解:(新编题)
(1)∵
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,
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,∴
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,-------------------------2分
∴
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.
∵
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成等差数列,∴
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,
即
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,∴
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.---------------------------------------------------5分
解得
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,或
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(舍去).-----------------------------------------------------------------6分
(2)∵

,
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,
∴
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,-------------------8分
∴
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,------------------------------------------9分
又

,∴数列

的通项公式是
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.-----------------------------------10分
(3)证明:∵数列

是首项为1,公比为

的等比数列,∴
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.---------11分
∵
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,
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,
∴
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, ①
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, ②
①式两边乘以
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得
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③
由②③得
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将
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代入上式,得
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.-----------------------------------------14分
另证: 先用错位相减法求
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,再验证
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.
∵数列

是首项为1,公比为

的等比数列,∴

. --------------11分
又
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,所以
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①
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②
将①乘以2得:
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③
①-③得:
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,
整理得:
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-------------------------12分
将②乘以
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得:
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④
②-④整理得:
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-----------------------------------------13分
∴
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-----------------------------------------14分