£¨10·Ö£©·¢É亽Ìì»ð¼ý³£ÓõªµÄÇ⻯Îï루N2H4£©×÷ȼÁÏ¡£ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©N2H4ȼÉÕʱÓÃNO2×÷Ñõ»¯¼Á£¬ËüÃÇÏ໥·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆø¡£
ÔòN2H4ºÍNO2·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆøµÄÈÈ»¯Ñ§·½³ÌʽΪ ¡£
£¨2£©ÀûÓÃë¡¢ÑõÆøÓëKOHÈÜÒº×é³É¼îÐÔȼÁϵç³Ø£¬µªÔªËر»Ñõ»¯ºóÖ»Éú³ÉµªÆø£¬Çëд³ö¸Ãµç³Ø¹¤×÷ʱ¸º¼«µÄµç¼«·´Ó¦ £»µç³Ø¹¤×÷ʱ£¬ ¼«pHÉý¸ß¡£
£¨3£©´«Í³ÖƱ¸ëµķ½·¨£¬ÊÇÒÔNaClOÑõ»¯NH3£¬ÖƵÃëµÄÏ¡ÈÜÒº¡£¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£
£¨4£©ÑÎËá루N2H6Cl2£©ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁÏ£¬ÊôÓÚÀë×Ó»¯ºÏÎÒ×ÈÜÓÚË®£¬ÈÜÒº³ÊËáÐÔ£¬Ë®½âÔÀíÓëNH4ClÀàËÆ¡£Ð´³öÑÎËáëµÚÒ»²½Ë®½â·´Ó¦µÄÀë×Ó·½³Ìʽ ¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£ºÐ¿αê2007Äê¸ß¿¼»¯Ñ§Ä£ÄâÊÔÌâ(ɽ¶«¾í) ÌâÐÍ£º022
|
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
(1)д³öN2µÄµç×Óʽ_________________________________¡£
(2)Һ̬NH3ÀàËÆH2O£¬Ò²ÄÜ΢ÈõµçÀëÇÒ²úÉúµç×ÓÊýÏàͬµÄÁ½ÖÖÀë×Ó£¬ÔòҺ̬NH3µçÀë·½³ÌʽΪ_________________________________¡£
(3)25¡æʱ£¬0.1 mol.L-1NH4NO3ÈÜÒºÖÐË®µÄµçÀë³Ì¶È___________(Ìî¡°´óÓÚ¡±¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±)0.1 mol¡¤L-1NaOHÈÜÒºÖÐË®µÄµçÀë³Ì¶È¡£Èô½«0.1 mOl¡¤L-1NaOHºÍ0.2 m01.L-1 NH4NO3Á½ÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ______________________¡£
(4)ÔڽṹÉÏN2H4ºÍNH3µÄ¹ØϵÓÐÈçH2O2ºÍH2OµÄ¹Øϵ¡£N2H4ÄÜ·¢ÉúÏÂÁз´Ó¦£º
N2H4+H3O+====+ H2O
N2H4+ H2O+ OH-
+H2O+OH-
+H2ON2H4+H3O+
¾Ý´Ë¿ÉµÃ³öµÄ½áÂÛÊÇ__________________¡£
A.ëÂË®½âÏÔËáÐÔ B.ëÂÔÚË®ÖеçÀë³öH+Àë×Ó
C.ëÂÊǶþÔªÈõ¼î D.ëÂÊǶþÔªÈõËá
(5)Íê³ÉÏÂÁз´Ó¦·½³Ìʽ²¢Åäƽ£º
______NH3+______NaClO====NaCl+______N2H4+______ ______
(6)·¢Éä»ð¼ýʱëÂ(N2H4)ΪȼÁÏ£¬¶þÑõ»¯µª×÷Ñõ»¯¼Á£¬Á½Õß·´Ó¦Éú³ÉµªÆøºÍÆø̬ˮ¡£ÒÑÖª4gN2H4(g)ÔÚÉÏÊö·´Ó¦Öзųö71kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ)___________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
·¢É亽Ìì»ð¼ý³£ÓõªµÄÇ⻯Îï루N2H4£©×÷ȼÁÏ¡£ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©Ð´³öN2µÄµç×Óʽ
£¨2£©ÒºÌ¬NH3ÀàËÆH2O£¬Ò²ÄÜ΢ÈõµçÀëÇÒ²úÉúµç×ÓÊýÏàͬµÄÁ½ÖÖÀë×Ó£¬ÔòҺ̬NH3µçÀë·½³ÌʽΪ_________________________________¡£
£¨3£©25¡æʱ£¬0.1 mol¡¤L£1 NH4NO3ÈÜÒºÖÐË®µÄµçÀë³Ì¶È________________ £¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡°»ò¡°Ð¡ÓÚ¡±£©0.1 mol¡¤L£l NaOHÈÜÒºÖÐË®µÄµçÀë³Ì¶È¡£Èô½«0.1mol¡¤L£1NaOHºÍ0.2mol¡¤L£1 NH4NO3Á½ÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ________________¡£
£¨4£©ÔڽṹÉÏN2H4ºÍNH3µÄ¹ØϵÓÐÈçH2O2ºÍH2OµÄ¹Øϵ¡£N2H4ÄÜ·¢ÉúÏÂÁз´Ó¦£º
N2H4+H3O+==N2H5£«+H2O N2H4+H2ON2H5£«+OH£
N2H5£«+H2ON2H62£«+OH£ N2H5£«+ H2ON2H4+H3O+
¾Ý´Ë¿ÉµÃ³öµÄ½áÂÛÊÇ______________________¡£
A£®ëÂË®½âÏÔËáÐÔ B£®ëÂÔÚË®ÖеçÀë³öH+Àë×Ó
C£®ëÂÊǶþÔªÈõ¼î D£®ëÂÊǶþÔªÈõËá
£¨5£©·¢Éä»ð¼ýʱ루N2H4£©ÎªÈ¼ÁÏ£¬Ë«ÑõË®×÷Ñõ»¯¼Á£¬Á½Õß·´Ó¦Éú³ÉµªÆøºÍÆø̬ˮ¡£ÒÑÖª3.2gN2H4(l)ÔÚÉÏÊö·´Ó¦Öзųö64.22kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ
________ ¡£
Òò´Ëë¿ÉÒÔ×÷Ϊ»ð¼ýÍƽø¼Á¡£¸ù¾Ý¸Ã·´Ó¦£¬ÄãÈÏΪÊÇ·ñ¿ÉÒÔͨ¹ý¸Ä±ä·´Ó¦Ìõ¼þ£¬ÓÉN2ºÍË®À´ÖÆÈ¡N2H4£¬ÈôÄÜ£¬Ö¸³ö¿ÉÄܵķ´Ó¦Ìõ¼þ£»Èô²»ÄÜ£¬ÇëÖ¸³öÔÒò¡£
¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º2011-2012ѧÄêºÓÄÏÊ¡ÂåÑôÊиßÈý¡°Ò»Á·¡±¿¼ÊÔ»¯Ñ§ÊÔ¾í ÌâÐÍ£ºÌî¿ÕÌâ
£¨10·Ö£©·¢É亽Ìì»ð¼ý³£ÓõªµÄÇ⻯Îï루N2H4£©×÷ȼÁÏ¡£ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©N2H4ȼÉÕʱÓÃNO2×÷Ñõ»¯¼Á£¬ËüÃÇÏ໥·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆø¡£
ÔòN2H4ºÍNO2·´Ó¦Éú³ÉµªÆøºÍË®ÕôÆøµÄÈÈ»¯Ñ§·½³ÌʽΪ ¡£
£¨2£©ÀûÓÃë¡¢ÑõÆøÓëKOHÈÜÒº×é³É¼îÐÔȼÁϵç³Ø£¬µªÔªËر»Ñõ»¯ºóÖ»Éú³ÉµªÆø£¬Çëд³ö¸Ãµç³Ø¹¤×÷ʱ¸º¼«µÄµç¼«·´Ó¦ £»µç³Ø¹¤×÷ʱ£¬ ¼«pHÉý¸ß¡£
£¨3£©´«Í³ÖƱ¸ëµķ½·¨£¬ÊÇÒÔNaClOÑõ»¯NH3£¬ÖƵÃëµÄÏ¡ÈÜÒº¡£¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£
£¨4£©ÑÎËá루N2H6Cl2£©ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤ÔÁÏ£¬ÊôÓÚÀë×Ó»¯ºÏÎÒ×ÈÜÓÚË®£¬ÈÜÒº³ÊËáÐÔ£¬Ë®½âÔÀíÓëNH4ClÀàËÆ¡£Ð´³öÑÎËáëµÚÒ»²½Ë®½â·´Ó¦µÄÀë×Ó·½³Ìʽ ¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖл¯Ñ§ À´Ô´£º ÌâÐÍ£º
·¢É亽Ìì»ð¼ý³£ÓõªµÄÇ⻯Îï루N2H4£©×÷ȼÁÏ¡£ÊԻشðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©Ð´³öN2µÄµç×Óʽ______________¡£
£¨2£©ÒºÌ¬NH3ÀàËÆH2O£¬Ò²ÄÜ΢ÈõµçÀëÇÒ²úÉúµç×ÓÊýÏàͬµÄÁ½ÖÖÀë×Ó£¬ÔòҺ̬NH3µçÀë·½³ÌʽΪ______________________________¡£
£¨3£©25¡æʱ£¬0£®1 mol?L-1 NH4NO3ÈÜÒºÖÐË®µÄµçÀë³Ì¶È_______£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡°»ò¡°Ð¡ÓÚ¡±£©0£®1 mol?L-l NaOHÈÜÒºÖÐË®µÄµçÀë³Ì¶È¡£Èô½«0£®1mol?L-1NaOHºÍ0£®2mol?L-1 NH4NO3Á½ÈÜÒºµÈÌå»ý»ìºÏ£¬ËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ_________¡£
£¨4£©ÔڽṹÉÏN2H4ºÍNH3µÄ¹ØϵÓÐÈçH2O2ºÍH2OµÄ¹Øϵ¡£N2H4ÄÜ·¢ÉúÏÂÁз´Ó¦£º
N2H4+H3O+==N2H+H2O¡¡ ¡¡¡¡¡¡¡¡¡¡¡¡N2H4+H2ON2H+OH-
N2H+H2ON2H+OH-¡¡ ¡¡¡¡¡¡¡¡¡¡N2H+ H2ON2H4+H3O+
¾Ý´Ë¿ÉµÃ³öµÄ½áÂÛÊÇ______________________¡£
A£®ëÂË®½âÏÔËáÐÔ¡¡ ¡¡¡¡¡¡¡¡¡¡ B£®ëÂÔÚË®ÖеçÀë³öH+Àë×Ó
C£®ëÂÊǶþÔªÈõ¼î¡¡¡¡¡¡¡¡¡¡¡¡¡¡ D£®ëÂÊǶþÔªÈõËá
£¨5£©Íê³ÉÏÂÁз´Ó¦·½³Ìʽ²¢Åäƽ£º
______NH3+______NaClO==_________NaCl+_______N2H4+_____ _____
£¨6£©·¢Éä»ð¼ýʱëÝ£¨N2+H4£©ÎªÈ¼ÁÏ£¬¶þÑõ»¯µª×÷Ñõ»¯¼Á£¬Á½Õß·´Ó¦Éú³ÉµªÆøºÍÆø̬ˮ¡£ÒÑÖª4gN2H4£¨g£©ÔÚÉÏÊö·´Ó¦Öзųö71kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄת»¯Ñ§·½³Ìʽ___________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com