Ö²Îï¼×¡¢ÒÒÊÇÁ½ÖÖ±ôΣҩÓÃÖ²Îï(¶þ±¶Ìå)¡£Çë°´ÒªÇó»Ø´ðÎÊÌ⣺
£¨1£©ÒÔÖ²Îï¼×¡¢Òҵľ¥¼âºÍҶƬΪ²ÄÁÏ£¬Í¨¹ý×éÖ¯ÅàÑø»ñµÃÁËÔÙÉúÖ²Ö꣬½â¾öÁË×ÔÈ»·±Ö³Âʵ͵ÄÎÊÌâ¡£Õâ±íÃ÷Ö²Îïϸ°û¾ßÓÐ________________¡£ÓÉҶƬµÈ²ÄÁÏÐγɵÄÓúÉË×éÖ¯µÄÐÎ̬½á¹¹ÌصãÊÇ_____________________________________________________________¡£
£¨2£©Í¼1ºÍͼ2·Ö±ðÊÇÖ²Îï¼×¡¢ÒÒµÄÃÈ·¢»¨·ÛÁ£ºÍδÊܾ«ÅßÖéµÄʾÒâͼ¡£
¢ÙÔÚ·ÖÀëÖ鱻ϸ°ûµÄÔÉúÖÊÌåʱ£¬Í¨³£Ê¹ÓÃÏËάËØøºÍ¹û½ºÃ¸ÆƳýϸ°û±Ú£¬ÆäÔÀíÊÇÀûÓÃÁËøµÄ________¡£
¢ÚÈç¹û½«Í¼1ÖеÄ1¸ö¾«×ÓÓëͼ2ÖеÄ2¸ö¼«ºËϸ°ûÈںϣ¬¿ÉÅàÓý³öÈý±¶ÌåÖ²Öê¡£ÓÃÊʵ±Å¨¶ÈµÄÇïË®ÏÉËØ´¦Àí¸ÃÈý±¶ÌåÖ²ÖêµÄÓ×Ã磬¿ÉÄÜ»ñµÃÒ©ÓóɷֽϸߵÄÁù±¶ÌåÖ²Öê¡£ÇïË®ÏÉËصÄ×÷ÓûúÀíÊÇ__________________________________¡£
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º ÌâÐÍ£º
£¨06ÖØÇì¾í£©(21·Ö)Ö²Îï¼×¡¢ÒÒÊÇÁ½ÖÖ±ôΣҩÓÃÖ²Î¶þ±¶Ì壩¡£Çë°´ÒªÇó»Ø´ðÎÊÌ⣺
£¨1£©ÒÔÖ²Îï¼×¡¢Òҵľ¥¼âºÍҶƬΪ²ÄÁÏ£¬Í¨¹ý×éÖ¯ÅàÑø»ñµÃÁËÔÙÉúÖ²Ö꣬½â¾öÁË×ÔÈ»·±Ö³Âʵ͵ÄÎÊÌâ¡£Õâ±íÃ÷Ö²Îïϸ°û¾ßÓÐ__________¡£ÓÉҶƬµÈ²ÄÁÏÐγɵÄÓúÉË×éÖ¯µÄÐÎ̬½á¹¹ÌصãÊÇ_____________ ______ _______________¡£
£¨2£©ÏÂͼ1ºÍͼ2·Ö±ðÊÇÖ²Îï¼×¡¢ÒÒµÄÃÈ·¢»¨·ÛÁ£ºÍδÊܾ«ÅßÖéµÄʾÒâͼ¡£
ͼ1 Ö²Îï¼×µÄÃÈ·¢»¨·ÛÁ£ ͼ2 Ö²ÎïÒÒµÄδÊܾ«ÅßÖé
ÔÚ·ÖÀëÖ鱻ϸ°ûµÄÔÉúÖÊÌåʱ£¬Í¨³£Ê¹ÓÃÏËάËØøºÍ¹û½ºÃ¸ÆƳýϸ°û±Ú¡£ÆäÔÀíÊÇÀûÓÃÁËøµÄ______ÐÔÖÊ¡£Èç¹û½«Í¼1ÖеÄ1¸ö¾«×ÓÓëͼ2ÖеÄ1¸ö_______ϸ°û»ò2¸ö_______Èںϣ¬¿ÉÅàÓý³öÈý±¶ÌåÖ²Öê¡£ÓÃÊʵ±Å¨¶ÈµÄÇïË®ÏÉËØ´¦Àí¸ÃÈý±¶ÌåÖ²ÖêµÄÓ×Ã磬¿ÉÄÜ»ñµÃÒ©ÓóɷֽϸߵÄÁù±¶ÌåÖ²Öê¡£ÇïË®ÏÉËصÄ×÷ÓûúÀíÊÇ__________¡£
£¨3£©Ö²ÎïÒÒ×ÔÈ»½áʵÂʵͣ¬Ö÷ÒªÔÒòÊÇ»¨·ÛÁ£ÃÈ·¢ºó¶àÊý»¨·Û¹Ü²»ÄÜÉ쳤¡£ÎªÌ½¾¿Éú³¤ËضÔÖ²ÎïÒÒ»¨·Û¹ÜÉ쳤µÄÓ°Ï죬ijÉúÎïÐËȤС×é½øÐÐÁË¿ÎÍâʵÑ飬µÃµ½Ï±í½á¹û£º
Éú³¤ËØŨ¶È(mg/L) | 0 | 1.0 | 2.0 | 3.0 | 4.0 | 5.0 | 6.0 | 7.0 |
»¨·Û¹Üƽ¾ù³¤¶È(mm) | 0.5 | 3.6 | 5.5 | 6.4 | 5.2 | 3.1 | 0.4 | 0.2 |
Çë½áºÏ±íÖÐÊý¾Ý¶ÔʵÑé½á¹û½øÐмòÒª·ÖÎö£º
____________________________________________________________________________________________________ ¡£
¸ù¾ÝÉÏÊö·ÖÎö£¬¿ÉÒԵóöµÄ½áÂÛÊÇ£º____________________________ ______________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º ÌâÐÍ£º
£¨06ÖØÇì¾í£©(21·Ö)Ö²Îï¼×¡¢ÒÒÊÇÁ½ÖÖ±ôΣҩÓÃÖ²Î¶þ±¶Ì壩¡£Çë°´ÒªÇó»Ø´ðÎÊÌ⣺
£¨1£©ÒÔÖ²Îï¼×¡¢Òҵľ¥¼âºÍҶƬΪ²ÄÁÏ£¬Í¨¹ý×éÖ¯ÅàÑø»ñµÃÁËÔÙÉúÖ²Ö꣬½â¾öÁË×ÔÈ»·±Ö³Âʵ͵ÄÎÊÌâ¡£Õâ±íÃ÷Ö²Îïϸ°û¾ßÓÐ__________¡£ÓÉҶƬµÈ²ÄÁÏÐγɵÄÓúÉË×éÖ¯µÄÐÎ̬½á¹¹ÌصãÊÇ_____________ ______ _______________¡£
£¨2£©ÏÂͼ1ºÍͼ2·Ö±ðÊÇÖ²Îï¼×¡¢ÒÒµÄÃÈ·¢»¨·ÛÁ£ºÍδÊܾ«ÅßÖéµÄʾÒâͼ¡£
ͼ1 Ö²Îï¼×µÄÃÈ·¢»¨·ÛÁ£ ͼ2 Ö²ÎïÒÒµÄδÊܾ«ÅßÖé
ÔÚ·ÖÀëÖ鱻ϸ°ûµÄÔÉúÖÊÌåʱ£¬Í¨³£Ê¹ÓÃÏËάËØøºÍ¹û½ºÃ¸ÆƳýϸ°û±Ú¡£ÆäÔÀíÊÇÀûÓÃÁËøµÄ______ÐÔÖÊ¡£Èç¹û½«Í¼1ÖеÄ1¸ö¾«×ÓÓëͼ2ÖеÄ1¸ö_______ϸ°û»ò2¸ö_______Èںϣ¬¿ÉÅàÓý³öÈý±¶ÌåÖ²Öê¡£ÓÃÊʵ±Å¨¶ÈµÄÇïË®ÏÉËØ´¦Àí¸ÃÈý±¶ÌåÖ²ÖêµÄÓ×Ã磬¿ÉÄÜ»ñµÃÒ©ÓóɷֽϸߵÄÁù±¶ÌåÖ²Öê¡£ÇïË®ÏÉËصÄ×÷ÓûúÀíÊÇ__________¡£
£¨3£©Ö²ÎïÒÒ×ÔÈ»½áʵÂʵͣ¬Ö÷ÒªÔÒòÊÇ»¨·ÛÁ£ÃÈ·¢ºó¶àÊý»¨·Û¹Ü²»ÄÜÉ쳤¡£ÎªÌ½¾¿Éú³¤ËضÔÖ²ÎïÒÒ»¨·Û¹ÜÉ쳤µÄÓ°Ï죬ijÉúÎïÐËȤС×é½øÐÐÁË¿ÎÍâʵÑ飬µÃµ½Ï±í½á¹û£º
Éú³¤ËØŨ¶È(mg/L) | 0 | 1.0 | 2.0 | 3.0 | 4.0 | 5.0 | 6.0 | 7.0 |
»¨·Û¹Üƽ¾ù³¤¶È(mm) | 0.5 | 3.6 | 5.5 | 6.4 | 5.2 | 3.1 | 0.4 | 0.2 |
Çë½áºÏ±íÖÐÊý¾Ý¶ÔʵÑé½á¹û½øÐмòÒª·ÖÎö£º
_________________________________________________________________________________________________ ¡£
¸ù¾ÝÉÏÊö·ÖÎö£¬¿ÉÒԵóöµÄ½áÂÛÊÇ£º____________________________ ______________¡£
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º¹ã¶«Ó¢µÂ2010½ì¸ß¿¼ÉúÎǰÈÈÉíÊÔÌâ ÌâÐÍ£º×ÛºÏÌâ
Ö²Îï¼×¡¢ÒÒÊÇÁ½ÖÖ±ôΣҩÓÃÖ²Î¶þ±¶Ì壩¡£Çë°´ÒªÇó»Ø´ðÎÊÌ⣺
£¨1£©ÒÔÖ²Îï¼×¡¢Òҵľ¥¼âºÍҶƬΪ²ÄÁÏ£¬Í¨¹ý×éÖ¯ÅàÑø»ñµÃÁËÔÙÉúÖ²Ö꣬½â¾öÁË×ÔÈ»·±Ö³Âʵ͵ÄÎÊÌâ¡£Õâ±íÃ÷Ö²Îïϸ°û¾ßÓÐ________________¡£ÓÉҶƬµÈ²ÄÁÏÐγɵÄÓúÉË×éÖ¯µÄÐÎ̬½á¹¹ÌصãÊÇ________________¡£
£¨2£©Ö²ÎïÒÒ×ÔÈ»½áʵÂʵͣ¬Ö÷ÒªÔÒòÊÇ»¨·ÛÁ£ÃÈ·¢ºó¶àÊý»¨·Û¹Ü²»ÄÜÉ쳤¡£ÎªÁË̽Ë÷Éú³¤ËضÔÖ²ÎïÒÒ»¨·Û¹ÜÉ쳤µÄÓ°Ï죬ijÉúÎïÐËȤС×é½øÐÐÁË¿ÎÍâʵÑ飬µÃµ½Ï±í½á¹û£º
Éú³¤ËØŨ¶È£¨mg/L£© | 0 | 1.0 | 2.0 | 3.0 | 4.0 | 5.0 | 6.0 | 7.0 |
»¨·Û¹Üƽ¾ù³¤¶È£¨mm£© | 0.5 | 3.6 | 5.5 | 6.4 | 5.2 | 3.1 | 0.4 | 0.2 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÉúÎï À´Ô´£º2013½ìÔÆÄÏÊ¡¸ß¶þÉÏѧÆÚÆÚÄ©¿¼ÊÔÉúÎïÊÔ¾í ÌâÐÍ£º×ÛºÏÌâ
Ö²Îï¼×¡¢ÒÒÊÇÁ½ÖÖ±ôΣҩÓÃÖ²Îï(¶þ±¶Ìå)¡£Çë°´ÒªÇó»Ø´ðÎÊÌ⣺
£¨1£©ÒÔÖ²Îï¼×¡¢Òҵľ¥¼âºÍҶƬΪ²ÄÁÏ£¬Í¨¹ý×éÖ¯ÅàÑø»ñµÃÁËÔÙÉúÖ²Ö꣬½â¾öÁË×ÔÈ»·±Ö³Âʵ͵ÄÎÊÌâ¡£Õâ±íÃ÷Ö²Îïϸ°û¾ßÓÐ________________¡£ÓÉҶƬµÈ²ÄÁÏÐγɵÄÓúÉË×éÖ¯µÄÐÎ̬½á¹¹ÌصãÊÇ_____________________________________________________________¡£
£¨2£©Í¼1ºÍͼ2·Ö±ðÊÇÖ²Îï¼×¡¢ÒÒµÄÃÈ·¢»¨·ÛÁ£ºÍδÊܾ«ÅßÖéµÄʾÒâͼ¡£
¢ÙÔÚ·ÖÀëÖ鱻ϸ°ûµÄÔÉúÖÊÌåʱ£¬Í¨³£Ê¹ÓÃÏËάËØøºÍ¹û½ºÃ¸ÆƳýϸ°û±Ú£¬ÆäÔÀíÊÇÀûÓÃÁËøµÄ________¡£
¢ÚÈç¹û½«Í¼1ÖеÄ1¸ö¾«×ÓÓëͼ2ÖеÄ2¸ö¼«ºËϸ°ûÈںϣ¬¿ÉÅàÓý³öÈý±¶ÌåÖ²Öê¡£ÓÃÊʵ±Å¨¶ÈµÄÇïË®ÏÉËØ´¦Àí¸ÃÈý±¶ÌåÖ²ÖêµÄÓ×Ã磬¿ÉÄÜ»ñµÃÒ©ÓóɷֽϸߵÄÁù±¶ÌåÖ²Öê¡£ÇïË®ÏÉËصÄ×÷ÓûúÀíÊÇ__________________________________¡£
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com