·´Ó¦aM(g£©£«bN(g£©cP(g£©£«d Q(g£©´ïµ½Æ½ºâʱ£¬MµÄÌå»ý·ÖÊýy(M£©Óë·´Ó¦Ìõ¼þµÄ¹ØϵÈçͼËùʾ¡£ÆäÖÐz ±íʾ·´Ó¦¿ªÊ¼Ê±NµÄÎïÖʵÄÁ¿ÓëMµÄÎïÖʵÄÁ¿Ö®±È¡£ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊÇ£¨ £©
A£®Í¬ÎÂͬѹͬzʱ£¬¼ÓÈë´ß»¯¼Á£¬Æ½ºâʱQµÄÌå»ý·ÖÊý²»¸Ä±ä
B£®Í¬ÎÂͬѹʱ£¬Ôö¼Óz£¬Æ½ºâʱQµÄÌå»ý·ÖÊýÒ»¶¨Ôö¼Ó
C£®Í¬ÎÂͬzʱ£¬Ôö¼Óѹǿ£¬Æ½ºâʱQµÄÌå»ý·ÖÊýÒ»¶¨¼õС
D£®Í¬Ñ¹Í¬zʱ£¬Éý¸ßζȣ¬Æ½ºâʱQµÄÌå»ý·ÖÊýÒ»¶¨Ôö¼Ó
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓÄÏÊ¡ÄÏÑôÊи߶þÉϵڶþ´ÎÔ¿¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÌî¿ÕÌâ
COÊÇÏÖ´ú»¯¹¤Éú²úµÄ»ù´¡ÔÁÏ£¬ÏÂÁÐÓйØÎÊÌⶼºÍCOµÄʹÓÃÓйء£
£¨1£© ¹¤ÒµÉÏ¿ÉÀûÓÃCOÉú²úÒÒ´¼:
2CO£¨g£©£«4H2£¨g£©CH3CH2OH£¨g£©£«H2O£¨g£© ¦¤H1
ÓÖÒÑÖª£ºH2O£¨l£©=== H2O£¨g£© ¦¤H2
CO£¨g£©£«H2O£¨g£© CO2£¨g£©£«H2£¨g£© ¦¤H3
¹¤ÒµÉÏÒ²¿ÉÀûÓÃCO2£¨g£©ÓëH2£¨g£©ÎªÔÁϺϳÉÒÒ´¼£º
2CO2£¨g£©£«6H2£¨g£© CH3CH2OH£¨g£©£«3H2O£¨l£© ¦¤H
Ôò£º¦¤HÓ릤H1¡¢¦¤H2¡¢¦¤H3Ö®¼äµÄ¹ØϵÊÇ£º¦¤H£½___________________¡£
£¨2£©Ò»¶¨Ìõ¼þÏ£¬H2¡¢COÔÚÌå»ý¹Ì¶¨µÄÃܱÕÈÝÆ÷Öз¢ÉúÈçÏ·´Ó¦£º
4H2£¨g£©+2CO£¨g£©CH3OCH3£¨g£©+H2O£¨g£©£¬ÏÂÁÐÑ¡ÏîÄÜÅжϸ÷´Ó¦´ïµ½Æ½ºâ״̬µÄÒÀ¾ÝµÄÓÐ___ ¡£
A£®2v£¨H2£©= v£¨CO£©
B£®COµÄÏûºÄËÙÂʵÈÓÚCH3OCH3µÄÉú³ÉËÙÂÊ
C£®ÈÝÆ÷ÄÚµÄѹǿ±£³Ö²»±ä
D£®»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä
E£®»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»Ëæʱ¼ä¶ø±ä»¯
£¨3£©¹¤Òµ¿É²ÉÓÃCOÓëH2·´Ó¦ºÏ³ÉÔÙÉúÄÜÔ´¼×´¼£¬·´Ó¦ÈçÏÂ:
CO£¨g£©+ 2H2£¨g£©CH3OH£¨g£©ÔÚÒ»ÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖгäÓÐ10molCOºÍ20molH2£¬ÔÚ´ß»¯¼Á×÷ÓÃÏ·¢Éú·´Ó¦Éú³É¼×´¼¡£COµÄƽºâת»¯ÂÊ£¨¦Á£©Óëζȣ¨T£©¡¢Ñ¹Ç¿£¨p£©µÄ¹ØϵÈ磨ͼ1£©Ëùʾ¡£
¢ÙºÏ³É¼×´¼µÄ·´Ó¦Îª £¨Ìî¡°·ÅÈÈ¡±»ò¡°ÎüÈÈ¡±£©·´Ó¦¡£
¢ÚA¡¢B¡¢CÈýµãµÄƽºâ³£ÊýKA¡¢KB¡¢KCµÄ´óС¹ØϵΪ ¡£
¢ÛÈô´ïµ½Æ½ºâ״̬Aʱ£¬ÈÝÆ÷µÄÌå»ýΪ10L£¬ÔòÔÚƽºâ״̬BʱÈÝÆ÷µÄÌå»ýΪ_________L¡£
¢Ü£¨Í¼2£©ÖÐÐéÏßΪ¸Ã·´Ó¦ÔÚʹÓô߻¯¼ÁÌõ¼þϹØÓÚÆðʼÇâÆøÓëCOͶÁϱȺÍCOƽºâת»¯ÂʵĹØϵͼ£® µ±ÆäÌõ¼þÍêÈ«Ïàͬʱ£¬ÓÃʵÏß»³ö²»Ê¹Óô߻¯¼ÁÇé¿öÏÂCOƽºâת»¯ÂʵÄʾÒâͼ£®
¢ÝCOµÄƽºâת»¯ÂÊ£¨¦Á£©Óëζȣ¨T£©¡¢Ñ¹Ç¿£¨p£©µÄ¹ØϵÈ磨ͼ3£©Ëùʾ£¬Êµ¼ÊÉú²úʱÌõ¼þ¿ØÖÆÔÚ250 ¡æ¡¢ 1.3¡Á104 kPa×óÓÒ£¬Ñ¡Ôñ´ËѹǿµÄÀíÓÉÊÇ__________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓÄÏÊ¡ÄÏÑôÊи߶þÉϵڶþ´ÎÔ¿¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÏàͬζÈÏ£¬Ìå»ý¾ùΪ1.5 LµÄÁ½¸öºãÈÝÈÝÆ÷Öз¢Éú¿ÉÄæ·´Ó¦£ºX2 (g£©+3Y2(g£© 2XY3(g£© ¦¤H=£92.6 kJ¡¤mol£1£¬ÊµÑé²âµÃÓйØÊý¾ÝÈçÏÂ±í£º
ÈÝÆ÷±àºÅ | Æðʼʱ¸÷ÎïÖÊÎïÖʵÄÁ¿/mol | ´ïƽºâʱÌåϵÄÜÁ¿µÄ±ä»¯ | ||
X2 | Y2 | XY3 | ||
¢Ù | 1 | 3 | 0 | ·ÅÈÈ46.3 kJ |
¢Ú | 0.8 | 2.4 | 0.4 | Q£¨Q£¾0£© |
ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ £¨ £©
A£®ÈÝÆ÷¢ÙÖдﵽƽºâʱ£¬Y2µÄת»¯ÂÊΪ50%
B£®Q=27.78 kJ
C£®ÏàͬζÈÏ£»ÆðʼʱÏòÈÝÆ÷ÖгäÈë1.0 X2 mol ¡¢3.0 mol Y2ºÍ2 mol XY3£»·´Ó¦´ïµ½Æ½ºâÇ°v(Õý£©>v(Ä棩
D£®ÈÝÆ÷¢Ù¡¢¢ÚÖз´Ó¦µÄƽºâ³£ÊýÏàµÈ£¬K=
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2016-2017ѧÄêºÓÄÏÊ¡ÄÏÑôÊи߶þÉϵڶþ´ÎÔ¿¼»¯Ñ§¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ÒÑÖª£º
2H2(g£©£«O2(g£©===2H2O(l£© ¦¤H£½£571.6 kJ¡¤mol£1
2CH3OH(l£©£«3O2(g£©===2CO2(g£©£«4H2O(l£© ¦¤H£½£1452 kJ¡¤mol£1
H£«(aq£©£«OH£(aq£©===H2O(l£© ¦¤H£½£57.3 kJ¡¤mol£1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨ £©
A£®H2(g£©µÄȼÉÕÈÈΪ571.6 kJ¡¤mol£1
B£®Í¬ÖÊÁ¿µÄH2(g£©ºÍCH3OH(l£©ÍêȫȼÉÕ£¬H2(g£©·Å³öµÄÈÈÁ¿¶à
C£®H2SO4(aq£©£«Ba(OH£©2(aq£©===BaSO4(s£©£«H2O(l£© ¦¤H£½£57.3 kJ¡¤mol£1
D£®3H2(g£©£«CO2(g£©=CH3OH(l£©£«H2O(l£© ¦¤H£½£«135.9 kJ¡¤mol£1
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìÎ÷²ØÈÕ¿¦ÔòÇøµÚÒ»¸ß¼¶ÖÐѧ¸ßÈýÉÏÆÚÖл¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ΪÔöÇ¿ÂÁµÄÄ͸¯Ê´ÐÔ£¬ÏÖÒÔǦÐîµç³ØΪÍâµçÔ´£¬ÒÔAl×÷Ñô¼«¡¢Pb×÷Òõ¼«£¬µç½âÏ¡ÁòËᣬʹÂÁ±íÃæµÄÑõ»¯Ä¤Ôöºñ¡£Æä·´Ó¦ÔÀíÈçÏ£º
µç³Ø£ºPb£¨s£©+PbO2£¨s£©+2H2SO4£¨aq£©¨T2PbSO4£¨s£©+2H2O£¨l£©
µç½â³Ø£º2Al+3H2OAl2O3+3H2£¬µç½â¹ý³ÌÖУ¬ÒÔÏÂÅжÏÕýÈ·µÄÊÇ£¨ £©
µç³Ø | µç½â³Ø | |
A | H£«ÒÆÏòPbµç¼« | H£«ÒÆÏòPbµç¼« |
B | ÿÏûºÄ3molPb | Éú³É2molAl2O3 |
C | Õý¼«£ºPbO2+4H£«+2e¨TPb2++2H2O | Ñô¼«£º2Al+3H2O?6e?¨TAl2O3+6H£« |
D |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2017½ìÉÂÎ÷Ê¡¸ßÈý10Ô¼ì²â»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
½«Ò»¶¨Á¿µÄSO2ͨÈëFeC13ÈÜÒºÖУ¬È¡»ìºÏÈÜÒº£¬·Ö±ð½øÐÐÏÂÁÐʵÑ飬ÄÜÖ¤Ã÷SO2ÓëFeCl3ÈÜÒº·¢ÉúÑõ»¯»¹Ô·´Ó¦µÄÊÇ£¨ £©
Ñ¡Ïî | ²Ù×÷ | ÏÖÏó |
A | ¼ÓÈëNaOH ÈÜÒº | ÓкìºÖÉ«³Áµí |
B | ¼ÓÈëBa £¨NO3£©2ÈÜÒº | Óа×É«³Áµí |
C | ¼ÓÈëËáÐÔKMnO4ÈÜÒº | ×ÏÉ«ÍÊÈ¥ |
D | ¼ÓÈëKSCNÈÜÒº | ÎÞÃ÷ÏÔÏÖÏó |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com