Question

9£®ÈçͼËùʾ£¬Ë®Æ½·ÅÖõÄÕý·½Ðι⻬²£Á§°åabcd£¬±ß³¤4Ã×£¬¾àµØÃæµÄ¸ß¶ÈΪH=5Ã×£¬²£Á§°åÕýÖмäÓÐÒ»¸ö¹â»¬µÄС¿×O£¬Ò»¸ùϸÏß´©¹ýС¿×£¬Á½¶Ë·Ö±ðϵ×ÅСÇòAºÍСÎï¿éB£¬µ±Ð¡ÇòAÒÔËÙ¶Èv=2m/sÔÚ²£Á§°åÉÏÈÆOµã×öÔÈËÙÔ²ÖÜÔ˶¯Ê±£¬AO¼äµÄ¾àÀëΪr=1Ã×£®ÒÑÖªAµÄÖÊÁ¿Îªm_A=2kg£¬ÖØÁ¦¼ÓËÙ¶Èg=10m/s²£¨½á¹û¿ÉÒÔÓøùºÅ±íʾ£©
£¨1£©ÇóСÎï¿éA×öÔÈËÙÔ²ÖÜÔ˶¯µÄÏòÐÄÁ¦£¿
£¨2£©µ±Ð¡ÇòËٶȷ½ÏòƽÐÐÓÚ²£Á§°åad±ßʱ£¬¼ô¶ÏϸÏߣ¬ÔòСÇòÂäµØǰ˲¼äµÄËٶȶà´ó£¿
£¨3£©ÔÚ£¨2£©µÄÇé¿öÏ£¬ÈôСÇòºÍÎïÌåÂäµØºó¾ù²»ÔÙÔ˶¯£¬ÔòÁ½ÕßÂäµØµã¼äµÄ¾àÀëΪ¶àÉÙ£¿

Answer 1

·ÖÎö £¨1£©¸ù¾ÝÏòÐÄÁ¦¹«Ê½Çó½âÏòÐÄÁ¦£»
£¨2£©¸ù¾Ý»úеÄÜÊغãÇóСÇòÂäµØʱµÄËٶȴóС£»
£¨3£©AÏÈ×öÒ»¶ÎÔÈËÙÖ±ÏßÔ˶¯£¬ÍÑÀë²£Á§°åºó×öƽÅ×Ô˶¯£¬B×ö×ÔÓÉÂäÌ壬½áºÏ¼¸ºÎ֪ʶÇóÁ½ÕßµÄÂäµØ¾àÀ룮

½â´ð ½â£º£¨1£©Ð¡Îï¿éA×öÔÈËÙÔ²ÖÜÔ˶¯µÄÏòÐÄÁ¦Îª£º
F=${m}_{A}\frac{{v}^{2}}{r}$=$2¡Á\frac{{2}^{2}}{1}=8N$
£¨2£©AÏÂÂä¹ý³Ì£¬¸ù¾Ý»úеÄÜÊغ㶨ÂÉ£º
$\frac{1}{2}{m}_{A}{v}^{2}+mgH=\frac{1}{2}{m}_{A}v{¡ä}^{2}$£¬
½âµÃ£º$v¡ä=\sqrt{104}m/s$
£¨3£©AÍÑÀë²£Á§°åºó×öƽÅ×Ô˶¯£¬ÊúÖ±·½Ïò×ÔÓÉÂäÌ壺
$H=\frac{1}{2}g{t}^{2}$£¬
½âµÃ£ºt=1s
ÔòƽÅ×ˮƽλÒÆ£º
x=v¡ät=$\sqrt{104}$m£¬
¶þÕßÂäµØµÄ¾àÀ룺
s=$\sqrt{{x}^{2}+{l}^{2}}$=$2\sqrt{30}m$£®
´ð£º£¨1£©Ð¡Îï¿éA×öÔÈËÙÔ²ÖÜÔ˶¯µÄÏòÐÄÁ¦Îª8N£»
£¨2£©µ±Ð¡ÇòËٶȷ½ÏòƽÐÐÓÚ²£Á§°åad±ßʱ£¬¼ô¶ÏϸÏߣ¬ÔòСÇòÂäµØǰ˲¼äµÄËÙ¶ÈΪ$\sqrt{104}m/s$£»
£¨3£©ÔÚ£¨2£©µÄÇé¿öÏ£¬ÈôСÇòºÍÎïÌåÂäµØºó¾ù²»ÔÙÔ˶¯£¬ÔòÁ½ÕßÂäµØµã¼äµÄ¾àÀëΪ$2\sqrt{30}m$£®

µãÆÀ ±¾ÌâÊôÓÚƽÅ×Ô˶¯ºÍÔ²ÖÜÔ˶¯µÄ×ÛºÏÓ¦ÓÃÌâÐÍ£¬ÇóµÚÈýÎÊʱעÒâÁ½ÕߵľàÀëÊÇÒÔÉþ³¤ºÍƽÅ×Ô˶¯Ë®Æ½Î»ÒÆΪÁڱߵÄб±ß³¤£®