¶ÌÖÜÆÚÔªËØX¡¢Y¡¢Z¡¢W µÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÇÒÔ­×Ó×îÍâ²ãµç×ÓÊýÖ®ºÍΪ13¡£X µÄ

Ô­×Ӱ뾶±ÈY µÄС£¬X ÓëW ͬÖ÷×壬Z ÊǵؿÇÖк¬Á¿×î¸ßµÄÔªËØ¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨    £©

     A£®Ô­×Ӱ뾶µÄ´óС˳Ðò: r(Y)>r(Z)>r(W)

     B£®ÔªËØZ¡¢W µÄ¼òµ¥Àë×ӵĵç×Ó²ã½á¹¹²»Í¬

     C£®ÔªËØY µÄ¼òµ¥Æø̬Ç⻯ÎïµÄÈÈÎȶ¨ÐÔ±ÈZ µÄÇ¿

     D£®Ö»º¬X¡¢Y¡¢Z ÈýÖÖÔªËصĻ¯ºÏÎ¿ÉÄÜÊÇÀë×Ó»¯ºÏÎҲ¿ÉÄÜÊǹ²¼Û»¯ºÏÎï

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÓÒͼ±íʾ4£­äå»·¼ºÏ©Ëù·¢ÉúµÄ4¸ö²»Í¬·´Ó¦£®ÆäÖУ¬²úÎïÖ»

º¬ÓÐÒ»ÖÖ¹ÙÄÜÍŵķ´Ó¦ÊÇ

A£®¢Ù¢Ü¡¡¡¡¡¡       B£®¢Ú¢Û        C£®¢Ù¢Ú¡¡¡¡¡¡        D£®¢Û¢Ü

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔªËØÖÜÆÚ±íÖеڢ÷A×åÔªËصĵ¥Öʼ°Æ仯ºÏÎïµÄÓÃ;¹ã·º¡£

(1)ÓëÂÈÔªËØͬ×åµÄ¶ÌÖÜÆÚÔªËصÄÔ­×ӽṹʾÒâͼΪ_________¡£

(2)ÄÜ×÷ΪÂÈ¡¢äå¡¢µâÔªËطǽðÊôÐÔ(Ô­×ӵõç×ÓÄÜÁ¦)µÝ±ä¹æÂɵÄÅжÏÒÀ¾ÝÊÇ________(ÌîÑ¡Ïî×Öĸ)¡£

a£®Cl2¡¢Br2¡¢I2µÄÈÛµã

b£®Cl2¡¢Br2¡¢I2µÄÑõ»¯ÐÔ

c£®HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔ

d£®HCl¡¢HBr¡¢HIµÄËáÐÔ

(3)¹¤ÒµÉÏ£¬Í¨¹ýÈçÏÂת»¯¿ÉÖƵÃKClO3¾§Ì壺

NaClÈÜÒºNaClO3ÈÜÒºKClO3¾§Ìå

¢ÙÍê³É¢ñÖз´Ó¦µÄ×Ü»¯Ñ§·½³Ìʽ£ºNaCl£«H2O===NaClO3£«________¡£

¢Ú¢òÖÐת»¯µÄ»ù±¾·´Ó¦ÀàÐÍÊÇ__________£¬¸Ã·´Ó¦¹ý³ÌÄÜÎö³öKClO3¾§Ìå¶øÎÞÆäËû¾§ÌåÎö³öµÄÔ­ÒòÊÇ_________________¡£

(4)Ò»¶¨Ìõ¼þÏ£¬ÔÚË®ÈÜÒºÖÐ1 mol Cl£­¡¢ClO(x£½1,2,3,4)µÄÄÜÁ¿(kJ)Ïà¶Ô´óСÈçͼËùʾ¡£

¢ÙDÊÇ________(ÌîÀë×Ó·ûºÅ)¡£

¢ÚB¨D¡úA£«C·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ_______________________(ÓÃÀë×Ó·ûºÅ±íʾ)¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÔÏÂÓйØÔªËØÐÔÖʵÄ˵·¨²»ÕýÈ·µÄÊÇ                                        (¡¡¡¡)

A£®¾ßÓÐÏÂÁеç×ÓÅŲ¼Ê½µÄÔ­×ÓÖУ¬¢Ù1s22s22p63s23p2

¢Ú1s22s22p3¡¡¢Û1s22s22p2¡¡¢Ü1s22s22p63s23p4¡¡Ô­×Ӱ뾶×î´óµÄÊÇ¢Ù

B£®¾ßÓÐÏÂÁÐ×îÍâ²ãµç×ÓÅŲ¼Ê½µÄÔ­×ÓÖУ¬¢Ù3s23p1¡¡¢Ú3s23p2¡¡¢Û3s23p3¡¡¢Ü3s23p4µÚÒ»µçÀëÄÜ×î´óµÄÊÇ¢Û

C£®¢ÙNa¡¢K¡¢Rb¡¡¢ÚN¡¢P¡¢As¡¡¢ÛO¡¢S¡¢Se¡¡¢ÜNa¡¢P¡¢Cl£¬ÔªËصĵ縺ÐÔËæÔ­×ÓÐòÊýÔö´ó¶øµÝÔöµÄÊÇ¢Ü

D£®Ä³ÔªËØÆø̬»ù̬ԭ×ÓµÄÖ𼶵çÀëÄÜ·Ö±ðΪ738¡¢1 451¡¢7 733¡¢10 540¡¢13 630¡¢17 995¡¢21 703£¬µ±ËüÓëÂÈÆø·´Ó¦Ê±¿ÉÄÜÉú³ÉµÄÑôÀë×ÓÊÇX3£«

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÏÂÁÐÓйØÎïÖÊÐÔÖʵÄ˵·¨´íÎóµÄÊÇ

A£®ÈÈÎȶ¨ÐÔ£ºHCl> HI          B£®Ô­×Ӱ뾶£ºNa> Mg

C£®ËáÐÔ£ºH2SO3>H2SO4¡£        D£®½áºÏÖÊ×ÓÄÜÁ¦£ºS2-> Cl-

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


X¡¢Y¾ùΪԪËØÖÜÆÚ±íÖÐÇ°20ºÅÔªËØ£¬Æä¼òµ¥Àë×ӵĵç×Ó²ã½á¹¹Ïàͬ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ

A£®X2£­µÄ»¹Ô­ÐÔÒ»¶¨´óÓÚY£­

B£®ÓÉmXa£«ÓënYb£­µÃm£«a£½n£­b

C£®X¡¢YÒ»¶¨²»ÊÇͬÖÜÆÚÔªËØ

D£®ÈôXµÄÔ­×Ӱ뾶´óÓÚY£¬ÔòÆø̬Ç⻯ÎïµÄÎȶ¨ÐÔÒ»¶¨ÊÇX´óÓÚY

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÔÚÒ»¶¨Ìõ¼þÏ£¬ÍêÈ«·Ö½âÏÂÁÐij»¯ºÏÎï2 g£¬²úÉúÑõÆø1.6 g£¬´Ë»¯ºÏÎïÊÇ¡¡¡¡

A£®1H216O       B£®2H216O       C£®1H218O       D£®1H218O  

   

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


ÒÑÖªA¡¢B¡¢C¡¢D¾ùΪ¶ÌÖÜÆÚÔªËØ£¬ËüÃǵÄÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£AÊÇÔ­×Ó×îÍâ²ãÓÐÒ»¸öµç×ӵķǽðÊôÔª

ËØ£¬CÔ­×ÓµÄ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3±¶£»CºÍD¿ÉÐγÉÁ½ÖÖ¹Ì̬»¯ºÏÎÆäÖÐÒ»ÖÖΪµ­»ÆÉ«¹Ì

Ì壻BºÍC¿ÉÐγɶàÖÖÆø̬»¯ºÏÎï¡£A¡¢B¡¢CÈýÖÖÔªËØ¿ÉÐγÉÀë×Ó»¯ºÏÎ¸Ã»¯ºÏÎïÖи÷ÔªËØÔ­×ÓµÄÎïÖÊ

µÄÁ¿Ö®±ÈΪn(A)¡Ãn(B)¡Ãn(C)£½4¡Ã2¡Ã3¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ð´³öCºÍDÐγɵĵ­»ÆÉ«¹ÌÌ廯ºÏÎïµÄµç×Óʽ£º____________________________¡£

£¨2£©¸÷ÔªËØÔ­×ÓµÄÎïÖʵÄÁ¿Ö®±ÈΪn(A)¡Ãn(B)¡Ãn(C)£½4¡Ã2¡Ã3µÄ»¯ºÏÎïµÄÃû³ÆΪ________£¬ÆäË®ÈÜÒº³Ê________ÐÔ¡£

£¨3£©Çëд³öÓëA2CºÍBA3·Ö×ÓÖеç×ÓÊýÏàͬ£¬ÇÒÈÔÓÉA¡¢B¡¢CÔªËØÖÐÈÎÒâÁ½ÖÖÔªËØ×é³ÉµÄÁ£×ӵķûºÅ(¾ÙÁ½Àý)_________________________¡¢________¡£

£¨4£©Ð´³öÓÉB¡¢CÔªËØ×é³ÉµÄÔªËØÔ­×ÓÖÊÁ¿±ÈΪn(B)¡Ãn(C)£½7¡Ã12µÄ»¯ºÏÎïµÄ»¯Ñ§Ê½________________________________________________________________________¡£

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º


¢ñ£®£¨12·Ö£©ÏÖÓÐÏÂÁÐÎïÖÊ£º¢ÙHNO3¡¡¢Ú±ù´×Ëá¡¡¢Û°±Ë®¡¡¢ÜAl(OH)3¡¡¢ÝNaHCO3(s)¡¡¢ÞCu¡¡¢ßÂÈË®¡¡¢àCaCO3   ¢áH2CO3  ¢âÑÎËá

£¨1£©ÉÏÊöÎïÖÊÖÐÊôÓÚÇ¿µç½âÖʵÄÓÐ________£¬ÊôÓÚÈõµç½âÖʵÄÓÐ________¡£

£¨2£©Ð´³öÏÂÁÐÎïÖʵĵçÀë·½³Ìʽ£º

¢Ú¡¢______________________£»¢Ü¡¢______________________£»

¢Ý¡¢______________________£»¢á¡¢                      ¡£

¢ò£®£¨4·Ö£©»¯Ñ§·´Ó¦4A(s)£«3B(g) 2C(g)£«D(g)¾­10 minCµÄŨ¶ÈÔö¼Ó0.6 mol/L¡£

£¨1£©ÓÃB±íʾµÄ·´Ó¦ËÙÂÊÊÇ________      ¡£

£¨2£©·Ö±ðÓÃB¡¢C¡¢D±íʾµÄ·´Ó¦ËÙÂÊÆä±ÈÖµÊÇ________         ¡£

¢ó£®£¨8·Ö£©Íê³ÉÏÂÁÐÎÊÌ⣺

£¨1£©ÆûÓ͵ÄÖØÒª³É·ÖÊÇÐÁÍ飨C8H18£©£¬1molC8H18£¨l£©ÔÚÓëO2£¨g£©ÖÐȼÉÕ£¬Éú³ÉCO2£¨g£©ºÍH2O£¨l£©£¬·Å³ö5518KJÈÈÁ¿£¬¸Ã·´Ó¦ÈÈ»¯Ñ§·½³ÌʽΪ£º

                                                                ¡£

£¨2£©ÒÑÖª½ð¸ÕʯºÍʯī·Ö±ðÔÚÑõÆøÖÐÍêȫȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ£º

C£¨½ð¸Õʯ¡¢s)£«O2(g)£½CO2(g)   ¡÷H£½£­395.41kJ/mol

C£¨Ê¯Ä«¡¢s£©£«O2(g)£½CO2(g)  ¡÷H£½£­393.51kJ/mol

Ôòʯīת»¯Îª½ð¸ÕʯµÄÈÈ»¯Ñ§·½³ÌʽΪ£º________                  £¬ÓÉ´Ë¿´À´½ð¸ÕʯµÄÎȶ¨ÐÔ    £¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±¡¢¡°²»È·¶¨¡±£©Ê¯Ä«µÄÎȶ¨ÐÔ¡£

£¨3£©·¢ÉäÎÀÐÇÓÃN2H4ΪȼÁÏ£¬NO2ΪÑõ»¯¼Á£¬Á½Õß·´Ó¦¡£ÒÑÖª£º

N2(g) £«2O2(g) £½2NO2(g)              ¨SH£½67.7kJ/mol

N2H4(g) £«O2(g) £½ N2(g) £«2H2O(g)    ¨SH£½£­534kJ/mol

H2 O (l) £½H2O (g)                     ¦¤H£½44 kJ/mol

1molN2H4(g)Óë NO2£¨g£©ÍêÈ«·´Ó¦Éú³ÉN2ºÍH2 O (l)ʱ·Å³öÈÈÁ¿Îª              ¡£

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸