Question

16£®Èçͼ1ÊÇ¡°Ñо¿Æ½Å×ÎïÌåÔ˶¯¡±µÄʵÑé×°ÖÃͼ£¬Í¨¹ýÃèµã»­³öƽÅ×СÇòµÄÔ˶¯¹ì¼££®

£¨1£©ÒÔÏÂÊÇʵÑé¹ý³ÌÖеÄһЩ×ö·¨£¬ÆäÖкÏÀíµÄÓÐac£®
a£®°²×°Ð±²Û¹ìµÀ£¬Ê¹ÆäÄ©¶Ë±£³Öˮƽ
b£®Ã¿´ÎСÇòÊͷŵijõʼλÖÿÉÒÔÈÎÒâÑ¡Ôñ
c£®Ã¿´ÎСÇòÓ¦´Óͬһ¸ß¶ÈÓɾ²Ö¹ÊÍ·Å
d£®ÎªÃè³öСÇòµÄÔ˶¯¹ì¼££¬Ãè»æµÄµã¿ÉÒÔÓÃÕÛÏßÁ¬½Ó
£¨2£©ÊµÑéµÃµ½Æ½Å×СÇòµÄÔ˶¯¹ì¼££¬Ôڹ켣ÉÏȡһЩµã£¬ÒÔƽÅ×ÆðµãOΪ×ø±êÔ­µã£¬²âÁ¿ËüÃǵÄˮƽ×ø±êxºÍÊúÖ±×ø±êy£¬Í¼2ÖÐy-x²Í¼ÏóÄÜ˵Ã÷ƽÅ×СÇòÔ˶¯¹ì¼£ÎªÅ×ÎïÏßµÄÊÇc£®
£¨3£©Ä³Í¬Ñ§¸ù¾ÝʵÑé»­³öµÄƽÅ×СÇòµÄÔ˶¯¹ì¼££¬ÊµÑéÖÐÖ»¼Ç¼ÁËÊúÖ±ÏßûÓмǼƽÅ×µÄÆðµã£¬ÔÚÊúÖ±ÏßÉÏȡijµã¼ÇΪO£¬¹ýOµÄˮƽÏßΪXÖᣬÔڹ켣ÉÏÈÎÈ¡ÈýµãA¡¢B¡¢C£¬²âA¡¢BºÍCµãÊúÖ±×ø±êy₁Ϊ40.0cm¡¢y₂Ϊ120.0cmy₃Ϊ175.0cm£¬A¡¢BÁ½µãˮƽ×ø±êΪ20.0cmºÍ40.0cm£®ÔòƽÅ×СÇòµÄ³õËÙ¶Èv₀Ϊ1 m/s£¬Ð¡ÇòÔÚCµãµÄËÙ¶Èv_CΪ$\sqrt{37}$ m/s£¨½á¹û¿ÉÒÔÓøùʽ±íʾ£¬gÈ¡10m/s²£©£®

Answer 1

·ÖÎö £¨1£©¸ù¾ÝʵÑéµÄÔ­Àí£¬½áºÏʵÑéÖеÄ×¢ÒâÊÂÏîÈ·¶¨ÕýÈ·µÄ²Ù×÷²½Ö裮
£¨2£©¸ù¾ÝƽÅ×Ô˶¯ÔÚˮƽ·½ÏòºÍÊúÖ±·½ÏòÉϵÄÔ˶¯¹æÂÉ£¬½áºÏÔ˶¯Ñ§¹«Ê½Çó³öyÓëx²µÄ¹Øϵʽ£¬´Ó¶øÈ·¶¨ÕýÈ·µÄͼÏߣ®
£¨3£©¸ù¾ÝÊúÖ±·½ÏòÏàÁÚµÄÏàµÈʱ¼äÄÚµÄλÒƲîÊǸö¶¨ÖµÇó³öOAºÍAB¼äµÄʱ¼ä£¬½áºÏˮƽλÒƺÍʱ¼äÇó³ö³õËٶȣ®¸ù¾ÝËÙ¶ÈλÒƹ«Ê½Çó³öCµãµÄÊúÖ±·ÖËٶȣ¬½áºÏƽÐÐËıßÐζ¨ÔòÇó³öCµãµÄËٶȣ®

½â´ð ½â£º£¨1£©a¡¢ÎªÁ˱£Ö¤Ð¡ÇòµÄ³õËÙ¶Èˮƽ£¬Ð±²ÛµÄÄ©¶ËÐèˮƽ£¬¹ÊaÕýÈ·£»
b¡¢ÎªÁËʹСÇòµÄ³õËÙ¶ÈÏàµÈ£¬Ã¿´ÎÈÃСÇò´Óб²ÛµÄͬһλÖÃÓɾ²Ö¹¹öÏ£¬¹Êb´íÎó£¬cÕýÈ·£»
d¡¢Ãè»æСÇòµÄÔ˶¯¹ì¼££¬ÓÃƽ»¬ÇúÏßÁ¬½Ó£¬¹Êd´íÎó£®
¹ÊÑ¡£ºac£®
£¨2£©¸ù¾Ýx=v₀t£¬y=$\frac{1}{2}g{t}^{2}$µÃ£¬y=$\frac{1}{2}g\frac{{x}^{2}}{{{v}_{0}}^{2}}$£¬¿ÉÖªy-x²µÄͼÏßΪһÌõ¹ýÔ­µãµÄÇãбֱÏߣ¬¹ÊCÕýÈ·£¬ABD´íÎó£®
¹ÊÑ¡£ºC
£¨3£©40cm=0.4m£¬120cm=1.20m£¬175cm=1.75m£¬20cm=0.20m£¬
¸ù¾Ý¡÷y=gT²µÃ£ºT=$\sqrt{\frac{£¨1.20-0.4£©-0.4}{10}}=0.2s$
ÔòСÇòƽÅ×Ô˶¯µÄ³õËÙ¶ÈΪ£ºv₀=$\frac{x}{T}=\frac{0.20}{0.2}=1m/s$£®
AµãµÄÊúÖ±·ÖËÙ¶ÈΪ£º${v}_{Ay}=\frac{{y}_{2}}{2T}=\frac{1.2}{0.4}=3m/s$£¬
${y}_{3}-{y}_{1}=\frac{{{v}_{Cy}}^{2}-{{v}_{Ay}}^{2}}{2g}$£¬
${v}_{C}=\sqrt{{{v}_{0}}^{2}+{{v}_{Cy}}^{2}}$£¬
½âµÃ£º
${v}_{C}=\sqrt{37}m/s$
¹Ê´ð°¸Îª£º£¨1£©ac£»£¨2£©c£»£¨3£©1£»$\sqrt{37}$

µãÆÀ ½â¾ö±¾ÌâµÄ¹Ø¼üÖªµÀƽÅ×Ô˶¯ÔÚˮƽ·½ÏòºÍÊúÖ±·½ÏòÉϵÄÔ˶¯¹æÂÉ£¬½áºÏÔ˶¯Ñ§¹«Ê½£¬×¥×¡µÈʱÐÔ½øÐÐÇó½â£®