖÃÖÐÓв»ÍêÉÆÖ®´¦£¬»¹Ó¦ÔÚ×°Ö㨢ô£©ºó²¹³ä______×°Öã®
II£®¸Ã¿ÎÍâС×éÉè¼ÆµÄ´ÓZnSO4¡¢FeCl3µÄ»ìºÏÈÜÒºÖÐÖÆÈ¡ZnSO4?7H2O¹ý³ÌÈçÏ£º
a£®ÔÚ»ìºÏÒºÖмÓÈë6mol?L-1 NaOHÈÜÒº£¬ÖÁpH=8Ϊֹ£®
b£®¹ýÂ˺óµÃµ½³Áµí£¬ÓÃÕôÁóË®¶à´ÎÏ´µÓ³Áµí£®
c£®ÏòÏ´µÓºóµÄ³ÁµíÖмÓÈë2mol?L-1µÄÁòËᣬ±£³ÖÈÜÒºµÄpHÔÚ4¡«6£¬¼ÓÈÈÖó·Ð£¬³ÃÈȹýÂË£¬ÂËÒº¼´ÎªZnSO4ÈÜÒº£®
d£®ÂËÒºÖмÓÈë2mol?L-1µÄÁòËᣬʹÆäpH=2£®
ÒÑÖª²¿·ÖÑôÀë×ÓÒÔÇâÑõ»¯ÎïµÄÐÎʽ¿ªÊ¼³ÁµíÖÁÍêÈ«³ÁµíʱÈÜÒºµÄpH¼ûÏÂ±í£¬»Ø´ðÏÂÁÐÎÊÌ⣺
³ÁµíÎïFe£¨OH£©3Zn£¨OH£©2
pH1.5¡«3.26.4¡«8.0
£¨1£©²½ÖèbÖÐÈçºÎ¼ìÑé³ÁµíÒѾ­Ï´µÓ¸É¾»______£®
£¨2£©²½ÖèdÖмÓÈëÁòËᣬʹÆäpH=2µÄÄ¿µÄÊÇ______£» ÒªÖƵÃZnSO4?7H2OµÄ²½Öèd»¹È±ÉٵIJÙ×÷ÊÇ______£¬ËùÓõÄÖ÷Òª¹èËáÑÎÒÇÆ÷ÊÇ______£®

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸