Question

17£®Èçͼʾ£¬AΪÁ£×ÓÔ´£¬ÔÚAºÍ¼«°åB ¼äµÄ¼ÓËÙµçѹΪU₁£¬ÔÚÁ½Ë®Æ½·ÅÖõÄƽÐдøµç°åC¡¢D¼äµÄµçѹΪU₂£¬ÏÖÉèÓÐÖÊÁ¿Îªm£®µçÁ¿ÎªqµÄÖÊ×Ó³õËÙΪÁã´ÓA±»¼ÓËÙµçѹU₁¼ÓËÙºóˮƽ½øÈëÊúÖ±·½ÏòµÄÔÈÇ¿µç³¡£¬Æ½Ðдøµç°åµÄ¼«°åµÄ³¤¶ÈΪL£¬Á½°å¼äµÄ¾àÀëΪd£¬²»¼Æ´øµçÁ£×ÓµÄÖØÁ¦£¬Çó£º
£¨1£©´øµçÁ£×ÓÔÚÉä³öB°åʱµÄËٶȣ»
£¨2£©´øµçÁ£×ÓÔÚC¡¢D¼«°å¼äÔ˶¯µÄʱ¼ä£»
£¨3£©´øµçÁ£×ӷɳöC¡¢Dµç³¡Ê±ÔÚÊúÖ±·½ÏòÉÏ·¢ÉúµÄλÒÆyºÍƫתµÄ½Ç¶È£®

Answer 1

·ÖÎö £¨1£©Á£×ÓÔÚAB°å¼ä×öÔȼÓËÙÖ±ÏßÔ˶¯£¬¸ù¾Ý¶¯Äܶ¨ÀíÁÐʽÇó½âÁ£×ÓÔÚÉä³öB°åʱµÄËٶȣ»
£¨2£©Á£×ÓÔÚCD°å¼ä×öÀàËÆƽÅ×Ô˶¯£¬¸ù¾ÝÀàƽÅ×Ô˶¯µÄˮƽ·ÖÔ˶¯¹«Ê½ÁÐʽÇó½â£»
£¨3£©Á£×ÓÔÚCD°å¼ä×öÀàËÆƽÅ×Ô˶¯£¬¸ù¾ÝÀàƽÅ×Ô˶¯µÄÊúÖ±·ÖÔ˶¯¹«Ê½ÁÐʽÇó½â£®

½â´ð ½â£º£¨1£©´øµçÁ£×ÓÓÉAµ½B£¬Éèµ½B°åµÄËÙ¶ÈΪv£¬¸ù¾Ý¶¯Äܶ¨Àí£º
$q{U_1}=\frac{1}{2}m{v^2}$£¬
½âµÃ£ºv=$\sqrt{\frac{{2U}_{1}q}{m}}$
£¨2£©Á£×Ó½øÈëC¡¢Dµç³¡ºóˮƽ·½Ïò×öÔÈËÙÖ±ÏßÔ˶¯£¬
ÔòL=vt£¬
½âµÃ£ºt=$\frac{L}{v}$=$L\sqrt{\frac{m}{2{U}_{1}q}}$£¬
£¨3£©Á£×ÓÔÚÊúÖ±·½Ïò×ö³õËÙ¶ÈΪÁãµÄÔȼÓËÙÖ±ÏßÔ˶¯£¬¼ÓËÙ¶ÈΪ£º
Eq=ma£¬E=$\frac{{U}_{2}}{d}$£¬ËùÒÔa=$\frac{{U}_{2}q}{md}$£®
Á£×Ó½øÈëC¡¢Dµç³¡ÔÚÊúÖ±·½Ïò·¢ÉúµÄλÒÆ
y=$\frac{1}{2}$at²=$\frac{1}{2}$$\frac{{U}_{2}q}{md}$ £¨$L\sqrt{\frac{m}{2{U}_{1}q}}$£©²=$\frac{{U}_{2}{L}^{2}}{4{U}_{1}d}$
$tan¦È=\frac{v_y}{v_x}=\frac{{2¡Á\frac{1}{2}{v_y}t}}{{{v_x}t}}=\frac{2y}{L}=\frac{{{U_2}L}}{{2{U_1}d}}$£¬
¦È=$arctan\frac{{U}_{2}L}{{2U}_{1}d}$
´ð£º£¨1£©´øµçÁ£×ÓÔÚÉä³öB°åʱµÄËÙ¶È$\sqrt{\frac{{2U}_{1}q}{m}}$£»
£¨2£©´øµçÁ£×ÓÔÚC¡¢D¼«°å¼äÔ˶¯µÄʱ¼ä$L\sqrt{\frac{m}{2{U}_{1}q}}$£»
£¨3£©´øµçÁ£×ӷɳöC¡¢Dµç³¡Ê±ÔÚÊúÖ±·½ÏòÉÏ·¢ÉúµÄλÒÆ$\frac{{U}_{2}{L}^{2}}{4{U}_{1}d}$ºÍƫתµÄ½Ç¶È$arctan\frac{{U}_{2}L}{{2U}_{1}d}$£®

µãÆÀ ±¾Ìâ¹Ø¼üÃ÷È·Á£×ÓµÄÔ˶¯ÐÔÖÊ£¬¶ÔÓ¦Ö±Ïß¼ÓËÙ¹ý³Ì£¬¸ù¾Ý¶¯Äܶ¨ÀíÁÐʽ£»¶ÔÓÚÀàËÆƽÅ×Ô˶¯¹ý³Ì£¬¸ù¾ÝÀàËÆƽÅ×Ô˶¯µÄ·ÖÔ˶¯¹«Ê½ÁÐʽÇó½â£»²»ÄÑ£®