试题分析:(1)由直线的两点式方程
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可直接得出,或者先由两点求其斜率,再用直线的点斜式方程
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;(2)求圆的方程 ,只需确定其圆心和半径,由题意可知,圆心横坐标是2,代入直线方程求其纵坐标,从而圆心确定,因为圆C与
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轴相切,所以半径就是圆心的纵坐标的绝对值,从而圆的方程确定.
试题解析:(1)由题可知:直线l经过点(2, 1), (6, 3),由两点式可得直线l的方程为:
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整理得:
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5分
(2)依题意:设圆C的方程为:
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其圆心为
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,∵圆心C在
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上,∴2-2·
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=0,
∴k=-1,∴圆C的方程为
即
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12分