Question

已知m∈R，a＞b＞1,f(x)=,试比较f(a)与f(b)的大小.

Answer 1

解析：f(x)=m(1+),

f(a)=m(1+),f(b)=m(1+),

由a＞b＞1,知a-1＞b-1＞0,所以

1+＜1+.

当m＞0时，m(1+  )＜m(1+),f(a)＜f(b);

当m=0时，f(a)=f(b);

当m＜0时，m(1+)＞m(1+),f(a)＞f(b).