试题分析:解:(1)由
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,
由
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代入
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可得
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,且
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.……………………………………………………2分
当
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时,
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(成立),当
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时,
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(舍去).
所以
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,
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.…………………………………………………………………………4分
(2)
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,即
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.
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时,
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.
所以,当
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时,由
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可得
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,
整理得,
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.
又
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得
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,且
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,
所以
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是首项为1,公差为1的等差数列,即
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,
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.
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. ………………………………………………………………………………7分
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,
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,
由上两式相减得
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.
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. ……………………………………………………………………10分
(3)由(2)知
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,只需证
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.设
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(
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且
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).
则
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,
可知
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在
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上是递减,
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.
由
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,则
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,
故
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. …………………………………………………………………………14分
点评:解决数列与函数与不等式的综合试题,是高考中常考的知识交汇点试题,熟练掌握错位相减法求和,属于中档题。