首先将函数g(x)=f(x)-log
a|x|恰有6个零点,这个问题转化成f(x)=log
a|x|的交点来解决.数形结合:如图,f(x+2)=f(x),知道周期为2,当-1<x≤1时,f(x)=x
3图象可以画出来,同理左右平移各2个单位,得到在(-7,7)上面的图象,以下分两种情况:
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(1)当a>1时,log
a|x|如图所示,左侧至少有4个交点,右侧至少2个,此时应满足log
a5≤1,即log
a5≤log
aa,所以
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.
(2)当0<a<1时,log
a|x|与f(x)交点,左侧至少有2个交点,右侧至少有4个,此时应满足log
a5>-1,即log
a5<-log
aa,所以
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.故
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.