Question

3£®ÈçͼËùʾÊǼÆËã»úÄ£Äâ³öµÄÒ»ÖÖÓîÖæ¿Õ¼äµÄÇé¾³£¬ÔÚ´ËÓîÖæ¿Õ¼ä´æÔÚÕâÑùÒ»¸öÔ¶ÀëÆäËü¿Õ¼äµÄÇøÓò£¨ÔÚ¸ÃÇøÓòÄÚ²»¿¼ÂÇÇøÓòÍâµÄÈκÎÎïÖʶÔÇøÓòÄÚÎïÌåµÄÒýÁ¦£©£¬ÒÔMNΪ½ç£¬ÉÏ¡¢ÏÂÁ½²¿·Ö´Å³¡´Å¸ÐӦǿ¶È´óС֮±ÈΪ2£º1£¬´Å³¡·½ÏòÏàͬ£¬·¶Î§×ã¹»´ó£¬ÔÚ¾àMNΪhµÄPµãÓÐÒ»¸öÓԱ´¦ÓÚ¾²Ö¹×´Ì¬£¬ÓԱÒÔƽÐÐÓÚ½çÏßµÄËÙ¶ÈÏòÓÒÍƳöÒ»¸öÖÊÁ¿ÎªmµÄ´ø¸ºµçÎïÌ壬·¢ÏÖÎïÌåÔÚ½çÏß´¦Ëٶȷ½ÏòÓë½çÏß³É60¡ã½Ç£¬½øÈëϲ¿´Å³¡£®ÓÉÓÚ·´³å£¬ÓԱÑØÓë½çÏßƽÐеÄÖ±ÏßÔÈËÙÔ˶¯£¬µ½´ïQµãʱ£¬¸ÕºÃÓÖ½ÓסÎïÌå¶ø¾²Ö¹£¬Çó£º
£¨1£©PQ¼ä¾àÀëd£»
£¨2£©ÓԱÖÊÁ¿M£®

Answer 1

·ÖÎö £¨1£©Ð¡ÇòÔÚÁ½¸ö´Å³¡¾ù×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÓÉÂåÂØ×ÈÁ¦³äµ±ÏòÐÄÁ¦¼°Ô²ÖÜÔ˶¯µÄÐÔÖÊ£¬¿ÉÇóµÃÁ£×ÓÔ˶¯µÄ¹Ø¾¶¼°ÖÜÆÚ£»ÓÉÁ£×ÓÔ˶¯µÄ¶Ô³ÆÐÔ¿ÉÇóµÃPQ¼äµÄ¾àÀ룻
£¨2£©ÓÉÁ£×ÓµÄÔ˶¯¹ý³Ì¿ÉÇóµÃÓԱÔ˶¯µÄËٶȣ»Óɶ¯Á¿Êغã¿ÉÇóµÃÓԱµÄÖÊÁ¿£®

½â´ð ½â£º£¨1£©ÉèÉÏÏ·½µÄ´Î´Å¸ÐӦǿ¶È·Ö±ðΪB₁=2B₀ºÍB₂=B₀£¬»­³öСÇòÔڴų¡B₁ÖÐÔ˶¯µÄ¹ì¼£ÈçͼËùʾ£¬
¿ÉÖª£ºR₁-h=R₁cos60¡ã£¬½âµÃ£ºR₁=2h
ÓÉqvB=m$\frac{{v}^{2}}{R}$ºÍB₁=2B₂£¬¿ÉÖª£ºR₂=2R₁=4h
ÓÉqv£¨2B₀£©=m$\frac{{v}^{2}}{{R}_{1}}$£¬µÃ£ºv=$\frac{4q{B}_{0}h}{m}$
¸ù¾ÝÔ˶¯µÄ¶Ô³ÆÐÔ£¬PQµÄ¾àÀëΪ£ºl=2£¨R₂sin60¡ã-R₁sin60¡ã£©=2$\sqrt{3}$h£»
£¨2£©Á£×ÓÓÉPÔ˶¯µ½QµÄʱ¼ä£ºt=$\frac{{T}_{1}}{3}$+$\frac{2{T}_{2}}{3}$=$\frac{1}{3}•\frac{2¦Ðm}{q£¨2{B}_{0}£©}$+$\frac{2}{3}•\frac{2¦Ðm}{q{B}_{0}}$=$\frac{5¦Ðm}{3q{B}_{0}}$
ÓԱÔÈËÙÔ˶¯µÄËٶȴóСΪ£ºV=$\frac{l}{t}$=$\frac{6\sqrt{3}q{B}_{0}h}{5¦Ðm}$
Óɶ¯Á¿Êغ㶨ÂɵãºMV-mv=0
¿ÉÇóµÃÓԱµÄÖÊÁ¿£ºM=$\frac{10\sqrt{3}¦Ðm}{9}$
´ð£º£¨1£©PQ¼äµÄ¾àÀëΪ2$\sqrt{3}$h£»
£¨2£©ÓԱµÄÖÊÁ¿ÎªÁ¿$\frac{10\sqrt{3}¦Ðm}{9}$£®

µãÆÀ ±¾ÌâÊÇÒ»µÀÐÅÏ¢¸øÓèÌ⣬ͬѧÃÇÐèÒª¸ù¾ÝÌâÖÐÎÄ×ÖÐðÊö½¨Á¢Ñ§¹ýµÄÎïÀíÄ£ÐÍ£¬ÔÚÓ¦ÓùæÂÉÈ¥Çó½â£¬ÊµÖÊÊÇ´øµçÁ£×ÓÔڴų¡ÖÐÔ˶¯µÄÀàÐÍ£¬»­³ö¹ì¼££¬¸ù¾Ý¹ì¼£µÄ¶Ô³ÆÐÔ£¬Óɼ¸ºÎ֪ʶÇó³ö¹ì¼£µÄ°ë¾¶Êǽâ¾ö±¾ÌâµÄ¹Ø¼ü£®