Question

6£®ÈçͼËùʾ£¬Êǹ¤³§ÖеÄÐгµÊ¾Òâͼ£¬ÖÊÁ¿Îªm₁=1kgµÄ»¬¿é£¨¿ÉÊÓΪÖʵ㣩·ÅÔÚ³¤¶ÈΪL=1m£¬µÄÐгµ×ó¶Ë£¬¸ÖË¿ÉþÐüµãOµ½ËùµõÖý¼þµÄÖØÐÄPµÄ¾àÀëΪl=3m£¬Öý¼þµÄÖÊÁ¿Îªm₂=2.77t£¬»¬¿éÓëÐгµÖ®¼äµÄ¶¯Ä¦²ÁÒòÊý¦Ì=0.2£¬ÏÖÈû¬¿éºÍÐгµÒÔ
Ò»¶¨µÄËÙ¶ÈÔÈËÙÐÐÊ»£¬µ±ÐгµÍ»È»É²³µÍ£Ö¹Ê±£¬»¬¿é¸ÕºÃ²»´ÓÐÐ
³µÉÏ»¬Ï£¬ÖØÁ¦¼ÓËÙ¶Èg=10m/s²£¬Ôò£º
£¨1£©ÐгµÔÈËÙÐÐÊ»µÄËÙ¶Èv₀Ϊ¶à´ó£¿
£¨2£©µ±ÐгµÍ»È»Í£Ö¹µÄ˲¼ä£¬¸ÖË¿ÉþÊܵ½µÄÀ­Á¦ÊǶà´ó£¿

Answer 1

·ÖÎö £¨1£©¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÇ󻬿é¼õËÙÔ˶¯µÄ¼ÓËٶȣ¬½áºÏËÙ¶ÈλÒƹ«Ê½Çó¼õËÙÔ˶¯µÄ³õËٶȼ´ÐгµÔÈËÙÔ˶¯µÄËٶȣ»£®
£¨2£©ÐгµÍ»È»Í£³µµÄ˲¼ä£¬¸Õ²ÅÓÉÓÚ¹ßÐÔ£¬Öý¼þÈÆÐгµ×öÔ²ÖÜÔ˶¯£¬ÔÚ×îµÍµãʱ£¬ÖØÁ¦ºÍÀ­Á¦µÄºÏÁ¦ÌṩÏòÐÄÁ¦£®

½â´ð ½â£º£¨1£©É軬¿é×ö¼õËÙÔ˶¯µÄ¼ÓËٶȵĴóСΪa£¬ÓÉÅ£¶ÙµÚ¶þ¶¨Âɵãº
$¦Ì{m}_{1}^{\;}g={m}_{1}^{\;}a$
½âµÃ£º$a=¦Ìg=2m/{s}_{\;}^{2}$
ÓÉÔ˶¯Ñ§¹«Ê½£¬ÓÐ
$2aL={v}_{0}^{2}$
½âµÃ£º${v}_{0}^{\;}=\sqrt{2aL}=\sqrt{2¡Á2¡Á1}m/s=2m/s$
£¨2£©ÉèÐгµÍ»È»Í£Ö¹µÄ˲¼ä£¬¸ÖË¿ÉþµÄÀ­Á¦ÎªF£¬ÓÉÅ£¶ÙµÚ¶þ¶¨Âɵãº
$F-{m}_{2}^{\;}g={m}_{2}^{\;}\frac{{v}_{0}^{2}}{l}$
´úÈëÊý¾Ý£º$F={m}_{2}^{\;}g+{m}_{2}^{\;}\frac{{v}_{0}^{2}}{l}$=$2.77¡Á1{0}_{\;}^{3}¡Á10+2.77¡Á1{0}_{\;}^{3}¡Á\frac{{2}_{\;}^{2}}{3}$=$3.06¡Á1{0}_{\;}^{4}N$
ÓÉÅ£¶ÙµÚÈý¶¨ÂɵãºÖý¼þ¶Ô¸ÖË¿ÉþµÄÀ­Á¦Îª$F¡ä=F=3.06¡Á1{0}_{\;}^{4}N$
´ð£º£¨1£©ÐгµÔÈËÙÐÐÊ»µÄËÙ¶Èv₀Ϊ2m/s
£¨2£©µ±ÐгµÍ»È»Í£Ö¹µÄ˲¼ä£¬¸ÖË¿ÉþÊܵ½µÄÀ­Á¦ÊÇ$3.06¡Á1{0}_{\;}^{4}N$

µãÆÀ ±¾Ìâ¹Ø¼üÒª·ÖÎöÇó³öÎïÌåµÄÔ˶¯Çé¿öºÍÊÜÁ¦Çé¿ö£¬È»ºó¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨ÂÉÁÐʽÇó½â£®