(I)利用等比数列的前n项和公式求出等比数列的首项,进一步求出数列的通项公式;(II)由第一问求得a
3,再根据三角函数最值知识求出角
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(I)由 q=3, S
3=
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得
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…………………2分
解得 a
1=
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…………………4分
所以a
n=
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×3
n-1=3
n-2 …………………6分
(II)由(I)可知
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…………………8分
因为函数
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的最大值为3,所以A="3." ………………… 9分
因为当
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时f(x)取得最大值, 所以sin(2×
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+
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)=1
又0<
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<π,故
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=
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…………………11分
所以函数f(x)的解析式为f(x)=3sin(2x+
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)