Question

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• A£® $\frac{{a}_{1}}{{a}_{2}}$=$\frac{5\sqrt{3}{L}^{2}}{12{R}^{2}}$
• B£® $\frac{{a}_{1}}{{a}_{2}}$=$\frac{\sqrt{3}{L}^{2}}{3{R}^{2}}$
• C£® $\frac{{T}_{1}}{{T}_{2}}$=$\sqrt{\frac{3{R}^{2}}{{L}^{4}}}$
• D£® $\frac{{T}_{1}}{{T}_{2}}$=$\sqrt{\frac{12{R}^{2}}{5{L}^{2}}}$

Answer 1

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½âµÃ${a}_{1}=\frac{5Gm}{4{R}^{2}}$£¬${T}_{1}=\sqrt{\frac{16{¦Ð}^{2}{R}^{3}}{5Gm}}$£¬
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½âµÃa₂=$\frac{\sqrt{3}Gm}{{L}^{2}}$£¬T₂=$\sqrt{\frac{4{¦Ð}^{2}{L}^{3}}{3Gm}}$£¬
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