Question

15£®îеķÅÉäÐÔͬλËØ${\;}_{94}^{239}$Pu¾²Ö¹Ê±Ë¥±äΪÓ˺˼¤·¢Ì¬${\;}_{92}^{235}$U^*ºÍ¦ÁÁ£×Ó£¬¶øÓ˺˼¤·¢Ì¬${\;}_{92}^{235}$U^*Á¢¼´Ë¥±äΪÓ˺Ë${\;}_{92}^{235}$U£¬²¢·Å³öÄÜÁ¿Îª0.097MeVµÄ¦Ã¹â×Ó£®ÒÑÖª£º${\;}_{94}^{239}$94Pu¡¢${\;}_{92}^{235}$UºÍ¦ÁÁ£×ÓµÄÖÊÁ¿·Ö±ðΪm_Pu=239.0521u¡¢m_U=235.0439uºÍm_¦Á=4.002 6u£¬1uµÄÖÊÁ¿Ï൱ÓÚ931.5MeVµÄÄÜÁ¿£®
£¨1£©Ð´³öË¥±ä·½³Ì£»
£¨2£©ÒÑ֪˥±ä·Å³öµÄ¹â×ӵĶ¯Á¿¿ÉºöÂÔ£¬Çó¦ÁÁ£×ӵĶ¯ÄÜ£®

Answer 1

·ÖÎö £¨1£©¸ù¾ÝÖÊÁ¿ÊýºÍµçºÉÊýÊغã¿ÉÕýÈ·Êéд¸ÃË¥±ä·½³Ì£®
£¨2£©Ë¥±ä¹ý³ÌÂú×㶯Á¿ÊغãºÍÄÜÁ¿Êغ㣬¸ù¾ÝÕâÁ½¸ö·½³ÌÁз½³Ì¼´¿ÉÇó½â£®

½â´ð ½â£º£¨1£©¸ù¾ÝÖÊÁ¿ÊýºÍµçºÉÊýÊغã¿ÉµÃË¥±ä·½³ÌΪ₉₄²³⁹Pu¡ú₉₂²³⁵U^*+¦Á₉₂²³⁵U^*¡ú₉₂²³⁵U+¦Ã
»òºÏÆðÀ´ÓÐ₉₄²³⁹Pu¡ú₉₂²³⁵U+¦Á+¦Ã
¹ÊË¥±ä·½³ÌΪ£º₉₄²³⁹Pu¡ú₉₂²³⁵U+¦Á+¦Ã£®
£¨2£©ÉÏÊöË¥±ä¹ý³ÌµÄÖÊÁ¿¿÷ËðΪ£º¡÷m=m_Pu-m_U-m_¦Á ¡­¢Ù
·Å³öµÄÄÜÁ¿Îª£º¡÷E=c²•¡÷m¡­¢Ú
ÕâЩÄÜÁ¿ÊÇÖáºË₉₂²³⁵UµÄ¶¯ÄÜE_U¡¢¦ÁÁ£×ӵĶ¯ÄÜE_aºÍy¹â×ÓµÄÄÜÁ¿E_yÖ®ºÍ£¬¼´ÓУº
¡÷E=E_U+E_¦Á+E_y¡­¢Û
ÓÉ¢Ù¢Ú¢ÛʽµÃ£ºE_U+E_¦Á=£¨m_Pu-m_U-m_¦Á£©c²-E_y¡­¢Ü
ÉèË¥±äºóµÄÖáºËºÍ¦ÁÁ£×ÓµÄËٶȷֱðΪv_UºÍv_¦Á£¬ÔòÓɶ¯Á¿ÊغãÓУº
m_Uv_U=m_¦Áv_¦Á ¡­¢Ý
ÓÖÓɶ¯ÄܵĶ¨ÒåÖª£º${E_U}=\frac{1}{2}{m_U}v_U^2£¬{E_¦Á}=\frac{1}{2}{m_¦Á}v_a^2$¡­¢Þ
¸ù¾Ý${E}_{K}=\frac{{P}^{2}}{2m}$
ÓɢݢÞʽµÃ£º$\frac{E_U}{E_a}=\frac{m_a}{m_y}$¡­¢ß
ÓɢܢßʽµÃ£º${E_a}=\frac{m_U}{{{m_U}-{m_¦Á}}}[{£¨{m_{Pu}}-{m_U}+{m_¦Á}£©{c^2}-{E_¦Ã}}]$
´úÈëÌâ¸øÊý¾ÝµÃ£ºE_¦Á=5.034MeV£®
¹Ê¦ÁÁ£×ӵĶ¯ÄÜΪ£ºE_¦Á=5.034MeV£®
´ð£º£¨1£©Ë¥±ä·½³ÌΪ₉₄²³⁹Pu¡ú₉₂²³⁵U+¦Á+¦Ã£»
£¨2£©ÒÑ֪˥±ä·Å³öµÄ¹â×ӵĶ¯Á¿¿ÉºöÂÔ£¬¦ÁÁ£×ӵĶ¯ÄÜΪ5.034MeV£®

µãÆÀ ±¾ÌâµÄÄѵãÔÚÓÚµÚ£¨2£©ÎÊ£¬×¢Ò⶯Á¿ÊغãºÍÄÜÁ¿ÊغãÔÚÔ­×ÓÎïÀíÖеÄÓ¦Óã¬ÓÈÆäÊÇÁÐÄÜÁ¿Êغ㷽³Ìʱ²»ÒªÂ©µô²¿·ÖÄÜÁ¿£®