¡¾ÌâÄ¿¡¿ÎÒ¹ú»¯¹¤×¨¼ÒºîµÂ°ñµÄ¡°ºîÊÏÖƼ¡±ÔøΪÊÀ½çÖƼҵ×ö³öÁËÍ»³ö¹±Ïס£ËûÒÔNaCl¡¢NH3¡¢CO2µÈΪԭÁÏÏÈÖƵÃNaHCO3£¬½ø¶øÉú²ú³ö´¿¼î¡£Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽÈçÏ£º

NH3£«CO2£«H2O=NH4HCO3 NH4HCO3£«NaCl=NaHCO3¡ý£«NH4Cl 2NaHCO3Na2CO3£«CO2¡ü£«H2O

£¨1£© ̼ËáÇâï§Óë±¥ºÍʳÑÎË®·´Ó¦£¬ÄÜÎö³ö̼ËáÇâÄƾ§ÌåµÄÔ­ÒòÊÇ________£¨Ìî×Öĸ£©¡£

a̼ËáÇâÄÆÄÑÈÜÓÚË®

b ̼ËáÇâÄÆÊÜÈÈÒ×·Ö½â

c ̼ËáÇâÄƵÄÈܽâ¶ÈÏà¶Ô½ÏС£¬ËùÒÔÔÚÈÜÒºÖÐÊ×ÏȽᾧÎö³ö

£¨2£© ij̽¾¿»î¶¯Ð¡×é¸ù¾ÝÉÏÊöÖƼîÔ­Àí£¬½øÐÐ̼ËáÇâÄƵÄÖƱ¸ÊµÑ飬ͬѧÃÇ°´¸÷×ÔÉè¼Æ·½°¸ÊµÑé¡£

¢Ùһλͬѧ½«¶þÑõ»¯Ì¼ÆøÌåͨÈ뺬°±µÄ±¥ºÍʳÑÎË®ÖÐÖƱ¸Ì¼ËáÇâÄÆ£¬ÊµÑé×°ÖÃÈçÏÂͼËùʾ£¨Í¼Öмг֡¢¹Ì¶¨ÓõÄÒÇÆ÷δ»­³ö£©¡£

£¨¢ñ£©ÒÒ×°ÖÃÖеÄÊÔ¼ÁÊÇ________________¡£

£¨¢ò£©ÊµÑé½áÊøºó£¬·ÖÀë³öNaHCO3¾§ÌåµÄ²Ù×÷ÊÇ________£¨ÌîÃû³Æ£©¡£

¢ÚÁíһλͬѧÓÃͼÖÐÎì×°Öã¨ÆäËû×°ÖÃδ»­³ö£©½øÐÐʵÑé¡£

£¨¢ñ£©ÊµÑéʱ£¬ÐëÏÈ´Ó________¹ÜͨÈë________ÆøÌ壬ÔÙ´Ó________¹ÜͨÈë________ÆøÌå¡£

£¨¢ò£©ÓÐͬѧ½¨ÒéÔÚÎì×°ÖõÄb¹Ü϶ËÁ¬½Ó¼º×°Öã¬ÀíÓÉÊÇ__________¡£

¡¾´ð°¸¡¿c ±¥ºÍ̼ËáÇâÄÆÈÜÒº ¹ýÂË a NH3 b CO2 Ôö´óÆøÌåÓëÈÜÒºµÄ½Ó´¥Ãæ»ý£¬Ìá¸ßCO2ÎüÊÕÂÊ

¡¾½âÎö¡¿

¹¤ÒµÉϺîÊÏÖƼÊÇÔÚ±¥ºÍʳÑÎË®ÖÐͨÈë°±ÆøºÍ¶þÑõ»¯Ì¼£¬ÓÉÓÚ°±ÆøÔÚË®ÖеÄÈܽâ¶È´ó£¬ËùÒÔÏÈͨÈë°±Æø£¬Í¨Èë×ãÁ¿µÄ°±ÆøºóÔÙͨÈë¶þÑõ»¯Ì¼£¬Éú³ÉÁË̼ËáÇâÄÆ£¬ÓÉÓÚ̼ËáÇâÄƵÄÈܽâ¶È½ÏС£¬ËùÒÔÈÜÒºÖÐÓÐ̼ËáÇâÄƾ§ÌåÎö³ö£¬½«Ì¼ËáÇâÄƾ§Ìå¼ÓÈȺóµÃ´¿¼î̼ËáÄÆ¡£

£¨1£©a¡¢Ì¼ËáÇâÄÆÒ×ÈÜÓÚË®£¬¹Ê´íÎó£»

B¡¢Ì¼ËáÇâÄÆÊÜÈÈÒ׷ֽ⣬ÓëÆäÔÚÈÜÒºÖÐÊ×ÏȽᾧÎö³öÎ޹أ¬¹Ê´íÎó£»

C¡¢Ì¼ËáÇâÄƵÄÈܽâ¶ÈÏà¶ÔÓÚÂÈ»¯ï§À´ËµÌ¼ËáÇâÄƵÄÈܽâ¶È¸üСһЩ£¬ËùÒÔÔÚÈÜÒºÖÐÊ×ÏȽᾧÎö³ö£¬¹ÊÕýÈ·£»

CÕýÈ·£¬¹Ê´ð°¸Îª£ºc£»

£¨2£©¢Ù£¨I£©ÀûÓÃÑÎËáÖÆÈ¡¶þÑõ»¯Ì¼Ê±£¬ÒòÑÎËáÒ×»Ó·¢£¬ËùÒÔ£¬¶þÑõ»¯Ì¼Öг£»áº¬ÓÐÂÈ»¯ÇâÆøÌ壬̼ËáÇâÄÆÄÜÓëÑÎËá·´Ó¦²»Óë¶þÑõ»¯Ì¼·´Ó¦£¬ËùÒÔͨ¹ý̼ËáÇâÄƵÄÈÜÒºÊÇ¿ÉÒÔ³ýµô¶þÑõ»¯Ì¼ÆøÌåÖеÄÂÈ»¯ÇâÆøÌ壬¹Ê´ð°¸Îª£º±¥ºÍ̼ËáÇâÄÆÈÜÒº£»

£¨II£©·ÖÀë³öNaHCO3¾§ÌåµÄ²Ù×÷ÊÇ·ÖÀë¹ÌÌåÓëÒºÌ壬³£²ÉÓõÄʵÑé²Ù×÷ÊǹýÂ˲Ù×÷£¬¹Ê´ð°¸Îª£º¹ýÂË£»

¢Ú£¨I£©ÖÆȡ̼ËáÇâÄÆʱÏÈÒªµÃµ½º¬°±µÄ±¥ºÍʳÑÎË®£¬°±Æø¼«Ò×ÈÜÓÚË®£¬¶þÑõ»¯Ì¼ÄÜÈÜÓÚË®£¬ËùÒÔÓ¦ÏÈͨÈë°±Æø£¬ËùÒÔa¶ËͨÈ룬´Ó¶ø±£Ö¤ÁË´ÓbͨÈë¶þÑõ»¯Ì¼Ê±£¬¶þÑõ»¯Ì¼±»³ä·Ö·´Ó¦£¬¹Ê´ð°¸Îª£ºa£»NH3£»b£»CO2£»

£¨II£©×°ÖøĶ¯ºó·´Ó¦ÎïµÄ¶þÑõ»¯Ì¼ÓëÈÜÒºµÄ½Ó´¥Ãæ»ý±ä´ó£¬Ìá¸ßÁ˶þÑõ»¯Ì¼µÄÎüÊÕÂÊ£¬
¹Ê´ð°¸Îª£ºÔö´óÆøÌåÓëÈÜÒº½Ó´¥Ãæ»ý£¬Ìá¸ßCO2ÎüÊÕÂÊ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÖÒÔµí·Û»òÒÒϩΪÖ÷ÒªÔ­Á϶¼¿ÉÒԺϳÉÒÒËáÒÒõ¥£¬ÆäºÏ³É·ÏßÈçͼËùʾ¡£

£¨ÒÑÖª£º2CH3CHO+O22CH3COOH£©

£¨1£©AÖк¬ÓеĹÙÄÜÍÅÃû³ÆÊÇ______________£»ÆäÖТ۵ķ´Ó¦ÀàÐÍÊÇ______________£»

¢ÞµÄ·´Ó¦ÀàÐÍÊÇ______________£»

£¨2£©Ð´ÒÒÏ©µÄµç×Óʽ£º_________________ÒÒÏ©µÄ½á¹¹¼òʽ£º____________;

£¨3£©Ð´³öÏÂÁз´Ó¦µÄ»¯Ñ§·½³Ìʽ£º¢Ù__________________;¢Ý______________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿Na2O2ÊÇÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬¾ßÓжàÖÖÓÃ;¡£

£¨1£©Na2O2¾ßÓÐÑõ»¯ÐÔ£¬¿ÉÒÔ½«SO2Ñõ»¯ÎªÁòËáÄÆ£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º______________£¬¸Ã·´Ó¦ÖУ¬Na2O2µÄ×÷ÓÃΪ____________£¨Ìî¡°»¹Ô­¼Á¡±¡¢¡°Ñõ»¯¼Á¡±»ò¡°¼ÈÊÇÑõ»¯¼ÁÓÖÊÇ»¹Ô­¼Á¡±£©¡£

£¨2£©Na2O2ÓëCO2·´Ó¦¿ÉÒÔ²úÉúÑõÆø¡£Ä³Í¬Ñ§Í¨¹ýÏÂÁÐ×°ÖÃÑéÖ¤Na2O2ÄÜ·ñÓëCO2·´Ó¦¡£ (ͼÖÐÌú¼Ų̈µÈ×°ÖÃÒÑÂÔÈ¥)¡£

¢Ù×°ÖÃAµÄÃû³ÆÊÇ_______£¬AÖеĹÌÌåΪ_________£¬×°ÖÃBÖÐÊÔ¼ÁµÄ×÷ÓÃΪ______

¢ÚÈôNa2O2ÄÜÓëCO2£¬Ôò×°ÖÃCÖеÄÏÖÏóÊÇ____________

£¨3£©ÎÞË®ÂÈ»¯¸ÆÊǸÉÔï¼Á£¬ÔÚa´¦ÊÕ¼¯ÆøÌ壬¼ì²â·¢ÏÖ¸ÃÆøÌåÖм¸ºõ¶¼ÊÇCO2ÆøÌ壨¹ýÑõ»¯ÄÆ×ãÁ¿£©£¬Ôò˵Ã÷¹ýÑõ»¯ÄÆÓëCO2ÆøÌå²»·´Ó¦¡£¸Ãͬѧ²éÔÄÏà¹ØÎÄÏ×£¬È»ºó³·µô×°ÖÃB£¬ÆäËû¶¼±£Áô£¨°üÀ¨ÊÔ¼Á£©£¬Á¬½ÓºÃ×°ÖúóÔٴνøÐÐʵÑ飬ÖØÐÂÊÕ¼¯ÆøÌå¼ì²â£¬·¢Ïֵõ½µÄÆøÌ弸ºõ¶¼ÊÇÑõÆø£¬¸ÃʵÑé½á¹û˵Ã÷¹ýÑõ»¯ÄÆÓëCO2ÆøÌå·´Ó¦ÐèÒª_______________¡£

£¨4£©½«Ò»¶¨Á¿µÄNa2O2¹ÌÌåͶÈëµ½º¬ÓÐÏÂÁÐÀë×ÓµÄÈÜÒºÖУºSO32£­¡¢HCO3-¡¢CO32£­¡¢Na£«£¬·´Ó¦Íê±Ïºó£¬ÈÜÒºÖÐÉÏÊöÀë×ÓÊýÄ¿¼¸ºõ²»±äµÄÓУ¨²»¿¼ÂÇÈÜÒºÌå»ýµÄ±ä»¯£©__________£¨ÌîÀë×Ó·ûºÅ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐʵÑé½áÂÛÕýÈ·µÄÊÇ£¨¡¡¡¡£©

A.ÏòijÈÜÒºÖмÓÈë·Ó̪£¬ÈÜÒº²»±äÉ«£¬Ôò¸ÃÈÜÒºÒ»¶¨ÏÔËáÐÔ

B.ÏòijÈÜÒºÖмÓÈëÂÈ»¯±µÈÜÒº²úÉú°×É«³Áµí£¬ÔÙ¼ÓÈëÑÎËá³Áµí²»Ïûʧ£¬Ôò¸ÃÈÜÒºÖÐÒ»¶¨ÓÐ

C.ÏòijÈÜÒºÖмÓÈëÏ¡ÑÎËá²úÉúÎÞÉ«ÎÞζÆøÌ壬½«ÆøÌåͨÈë³ÎÇåʯ»ÒË®ÖУ¬Ê¯»ÒË®±ä»ë×Ç£¬ÔòÔ­ÈÜÒºÖÐÒ»¶¨ÓÐ

D.ÏòijÈÜÒºÖеμÓKSCNÊÔ¼Á£¬ÈÜÒº±ä³ÉѪºìÉ«£¬Ôò¸ÃÈÜÒºÖÐÒ»¶¨ÓÐFe3£«

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨NA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£©£¨¡¡¡¡£©

A.³£Î³£Ñ¹Ï£¬18 g Ëùº¬µÄµç×ÓÊýΪ10NA

B.56 g½ðÊôÌúÓëÂÈÆø·´Ó¦Ê±µÃµ½µÄµç×ÓÊýΪ3NA

C.±ê×¼×´¿öÏ£¬22.4 LÑõÆøËùº¬µÄÑõÔ­×ÓÊýΪ2NA

D.³£Î³£Ñ¹Ï£¬22.4 L CO2Óë×ãÁ¿Na2O2·´Ó¦×ªÒƵç×ÓÊýΪNA

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿µâ»¯¼ØÊÇÒ»ÖÖÎÞÉ«¾§Ì壬Ò×ÈÜÓÚË®¡£ÊµÑéÊÒÖƱ¸KI¾§ÌåµÄ²½ÖèÈçÏ£º

¢ñ.ÔÚÈçÏÂͼËùʾµÄÈý¾±ÉÕÆ¿ÖмÓÈëÑÐϸµÄI2ºÍÒ»¶¨Á¿µÄ30%KOHÈÜÒº£¬½Á°è£¨ÒÑÖª£ºI2ÓëKOH·´Ó¦²úÎïÖ®Ò»ÊÇKIO3£©£»

¢ò.µâÍêÈ«·´Ó¦ºó£¬´ò¿ª·ÖҺ©¶·ÖеĻîÈû¡¢µ¯»É¼Ð1¡¢2£¬Ïò×°ÖÃCÖÐͨÈë×ãÁ¿µÄH2S£»

¢ó.·´Ó¦½áÊøºó£¬Ïò×°ÖÃCÖмÓÈëÏ¡H2SO4Ëữ£¬Ë®Ô¡¼ÓÈÈ£»

¢ô.ÀäÈ´£¬¹ýÂ˵ÃKI´ÖÈÜÒº¡£

£¨1£©ÒÇÆ÷aµÄÃû³ÆÊÇ__________£¬²½Öè¢ñÖпØÖÆKOHÈÜÒº¹ýÁ¿µÄÄ¿µÄÊÇ______________¡£

£¨2£©×°ÖÃBµÄ×÷ÓÃÊÇ_____________£¬×°ÖÃDÖÐÊ¢·ÅµÄÈÜÒºÊÇ________________¡£

£¨3£©×°ÖÃCÖÐH2SºÍKIO3·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______________________¡£

£¨4£©²½Öè¢óÖÐˮԡ¼ÓÈȵÄÄ¿µÄÊdzýÈ¥_________________________£¨Ìѧʽ£©¡£

£¨5£©Óɲ½Öè¢ôËùµÃµÄKI´ÖÈÜÒºÖк¬ÓÐÉÙÁ¿K2SO4£¬Ðè½øÐÐÌá´¿£¬Ìá´¿Á÷³ÌÈçÏ£º

¢ÙÒÑÖª°×É«¹ÌÌåBÊÇ»ìºÏÎÊÔ¼ÁAΪ__________£¬Îª³ýÈ¥ÈÜÒºCÖеÄÔÓÖÊ£¬²½Öè¢ÚÖе÷½ÚÈÜҺΪÈõËáÐÔ£¬Ôò¼ÓÈëHIÈÜÒººó²úÉúµÄÏÖÏóÊÇ___________________¡£

¢ÚΪ²â¶¨×îºóËùµÃKI¾§ÌåµÄ´¿¶È£¬È¡a g¾§ÌåÅäÖÆ100mLÈÜÒº£¬È¡³ö25mLÈÜÒº£¬µÎÈë×ãÁ¿Ï¡µÄËáÐÔK2Cr2O7ÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬µÎ¼Ó¼¸µÎµí·ÛÈÜҺΪָʾ¼Á£¬ÓÃb mol¡¤L£­1µÄNa2S2O3ÈÜÒº½øÐе樣¬ÏûºÄNa2S2O3ÈÜÒºVmL¡£

µÎ¶¨¹ý³ÌÖÐÉæ¼°µÄ·´Ó¦Îª£º£¬ÔòµÎ¶¨ÖÕµãʱµÄÏÖÏóΪ________________________£¬¾§ÌåµÄ´¿¶ÈΪ_______________________£¨Áгö¼ÆËãʽ£©¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿WÊÇÓÉA¡¢BÁ½ÖÖÔªËØ×é³ÉµÄAB2ÐÍ»¯ºÏÎï¡£

£¨1£©ÈôWºÍ½¹Ì¿ÔÚ¸ßÎÂÏ·¢Éú·´Ó¦£¬ËùÖƵõİ뵼Ìå²ÄÁÏÓ¦Óù㷺¡£ÔòWΪ________________(Ìѧʽ)¡£

£¨2£©ÈôÈ¡Á½Ö§ÊԹֱܷð¼ÓÈëÉÙÁ¿WÈÜÒº£¬ÍùÒ»Ö§ÊÔ¹ÜÖеÎÈëKSCNÈÜÒº£¬ÎÞÃ÷ÏÔÏÖÏó¡£ÍùÁíÒ»Ö§ÊÔ¹ÜÖмÓÈë×ãÁ¿ÂÈË®£¬ÔÙ¼ÓÈëÊÊÁ¿CCl4£¬Õñµ´£¬¾²Öã¬Ï²ãÈÜÒº³Ê×ϺìÉ«£»ÍùÉϲãÈÜÒºÖеÎÈëKSCNÈÜÒº£¬ÈÜÒº³ÊºìÉ«¡£

¢ÙWÈÜÒºÖÐËùº¬½ðÊôÑôÀë×ÓΪ________________¡£

¢ÚÉÏÊöʵÑéÖУ¬WÓë×ãÁ¿ÂÈË®·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________________________________________¡£

£¨3£©ÈôWÊÇÀë×Ó»¯ºÏÎÆäÒõ¡¢ÑôÀë×Ó¾ùº¬18¸öµç×Ó£¬ÇÒÒõ¡¢ÑôÀë×Ó¸öÊý±ÈΪ1¡Ã1¡£

¢ÙÒõÀë×ӵĵç×ÓʽΪ___________________¡£

¢Ú1mol WÓë×ãÁ¿Ë®³ä·Ö·´Ó¦£¬×ªÒƵç×ÓµÄÎïÖʵÄÁ¿Îª_____________mol¡£

£¨4£©ÈôA¡¢BÊÇͬÖ÷×åÔªËØ£¬WÈÜÓÚË®Éú³ÉÒ»ÖÖ¶þÔªÈõËá¡£

¢ÙBÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ______________________________¡£

¢ÚÈç¹û³£ÎÂÏÂWΪÆøÌ壬WËùÐγɵĶþÔªÈõËáÈÜÒºÖУ¬º¬AÔªËصÄij΢Á£Õ¼ËùÓк¬AÔªËØ΢Á£µÄÎïÖʵÄÁ¿·ÖÊýÓëÈÜÒºpHµÄ¹ØϵÈçÏÂͼËùʾ£¬¸Ã΢Á£µÄ»¯Ñ§Ê½Îª______________________£»

¸Ã¶þÔªÈõËáµÄÒ»¼¶µçÀë³£ÊýΪKa1£¬ÔòpKa1=¡ªlgKa1¡Ö______________________¡£

¢ÛÈç¹ûAÔªËصÄÖÜÆÚÐòÊýÊÇBÔªËصÄÁ½±¶£¬WµÄË®ÈÜÒº±»Ë«ÑõË®Ñõ»¯µÄ»¯Ñ§·½³ÌʽΪ_________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿°±Æø¿É×÷ΪÍÑÏõ¼Á£¬ÔÚºãκãÈÝÃܱÕÈÝÆ÷ÖгäÈëÒ»¶¨Á¿µÄNOºÍNH3£¬ÔÚÒ»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£º6NO£¨g£©+4NH3£¨g£©5N2£¨g£©+6H2O£¨g£©¡£

£¨1£©ÄÜ˵Ã÷¸Ã·´Ó¦ÒѴﵽƽºâ״̬µÄ±êÖ¾ÊÇ___£¨Ìî×ÖĸÐòºÅ£©

a.·´Ó¦ËÙÂÊ4vÕý£¨NH3£©=5vÄ棨N2£©

b.µ¥Î»Ê±¼äÀïÿÉú³É5mol N2£¬Í¬Ê±Éú³É4mol NH3

c.ÈÝÆ÷ÄÚѹǿ²»ÔÙËæʱ¼ä¶ø·¢Éú±ä»¯

d.ÈÝÆ÷ÄÚn(NO£©£ºn£¨NH3£©£ºn£¨N2£©£ºn£¨H2O£©=6£º4£º5£º6

£¨2£©Ä³´ÎʵÑéÖвâµÃÈÝÆ÷ÄÚNO¼°N2µÄÎïÖʵÄÁ¿Ëæʱ¼ä±ä»¯ÈçͼËùʾ£¬Í¼ÖÐv£¨Õý£©Óëv£¨Ä棩ÏàµÈµÄµãΪ____£¨Ñ¡Ìî×Öĸ£©¡£

£¨3£©Ò»¶¨Ìõ¼þÏ£¬ÔÚ2LÃܱÕÈÝÆ÷ÄÚ£¬·´Ó¦2NO2N2O4£¬n£¨NO2£©Ëæʱ¼ä±ä»¯Èç±í£º

ʱ¼ä/s

0

1

2

3

4

5

n(NO2)/mol

0.040

0.020

0.010

0.005

0.005

0.005

ÓÃNO2±íʾ0~2sÄڸ÷´Ó¦µÄƽ¾ù·´Ó¦ËÙÂÊ____¡£ÔÚµÚ5sʱ£¬NO2µÄת»¯ÂÊΪ____¡£¸ù¾Ý±íÖпÉÒÔ¿´³ö£¬Ëæ×Å·´Ó¦½øÐУ¬·´Ó¦ËÙÂÊÖð½¥¼õС£¬ÆäÔ­ÒòÊÇ___¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

¡¾ÌâÄ¿¡¿CO2ÊÇ×ÔÈ»½ç̼ѭ»·ÖеÄÖØÒªÎïÖÊ¡£ÏÂÁйý³Ì»áÒýÆð´óÆøÖÐCO2º¬Á¿ÉÏÉýµÄÊÇ

A. ¹âºÏ×÷Óà B. ×ÔÈ»½µÓê

C. »¯Ê¯È¼ÁϵÄȼÉÕ D. ̼ËáÑεijÁ»ý

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸