²â¶¨Na2S2O3·5H2O²úÆ·´¿¶È
׼ȷ³ÆÈ¡W g Na2S2O3·5H2O²úÆ·£¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣬ÒÔµí·Û×÷ָʾ¼Á£¬ÓÃ0.100 0 mol·L£1µâµÄ±ê×¼ÈÜÒºµÎ¶¨¡£
·´Ó¦ÔÀíΪ2S2O£«I2===S4O£«2I£
(5)µÎ¶¨ÖÁÖÕµãʱ£¬ÈÜÒºÑÕÉ«µÄ±ä»¯£º___________________________¡£
(6)²â¶¨ÆðʼºÍÖÕµãµÄÒºÃæλÖÃÈçͼ£¬ÔòÏûºÄµâµÄ±ê×¼ÈÜÒºÌå»ýΪ________mL¡£²úÆ·µÄ´¿¶ÈΪ(ÉèNa2S2O3·5H2OÏà¶Ô·Ö×ÓÖÊÁ¿ÎªM)________¡£
´ð°¸¡¡(5)ÓÉÎÞÉ«±äÀ¶É«
(6)18.10¡¡¡Á100%
½âÎö¡¡(5)Óõí·Û×÷ָʾ¼Á£¬´ïµ½ÖÕµãʱµÄÏÖÏóÊÇÈÜÒºÓÉÎÞÉ«±äΪÀ¶É«¡£
(6)¸ù¾Ýͼʾ£ºµÎ¶¨¹ÜµÄ¶ÁÊýÐèÒª±£Áô2λСÊý£¬ËùÒÔÏûºÄµâµÄ±ê×¼ÈÜÒºµÄÌå»ýΪ18.10 mL¡£
¸ù¾Ý2S2O£«I2===S4O£«2I£Öª£ºn(S2O)£½2n(I2)£½0.100 0 mol·L£1¡Á18.10 mL¡Á10£3 L·mL£1¡Á2£½3.620¡Á10£3 mol¡£²úÆ·µÄ´¿¶ÈΪ3.620¡Á10£3 mol¡ÁM/W¡Á100%£½¡Á100%¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¼×ͬѧÈÏΪ£¬ÔÚË®ÖмÓÈëH2SO4£¬Ë®µÄµçÀëƽºâÏò×óÒƶ¯£¬½âÊÍÊǼÓÈëH2SO4ºóc(H£«)Ôö´ó£¬Æ½ºâ×óÒÆ¡£ÒÒͬѧÈÏΪ£¬¼ÓÈëH2SO4ºó£¬Ë®µÄµçÀëƽºâÏòÓÒÒƶ¯£¬½âÊÍΪ¼ÓÈëH2SO4ºó£¬c(H£«)Ũ¶ÈÔö´ó£¬H£«ÓëOH£Öкͣ¬Æ½ºâÓÒÒÆ¡£ÄãÈÏΪÄÄÖÖ˵·¨ÕýÈ·£¿²¢ËµÃ÷ÔÒò¡£Ë®µÄµçÀëƽºâÒƶ¯ºó£¬ÈÜÒºÖÐc(H£«)·c(OH£)ÊÇÔö´ó»¹ÊǼõС£¿
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÒÑ֪ijζÈÏÂCH3COOHµÄµçÀë³£ÊýK£½1.6¡Á10£5¡£¸ÃζÈÏ£¬Ïò20 mL 0.01 mol·L£1 CH3COOHÈÜÒºÖÐÖðµÎ¼ÓÈë0.01 mol·L£1 KOHÈÜÒº£¬ÆäpH±ä»¯ÇúÏßÈçͼËùʾ(ºöÂÔζȱ仯)¡£Çë»Ø´ðÏÂÁÐÓйØÎÊÌ⣺
(1)aµãÈÜÒºÖÐc(H£«)Ϊ________£¬pHԼΪ________¡£
(2)a¡¢b¡¢c¡¢dËĵãÖÐË®µÄµçÀë³Ì¶È×î´óµÄÊÇ________£¬µÎ¶¨¹ý³ÌÖÐÒËÑ¡ÓÃ__________×÷ָʾ¼Á£¬µÎ¶¨ÖÕµãÔÚ________(Ìî¡°cµãÒÔÉÏ¡±»ò¡°cµãÒÔÏ¡±)¡£
(3)ÈôÏò20 mLÏ¡°±Ë®ÖÐÖðµÎ¼ÓÈëµÈŨ¶ÈµÄÑÎËᣬÔòÏÂÁб仯Ç÷ÊÆÕýÈ·µÄÊÇ________(Ìî×Öĸ)¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂͼ±íʾˮÖÐc(H£«)ºÍc(OH£)µÄ¹Øϵ£¬ÏÂÁÐÅжϴíÎóµÄÊÇ (¡¡¡¡)
A£®Á½ÌõÇúÏß¼äÈÎÒâµã¾ùÓÐc(H£«)¡Ác(OH£)£½Kw
B£®MÇøÓòÄÚÈÎÒâµã¾ùÓÐc(H£«)£¼c(OH£)
C£®Í¼ÖÐT1£¼T2
D£®XZÏßÉÏÈÎÒâµã¾ùÓÐpH£½7
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
0.1 mol·L£1ij¼îAOHÈÜÒºµÄpH£½11£¬½«¸ÃÈÜҺϡÊÍ10±¶ºó£¬ÈÜÒºµÄpH²»¿ÉÄÜΪ(¡¡¡¡)
¢Ù10.1 ¢Ú10.8 ¢Û12 ¢Ü11.5
A£®¢Û¢Ü B£®¢Ù¢Ú
C£®¢Ù¢Û D£®¢Ú¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ijУ»¯Ñ§ÐËȤС×éµÄͬѧ¶ÔÒ»º¬ÓÐÉÙÁ¿Na2SO4µÄNaOHÑùÆ·ÖÐNaOHµÄº¬Á¿½øÐвⶨ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)¼×ͬѧÔËÓóÁµí·¨²â¶¨ÑùÆ·ÖÐNaOHµÄº¬Á¿¡£¸ÃͬѧѡÓõÄÒ©Æ·³ýÑùÆ·Í⣬»¹Ó¦ÓÐ________£»ÊµÑéÖÐÓ¦²â¶¨µÄÊý¾ÝÓÐ________¡£
(2)ÒÒͬѧÔËÓõζ¨·¨²â¶¨ÑùÆ·ÖÐNaOHµÄº¬Á¿¡£
¢ÙÓ÷ÖÎöÌìƽ׼ȷ³ÆÈ¡¸ÃÑùÆ·5.000 0 g£¬È«²¿ÈÜÓÚË®ÅäÖƳÉ1 000.0 mLÈÜÒº¡£ÓüîʽµÎ¶¨¹ÜÁ¿È¡20.00 mLËùÅäÈÜÒº·ÅÔÚ׶ÐÎÆ¿ÖУ¬µÎ¼Ó¼¸µÎָʾ¼Á£¬´ý²â¡£µÎ¶¨¹ÜÔÚʹÓÃÇ°³ýÏ´µÓÍ⣬»¹Ó¦____________________________________¡£
¢ÚÓÃŨ¶ÈΪ0.100 0 mol·L£1µÄÑÎËá±ê×¼ÈÜÒº½øÐеζ¨¡£¿ªÊ¼µÎ¶¨Ç°µÄÒ»²½²Ù×÷ÊÇ________¡£
¢ÛµÎ¶¨¹ý³ÌÖÐÓÃpH¼Æ²â¶¨×¶ÐÎÆ¿ÖÐÈÜÒºµÄpH£¬ÁÙ½üµÎ¶¨ÖÕµãʱ²â¶¨pHӦÿµÎÒ»µÎ²âÒ»´Î¡£
¢ÜµÎ¶¨¹ý³ÌÖУ¬×¶ÐÎÆ¿ÖÐÈÜÒºµÄpH±ä»¯ÈçÏ£º
V(HCl)/mL | 0.00 | 12.00 | 18.00 | 22.00 | 23.00 | 23.96 | 24.00 | 24.04 | 25.00 | 26.00 | 30.00 |
pH | 13.1 | 12.6 | 12.2 | 11.7 | 11.4 | 9.9 | 7.0 | 4.0 | 2.7 | 2.4 | 1.9 |
ÇëÔÚ×ø±êͼÖлæÖƳöÉÏÊöÖк͵樵ÄÇúÏß¡£
¢ÝÈç±íËùʾÊǼ¸ÖÖËá¼îָʾ¼ÁµÄ±äÉ«·¶Î§£¬¸ù¾ÝÄãËù×÷µÄÖк͵ζ¨ÇúÏß·ÖÎö£¬ÉÏÊöÖк͵ζ¨ÖÐӦѡÓõÄָʾ¼ÁÊÇ________¡£
ָʾ¼Á | ±äÉ«·¶Î§(pH) | ÑÕÉ« | |
Ëá | ¼î | ||
¼×»ù³È | 3.1¡«4.4 | ºì | »Æ |
ʯÈï | 5.0¡«8.0 | ºì | À¶ |
·Ó̪ | 8.2¡«10.0 | ÎÞ | ºì |
¢ÞÑùÆ·ÖУ¬NaOHµÄÖÊÁ¿°Ù·Öº¬Á¿Îª____________¡£
´ð°¸¡¡(1)MgCl2ÈÜÒº¡¡ÑùÆ·ÖÊÁ¿ºÍ¼ÓÈë×ãÁ¿MgCl2ÈÜÒººóÉú³ÉµÄ³ÁµíÖÊÁ¿
(2)¢Ù¼ì©¡¢ÈóÏ´¡¡¢Úµ÷½ÚÊ¢±ê×¼ÒºµÄµÎ¶¨¹ÜµÄÒºÃæÓÚ¡°0¡±¿Ì¶È»ò¡°0¡±¿Ì¶ÈÒÔÏÂ
¢ÜµÎ¶¨ÇúÏßÈçͼËùʾ
¢Ý¼×»ù³È»ò·Ó̪¡¡¢Þ96%
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
¸ù¾ÝÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺
A.µÚÒ»µçÀëÄÜI1ÊÇÖ¸Æø̬Ô×ÓX(g)´¦ÓÚ»ù̬ʱ£¬Ê§È¥Ò»¸öµç×Ó³ÉΪÆø̬ÑôÀë×ÓX£«(g)ËùÐèµÄ×îµÍÄÜÁ¿¡£ÏÂͼÊDz¿·ÖÔªËØÔ×ӵĵÚÒ»µçÀëÄÜI1ËæÔ×ÓÐòÊý±ä»¯µÄÇúÏßͼ(ÆäÖÐ12ºÅÖÁ17ºÅÔªËصÄÓйØÊý¾Ýȱʧ)¡£
B.²»Í¬ÔªËصÄÔ×ÓÔÚ·Ö×ÓÄÚÎüÒýµç×ÓµÄÄÜÁ¦´óС¿ÉÓÃÊýÖµ±íʾ£¬¸ÃÊýÖµ³ÆΪµç¸ºÐÔ¡£Ò»°ãÈÏΪ£ºÈç¹ûÁ½¸ö³É¼üÔ×Ó¼äµÄµç¸ºÐÔ²îÖµ´óÓÚ1.7£¬Ô×ÓÖ®¼äͨ³£ÐγÉÀë×Ó¼ü£»Èç¹ûÁ½¸ö³É¼üÔ×Ó¼äµÄµç¸ºÐÔ²îֵСÓÚ1.7£¬Í¨³£Ðγɹ²¼Û¼ü¡£Ï±íÊÇijЩԪËصĵ縺ÐÔÖµ£º
ÔªËØ·ûºÅ | Li | Be | B | C | O | F | Na | Al | Si | P | S | Cl |
µç¸ºÐÔÖµ | 1.0 | 1.5 | 2.0 | 2.5 | 3.5 | 4.0 | 0.9 | 1.5 | 1.8 | 2.1 | 2.5 | 3.0 |
(1)ÈÏÕæ·ÖÎöÐÅÏ¢AͼÖÐͬÖÜÆÚÔªËصÚÒ»µçÀëÄܵı仯¹æÂÉ£¬ÍƶϵÚÈýÖÜÆÚNa¡«ArÕ⼸ÖÖÔªËØÖУ¬AlµÄµÚÒ»µçÀëÄܵĴóС·¶Î§Îª______£¼Al£¼______(ÌîÔªËØ·ûºÅ)¡£
(2)´ÓÐÅÏ¢AͼÖзÖÎö¿ÉÖª£¬Í¬Ò»Ö÷×åÔªËØÔ×ӵĵÚÒ»µçÀëÄÜI1µÄ±ä»¯¹æÂÉÊÇ________________¡£
(3)ÐÅÏ¢AͼÖеÚÒ»µçÀëÄÜ×îСµÄÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ________ÖÜÆÚ________×å¡£
(4)¸ù¾Ý¶Ô½ÇÏß¹æÔò£¬Be¡¢AlÔªËØ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄÐÔÖÊÏàËÆ£¬ËüÃǶ¼¾ßÓÐ________ÐÔ£¬ÆäÖÐBe(OH)2ÏÔʾÕâÖÖÐÔÖʵÄÀë×Ó·½³ÌʽÊÇ________________________________________________________________________¡£
(5)ͨ¹ý·ÖÎöµç¸ºÐÔÖµµÄ±ä»¯¹æÂÉ£¬È·¶¨MgÔªËصĵ縺ÐÔÖµµÄ×îС·¶Î§________________¡£
(6)Çë¹éÄÉÔªËصĵ縺ÐԺͽðÊôÐÔ¡¢·Ç½ðÊôÐԵĹØϵÊÇ________________¡£
(7)´Óµç¸ºÐԽǶȣ¬ÅжÏAlCl3ÊÇÀë×Ó»¯ºÏÎﻹÊǹ²¼Û»¯ºÏÎ˵³öÀíÓɲ¢Ð´³öÅжϵķ½·¨________________________________________________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
ÏÂÁйØÓÚ»¯Ñ§¼üµÄ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®¹¹³Éµ¥ÖÊ·Ö×ÓµÄÁ£×ÓÖÐÒ»¶¨º¬Óй²¼Û¼ü
B£®ÓɷǽðÊôÔªËØ×é³ÉµÄ»¯ºÏÎï²»Ò»¶¨Êǹ²¼Û»¯ºÏÎï
C£®·Ç¼«ÐÔ¼üÖ»´æÔÚÓÚË«Ô×Óµ¥ÖÊ·Ö×ÓÀï
D£®²»Í¬ÔªËØ×é³ÉµÄ¶àÔ×Ó·Ö×ÓÖеĻ¯Ñ§¼üÒ»¶¨ÊǼ«ÐÔ¼ü
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com