ÏÖÓÐijÌú̼ºÏ½ð£¨ÌúºÍ̼Á½ÖÖµ¥ÖʵĻìºÏÎ£¬Ä³»¯Ñ§ÐËȤС×éΪÁ˲ⶨÌú̼ºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊý£¬²¢Ì½¾¿Å¨ÁòËáµÄijЩÐÔÖÊ£¬Éè¼ÆÁËÏÂͼËùʾµÄʵÑé×°Ö㨼гÖÒÇÆ÷ÒÑÊ¡ÂÔ£©ºÍʵÑé·½°¸½øÐÐʵÑé̽¾¿¡£
I.²â¶¨ÌúµÄÖÊÁ¿·ÖÊý£º
£¨1£©¼ì²éÉÏÊö×°ÖÃÆøÃÜÐÔµÄÒ»ÖÖ·½·¨ÊÇ£º¹Ø±Õ·ÖҺ©¶·µÄ»îÈû£¬ÔÚE×°ÖúóÃæÁ¬ÉÏÒ»¸ù
µ¼¹Ü£¬È»ºó________________________________________£¬ÔòÖ¤Ã÷×°ÖõÄÆøÃÜÐÔÁ¼ºÃ¡£
£¨2£©³ÆÁ¿EµÄÖÊÁ¿£¬²¢½«a gÌú̼ºÏ½ðÑùÆ··ÅÈë×°ÖÃAÖУ¬ÔÙ¼ÓÈë×ãÁ¿µÄŨÁòËᣬ´ýAÖв»ÔÙÒݳöÆøÌåʱ£¬Í£Ö¹¼ÓÈÈ£¬²ðÏÂE²¢³ÆÖØ£¬EÔöÖØbg¡£Ìú̼ºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊýΪ_____________________________________________£¨Ð´±í´ïʽ£©¡£
£¨3£©×°ÖÃCÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ________________________________________¡£
£¨4£©¼×ͬѧÈÏΪ£¬ÒÀ¾Ý´ËʵÑé²âµÃµÄÊý¾Ý£¬¼ÆËãºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊý¿ÉÄÜ»áÆ«µÍ£¬ÔÒòÊÇ¿ÕÆøÖÐCO2¡¢H2O½øÈëE¹ÜʹbÔö´ó¡£ÄãÈÏΪ¸Ä½øµÄ·½·¨ÊÇ____________________________________.
£¨5£©ÒÒͬѧÈÏΪ£¬¼´Ê¹¼×ͬѧÈÏΪµÄÆ«²îµÃµ½¸Ä½ø£¬ÒÀ¾Ý´ËʵÑé²âµÃºÏ½ðÖÐÌúµÄÖÊÁ¿·Ö
ÊýÒ²¿ÉÄÜ»áÆ«Àë¡£ÄãÈÏΪÆäÖеÄÔÒòÊÇ_________________________________________¡£
¢ò.̽¾¿Å¨ÁòËáµÄijЩÐÔÖÊ£º
£¨6£©ÍùAÖеμÓ×ãÁ¿µÄ¹öÁòËᣬδµãȼ¾Æ¾«µÆÇ°£¬A¡¢B¾ùÎÞÃ÷ÏÔÏÖÏó£¬ÆäÔÒòÊÇ£º
_____________________________________________________________________¡£
£¨7£©½«AÖйÌÌ廻Ϊ½ðÊôÍÔòÓëŨÁòËá·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ__________________
_______________________£¬·´Ó¦ÖÐŨÁòËá±íÏÖ³öµÄÐÔÖÊÊÇ______________________¡£
£¨1£©°Ñµ¼¹Ü·ÅÈëʢˮµÄË®²ÛÖУ¬Î¢ÈÈÉÕÆ¿£¬Èç¹ûµ¼¹Ü¿ÚÓÐÆøÅݲúÉú£¬Í£Ö¹¼ÓÈȺ󵼹ܿڲúÉúÒ»¶ÎÎȶ¨µÄË®Öù¡££¨2·Ö£©
£¨2£©(11a-3b)/11a¡Á100¨G£¨2·Ö£©
£¨3£©2MnO4-+5SO2+2H2O=2Mn2++5SO42-+4H+£¨2·Ö£©
£¨4£©ÔÚ×°ÖÃEµÄºó±ßÔÙÁ¬½ÓÒ»¸öÓëEÏàͬµÄ×°Öᣣ¨2·Ö£©
£¨5£©·´Ó¦²úÉúµÄCO2ÆøÌåδÄÜÍêÈ«Åŵ½×°ÖÃEÖУ¬µ¼ÖÂbÆ«µÍ¡£
£¨6£©³£ÎÂÏ£¬Ìú±»Å¨ÁòËá¶Û»¯£¬Ì¼²»ÓëŨÁòËá·´Ó¦¡££¨2·Ö£©
£¨7£© 2H2SO4(Ũ)+CuCuSO2+ SO2¡ü+2H2O; £¨2·Ö£© ËáÐÔºÍÇ¿Ñõ»¯ÐÔ£¨2·Ö£©
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©ÓÃ΢ÈÈ·¨¼ìÑéÃÜ·â×°ÖõÄÆøÃÜÐÔ¡£
£¨2£©EÔöÖØbg,ÊÇCO2µÄÖÊÁ¿£¬¿ÉÒÔ¼ÆËã̼µÄÖÊÁ¿3b/11g,ÌúµÄÖÊÁ¿ (a-3b/11)g, ÌúµÄÖÊÁ¿·ÖÊýΪ(11a-3b)/11a¡Á100¨G.
£¨3£©×°ÖÃCÖÐÊÇK MnO4ÈÜÒº£¬ÓÐÇ¿Ñõ»¯ÐÔ,ÄܺÍÓл¹ÔÐÔµÄSO2·´Ó¦£¬Àë×Ó·½³ÌʽΪ2MnO4-+5SO2+2H2O=2Mn2++5SO42-+4H+¡£
£¨4£©Îª·ÀÖ¹¿ÕÆøÖÐCO2¡¢H2O½øÈëE¹Ü£¬¿ÉÒÔÔÚEµÄºó±ßÔÙÁ¬½ÓÒ»¸öÓëEÏàͬµÄ×°Öã¬ÎüÊÕ¿ÕÆøÖÐCO2¡¢H2O¡£
£¨5£©·´Ó¦½áÊøºó£¬×°ÖÃÄÚ»¹ÓÐÉú³ÉµÄÆøÌå²ÐÁô¡£
£¨6£© ³£ÎÂÏ£¬Ìú±»Å¨ÁòËá¶Û»¯£¬Ì¼²»ÓëŨÁòËá·´Ó¦¡£
£¨7£© ÍÓëŨÁòËá¼ÓÈȵÄÌõ¼þÏ·¢Éú·´Ó¦£¬Éú³ÉCuSO2ºÍ SO2¡£
¿¼µã£ºÅ¨ÁòËáµÄÐÔÖÊ£»Í¨¹ýʵÑéÀ´²â¶¨ÎïÖʵĴ¿¶È¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºÓ±±Ê¡¸ßÈýÉÏѧÆÚµÚÈý´ÎÔ¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ
£¨12·Ö£©ÏÖÓÐijÌú̼ºÏ½ð£¬Ä³»¯Ñ§ÐËȤС×éΪÁ˲ⶨÌú̼ºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊý£¬²¢Ì½¾¿Å¨ÁòËáµÄijЩÐÔÖÊ£¬Éè¼ÆÁËÏÂͼËùʾµÄʵÑé×°ÖúÍʵÑé·½°¸£¨¼Ð³ÖÒÇÆ÷ÒÑÊ¡ÂÔ£©£¬ÇëÄã²ÎÓë´ËÏî»î¶¯²¢»Ø´ðÏàÓ¦ÎÊÌâ¡£
¢ñ ̽¾¿Å¨ÁòËáµÄijЩÐÔÖÊ£º
¢Å°´Í¼Ê¾µÄÁ¬½Ó×°Ö㬼ì²é×°ÖõÄÆøÃÜÐÔ£¬³ÆÁ¿EµÄÖÊÁ¿¡£
¢Æ½«a gÌú̼ºÏ½ðÑùÆ··ÅÈëAÖУ¬ÔÙ¼ÓÈëÊÊÁ¿µÄŨÁòËá¡£ÒÇÆ÷AµÄÃû³ÆΪ________¡£Î´µãȼ¾Æ¾«µÆÇ°£¬A¡¢B¾ùÎÞÃ÷ÏÔÏÖÏó£¬ÆäÔÒòÊÇ£º_____________________________¡£
¢Çµãȼ¾Æ¾«µÆÒ»¶Îʱ¼äºó£¬A¡¢BÖпɹ۲쵽Ã÷ÏÔµÄÏÖÏó¡£Ð´³öAÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ________________________________£¨Ö»Ð´Ò»¸ö£©¡£BÖеÄÏÖÏóÊÇ______________,Óɴ˿ɵõ½Å¨ÁòËá¾ßÓÐ____________ÐÔ¡£
¢ÈËæ×Å·´Ó¦µÄ½øÐУ¬AÖл¹¿ÉÄÜ·¢ÉúijЩÀë×Ó·´Ó¦¡£Ð´³öÏàÓ¦µÄÀë×Ó·½³Ìʽ______________£¨Ö»Ð´Ò»¸ö£©¡£
¢É·´Ó¦Ò»¶Îʱ¼äºó£¬´ÓAÖÐÒݳöÆøÌåµÄËÙÂÊÈÔÈ»½Ï¿ì£¬³ýÒòζȽϸߣ¬·´Ó¦·ÅÈÈÍ⣬»¹¿ÉÄܵÄÔÒòÊÇ_____________________________________¡£
¢ò ²â¶¨ÌúµÄÖÊÁ¿·ÖÊý£º
¢Ê´ýAÖв»ÔÙÒݳöÆøÌåʱ£¬Í£Ö¹¼ÓÈÈ£¬²ðÏÂE²¢³ÆÖØ¡£EÔöÖØb g¡£Ìú̼ºÏ½ðÖÐÌúµÄÖÊÁ¿·ÖÊýΪ_____________________£¨Ð´±í´ïʽ£©¡£
¢ËijͬѧÈÏΪÉÏÊö·½·¨½Ï¸´ÔÓ£¬Ê¹ÓÃÏÂͼËùʾµÄ×°ÖúÍÆäËü³£ÓÃʵÑéÒÇÆ÷²â¶¨Ä³Ð©Êý¾Ý¼´¿É¡£
ΪÁË¿ìËÙºÍ׼ȷµÄ¼ÆËã³öÌúµÄÖÊÁ¿·ÖÊý£¬×î¼ò±ãµÄʵÑé²Ù×÷ÊÇ__________£¨Ìîд´úºÅ£©¡£
A£®ÓÃÅÅË®·¨²â¶¨H2µÄÌå»ý
B£®·´Ó¦½áÊøºó£¬¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿²ÐÔüµÄÖÊÁ¿
C£®²â¶¨·´Ó¦Ç°ºó×°ÖúÍÒ©Æ·µÄ×ÜÖÊÁ¿¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com