(8·Ö)ÓÃ98%µÄŨÁòËá(ÆäÃܶÈΪ1.84g/cm?3)ÅäÖÆ100mL1.0mol¡¤L£­1Ï¡ÁòËá,ÈôʵÑéÒÇÆ÷ÓÐ:

A£®100mLÁ¿Í²             B£®ÍÐÅÌÌìƽ          C£®²£Á§°ô               D£®50mLÈÝÁ¿Æ¿

E.10mLÁ¿Í²        F.½ºÍ·µÎ¹Ü      G.50mLÉÕ±­      H.100mLÈÝÁ¿Æ¿

£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ        mL¡£

£¨2£©ÊµÑéʱѡÓõÄÒÇÆ÷ÓÐ(ÌîÐòºÅ)       

£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)

¢Ù¶¨ÈÝʱ¸©Êӿ̶ÈÏß¹Û²ìÒºÃæ

¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï

¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏß

£¨4£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖÐ,ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(ÌîÐòºÅ)       

     A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ

     B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´

     C£®½«ÇâÑõ»¯ÄƹÌÌå·ÅÔÚÌìƽÍÐÅ̵ÄÂËÖ½ÉÏ,׼ȷ³ÆÁ¿²¢·ÅÈëÉÕ±­ÖÐÈܽâºó,Á¢¼´×¢ÈëÈÝÁ¿Æ¿ÖÐ

D£®½«×¼È·Á¿È¡µÄ18.4mol¡¤L£­1µÄÁòËᣬעÈëÒÑÊ¢ÓÐ30mLË®µÄ100mLµÄÈÝÁ¿Æ¿ÖУ¬¼ÓË®ÖÁ¿Ì¶ÈÏß

E.¶¨ÈݺóÈûºÃÆ¿Èû,ÓÃʳָ¶¥×¡Æ¿Èû,ÓÃÁíÒ»Ö»ÊÖµÄÊÖÖ¸ÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ

 

¡¾´ð°¸¡¿

 

£¨1£©5.4  £¨2£©C¡¢E¡¢F¡¢G¡¢H  £¨3£©¢Ù  £¨4£©B¡¢C¡¢D

¡¾½âÎö¡¿

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

(8·Ö)ÓÃ98%µÄŨÁòËá(ÆäÃܶÈΪ1.84g/cm?3)ÅäÖÆ100mL1.0mol¡¤L£­1Ï¡ÁòËá,ÈôʵÑéÒÇÆ÷ÓÐ:

A£®100mLÁ¿Í²             B£®ÍÐÅÌÌìƽ          C£®²£Á§°ô               D£®50mLÈÝÁ¿Æ¿

E.10mLÁ¿Í²        F.½ºÍ·µÎ¹Ü     G.50mLÉÕ±­     H.100mLÈÝÁ¿Æ¿

£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ       mL¡£

£¨2£©ÊµÑéʱѡÓõÄÒÇÆ÷ÓÐ(ÌîÐòºÅ)       

£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)

¢Ù¶¨ÈÝʱ¸©Êӿ̶ÈÏß¹Û²ìÒºÃæ

¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï

¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏß

£¨4£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖÐ,ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(ÌîÐòºÅ)       

     A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ

     B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´

     C£®½«ÇâÑõ»¯ÄƹÌÌå·ÅÔÚÌìƽÍÐÅ̵ÄÂËÖ½ÉÏ,׼ȷ³ÆÁ¿²¢·ÅÈëÉÕ±­ÖÐÈܽâºó,Á¢¼´×¢ÈëÈÝÁ¿Æ¿ÖÐ

D£®½«×¼È·Á¿È¡µÄ18.4mol¡¤L£­1µÄÁòËᣬעÈëÒÑÊ¢ÓÐ30mLË®µÄ100mLµÄÈÝÁ¿Æ¿ÖУ¬¼ÓË®ÖÁ¿Ì¶ÈÏß

E.¶¨ÈݺóÈûºÃÆ¿Èû,ÓÃʳָ¶¥×¡Æ¿Èû,ÓÃÁíÒ»Ö»ÊÖµÄÊÖÖ¸ÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2012-2013ѧÄêÖØÇìÊÐ49ÖÐÆßУÁªÃ˸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨´ø½âÎö£© ÌâÐÍ£ºÊµÑéÌâ

(8·Ö)ÓÃ98%µÄŨÁòËá(ÆäÃܶÈΪ1.84 g/cm3)ÅäÖÆ100 mL 1.0 mol¡¤L£­1Ï¡ÁòËá,ÈôʵÑéÒÇÆ÷ÓÐ:
A 100 mLÁ¿Í²       B²£Á§°ô         C 50 mLÈÝÁ¿Æ¿      D 10 mLÁ¿Í²
E ½ºÍ·µÎ¹Ü         F 50 mLÉÕ±­      G 100 mLÈÝÁ¿Æ¿
£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ       mL£¬
£¨2£©ÊµÑéʱ²»Ñ¡ÓõÄÒÇÆ÷ÓÐ(ÌîÐòºÅ)                      £¬
£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)                 £¬
¢Ù¶¨ÈÝʱ¸©Êӿ̶ÈÏß¹Û²ìÒºÃæ
¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï
¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏß
¢ÜŨÁòËáÔÚÉÕ±­ÖÐÏ¡ÊͺóδÀäÈ´µ½ÊÒξÍתÒƵ½ÈÝÁ¿Æ¿Öж¨ÈÝ
£¨4£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖÐ,ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(ÌîÐòºÅ)             

A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´
C£®¶¨ÈݺóÈûºÃÆ¿Èû,ÓÃʳָ¶¥×¡Æ¿Èû,ÓÃÁíÒ»Ö»ÊÖµÄÊÖÖ¸ÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ
D£®½«×¼È·Á¿È¡µÄ18.4 mol¡¤L£­1µÄÁòËᣬעÈëÒÑÊ¢ÓÐ30 mLË®µÄ100 mLµÄÈÝÁ¿Æ¿ÖУ¬¼ÓË®ÖÁ¿Ì¶ÈÏß

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2010ÄêÄþÏÄÎ÷¼ªÏØ»ØÃñÖÐѧ¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔÌâ ÌâÐÍ£ºÊµÑéÌâ

(8·Ö)ÓÃ98%µÄŨÁòËá(ÆäÃܶÈΪ1.84g/cm?3)ÅäÖÆ100mL1.0mol¡¤L£­1Ï¡ÁòËá,ÈôʵÑéÒÇÆ÷ÓÐ:
A£®100mLÁ¿Í²             B£®ÍÐÅÌÌìƽ          C£®²£Á§°ô               D£®50mLÈÝÁ¿Æ¿
E.10mLÁ¿Í²        F.½ºÍ·µÎ¹Ü      G.50mLÉÕ±­      H.100mLÈÝÁ¿Æ¿
£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ       mL¡£
£¨2£©ÊµÑéʱѡÓõÄÒÇÆ÷ÓÐ(ÌîÐòºÅ)       
£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)
¢Ù¶¨ÈÝʱ¸©Êӿ̶ÈÏß¹Û²ìÒºÃæ
¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï
¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏß
£¨4£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖÐ,ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(ÌîÐòºÅ)       
A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ
B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´
C£®½«ÇâÑõ»¯ÄƹÌÌå·ÅÔÚÌìƽÍÐÅ̵ÄÂËÖ½ÉÏ,׼ȷ³ÆÁ¿²¢·ÅÈëÉÕ±­ÖÐÈܽâºó,Á¢¼´×¢ÈëÈÝÁ¿Æ¿ÖÐ
D£®½«×¼È·Á¿È¡µÄ18.4mol¡¤L£­1µÄÁòËᣬעÈëÒÑÊ¢ÓÐ30mLË®µÄ100mLµÄÈÝÁ¿Æ¿ÖУ¬¼ÓË®ÖÁ¿Ì¶ÈÏß
E.¶¨ÈݺóÈûºÃÆ¿Èû,ÓÃʳָ¶¥×¡Æ¿Èû,ÓÃÁíÒ»Ö»ÊÖµÄÊÖÖ¸ÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ìÖØÇìÊÐÆßУÁªÃ˸ßÒ»ÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

 (8·Ö)ÓÃ98%µÄŨÁòËá(ÆäÃܶÈΪ1.84 g/cm3)ÅäÖÆ100 mL 1.0 mol¡¤L£­1Ï¡ÁòËá,ÈôʵÑéÒÇÆ÷ÓÐ:

A 100 mLÁ¿Í²       B²£Á§°ô         C 50 mLÈÝÁ¿Æ¿      D 10 mLÁ¿Í²

E ½ºÍ·µÎ¹Ü         F 50 mLÉÕ±­      G 100 mLÈÝÁ¿Æ¿

£¨1£©ÐèÁ¿È¡Å¨ÁòËáµÄÌå»ýΪ        mL£¬

£¨2£©ÊµÑéʱ²»Ñ¡ÓõÄÒÇÆ÷ÓÐ(ÌîÐòºÅ)                       £¬

£¨3£©ÅäÖƹý³ÌÖУ¬ÏÂÁÐÇé¿ö»áʹÅäÖƽá¹ûÆ«¸ßµÄÊÇ(ÌîÐòºÅ)                 £¬

¢Ù¶¨ÈÝʱ¸©Êӿ̶ÈÏß¹Û²ìÒºÃæ

¢ÚÈÝÁ¿Æ¿Ê¹ÓÃʱδ¸ÉÔï

¢Û¶¨Èݺó¾­Õñµ´¡¢Ò¡ÔÈ¡¢¾²Ö㬷¢ÏÖÒºÃæµÍÓڿ̶ÈÏߣ¬ÔÙ¼ÓÕôÁóË®²¹ÖÁ¿Ì¶ÈÏß

¢ÜŨÁòËáÔÚÉÕ±­ÖÐÏ¡ÊͺóδÀäÈ´µ½ÊÒξÍתÒƵ½ÈÝÁ¿Æ¿Öж¨ÈÝ

£¨4£©ÔÚÈÝÁ¿Æ¿Ê¹Ó÷½·¨ÖÐ,ÏÂÁвÙ×÷²»ÕýÈ·µÄÊÇ(ÌîÐòºÅ)             

A£®Ê¹ÓÃÈÝÁ¿Æ¿Ç°¼ì²éËüÊÇ·ñ©ˮ

B£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó£¬ÔÙÓôýÅäÒºÈóÏ´

C£®¶¨ÈݺóÈûºÃÆ¿Èû,ÓÃʳָ¶¥×¡Æ¿Èû,ÓÃÁíÒ»Ö»ÊÖµÄÊÖÖ¸ÍÐסƿµ×,°ÑÈÝÁ¿Æ¿µ¹×ªÒ¡ÔÈ

D£®½«×¼È·Á¿È¡µÄ18.4 mol¡¤L£­1µÄÁòËᣬעÈëÒÑÊ¢ÓÐ30 mLË®µÄ100 mLµÄÈÝÁ¿Æ¿ÖУ¬¼ÓË®ÖÁ¿Ì¶ÈÏß

 

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸