Question

12£®ÈçͼËùʾ£¬ÔÈÇ¿´Å³¡µÄ´Å¸ÐӦǿ¶ÈB=0.5T£¬±ß³¤L=10cmµÄÕý·½ÐÎÏßȦ¹²100ÔÑ£¬ÏßȦ×ܵç×èr=1¦¸£¬ÏßȦÈÆ´¹Ö±ÓڴŸÐÏߵĶԳÆÖáOO'ÔÈËÙת¶¯£¬½ÇËٶȦØ=2¦Ðrad/s£¬Íâµç·Öеĵç×èR=4¦¸£¬Ç󣺣¨¼ÆËã½á¹ûСÊýµãºó±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨1£©¸ÐÓ¦µç¶¯ÊƵÄ×î´óÖµ£»
£¨2£©ÓÉͼʾλÖã¨ÏßȦƽÃæÓë´Å¸ÐÏßƽÐУ©×ª¹ý60¡ãʱµÄ˲ʱ¸ÐÓ¦µç¶¯ÊÆ£»
£¨3£©½»Á÷µçѹ±íµÄʾÊý£»
£¨4£©ÏßȦת¶¯Ò»ÖܲúÉúµÄ×ÜÈÈÁ¿£»
£¨5£©´ÓͼʾλÁD¿ªÊ¼µÄ$\frac{1}{6}$ÖÜÆÚÄÚͨ¹ýRµÄµçºÉÁ¿£®

Answer 1

·ÖÎö £¨1£©ÓÉ×î´óÖµ±í´ïʽ¿ÉÇóµÃ×î´óÖµ£»
£¨2£©ÓÉ˲ʱ±í´ïʽ¿ÉÇó½âÓÉͼʾλÖÃת¹ý60¡ãʱµÄ˲ʱ¸ÐÓ¦µç¶¯ÊÆ£®
£¨3£©µçѹ±íµÄʾÊýΪÓÐЧֵ£¬Çó½âRÁ½¶ËµçѹµÄÓÐЧֵ¼´¿É£»
£¨4£©Óɽ¹¶ú¶¨ÂÉ¿ÉÇóµÃÒ»ÖÜÄÚ²úÉúµÄÈÈÁ¿£»
£¨5£©¸ù¾Ý·¨À­µÚµç´Å¸ÐÓ¦¶¨ÂÉÇó½âƽ¾ùµç¶¯ÊÆ£¬ÔÙÓɵçÁ÷µÄ¶¨ÒåÇó½âµçÁ¿£®

½â´ð ½â£º£¨1£©¸ÐÓ¦µç¶¯ÊƵÄ×î´óֵΪ£ºE_m=NBS¦Ø=100¡Á0.5¡Á0.1²¡Á2¡Á3.14V=3.1V£®
£¨2£©ÓÉͼʾλÖÃת¹ý60¡ãʱµÄ˲ʱ¸ÐÓ¦µç¶¯ÊÆΪ£ºe=E_mcos 60¡ã=¦Ð¡Á0.5V=$\frac{¦Ð}{2}$V=1.6V
£¨3£©½»Á÷µçѹ±íµÄʾÊýΪÍâµç·µçѹµÄÓÐЧֵ£¬¼´Îª£ºU=$\frac{E}{R+r}R$=$\frac{\frac{¦Ð}{\sqrt{2}}}{4+1}$¡Á4V=$\frac{2\sqrt{2}¦Ð}{5}V$=1.8V
£¨4£©ÖÜÆÚT=$\frac{2¦Ð}{¦Ø}=1s$                 
ÏßȦת¶¯Ò»ÖܲúÉúµÄ×ÜÈÈÁ¿Îª£ºQ=£¨$\frac{{E}_{m}}{\sqrt{2}}$£©²$\frac{1}{R+r}$T=$\frac{{¦Ð}^{2}}{10}J$=0.98J
£¨5£©Æ½¾ùµç¶¯ÊÆ£º$\overline{E}=N\frac{¡÷∅}{¡÷t}$
µçÁ÷£º$\overline{I}=\frac{\overline{E}}{R+r}$         
ÔÚ$\frac{1}{6}$ÖÜÆÚÄÚͨ¹ýµç×èRµÄµçºÉÁ¿Îª£º
q=$\overline{I}•¡÷t$           
¼´Îª£ºq=N$\frac{¡÷∅}{R+r}$
µÄ£ºq=$\frac{\sqrt{3}}{20}C$=0.09C£®
´ð£º£¨1£©¸ÐÓ¦µç¶¯ÊƵÄ×î´óÖµ3.1V£®
£¨2£©ÓÉͼʾλÖÃת¹ý60¡ãʱµÄ˲ʱ¸ÐÓ¦µç¶¯ÊÆΪ1.6V
£¨3£©½»Á÷µçѹ±íµÄʾÊý1.8V£®
£¨4£©ÏßȦת¶¯Ò»ÖܲúÉúµÄ×ÜÈÈÁ¿0.98J£®
£¨5£©ÔÚ$\frac{1}{6}$ÖÜÆÚÄÚͨ¹ýµç×èRµÄµçºÉÁ¿Îª0.09C

µãÆÀ ±¾Ìâ¹Ø¼üÊÇÒªÇø·Ö½»Á÷µçµÄÓÐЧֵ¡¢Ë²Ê±Öµ¡¢Æ½¾ùÖµºÍ×î´óÖµµÄÇø±ð£¬ÖªµÀµçÁ÷±íºÍµçѹ±í¶ÁÊýÊÇÓÐЧֵ£¬¼ÆËãÈÈÁ¿ÓÃÓÐЧֵ£¬¼ÆËãµçÁ¿ÓÃƽ¾ùÖµ£®