·ÖÎö £¨1£©·ÖÎö´øµçÀë×ÓÔÚƽÐаåa¡¢bÖ®¼äºÍM¡¢NÖ®¼äµÄÔ˶¯Çé¿ö£¬ÔËÓÃÅ£¶ÙµÚ¶þ¶¨ÂɺÍÔ˶¯Ñ§¹«Ê½Çó½â£®
£¨2£©´øµçÀë×ÓÔÚƽÐаåM¡¢NÖ®¼ä×öÀàƽÅ×Ô˶¯£¬Çó³ö¹ì¼£·½³ÌÅжϣ®
£¨3£©À뿪ƫתµç³¡Ê±x=L£¬ÇÒÂú×ãy£¼$\frac{L}{2}$ʱÀë×Ó²»´òÔÚ¼«°åÉÏ£¬´Ó¶øÇó³öU0ÓëU1µÄ¹Øϵ£®
½â´ð ½â£º£¨1£©´øµçÀë×ÓÔÚƽÐаåa¡¢b¼äÔ˶¯Ê±£¬¸ù¾Ý¶¯Äܶ¨ÀíµÃ£º$q{U}_{0}=\frac{1}{2}m{v}^{2}-0$£¬
½âµÃ£ºv=$\sqrt{\frac{2q{U}_{0}}{m}}$£¬¼´£ºv=$\sqrt{2k{U}_{0}}$£®
´øµçÀë×ÓÔÚƽÐаåa¡¢b¼äµÄ¼ÓËÙ¶È${a}_{1}=\frac{q{U}_{0}}{md}$£¬¼´£º${a}_{1}=\frac{k{U}_{0}}{d}$£®
ËùÒÔ£¬´øµçÀë×ÓÔÚƽÐаåa¡¢b¼äÔ˶¯µÄʱ¼äΪ¡°${t}_{1}=\frac{v}{{a}_{1}}=\frac{d\sqrt{2k{U}_{0}}}{k{U}_{0}}$£®
´øµçÀë×ÓÔÚƽÐаåM¡¢N¼äÔ˶¯µÄʱ¼äΪ£º${t}_{2}=\frac{L}{v}=\frac{L}{\sqrt{2k{U}_{0}}}$£®
ËùÒÔ£¬´øµçÀë×ÓµÄÈ«²¿·ÉÐÐʱ¼äΪ£ºt=t1+t2=$\frac{2d+L}{\sqrt{2k{U}_{0}}}$£®
£¨2£©ÕýÀë×ÓÔÚƽÐаåM¡¢N¼äˮƽ·½ÏòÔ˶¯Î»ÒÆΪxʱ£¬ÔÚÊúÖ±·½ÏòÔ˶¯µÄλÒÆΪy£¬
ˮƽ·½ÏòÂú×ãx=vt¡¢Ù
ÊúÖ±·½ÏòÂú×ãy=$\frac{1}{2}{a}_{2}{t}^{2}$¡¢Ú
¼ÓËٶȣº${a}_{2}=\frac{{U}_{1}k}{L}$¡¢Û
ÓÉÉÏÊö¢Ù¢Ú¢ÛµÃ£ºy=$\frac{{U}_{1}{x}^{2}}{4L{U}_{0}}$¡¢Ü
¢ÜʽÊÇÕýÀë×ӵĹ켣·½³Ì£¬ÓëÕýÀë×ÓµÄÖÊÁ¿ºÍµçºÉÁ¿¾ùÎ޹أ¬ËùÒÔ£¬²»Í¬ÕýÀë×ӵĹ켣ÊÇÖغϵģ®
£¨3£©À뿪ƫתµç³¡Ê±x=L£¬ÇÒÂú×ãy£¼$\frac{L}{2}$ʱÀë×Ó²»´òÔÚ¼«°åÉÏ£®ÁÙ½çÇé¿öÏÂÓÐvx=vy
¸ù¾ÝµçÊÆÄÜת»¯ÎªÁ£×Ó¶¯ÄÜ£¬ÓÐ$\frac{1}{2}m{{v}_{x}}^{2}=q{U}_{0}=\frac{1}{2}m{{v}_{y}}^{2}=\frac{1}{2}q{U}_{1}$
´Ó¶ø¿ÉÖªU1£¼2U0ʱ£¬Àë×Ó²»´òÔÚ¼«°åÉÏ£®
´ð£º£¨1£©Àë×Ó´Óa°åµ½Ì½²âÆ÷µÄ·ÉÐÐʱ¼äΪ$\frac{2d+L}{\sqrt{2k{U}_{0}}}$£®
£¨2£©Ö¤Ã÷ÈçÉÏËùʾ£®
£¨3£©U1£¼2U0ʱ£¬Àë×Ó²»´òÔÚ¼«°åÉÏ£®
µãÆÀ ±¾Ì⿼²éÁ˵çºÉµÄ¼ÓËÙÓëµçºÉµÄƫת£¬¹Ø¼ü½«µçºÉµÄƫת½øÐзֽ⣬֪µÀÔÚˮƽ·½ÏòºÍÊúÖ±·½ÏòÉϵÄÔ˶¯¹æÂÉ£®½â¾ö¸ÃÌâ¹Ø¼üÒª°Ñ¶¯Äܶ¨Àí¡¢ÀàƽÅ×Ô˶¯¹æÂÉ¡¢Å£¶ÙÔ˶¯¶¨Âɼ°ÆäÏà¹Ø½áºÏ½â´ð£®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | P0-¦Ñg£¨h1+h2-h3£© | B£® | P0-¦Ñg£¨h1+h3£© | C£® | P0-¦Ñg£¨h1-h2+h3£© | D£® | P0-¦Ñg£¨h1+h2£© |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | MµãµçÊÆΪÁ㣬Nµã³¡Ç¿ÎªÁã | |
B£® | Mµã³¡Ç¿ÎªÁ㣬NµãµçÊÆΪÁã | |
C£® | Q1´ø¸ºµç£¬Q2´øÕýµç£¬ÇÒQ2µçºÉÁ¿½Ï´ó | |
D£® | Q1´øÕýµç£¬Q2´ø¸ºµç£¬ÇÒQ2µçºÉÁ¿½Ï´ó |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
A£® | ÔÚ1sµ½3sʱ¼äÄÚÖʵ㾲ֹ | |
B£® | Ç°1sÖʵã×ö¼ÓËÙÔ˶¯£¬×îºó1sÖʵã×ö¼õËÙÔ˶¯ | |
C£® | Ç°1sºÍ×îºó1sÖʵãµÄ¼ÓËٶȴóС¾ùΪ3m/s2 | |
D£® | µÚ4sÄÚÖʵãµÄ¼ÓËÙ¶ÈΪ0 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com