ijУÀûÓýڼÙÈÕ×é֯ѧÉúÒåÎñΪÌÇÄò²¡»¼Õß¼ì²âÄòÒº£¬¿´ÆäÊÇ·ñ¿µ¸´¡£ÏÂÁÐÐðÊö²»
ÕýÈ·µÄÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ (¡¡¡¡)
¢ÙËùÓÃÊÔ¼ÁΪÖÊÁ¿Å¨¶ÈΪ0.1 g/mLµÄNaOHÈÜÒººÍ0.01 g/mL µÄCuSO4ÈÜÒº¡¡¢ÚÏò
ÄòÒºÖÐÏȼÓÈëNaOHÈÜÒº£¬Ò¡µ´¾ùÔȺó£¬ÔÙ¼ÓÈëCuSO4ÈÜÒº¡¡¢ÛÏòÄòÒºÖмÓÈëÊÔ¼Á
ºó£¬Ë®Ô¡¼ÓÈÈ£¬¹Û²ìÊÇ·ñÓÐ×ÏÉ«·´Ó¦¡¡¢ÜΪÁËʹ½á¹û¸ü¿ÉÐÅ£¬Ó¦È¡µÈÁ¿µÄº¬ÓÐÕáÌÇ
µÄÕôÁóË®ÈÜҺΪ¶ÔÕÕ×é
A£®¢Ù¢Ú¢Û ¡¡¡¡¡¡¡¡¡¡¡¡¡¡B£®¢Ú¢Û¢Ü
C£®¢Ù¢Ú¢Ü ¡¡¡¡¡¡¡¡¡¡¡¡¡¡D£®¢Ù¢Ú¢Û¢Ü
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2014½ì½Î÷Ê¡¸ßÈýµÚ¶þ´ÎÄ£¿¼ÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijУÀûÓýڼÙÈÕ×é֯ѧÉúÒåÎñΪÌÇÄò²¡»¼Õß¼ì²âÄòÒº£¬¿´ÆäÊÇ·ñ¿µ¸´¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ:£¨ £©
¢ÙËùÓÃÊÔ¼ÁΪÖÊÁ¿Å¨¶ÈΪ0.1 g/mLµÄNaOHÈÜÒººÍ0.01 g/mLµÄCuSO4ÈÜÒº¡¡
¢ÚÏòÄòÒºÖÐÏȼÓÈëNaOHÈÜÒº£¬Ò¡µ´¾ùÔȺó£¬ÔÙ¼ÓÈëCuSO4ÈÜÒº¡¡
¢ÛÏòÄòÒºÖмÓÈëÊÔ¼Áºó£¬Ë®Ô¡¼ÓÈÈ£¬¹Û²ìÊÇ·ñÓÐ×ÏÉ«·´Ó¦¡¡
¢ÜΪÁËʹ½á¹û¸ü¿ÉÐÅ£¬Ó¦È¡µÈÁ¿µÄº¬ÓÐÕáÌǵÄÕôÁóË®ÈÜҺΪ¶ÔÕÕ×é
A£®¢Ù¢Ú¢Û B£®¢Ú¢Û¢Ü C£®¢Ù¢Ú¢Ü D£®¢Ù¢Ú¢Û¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2013-2014ѧÄê¹ã¶«Ê¡ÉÇÍ·ÊиßÒ»ÉÏѧÆÚ10ÔÂÔ¿¼ÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijУÀûÓýڼÙÈÕ×é֯ѧÉúÒåÎñΪÌÇÄò²¡»¼Õß¼ì²âÄòÒº£¬¿´ÆäÊÇ·ñ¿µ¸´¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
¢ÙËùÓÃÊÔ¼ÁΪì³ÁÖÊÔ¼Á¡¡ ¢ÚÏòÄòÒºÖÐÏȼÓÈëNaOHÈÜÒº£¬Ò¡µ´¾ùÔȺóÔÙ¼ÓCuSO4ÈÜÒº¡¡
¢ÛÏòÄòÒºÖмÓÈëÊÔ¼Áºó£¬Ë®Ô¡¼ÓÈÈ£¬¹Û²ìÊÇ·ñÓÐ×ÏÉ«·´Ó¦¡¡
¢ÜΪÁËʹ½á¹û¸ü¿ÉÐÅ£¬Ó¦È¡µÈÁ¿µÄº¬ÓÐÕáÌǵÄÕôÁóË®ÈÜҺΪ¶ÔÕÕ×é
A£®¢Ù¢Ú¢Û B£®¢Ú¢Û¢Ü C£®¢Ù¢Ú¢Ü D£®¢Ù¢Ú¢Û¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2012-2013ѧÄêÁÉÄþÊ¡ÎåУÐ×÷Ìå¸ßÈýÉÏѧÆÚÆÚ³õÁª¿¼ÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijУÀûÓýڼÙÈÕ×é֯ѧÉúÒåÎñΪÌÇÄò²¡»¼Õß¼ì²âÄòÒº£¬¿´ÆäÊÇ·ñ¿µ¸´¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ:
¢ÙËùÓÃÊÔ¼ÁΪÖÊÁ¿Å¨¶ÈΪ0.1 g/mLµÄNaOHÈÜÒººÍ0.01 g/mLµÄCuSO4ÈÜÒº
¢ÚÏòÄòÒºÖÐÏȼÓÈëNaOHÈÜÒº£¬Ò¡µ´¾ùÔȺó£¬ÔÙ¼ÓÈëCuSO4ÈÜÒº
¢ÛÏòÄòÒºÖмÓÈëÊÔ¼Áºó£¬Ë®Ô¡¼ÓÈÈ£¬¹Û²ìÊÇ·ñÓÐ×ÏÉ«·´Ó¦
¢ÜΪÁËʹ½á¹û¸ü¿ÉÐÅ£¬Ó¦È¡µÈÁ¿µÄº¬ÓÐÕáÌǵÄÕôÁóË®ÈÜҺΪ¶ÔÕÕ×é
A£®¢Ù¢Ú¢Û B£®¢Ú¢Û¢Ü C£®¢Ù¢Ú¢Ü D£®¢Ù¢Ú¢Û¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2013½ì¼ªÁÖÊ¡¸ß¶þÏÂѧÆÚÆÚÄ©¿¼ÊÔÉúÎïÊÔ¾í£¨½âÎö°æ£© ÌâÐÍ£ºÑ¡ÔñÌâ
ijУÀûÓýڼÙÈÕ×é֯ѧÉúÒåÎñΪÌÇÄò²¡»¼Õß¼ì²âÄòÒº£¬¿´ÆäÊÇ·ñ¿µ¸´¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
¢ÙËùÓÃÊÔ¼ÁΪÖÊÁ¿Å¨¶ÈΪ0.1 g/mLµÄNaOHÈÜÒººÍ0.01 g/mLµÄCuSO4ÈÜÒº¡¡¢ÚÏòÄòÒºÖÐÏȼÓÈëNaOHÈÜÒº£¬Ò¡µ´¾ùÔȺó£¬ÔÙ¼ÓÈëCuSO4ÈÜÒº¡¡¢ÛÏòÄòÒºÖмÓÈëÊÔ¼Áºó£¬Ë®Ô¡¼ÓÈÈ£¬¹Û²ìÊÇ·ñÓÐ×ÏÉ«·´Ó¦¡¡¢ÜΪÁËʹ½á¹û¸ü¿ÉÐÅ£¬Ó¦È¡µÈÁ¿µÄº¬ÓÐÕáÌǵÄÕôÁóË®ÈÜҺΪ¶ÔÕÕ×é
A£®¢Ù¢Ú¢Û B£®¢Ú¢Û¢Ü C£®¢Ù¢Ú¢Ü D£®¢Ù¢Ú¢Û¢Ü
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com