【答案】
分析:首先分析题目已知不等式组的整数解集为{-2},求k的取值范围,考虑到通过分解因式的方法化简方程组,然后分类讨论当k>
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时和当k≤
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时的情况解出方程组含有参数k的解集,然后根据整数解集为{-2},判断k的取值范围即可.
解答:解:关于x的不等式组
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,变形为
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当k>
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时:
原方程组变形为:
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,故方程解为
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,不满足整数解集为{-2},故不成立.
当k≤
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时:
原方程变形为
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,因为方程整数解集为{-2},故-k>-2,且k≤
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.
故-
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≤k<2
故答案为-
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≤k<2.
点评:此题主要考查一元二次不等式组的解集的问题,题中应用到分类讨论的思想,在解不等式中经常用到.题目涵盖知识点少但有一点的计算量,属于中档题目.