ʵÑéÊÒÐèÒªÅäÖÆ100mL 1mol/LµÄNaOHÈÜÒº£¬½øÐÐÁËÈçϲÙ×÷£º
¢Ù°Ñ³ÆÁ¿ºÃµÄ¹ÌÌåNaOH·ÅÈëСÉÕ±­ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⣮Ϊ¼ÓËÙÈܽ⣬¿ÉÓÃ______£¨ÌîÒÇÆ÷Ãû³Æ£©½Á°è£»
¢Ú°Ñ¢ÙËùµÃÈÜÒº______ºó£¬Ð¡ÐÄתÈë______£¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ»
¢Û¼ÌÐø¼ÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1-2cm´¦£¬¸ÄÓÃ______£¨ÌîÒÇÆ÷Ãû³Æ£©Ð¡ÐĵμÓÕôÁóË®ÖÁÈÜÒº°¼ÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇУ»
¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2-3´Î£¬Ã¿´ÎÏ´µÓµÄÒºÌ嶼ҪСÐÄתÈëÈÝÁ¿Æ¿£¬²¢ÇáÇáÒ¡ÔÈ£»
¢Ý½«ÈÝÁ¿Æ¿Èû½ô£¬³ä·ÖÒ¡ÔÈ£®
¢Þ¼ÆËãÐèÒªNaOH¹ÌÌåµÄÖÊÁ¿£º______ g
Çë»Ø´ð£º
£¨1£©ÕýÈ·µÄ²Ù×÷˳ÐòΪ______£¨ÌîÐòºÅ£©£®
£¨2£©È¡³ö50mLÅäÖƺõÄÈÜÒº£¬´ËÈÜÒºÖÐNaOHµÄÎïÖʵÄÁ¿Å¨¶ÈΪ______£®
£¨3£©Èô½«ÉÕ±­ÖеÄÈÜҺתÒƵ½ÈÝÁ¿Æ¿Ê±²»É÷Èöµ½ÈÝÁ¿Æ¿Í⣬ÆäËü²Ù×÷¾ùÕýÈ·£¬Ôò×îºóÅä³ÉµÄÈÜÒºÖÐÈÜÖʵÄʵ¼ÊŨ¶È±ÈËùÒªÇóŨ¶È______£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±£©

½â£º¢ÙΪ¼ÓËÙÈܽ⣬¿ÉÓò£Á§°ô½Á°è£»
¹Ê´ð°¸Îª£º²£Á§°ô£»
¢ÚÓÉÓÚÇâÑõ»¯ÄƹÌÌåÈܽâ¹ý³Ì»á·Å³öÈÈÁ¿£¬×ªÒƵ½ÈÝÁ¿Æ¿Ç°±ØÐëÀäÈ´µ½ÊÒΣ»
¹Ê´ð°¸Îª£ºÀäÈ´µ½ÊÒΣ»100mLÈÝÁ¿Æ¿£»
¢Û¼ÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1-2cm´¦£¬¸ÄÓýºÍ·µÎ¹Ü¶¨ÈÝ£»
¹Ê´ð°¸Îª£º½ºÍ·µÎ¹Ü£»
¢Þ100mL 1mol/LµÄNaOHÈÜÒºÖÐÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿ÊÇ0.1mol£¬ÖÊÁ¿ÊÇ4g£»
¹Ê´ð°¸Îª£º4£»
£¨1£©°´ÕÕ³ÆÁ¿¡¢Èܽ⡢ÀäÈ´ÒÆÒº¡¢Ï´µÓ¡¢¶¨ÈÝ¡¢Ò¡ÔȵÄ˳Ðò£¬ÕýȷΪ£º¢Þ¢Ù¢Ú¢Ü¢Û¢Ý£»
¹Ê´ð°¸Îª£º¢Þ¢Ù¢Ú¢Ü¢Û¢Ý
£¨2£©ÈÜÒºµÄŨ¶È²»±ä£¬¹ÊNaOHµÄÎïÖʵÄÁ¿Å¨¶ÈΪ£º1 mol/L£»
¹Ê´ð°¸Îª£º1 mol/L£»
£¨3£©½«ÉÕ±­ÖеÄÈÜҺתÒƵ½ÈÝÁ¿Æ¿Ê±²»É÷Èöµ½ÈÝÁ¿Æ¿Í⣬µ¼ÖÂÈÜÖʵÄÎïÖʵÄÁ¿¼õÉÙ£¬ÅäÖÆÈÜÒºµÄŨ¶È¼õС£»
¹Ê´ð°¸Îª£ºÆ«Ð¡£®
·ÖÎö£º¢ÙÓò£Á§°ô½Á°è¿ÉÒÔ¼ÓËÙÈܽ⣻
¢ÚÇâÑõ»¯ÄƹÌÌåÈܽâ»á·ÅÈÈ£¬ÐëÀäÈ´ÖÁÊÒκóתÒƵ½100mLÈÝÁ¿Æ¿ÖУ»
¢Û¶¨ÈݲÙ×÷£¬¶¨ÈÝÓõ½½ºÍ·µÎ¹Ü£»
¢Þ¸ù¾ÝÅäÖÆÈÜÒºÌå»ýºÍŨ¶È£¬¼ÆËã³öÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿£¬Çó³öÇâÑõ»¯ÄƵÄÖÊÁ¿£®
£¨1£©°´ÕÕÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒºµÄÅäÖƲ½ÖèÍê³É£»
£¨2£©ÈÜÒºµÄŨ¶ÈÓëÈÜÒºµÄÌå»ý´óСÎ޹أ»
£¨3£©ÈÜÒºÈöµ½ÈÝÁ¿Æ¿Í⣬ÈÜÖʵÄÎïÖʵÄÁ¿¼õÉÙ£®
µãÆÀ£º±¾Ì⿼²éÁËÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈÈÜÒºµÄÅäÖƲ½Öè¼°Îó²î·ÖÎö£¬×¢ÖØÁË»ù´¡ÖªÊ¶µÄ¿¼²é£¬ÄѶÈÒ»°ã£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

£¨1£©ÊµÑéÊÒÐèÒªÅäÖÆ0.3 mol /LÇâÑõ»¯ÄÆÈÜÒº100 mL£¬ÏÖÓÐ6mol/LµÄŨÇâÑõ»¯ÄÆÈÜÒº£¬¼ÆËãËùÐèŨÇâÑõ»¯ÄÆÈÜÒºµÄÌå»ý(mL)£»£¨4·Ö£©

£¨2£©ÈôÓýðÊôÄƺÍË®·´Ó¦ÖƵÃ4gÇâÑõ»¯ÄÆ£¬Ôòͬʱ¿ÉÒÔÉú³É±ê×¼×´¿öϵÄÆøÌå¶àÉÙL£¿£¨5·Ö£©

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄê±±¾©ÊÐÖصãÖÐѧ¸ß¶þÉÏѧÆÚÆÚÖп¼ÊÔ»¯Ñ§£¨ÎÄ£©ÊÔ¾í ÌâÐÍ£ºÊµÑéÌâ

£¨8·Ö£©ÊµÑéÊÒÐèÒªÅäÖÆ100 mL 1 mol/LµÄNaOHÈÜÒº£¬½øÐÐÁËÈçϲÙ×÷£º
¢Ù°Ñ³ÆÁ¿ºÃµÄ¹ÌÌåNaOH·ÅÈëСÉÕ±­ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⡣Ϊ¼ÓËÙÈܽ⣬¿ÉÓà    
£¨ÌîÒÇÆ÷Ãû³Æ£©½Á°è£»
¢Ú°Ñ¢ÙËùµÃÈÜÒº           ºó£¬Ð¡ÐÄתÈë                    £¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ»
¢Û¼ÌÐø¼ÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡ª2 cm´¦£¬¸ÄÓà                £¨ÌîÒÇÆ÷Ãû³Æ£©
СÐĵμÓÕôÁóË®ÖÁÈÜÒº°¼ÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇУ»
¢ÜÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡ª3´Î£¬Ã¿´ÎÏ´µÓµÄÒºÌ嶼ҪСÐÄתÈëÈÝÁ¿Æ¿£¬²¢ÇáÇáÒ¡ÔÈ£»
¢Ý½«ÈÝÁ¿Æ¿Èû½ô£¬³ä·ÖÒ¡ÔÈ¡£
¢Þ¼ÆËãÐèÒªNaOH¹ÌÌåµÄÖÊÁ¿£º      g
Çë»Ø´ð£º
£¨1£©ÕýÈ·µÄ²Ù×÷˳ÐòΪ                           £¨ÌîÐòºÅ£©¡£
£¨2£©È¡³ö50 mLÅäÖƺõÄÈÜÒº£¬´ËÈÜÒºÖÐNaOHµÄÎïÖʵÄÁ¿Å¨¶ÈΪ           ¡£
£¨3£©Èô½«ÉÕ±­ÖеÄÈÜҺתÒƵ½ÈÝÁ¿Æ¿Ê±²»É÷Èöµ½ÈÝÁ¿Æ¿Í⣬ÆäËü²Ù×÷¾ùÕýÈ·£¬Ôò×îºóÅä³ÉµÄÈÜÒºÖÐÈÜÖʵÄʵ¼ÊŨ¶È±ÈËùÒªÇóŨ¶È            £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2015½ì±±¾©ÊÐÎ÷³ÇÇø£¨±±Çø£©¸ßÒ»ÉÏѧÆÚÆÚÄ©¿¼ÊÔ»¯Ñ§ÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÊµÑéÌâ

NaClÔÚÉú»î¡¢Éú²úºÍ¿ÆÑÐÖж¼Óй㷺µÄÓÃ;¡£

I. ´Óº£Ë®ÖÐÌáÈ¡µÄ´ÖÑκ¬ÓÐCa2+¡¢Mg2+¡¢SO4£­µÈÀë×Ó£¬ÎªÖƱ¸¾«ÑοÉʹÓÃÒÔÏÂËÄÖÖÊÔ¼Á£º¢ÙNa2CO3ÈÜÒº ¢ÚBaCl2ÈÜÒº ¢ÛNaOHÈÜÒº ¢ÜÑÎËᣨÓÃÓÚ³ÁµíµÄÊÔ¼Á¾ùÉÔ¹ýÁ¿£©¡£

£¨1£©¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòÊÇ________£¨ÌîÑ¡Ï¡£

a. ¢Ù¢Ú¢Û¢Ü    b. ¢Û¢Ù¢Ú¢Ü    c. ¢Ú¢Ù¢Û¢Ü    d. ¢Û¢Ú¢Ù¢Ü

£¨2£©¼ÓÈë¹ýÁ¿Na2CO3ÈÜÒºµÄ×÷ÓÃÊÇ________________¡£

II. ʵÑéÊÒÒªÅäÖÆ100 mL 0.2 mol¡¤L-1 NaClÈÜÒº¡£

£¨1£©ÓÃÍÐÅÌÌìƽ³ÆÂÈ»¯ÄƹÌÌåµÄÖÊÁ¿ÊÇ________g¡£

£¨2£©ÅäÖÆÈÜÒºÐèҪʹÓõÄÖ÷Òª²£Á§ÒÇÆ÷ÓÐÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜºÍ________¡£

£¨3£©ÏÂÁвÙ×÷ÖУ¬¿ÉÄÜÔì³ÉËùÅäÖÆÈÜÒºµÄŨ¶ÈÆ«µÍµÄÊÇ________£¨ÌîÑ¡Ï¡£

a. ûÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô    b. ¶¨ÈÝʱ£¬¸©Êӿ̶ÈÏß

c. Ï´µÓºóµÄÈÝÁ¿Æ¿ÖвÐÁôÉÙÁ¿ÕôÁóË®

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2014½ìÌì½òÊиßÒ»ÉÏѧÆÚÆÚÄ©Áª¿¼»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ

£¨4·Ö£©ÊµÑéÊÒÒªÅäÖÆ100 mL 2 mol/L NaClÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌâ

£¨1£©Öƹý³ÌÖÐÐèҪʹÓõÄÖ÷Òª²£Á§ÒÇÆ÷°üÀ¨ÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹Ü¡¢Á¿Í²ºÍ                ¡£

£¨2£©ÓÃÍÐÅÌÌìƽ³ÆÈ¡ÂÈ»¯ÄƹÌÌ壬ÆäÖÊÁ¿Îª                 g¡£

£¨3£©Èô¶¨ÈÝʱ¸©ÊÓÈÝÁ¿Æ¿¿Ì¶ÈÏߣ¬»áÔì³ÉËùÅäÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È_________£¨Æ«´ó¡¢Æ«Ð¡»òÎÞÓ°Ï죩¡£

 

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º

ʵÑéÊÒÐèÒªÅäÖÆ100 mL 1 mol/LµÄNaOHÈÜÒº£¬½øÐÐÁËÈçϲÙ×÷£º

¢Ù °Ñ³ÆÁ¿ºÃµÄ¹ÌÌåNaOH·ÅÈëСÉÕ±­ÖУ¬¼ÓÊÊÁ¿ÕôÁóË®Èܽ⡣Ϊ¼ÓËÙÈܽ⣬¿ÉÓà     

£¨ÌîÒÇÆ÷Ãû³Æ£©½Á°è£»

¢Ú °Ñ¢ÙËùµÃÈÜÒº            ºó£¬Ð¡ÐÄתÈë                     £¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ»

¢Û ¼ÌÐø¼ÓÕôÁóË®ÖÁÒºÃæ¾à¿Ì¶ÈÏß1¡ª2 cm´¦£¬¸ÄÓà                 £¨ÌîÒÇÆ÷Ãû³Æ£©

СÐĵμÓÕôÁóË®ÖÁÈÜÒº°¼ÒºÃæ×îµÍµãÓë¿Ì¶ÈÏßÏàÇУ»

¢Ü ÓÃÉÙÁ¿ÕôÁóˮϴµÓÉÕ±­ºÍ²£Á§°ô2¡ª3´Î£¬Ã¿´ÎÏ´µÓµÄÒºÌ嶼ҪСÐÄתÈëÈÝÁ¿Æ¿£¬²¢ÇáÇáÒ¡ÔÈ£»

¢Ý ½«ÈÝÁ¿Æ¿Èû½ô£¬³ä·ÖÒ¡ÔÈ¡£

¢Þ ¼ÆËãÐèÒªNaOH¹ÌÌåµÄÖÊÁ¿£º       g

Çë»Ø´ð£º

£¨1£©ÕýÈ·µÄ²Ù×÷˳ÐòΪ                            £¨ÌîÐòºÅ£©¡£

£¨2£©È¡³ö50 mLÅäÖƺõÄÈÜÒº£¬´ËÈÜÒºÖÐNaOHµÄÎïÖʵÄÁ¿Å¨¶ÈΪ            ¡£

£¨3£©Èô½«ÉÕ±­ÖеÄÈÜҺתÒƵ½ÈÝÁ¿Æ¿Ê±²»É÷Èöµ½ÈÝÁ¿Æ¿Í⣬ÆäËü²Ù×÷¾ùÕýÈ·£¬Ôò×îºóÅä³ÉµÄÈÜÒºÖÐÈÜÖʵÄʵ¼ÊŨ¶È±ÈËùÒªÇóŨ¶È             £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±£©

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸