10£®ÔÚÎÒУ½øÐеÄÑ¡Ð޿νáÒµ¿¼ÊÔÖУ¬ËùÓÐÑ¡ÐÞ¡°ÊýѧÓëÂß¼­¡±µÄͬѧ¶¼Í¬Ê±Ò²Ñ¡ÐÞÁË¡°ÔĶÁÓë±í´ï¡±µÄ¿Î³Ì£¬Ñ¡ÐÞ¡°ÔĶÁÓë±í´ï¡±µÄͬѧ¶¼Í¬Ê±Ò²Ñ¡ÐÞÁË¡°ÊýѧÓëÂß¼­¡±µÄ¿Î³Ì£®Ñ¡Ð޿νáÒµ³É¼¨·ÖΪA£¬B£¬C£¬D£¬EÎå¸öµÈ¼¶£®Ä³¿¼³¡¿¼ÉúµÄÁ½¿Æ¿¼ÊԳɼ¨µÄÊý¾Ýͳ¼ÆÈçͼËùʾ£¬ÆäÖС°ÊýѧÓëÂß¼­¡±¿ÆÄ¿µÄ³É¼¨ÎªBµÄ¿¼ÉúÓÐ10ÈË£¬

£¨1£©Çó¸Ã¿¼³¡¿¼ÉúÖС°ÔĶÁÓë±í´ï¡±¿ÆÄ¿Öгɼ¨ÎªAµÄÈËÊý£»
£¨2£©ÏÖÔÚ´Ó¡°ÊýѧÓëÂß¼­¡±¿ÆÄ¿µÄ³É¼¨ÎªAºÍDµÄ¿¼ÉúÖÐËæ»ú³éÈ¡Á½ÈË£¬ÔòÇó³éµ½µÄÁ½Ãû¿¼Éú¶¼Êdzɼ¨ÎªAµÄ¿¼ÉúµÄ¸ÅÂÊ£®

·ÖÎö £¨1£©¸ù¾Ý¡°ÊýѧÓëÂß¼­¡±¿ÆÄ¿µÄ³É¼¨ÎªBµÄ¿¼ÉúÓÐ10ÈË£¬½áºÏÑù±¾ÈÝÁ¿=ƵÊý¡ÂƵÂʵóö¸Ã¿¼³¡¿¼ÉúÈËÊý£¬´Ó¶øµÃµ½¸Ã¿¼³¡¿¼ÉúÖС°ÔĶÁÓë±í´ï¡±¿ÆÄ¿Öгɼ¨µÈ¼¶ÎªAµÄÈËÊý£»
£¨2£©Í¨¹ýÁоٵķ½·¨¼ÆËã³öÑ¡³öµÄ2ÈËËùÓпÉÄܵÄÇé¿ö¼°ÕâÁ½È˵ÄÁ½¿Æ³É¼¨µÈ¼¶¾ùΪAµÄÇé¿ö£»ÀûÓùŵä¸ÅÐ͸ÅÂʹ«Ê½Çó³öËæ»ú³éÈ¡Á½È˽øÐзÃ̸£¬ÕâÁ½È˵ÄÁ½¿Æ³É¼¨µÈ¼¶¾ùΪAµÄ¸ÅÂÊ£®

½â´ð ½â£º£¨1£©ÒòΪ¡°ÊýѧÓëÂß¼­¡±¿ÆÄ¿Öгɼ¨µÈ¼¶ÎªBµÄ¿¼ÉúÓÐ10ÈË£¬
ËùÒԸÿ¼³¡ÓÐ10¡Â0.25=40ÈË£¬¡­£¨2·Ö£©
ËùÒԸÿ¼³¡¿¼ÉúÖС°ÔĶÁÓë±í´ï¡±¿ÆÄ¿Öгɼ¨µÈ¼¶ÎªAµÄÈËÊýΪ40¡Á£¨1-0.375-0.375-0.15-0.025£©=3 ÈË£»  ¡­£¨4·Ö£©
£¨2£©ÒòΪ¡°ÊýѧÓëÂß¼­¡±¿ÆÄ¿Öгɼ¨µÈ¼¶ÎªBµÄ¿¼ÉúÓÐ10ÈË£¬ËùÒԸÿ¼³¡ÓÐ10¡Â0.25=40ÈË£¬Ôò³É¼¨ÎªAµÄ¿¼ÉúÓÐ40¡Á0.075=3ÈË£¬¡­£¨6·Ö£©
³É¼¨ÎªDµÄ¿¼ÉúÓÐ40¡Á£¨1-0.2-0.375-0.25-0.075£©=4ÈË        ¡­£¨8·Ö£©
Éè³É¼¨ÎªAµÄ¿¼ÉúΪa¡¢b¡¢c£¬³É¼¨ÎªDµÄ¿¼ÊÔΪd¡¢e¡¢f¡¢g£®
Ëæ»ú³éÈ¡Á½È˽øÐзÃ̸£¬»ù±¾Ê¼þ¹²ÓÐ21¸ö£¬·Ö±ðΪ£¨a£¬b£©£¨a£¬c£©£¨a£¬d£©£¨a£¬e£©£¨a£¬f£©£¨a£¬g£©£¨b£¬c£©£¨b£¬d£©£¨b£¬e£©£¨b£¬f£©£¨b£¬g£©£¨c£¬d£©£¨c£¬e£©£¨c£¬f£©£¨c£¬g£©£¨d£¬e£©£¨d£¬f£©£¨d£¬g£©£¨e£¬f£©£¨e£¬g£©£¨f£¬g£©
ÉèʼþN£º³éµ½µÄÁ½Ãû¿¼Éú¶¼Êdzɼ¨ÎªAµÄ¿¼Éú£¬¡­£¨10·Ö£©
ÔòʼþN°üº¬£¨a£¬b£©£¨a£¬c£©£¨b£¬c£©£¬
Ôò$P£¨N£©=\frac{3}{21}=\frac{1}{7}$¡­£¨12·Ö£©

µãÆÀ ±¾Ð¡ÌâÖ÷Òª¿¼²éͳ¼ÆÓë¸ÅÂʵÄÏà¹Ø֪ʶ£¬¾ßÌåÉæ¼°µ½ÆµÂÊ·Ö²¼Ö±·½Í¼¼°¹Åµä¸ÅÐ͵ÈÄÚÈÝ£®ÊôÓÚ»ù´¡Ì⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

20£®ÏÂÁÐÈý½Çº¯ÊýÖµ´óС±È½ÏÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®sin$\frac{19¦Ð}{8}$£¼cos$\frac{14¦Ð}{9}$B£®sin£¨-$\frac{54¦Ð}{7}$£©£¼sin£¨-$\frac{63¦Ð}{8}$£©
C£®tan£¨-$\frac{13¦Ð}{4}$£©£¾tan£¨-$\frac{17¦Ð}{5}$£©D£®tan138¡ã£¾tan143¡ã

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

1£®¹ýË«ÇúÏß$\frac{{x}^{2}}{{a}^{2}}$-$\frac{{y}^{2}}{{b}^{2}}$=1£¨a£¾0£¬b£¾0£©µÄÓÒ½¹µãF×öÔ²x2+y2=a2µÄÇÐÏߣ¬ÇеãΪM£¬ÇÐÏß½»yÖáÓÚµãP£¬ÇÒ$\overrightarrow{FM}$=2$\overrightarrow{MP}$£¬ÔòË«ÇúÏßµÄÀëÐÄÂÊΪ£¨¡¡¡¡£©
A£®$\sqrt{2}$B£®$\sqrt{3}$C£®2D£®$\sqrt{5}$

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

18£®Èçͼ£¬ÕýÈýÀâÖùABC-A1B1C1µÄµ×Ãæ±ß³¤ÊÇ2£¬²àÀⳤÊÇ$\sqrt{3}$£¬DÊÇACµÄÖе㣮
£¨¢ñ£©ÇóÖ¤£ºB1C¡ÎƽÃæA1BD£»
£¨¢ò£©Çó¶þÃæ½ÇA-A1B-DµÄÓàÏÒÖµ£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

5£®ÈôÍÖÔ²$\frac{y^2}{16}+\frac{x^2}{9}=1ºÍË«ÇúÏß\frac{y^2}{4}-\frac{x^2}{5}=1$µÄ¹²Í¬½¹µãΪF1¡¢F2£¬PÊÇÁ½ÇúÏßµÄÒ»¸ö½»µã£¬Ôò|PF1|•|PF2|µÄֵΪ£¨¡¡¡¡£©
A£®12B£®14C£®3D£®21

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

15£®ÕýÏîµÈ²îÊýÁÐ{an}µÄÇ°nÏîºÍΪSn£¬ÒÑÖªa4+a10-a72+15=0£¬ÔòS13=£¨¡¡¡¡£©
A£®-39B£®5C£®39D£®65

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

2£®Ä³ÐËȤС×éÓûÑо¿Öçҹβî´óСÓ뻼¸ÐðÈËÊý¶àÉÙÖ®¼äµÄ¹Øϵ£¬ËûÃÇ·Ö±ðµ½ÆøÏó¾ÖÓëijҽԺ³­Â¼ÁË1ÖÁ6Ô·ÝÿÔÂ10ºÅµÄÖçҹβîÇé¿öÓëÒò»¼¸Ðð¶ø¾ÍÕïµÄÈËÊý£¬µÃµ½ÈçÏÂ×ÊÁÏ£º
ÈÕ    ÆÚ1ÔÂ10ÈÕ2ÔÂ10ÈÕ3ÔÂ10ÈÕ4ÔÂ10ÈÕ5ÔÂ10ÈÕ6ÔÂ10ÈÕ
Öçҹβîx£¨¡ãC£©1011131286
¾ÍÕïÈËÊýy£¨¸ö£©222529261612
¸ÃÐËȤС×éÈ·¶¨µÄÑо¿·½°¸ÊÇ£ºÏÈ´ÓÕâÁù×éÊý¾ÝÖÐÑ¡È¡2×飬ÓÃʣϵÄ4×éÊý¾ÝÇóÏßÐԻع鷽³Ì£¬ÔÙÓñ»Ñ¡È¡µÄ2×éÊý¾Ý½øÐмìÑ飮
£¨1£©ÇóÑ¡È¡µÄ2×éÊý¾ÝÇ¡ºÃÊÇÏàÁÚÁ½¸öÔµĸÅÂÊ£»
£¨2£©ÈôÑ¡È¡µÄÊÇ1ÔÂÓë6ÔµÄÁ½×éÊý¾Ý£¬Çë¸ù¾Ý2ÖÁ5Ô·ݵÄÊý¾Ý£¬Çó³öy¹ØÓÚxµÄÏßÐԻع鷽³Ìy=bx+a£»
£¨¸½£º$\widehat{b}$=$\frac{\sum_{i=1}^{n}£¨{x}_{i}-\overline{x}£©£¨{y}_{i}-\overline{y}£©}{\sum_{i=1}^{n}£¨{x}_{i}-\overline{x}£©^{2}}$=$\frac{\sum_{i=1}^{n}{x}_{i}{y}_{i}-n\overline{x}\overline{y}}{\sum_{i=1}^{n}{x}_{i}^{2}-n{\overline{x}}^{2}}$£©

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£º½â´ðÌâ

19£®ÊýÁÐ{an}µÄÇ°nÏîºÍΪSn£®
£¨1£©µ±{an}ÊǵȱÈÊýÁУ¬a1=1£¬ÇÒ$\frac{1}{a_1}$£¬$\frac{1}{a_3}$£¬$\frac{1}{a_4}$-1ÊǵȲîÊýÁÐʱ£¬Çóan£»
£¨2£©Èô{an}ÊǵȲîÊýÁУ¬ÇÒS1+a2=7£¬S2+a3=15£¬Ö¤Ã÷£º¶ÔÓÚÈÎÒân¡ÊN*£¬¶¼ÓУº$\frac{1}{{{S_1}+1}}+\frac{1}{{{S_2}+2}}+\frac{1}{{{S_3}+3}}+¡­+\frac{1}{{{S_n}+n}}£¼\frac{2}{3}$£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÊýѧ À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

20£®ÒÑÖªº¯Êýf£¨x£©=Asin£¨¦Øx+¦Õ£©£¨A£¾0£¬¦Ø£¾0£©µÄ²¿·ÖͼÏóÈçͼËùʾ£¬Ôòf£¨-$\frac{¦Ð}{6}$£©µÄֵΪ£¨¡¡¡¡£©
A£®-1B£®1C£®-$\frac{1}{2}$D£®$\frac{1}{2}$

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸