6£®Ä³±Ä´²Ô˶¯Ô±ÔÚÒ»´Î±Ä´²Ô˶¯ÖнöÔÚÊúÖ±·½ÏòÔ˶¯£¬ÈçͼΪ±Ä´²¶Ô¸ÃÔ˶¯Ô±µÄ×÷ÓÃÁ¦FËæʱ¼ätµÄ±ä»¯Í¼Ï󣬲»¿¼ÂÇ¿ÕÆø×èÁ¦µÄÓ°Ï죬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®t1ÖÁt2¹ý³ÌÄÚÔ˶¯Ô±ºÍ±Ä´²¹¹³ÉµÄϵͳ»úеÄÜÔö¼Ó
B£®t1ÖÁt2¹ý³ÌÄÚÔ˶¯Ô±ºÍ±Ä¹¹³ÉµÄϵͳ»úеÄÜÊغã
C£®t3ÖÁt4¹ý³ÌÄÚÔ˶¯Ô±ºÍ±Ä´²µÄÊÆÄÜÖ®ºÍÔö¼Ó
D£®t3ÖÁt4¹ý³ÌÄÚÔ˶¯Ô±ºÍ±Ä´²µÄÊÆÄÜÖ®ºÍÏȼõСºóÔö¼Ó

·ÖÎö ÌøÔ¾ÕßËùÊܵÄÀ­Á¦Ô½´ó£¬Î»ÖÃÔ½µÍ£»µ±À­Á¦×î´ó£¬Î»ÖÃ×îµÍʱ£¬ÌøÔ¾ÕßËÙ¶ÈΪÁ㣻µ±ÌøÔ¾ÕßËٶȴﵽ×î´óֵʱ£¬ÌøÔ¾ÕßËùÊÜÀ­Á¦ÓëÖØÁ¦ÏàµÈ£¬»úеÄÜÊغãµÄÌõ¼þÊÇÖ»ÓÐÖØÁ¦»òµ¯»ÉµÄµ¯Á¦×ö¹¦£®

½â´ð ½â£º»úеÄÜÊغãµÄÌõ¼þÊÇÖ»ÓÐÖØÁ¦»òµ¯»ÉµÄµ¯Á¦×ö¹¦£¬ËùÒÔÕû¸ö¹ý³ÌÖØÁ¦ÊÆÄÜ¡¢µ¯ÐÔÊÆÄܺͶ¯ÄÜ×ÜÁ¿±£³Ö²»±ä£¬
A¡¢B¡¢t1ÖÁt2¹ý³ÌÄÚµ¯»ÉµÄµ¯Á¦Öð½¥±ä´ó£¬×ö¹¦Ôö¼Ó£¬Ô˶¯Ô±ºÍ±Ä´²¹¹³ÉµÄϵͳ»úеÄÜÔö¼Ó£¬¹ÊAÕýÈ·£¬B´íÎó£»
C¡¢D¡¢t2ÒԺ󣬱Ĵ²µÄµ¯Á¦×î´óÖµ²»±ä£¬Õû¸ö¹ý³ÌÖØÁ¦ÊÆÄÜ¡¢µ¯ÐÔÊÆÄܺͶ¯ÄÜ×ÜÁ¿±£³Ö²»±ä£¬t3ʱ¿Ìµ¯Á¦ÎªÁ㣬ÖØÁ¦´óÓÚµ¯Á¦£¬Ô˶¯Ô±×ö¼ÓËٶȼõСµÄ¼ÓËÙÔ˶¯£¬Ô˶¯Ô±µÄ¶¯ÄÜÔö¼Ó£¬µ±ÖØÁ¦µÈÓÚµ¯Á¦Ê±£¬¼ÓËÙ¶ÈΪÁãËÙ¶È×î´ó£¬ÔÙÏòºó£¬µ¯Á¦´óÓÚÖØÁ¦£¬Ô˶¯Ô±×ö¼ÓËÙ¶ÈÔö´óµÄ¼õËÙÔ˶¯£¬Ô˶¯Ô±µÄ¶¯ÄܼõС£¬t4ʱËÙ¶È×îС£¬¹Ê¶¯ÄÜÏÈÔö´óºó¼õС£¬¹ÊÔ˶¯Ô±ºÍ±Ä´²µÄÊÆÄÜÖ®ºÍÏȼõСºóÔö¼Ó£¬¹ÊC´íÎó£»DÕýÈ·£»
¹ÊÑ¡£ºAD

µãÆÀ ±¾ÌâÖÐÔ˶¯Ô±ºÍµ¯ÐÔÉþϵͳ»úеÄÜÊغ㣬·ÖÎöÀ­Á¦Ëæʱ¼ä±ä»¯µÄ¹ØϵÊǽâÌâµÄ¹Ø¼ü£¬Í¨¹ýÔ˶¯Ô±±Ä´²Ê±£¬¿¼²éÁËÖØÁ¦ÊÆÄܱ仯¡¢×ö¹¦¡¢ºÏÁ¦µÈµÈ£¬ÌåÏÖÁËÌåÓýÔ˶¯Öаüº¬Á˺ܶàµÄÎïÀí֪ʶ£¬Äã¿ÉÒÔÊÔ×Å·ÖÎöÒ»ÏÂÆäËüµÄÌåÓýÔ˶¯ÖеÄÎïÀí֪ʶ£¬±¾ÌâÓÐÒ»¶¨µÄÄѶȣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÏ°Ìâ

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

16£®ÈçͼËùʾ£¬LÊÇ×Ô¸ÐϵÊýºÜ´ó¡¢µç×èºÜСµÄÏßȦ£¬ÈôºÏÉÏ»ò¶Ï¿ª¿ª¹ØS1ºÍS2ʱ£¬ÒÔÏÂ˵·¨²»ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Ö»±ÕºÏS1µÄ˲¼ä£¬L1µÆÖð½¥ÁÁÆðÀ´
B£®ÔÙºÏÉÏS2Îȶ¨ºó£¬L2µÆÊÇ°µµÄ
C£®Ö»¶Ï¿ªS1˲¼ä£¬L1µÆÁ¢¼´Ï¨Ãð£¬L2µÆÁÁÒ»ÏÂÔÙϨÃð
D£®Ö»¶Ï¿ªS1˲¼ä£¬L2ºÍL1µÆ¹ýÒ»»á¶ù²ÅϨÃð

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ

17£®ÒÑÖªµØÇò°ë¾¶ÎªR£¬µØÇò±íÃæµÄÖØÁ¦¼ÓËÙ¶ÈΪg£¬×Ôת½ÇËÙ¶ÈΪ¦Ø£¬Éèij¿Åͬ²½ÎÀÐǾàµØ±í¸ß¶ÈΪh£¬Ôò¹ØÓÚͬ²½ÎÀÐÇÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÔÚ±¦¼¦µØÇøµÄÕýÉÏ·½ÓпÉÄܹ۲쵽Õâ¿Åͬ²½ÎÀÐÇ
B£®´Ëͬ²½ÎÀÐǵÄÏßËٶȴóСΪ¦ØR
C£®²»Í¬¹ú¼Ò·¢ÉäµÄͬ²½ÎÀÐÇ¿ÉÒÔÔÚÀëµØ²»Í¬¸ß¶È´¦ÔËÐÐ
D£®ÎÞÂÛÄĸö¹ú¼Ò·¢ÉäµÄͬ²½ÎÀÐÇÔÚ¹ìµÀÉÏÔËÐеÄÏßËٶȶ¼ÊÇR$\sqrt{\frac{g}{R+h}}$

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

14£®ÈçͼËùʾ£¬ÖÊÁ¿ÎªmµÄÎïÌå·ÅÔÚµ¯»ÉÉÏ£¬Ó뵯»ÉÒ»ÆðÔÚÊúÖ±·½ÏòÉÏ×ö¼òгÔ˶¯£®µ±Õñ·ùΪAʱ£¬ÒÑÖªÎïÌåÕñ¶¯µ½×îµÍµãʱ¶Ôµ¯»ÉµÄѹÁ¦ÎªÎïÌåÖØÁ¦µÄ1.5±¶£®Çó£º
£¨1£©µ¯»ÉµÄ¾¢¶ÈϵÊýKºÍÎïÌåÕñ¶¯µ½×îµÍµãʱËùÐèµÄ»Ø¸´Á¦µÄ´óС£®
£¨2£©ÎïÌåÕñ¶¯µ½Æ½ºâλÖÃʱµ¯»ÉµÄÐαäÁ¿µÄ´óС£®
£¨3£©ÎïÌåÕñ¶¯µ½×î¸ßµãʱµ¯»ÉµÄµ¯Á¦ÊǶà´ó£®
£¨4£©ÒªÊ¹ÎïÌåÔÚÕñ¶¯Öв»À뿪µ¯»É£¬Õñ·ù²»Äܳ¬¹ý¶à´ó£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

1£®Èçͼ£¬Æøµæµ¼¹ìÉÏ»¬¿éµÄÖÊÁ¿ÎªM£¬¹³ÂëµÄÖÊÁ¿Îªm£¬ÕÚ¹âÌõ¿í¶ÈΪd£¬Á½¹âµçÃżäµÄ¾àÀëΪL£¬ÆøÔ´¿ªÍ¨ºó»¬¿éÔÚÇ£ÒýÁ¦µÄ×÷ÓÃÏÂÏȺóͨ¹ýÁ½¸ö¹âµçÃŵÄʱ¼äΪ¡÷t1ºÍ¡÷t2£®µ±µØµÄÖØÁ¦¼ÓËÙ¶ÈΪg
£¨1£©ÓÃÉÏÊö×°ÖòâÁ¿»¬¿é¼ÓËٶȵıí´ïʽΪ$a=\frac{d^2}{2L}£¨\frac{1}{{¡÷t{\;}_2^2}}-\frac{1}{¡÷t_1^2}£©$£¨ÓÃÒÑÖªÁ¿±íʾ£©£»
£¨2£©ÓÃÉÏÊö×°ÖÃ̽¾¿»¬¿é¼ÓËÙ¶ÈaÓëÖÊÁ¿M¼°À­Á¦FµÄ¹Øϵ£¬ÒªÊ¹ÉþÖÐÀ­Á¦½üËƵÈÓÚ¹³ÂëµÄÖØÁ¦£¬ÔòmÓëMÖ®¼äµÄ¹ØϵӦÂú×ãM£¾£¾m£»
£¨3£©ÓÃÉÏÊö×°ÖÃ̽¾¿ÏµÍ³ÔÚÔ˶¯ÖеĻúеÄܹØϵ£¬»¬¿é´Ó¹âµçÃÅ1Ô˶¯µ½¹âµçÃÅ2µÄ¹ý³ÌÖÐÂú×ã¹Øϵʽ$mgL=\frac{1}{2}£¨M+m£©£¨\frac{d^2}{¡÷t_2^2}-\frac{d^2}{¡÷t_1^2}£©$ʱ£¨ÓÃÒÑÖªÁ¿±íʾ£©£¬ÏµÍ³»úеÄÜÊغ㣮Èô²âÁ¿¹ý³ÌÖз¢ÏÖϵͳ¶¯ÄÜÔöÁ¿×ÜÊÇ´óÓÚ¹³ÂëÖØÁ¦ÊÆÄܵļõÉÙÁ¿£¬¿ÉÄܵÄÔ­ÒòÊǵ¼¹ì²»Æ½£¬ÓҶ˸ߣ®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

11£®Èçͼ£¬ÊúֱƽÃæÄÚÓÐÊúÖ±·ÅÖõÄ×ã¹»³¤µÄƽÐй⻬µ¼¹ì£¬µ¼¹ì¼ä¾àΪl£¬µç×è²»¼Æ£¬µ¼¹ì¼äÓÐˮƽ·½ÏòµÄÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶È´óСΪB£¬·½ÏòÈçͼËùʾ£¬ÓÐÁ½¸ùÖÊÁ¿¾ùΪm£¬³¤¶È¾ùΪl£¬µç×è¾ùΪRµÄµ¼Ìå°ôabºÍcdʼÖÕÓëµ¼¹ì½Ó´¥Á¼ºÃ£¬µ±ÓÃÊúÖ±ÏòÉϵÄÁ¦Fʹab°ôÏòÉÏ×öÔÈËÙÔ˶¯£¬cd°ôÒ²ÒÔÏàͬµÄËÙÂÊÏòÏÂÔÈËÙÔ˶¯£¬²»¼Æ¿ÕÆø×èÁ¦£¬ÖØÁ¦¼ÓËÙ¶ÈΪg£¬ÔòÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Á½°ôÔ˶¯µÄËÙ¶ÈΪv=$\frac{mgR}{2{B}^{2}{l}^{2}}$
B£®Á¦FµÄ´óСΪ2mg
C£®»Ø·ÖеÄÈȹ¦ÂÊΪP=$\frac{2{m}^{2}{g}^{2}R}{{B}^{2}{l}^{2}}$
D£®Èô³·È¥À­Á¦Fºó£¬Á½°ô×îÖÕÒÔ´óСΪgµÄ¼ÓËÙ¶ÈÔȼÓËÙÔ˶¯

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ

5£®ÓÃÈçͼ1ʵÑé×°ÖÃÑéÖ¤m1¡¢m1×é³ÉµÄϵͳ»úеÄÜÊغ㣮m2´Ó¸ß´¦Óɾ²Ö¹¿ªÊ¼ÏÂÂ䣬m1ÏòÉÏÍÏ×ŵÄÖ½´ø´ò³öһϵÁеĵ㣬¶ÔÖ½´øÉϵĵ㼣½øÐвâÁ¿£¬¼´¿ÉÑéÖ¤»úеÄÜÊغ㶨ÂÉ£®Í¼2¸ø³öµÄÊÇʵÑéÖлñÈ¡µÄÒ»ÌõÖ½´ø£º0ÊÇ´òϵĵÚÒ»¸öµã£¬Ã¿ÏàÁÚÁ½¼ÆÊýµã¼ä»¹ÓÐ4¸öµã£¨Í¼ÖÐδ±ê³ö£©£¬¼ÆÊýµã¼äµÄ¾àÀëÈçͼËùʾ£®ÒÑÖªm1=50g¡¢m2=150g£¬´òµã¼ÆʱÆ÷ʹÓõĽ»Á÷µçƵÂÊΪ50Hz£¬Ôò£¨gÈ¡9.8m/s2£¬ËùÓнá¹û¾ù±£ÁôÈýλÓÐЧÊý×Ö£©£®

£¨1£©ÔÚÖ½´øÉÏ´òϼÆÊýµã5ʱµÄËÙ¶Èv5=2.40m/s£»
£¨2£©ÔÚ´òµã0¡«5¹ý³ÌÖÐϵͳ¶¯ÄܵÄÔöÁ¿¡÷Ek=0.576J£¬ÏµÍ³ÊÆÄܵļõÉÙÁ¿¡÷Ep=0.588J£»
£¨3£©Èôijͬѧ×÷³ö$\frac{{v}^{2}}{2}$-hͼÏóÈçͼ3£¬Ôòµ±µØµÄÖØÁ¦¼ÓËÙ¶Èg=9.70m/s2£®

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

2£®ÈçͼΪÇâÔ­×ÓµÄÄܼ¶Ê¾Òâͼ£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®´¦ÓÚn=2Äܼ¶µÄÇâÔ­×ÓÎüÊÕÒ»¸öÄÜÁ¿Îª10.2evµÄ¹â×ÓÄÜÁ¿Ô¾Ç¨µ½n=1Äܼ¶
B£®´¦ÓÚn=1Äܼ¶µÄÇâÔ­×ÓÎüÊÕÒ»¸öÄÜÁ¿Îª12.0evµÄÁ£×ÓµÄÄÜÁ¿Ô¾Ç¨µ½n=2Äܼ¶
C£®Ò»Èº´¦ÓÚn=3Äܼ¶µÄÇâÔ­×Ó×Ô·¢Ô¾Ç¨Ê±ÄÜ·¢³ö3ÖÖ²»Í¬ÆµÂʵĹâ×Ó
D£®Ò»¸ö´¦ÓÚn=4Äܼ¶µÄÇâÔ­×Ó×Ô·¢Ô¾Ç¨Ê±ÄÜ·¢³ö6ÖÖ²»Í¬ÆµÂʵĹâ×Ó

²é¿´´ð°¸ºÍ½âÎö>>

¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ

3£®¡°æ϶ðÈýºÅ¡±´ÓÈÆÔÂÔ²¹ìµÀ¢ñÉϵÄPµãʵʩ±ä¹ì£¬½øÈëÍÖÔ²¹ìµÀ¢ò£¬ÓɽüÔµãQ³É¹¦ÂäÔ£¬ÈçͼËùʾ£®¹ØÓÚ¡°æ϶ðÈýºÅ¡±£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÑعìµÀ¢ñÔ˶¯ÖÁPʱ£¬Ðè¼ÓËÙ²ÅÄܽøÈë¹ìµÀ¢ò
B£®ÑعìµÀ¢òÔËÐеÄÖÜÆÚСÓÚÑعìµÀ¢ñÔËÐеÄÖÜÆÚ
C£®ÑعìµÀ¢òÔËÐÐʱ£¬ÔÚPµãµÄ¼ÓËٶȴóÓÚÔÚQµãµÄ¼ÓËÙ¶È
D£®ÔÚ¹ìµÀ¢ñÉϵĻúеÄÜ´óÓÚ¹ìµÀ¢òÉϵĻúеÄÜ

²é¿´´ð°¸ºÍ½âÎö>>

ͬ²½Á·Ï°²á´ð°¸