试题分析:由等比数列的性质,
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又对任意
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恒成立,所以
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,所以
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.
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科目:高中数学
来源:不详
题型:解答题
等比数列
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的前
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项和
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,已知
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,
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,
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,
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成等差数列.
(1)求数列
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的公比
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和通项
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;
(2)若
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是递增数列,令
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,求
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.
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科目:高中数学
来源:不详
题型:解答题
各项均为正数的等比数列
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中,
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.
(1)求数列
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通项公式;
(2)若
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,求证:
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.
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科目:高中数学
来源:不详
题型:解答题
已知等比数列
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中,
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,
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,等差数列
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中,
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,且
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.
⑴求数列
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的通项公式
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;
⑵求数列
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的前
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项和
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.
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科目:高中数学
来源:不详
题型:单选题
在各项都为正数的等比数列
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中,首项为3,前3项和为21,则
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等于( )
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科目:高中数学
来源:不详
题型:单选题
已知数列{a
n}是逐项递减的等比数列,其首项a
1<0,则其公比q的取值范围是( )
A.(- ,-1) | B.(-1,0) | C.(0,1) | D.(1,+ ) |
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