·ÖÎö £¨1£©¸ÃÌâûÓиø¶¨µçѹ±í£¬ËùÒÔÐèÒªÓõçÁ÷±í¸Ä×°Ò»¸ö£¬´ËʱѡÓõçÁ÷±íӦѡÓÃÁ¿³Ì½ÏСµÄ£¬½áºÏµçÁ÷£¬Í¨¹ý¼ÆËã¿É֪ѡÓÃÄĸö¶¨Öµµç×裮Òò¿ÉʹÔÚ¾¡¿ÉÄÜ´óµÄ·¶Î§ÄÚ²âµÃ¶à×éA1±í¡¢A2±íµÄ¶ÁÊýI1¡¢I2£¬ËùÒÔÒªÓ÷Öѹµç·£¬Ñ¡Ôñ½ÏСµÄ»¬¶¯±ä×èÆ÷£®
£¨2£©£¨4£©¸ù¾Ý²¿·Öµç·µÄÅ·Ä·¶¨Âɿɱíʾ³öͨ¹ýÁ½¸öµç±íµÄµçÁ÷¹Øϵ£¬Çó³öµç¸ÐÏßȦµÄµç×裮
£¨3£©ÊµÑéÖÐÒª±£»¤µçÁ÷±íA1£¬´Ó¶øÅжÏÏȶϿªÄĸöµç¼ü£®
½â´ð ½â£º£¨1£©²ÉÓÃÒÑÖªÄÚ×èµÄСÁ¿³ÌµçÁ÷±íA1Ìæ´úµçѹ±í²âÁ¿µçѹ£¬ÐèÒª´®ÁªÒ»¸ö´óÓÚµÈÓÚR=$\frac{2¡Á2V}{0.6A}$=6.7¦¸µÄ¶¨Öµµç×裮ËùÒÔʵÑéÖж¨Öµµç×èӦѡÓÃ×èֵΪ10¦¸µÄR3£¬
ÒªÓ÷Öѹµç·£¬Ñ¡Ôñ½ÏСµÄ»¬¶¯±ä×èÆ÷£¬»¬¶¯±ä×èÆ÷ӦѡÓÃ×èֵΪ1¡«10¦¸µÄR1£®
£¨2£©ÓÉI1£¨R3+r£©=£¨I2-I1£©RL
µÃ£º$\frac{{I}_{2}}{{I}_{1}}=\frac{{R}_{L}+{R}_{3}+r}{{R}_{L}}$
ËùÒÔ£º${I}_{2}=\frac{{R}_{L}+{R}_{3}+r}{{R}_{L}}•{I}_{1}$
£¨3£©ÊµÑé½áÊøʱΪ·ÀÖ¹ÉÕ»µµç·£¬Ó¦ÏȶϿª¿ª¹ØS2
£¨4£©ÓÉ${I}_{2}=\frac{{R}_{L}+{R}_{3}+r}{{R}_{L}}•{I}_{1}$
´úÈëÊý¾ÝµÃ£ºRL=$\frac{{R}_{3}+r}{5}$=2.04¦¸£®
¹Ê´ð°¸Îª£º£¨1£©R3 R1 £¨2£©${I}_{2}=\frac{{R}_{L}+{R}_{3}+r}{{R}_{L}}•{I}_{1}$£»£¨3£©S2£»£¨4£©2.04¦¸
µãÆÀ ÒªÇóµçÁ÷»òµçѹµÄ²âÁ¿Öµ´ÓÁã»òºÜС¿ªÊ¼Öð½¥Ôö´óµÄʵÑé±ØÐë²ÉÓ÷Öѹµç·£»·Öѹµç·Ö묶¯±ä×èÆ÷Ñ¡Ôñ×èÖµ½ÏСµÄ£»¶ÔÓÚµç±íµÄÑ¡ÔñÓ¦×ñÑ°²È«ÐÔ¡¢¾«È·ÐÔ¡¢½ÚÄÜÐÔ¡¢·½±ãÐÔÔÔò×ۺϿ¼ÂÇ£¬Áé»îÔñÈ¡£®
Ä꼶 | ¸ßÖÐ¿Î³Ì | Ä꼶 | ³õÖÐ¿Î³Ì |
¸ßÒ» | ¸ßÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ | ³õÒ» | ³õÒ»Ãâ·Ñ¿Î³ÌÍƼö£¡ |
¸ß¶þ | ¸ß¶þÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õ¶þ | ³õ¶þÃâ·Ñ¿Î³ÌÍƼö£¡ |
¸ßÈý | ¸ßÈýÃâ·Ñ¿Î³ÌÍƼö£¡ | ³õÈý | ³õÈýÃâ·Ñ¿Î³ÌÍƼö£¡ |
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º½â´ðÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | µ¥Î»Ìå»ýÄڵķÖ×ÓÊý±äÉÙ£¬µ¥Î»Ê±¼äÄÚ¶Ôµ¥Î»Ãæ»ýÆ÷±ÚÅöײµÄ´ÎÊý¼õÉÙ | |
B£® | ÆøÌå·Ö×ÓµÄÃܼ¯³Ì¶È±äС£¬·Ö×Ó¶ÔÆ÷±ÚµÄÎüÒýÁ¦±äС | |
C£® | ÿ¸ö·Ö×Ó¶ÔÆ÷±ÚµÄƽ¾ùײ»÷Á¦±äС | |
D£® | ÆøÌå·Ö×ÓµÄÃܼ¯³Ì¶È±äС£¬µ¥Î»Ìå»ýÄÚ·Ö×ÓµÄÖØÁ¿±äС |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£º¶àÑ¡Ìâ
A£® | СÇòͨ¹ý×î¸ßµãʱ£¬¶Ô¸ËµÄÀÁ¦´óСÊÇ18N | |
B£® | СÇòͨ¹ý×î¸ßµãʱ£¬¶Ô¸ËµÄѹÁ¦´óСÊÇ2N | |
C£® | СÇòͨ¹ý×îµÍµãʱ£¬¶Ô¸ËµÄÀÁ¦´óСÊÇ18N | |
D£® | СÇòͨ¹ý×îµÍµãʱ£¬¶Ô¸ËµÄÀÁ¦´óСÊÇ38N |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÌî¿ÕÌâ
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ÀÁ¦F×öµÄ¹¦µÈÓÚ±¡Ö½°åºÍСľ¿é¶¯ÄܵÄÔö¼Ó | |
B£® | Ħ²ÁÁ¦¶ÔСľ¿é×öµÄ¹¦Ò»¶¨´óÓÚСľ¿é¶¯ÄܵÄÔö¼Ó | |
C£® | À뿪±¡Ö½°åǰСľ¿é¿ÉÄÜÏÈ×ö¼ÓËÙÔ˶¯£¬ºó×öÔÈËÙÔ˶¯ | |
D£® | Сľ¿é¶¯ÄܵÄÔö¼Ó¿ÉÄÜСÓÚϵͳµÄĦ²ÁÉúÈÈ |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | ËüÃǵİ뾶֮±ÈΪRA£ºRB=2£º3 | B£® | ËüÃǵİ뾶֮±ÈΪRA£ºRB=9£º4 | ||
C£® | ËüÃǵÄÖÜÆÚÖ®±ÈΪTA£ºTB=2£º3 | D£® | ËüÃǵÄÖÜÆÚÖ®±ÈΪTA£ºTB=3£º2 |
²é¿´´ð°¸ºÍ½âÎö>>
¿ÆÄ¿£º¸ßÖÐÎïÀí À´Ô´£º ÌâÐÍ£ºÑ¡ÔñÌâ
A£® | $\frac{{¦Ð{B^2}{L^2}v_m^2}}{{4¦Ø£¨R+{R_0}£©}}$+$\frac{1}{2}$mvm2 | B£® | $\frac{{¦Ð{B^2}{L^2}v_m^2}}{{4¦Ø£¨R+{R_0}£©}}$ | ||
C£® | $\frac{{¦Ð{B^2}{L^2}v_m^2}}{{4¦Ø£¨R+{R_0}£©}}$-$\frac{1}{2}$mvm2 | D£® | $\frac{{¦Ð{B^2}{L^2}v_m^2}}{{2¦Ø£¨R+{R_0}£©}}$ |
²é¿´´ð°¸ºÍ½âÎö>>
°Ù¶ÈÖÂÐÅ - Á·Ï°²áÁбí - ÊÔÌâÁбí
ºþ±±Ê¡»¥ÁªÍøÎ¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨Æ½Ì¨ | ÍøÉÏÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | µçÐÅթƾٱ¨×¨Çø | ÉæÀúÊ·ÐéÎÞÖ÷ÒåÓк¦ÐÅÏ¢¾Ù±¨×¨Çø | ÉæÆóÇÖȨ¾Ù±¨×¨Çø
Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com